Add an object 3d without parent/child relationship.

Similar Questions

• parent/child relationship hirarchy

  Hi everyone, consider the sample data

  SELECT LFROM '1TR1Y6', NULL LTO, MID '11ZFDD', '21XHK7' double UNION ALL TID-

  SELECT '1TR1YF' LFROM, LTO NULL, '11ZFDD' MI '21XHK5' TID FROM dual UNION ALL-

  SELECT '1TR1X1' LFROM, LTO NULL, '11ZFDD' MI '21XHK8' TID FROM dual UNION ALL-

  SELECT '1LSZX1' LFROM, LTO NULL, '11ZFDD' MI '1TR1YD' TID FROM dual UNION ALL-

  SELECT LFROM "1LSZWQ", "21XHK7" LTO, MID '11ZFDD', '1TR1Y6' TID FROM dual UNION ALL-

  SELECT LFROM "1LSZX2", "21XHK5" LTO, MID '11ZFDD', '1TR1YF' TID FROM dual UNION ALL-

  SELECT LFROM "1LSZVG", "21XHK8" LTO, MID '11ZFDD', '1TR1X1' TID FROM dual UNION ALL-

  SELECT LFROM "4LSSVG", "21XHK9" LTO "11AAA' MI '1TR1X1' TID double UNION ALL

  SELECT "AAAAA" LFROM, LTO NULL, '11ABB' e, 'CCCCCC' double UNION ALL TID

  SELECT "BATH" LFROM, 'CCCCCC' LTO, MID '11ABB', 'AAAAA' double UNION ALL TID

  some of them have a parent/child releationship. for example, let take rank with LFROM = 1TR1Y6

  1TR1Y6 (lfrom) corresponds to the fifth line with TID 1TR1Y6.  TID 1TR1Y6 LTO COLUMN value corresponds to the first line TID (21XHK7)

  It before these two LINES are IN a parent/child relationship.

  lets take another example.  LINE two WITH LFROM = 1TR1YF matches sixth RANK WITH TID 1TR1YF.  the sixth LINE LTO COLUMN (21XHK5) corresponds to the SECOND TID of LINE.

  Once again the parent child relationship. There are two lines that do not have the relationship of parent/child (ex.  line 8)

  Im trying to write a query that can partition the data in the middle column and find the parent/child relationship. the output of the above data should be

  LTO LFROM MIDDLE TID FLAG

  1TR1Y6 NULL 11ZFDD 21XHK7 1

  1LSZWQ 21XHK7 11ZFDD 1TR1Y6 1

  1TR1YF NULL 11ZFDD 21XHK5 1

  1LSZX2 21XHK5 11ZFDD 1TR1YF 1

  1TR1X1 NULL 11ZFDD 21XHK8 1

  1LSZVG 21XHK8 11ZFDD 1TR1X1 1

  1LSZX1 NULL 11ZFDD 1TR1YD 0

  4LSSVG 21XHK9 11AAA 1TR1X1 0

  ABDELKÉBIR 11ABB CCCCCC NULL 1

  CCCCCC 11ABB AAAAA BATH 1

  For simplicity, I posted the release with parent/child, side by side in the sequence.  the order does not matter as long as the flag column (pull the column) is set to an appropriate value (1 if parent/child, 0 no parent/child)

  the flag column value is derived from column to indicate the parent/child relationship was found.

  I try using lead, the lag function but I have problem of sorting data from parent and child line could come at random order (they are not side by side).

  It is therefore difficult to use lead because you don't know how many lines to carry forward.

  can someone help me write a query that displays the output above

  SELECT T1. LFROM,

  T1. LTO,

  T1. ENVIRONMENT,

  T1. TID,

  (

  SELECT COUNT (*)

  OF TBL T2

  WHERE)

  T2. TID = T1. LFROM

  OR

  T2. LFROM = T1. TID

  )

  AND T2. MI = T1. MID

  ) FLAG

  OF TBL T1

  /

  LTO LFROM MIDDLE TID FLAG
  ------ ------ ------ ------ ----------
  1LSZWQ 21XHK7 11ZFDD 1TR1Y6 1
  1LSZX2 21XHK5 11ZFDD 1TR1YF 1
  1LSZVG 21XHK8 11ZFDD 1TR1X1 1
  CCCCCC 11ABB AAAAA BATH 1
  1TR1X1 11ZFDD 21XHK8 1
  1TR1X1 11ZFDD 21XHK8 1
  1LSZX1 11ZFDD 1TR1YD 0
  1TR1Y6 11ZFDD 21XHK7 1
  ABDELKÉBIR 11ABB CCCCCC 1
  1TR1YF 11ZFDD 21XHK5 1
  4LSSVG 21XHK9 11AAA 1TR1X1 0

  11 selected lines.

  SQL >

  SY.

• in the query and parent/child relationship

  WITH the data AS

  (

  SELECT '213NY1' lfrom, NULL, '215ZVD' mi lto, "215ZV9 ' id, 1 January 2014' sdate, January 2, 2014' edate, 3 January, 2014 'mdate' January 5, 2014 medate double UNION ALL.

  Lfrom SELECT NULL, '215ZVD' mi, id "213NY1", "215ZV9" lto 4 January 2014 'sdate', 6 January 2014 edate, January 7, 2014 'mdate', 8 January 2014 medate double UNION ALL

  SELECT '216TVZ' lfrom, NULL, "213JW7" e "217LVQ" id lto, 21 January, 2014 'sdate' January 9, 2014 edate, 10 January 2014 'mdate', 11 January 2014 medate double UNION ALL

  SELECT lfrom "215Y71", "217LVQ" lto, mi, "216TVZ" id "213JW7", 22 January, 2014 'sdate' January 23, 2014 edate, 24 January, 2014 'mdate' January 25, 2014 medate double UNION ALL

  SELECT '234IJF' lfrom, NULL, "234YU" e "3IUED" id lto, 26 January 2014 'sdate', 27 January 2014 edate, 28 January 2014 'mdate', 29 January 2014 medate OF double

  )

  some lines have parent/child relationship and some does not. for example, the first two query (data) are link together. online, the value of lto (215ZV9) corresponds to the id value

  in line 1.  the value of lfrom in row1 (213NY1) corresponds to the value of online id.

  the same scenario occurs in rows 3 and 4.  5th doesn't have any line which is a child. tier 5 is a single parent

  I want to WRITE a query that gives the following result.

  Mid id initial_date final_date

  =======================================

  215ZVD 215ZV9 1 January 2014 "January 5, 2014"

  "215ZVD 213NY1 7 January 2014" January 6, 2014 "

  "213JW7 217LVQ 21 January 2014 ' 11 January 2014"

  "213JW7 216TVZ 24 January 2014 ' 23 January 2014"

  "234YU 3IUED 26 January 2014 ' 27 January 2014"

  ONLY WHEN there is a parent/child relationship, initial DATE AND follow the final data WHAT such as

  FIRST date of deadline DATE

  < Mdate > < EDate > - for child

  < SDate > < MEDate > - for parent

  WHEN there is no relationship of parent/child (e.g. ONLY a parent ROW) THEN

  FIRST date of deadline DATE

  < SDate > < EDate-> parent

  can someone help me write a query for the above output

  with tt AS

  (SELECT a.*,

  ROW_NUMBER () ON LV (MIDDLE ORDER BY SDATE PARTITION),

  CASE

  WHEN ID = NVL (ADVANCE (lto, 1) OVER (PARTITION BY Middle ORDER BY sdate), LAG (lfrom) OVER (ORDER BY sdate Middle PARTITION))

  THEN 1

  END flg

  DATA one

  )

  SELECT THE MIDDLE,

  ID,

  CASE

  WHEN flg IS NOT NULL

  THEN

  CASE

  WHAT LV = 1

  THEN SDATE

  WHAT LV = 2

  THEN mDATE

  END

  Of ANOTHER sdate

  END INITIALDATE

  CASE

  WHEN flg IS NOT NULL

  THEN

  CASE

  WHAT LV = 1

  THEN mEDATE

  WHAT LV = 2

  THEN EDATE

  END

  Of ANOTHER edate

  END FINALDATE

  TT;

  Output:

  -------------

  MID ID INITIALDATE FINALDATE

  213JW7 217LVQ 21 January 2014 January 11, 2014

  213JW7 216TVZ 24 January 2014 23 January 2014

  215ZVD 215ZV9 January 1, 2014 5 January 2014

  215ZVD 213NY1 January 7, 2014 6 January 2014

  234YU 3IUED 26 January 2014 January 27, 2014

• Implementation of Parent / child relationships

  How to define a group of elements (symbols placed on the stage) as children of another element.  When I drag/select the Group of elements that are the children and drop them on top of the element that must be the parent, the relationship is not to be trained and the 'drop' is not currently permitted.

  I guess I must be watching older videos because the tutorials I have seen has indicated that dragging a layer on top of the other in the assets Panel would lead the moved element becomes the child of the element on which it was abandoned, but this doesn't seem to work.

  Thank you.

  Andy.

  Hi, Andy.

  Yes, it should work, but there are some types of items that may not be parents, like Text and Image divs.  You can try to draw a rectangle, then by dragging on it.  If this does not work, let us know so that we can begin to study more deeply.

  Thank you

  -Elaine

• Parent - child relationship constraint Unique 5.0 apex oracle

  Oky so I will try to avoid duplicate values get inserted in the parent-child node.

  So basically when there's a node parent (Mobile) I can't create same node with the same name.

  Even for the child node, if there is a child node name there may be another named A.

  Structure:

  Mobile (parent) /Android (Child) /KitKat (subchild) (allowed)

  Mobile/apple/ios(Now allowed Same Parent name)

  Win7/Windows/win7(not allowed same child)

  So a big child and the parent must be unique at any time.

  

  create an index of single "TEST_UK" on tablename (parent_id, upper (child_name));

  see this too for a case-insensitive unique constraint

  Case-insensitive unique constraint

• How to create parent/child relationships between objects? whereas if I change one, I change all

  I have multiple instances of an object, and I would like to make the changes that I put on one of these objects in order to perpetuate and change on the other instances of the object

  turn your object into a symbol and place several instances of it on the artboard when you edit the symbol of all instances will be updated.

• Effort using Outer join parent-child relationship

  Oracle Database 10 g Express Edition Release 10.2.0.1.0 - product
  
  I have the following tables
  
  

  CREATE TABLE  "ADDPROJECT" 
     (     "PROJID" VARCHAR2(30) NOT NULL ENABLE, 
       "PROJNAME" VARCHAR2(30), 
       "PROJSTARTDATE" DATE, 
       "PROJENDDATE" DATE, 
       "PARENTPROJID" VARCHAR2(30), 
       "PROJTYPE" VARCHAR2(30), 
       "PROJSTATUS" VARCHAR2(30), 
        PRIMARY KEY ("PROJID") ENABLE
     )
  
  CREATE TABLE  "ALLOCATEASSOCIATES" 
     (     "PROJID" VARCHAR2(30) NOT NULL ENABLE, 
       "ASSOCIATEID" NUMBER(*,0) NOT NULL ENABLE, 
       "ALLOCATIONSTARTDATE" DATE, 
       "ALLOCATIONPERCENT" NUMBER(*,0), 
       "ENDDATE" DATE, 
        PRIMARY KEY ("PROJID", "ASSOCIATEID") ENABLE
     )
  
  CREATE TABLE  "ADDRESEARCHAREA" 
     (     "RAID" VARCHAR2(30) NOT NULL ENABLE, 
       "RANAME" VARCHAR2(30), 
       "RASTARTDATE" DATE, 
       "RAENDDATE" DATE, 
       "PARENTRAID" VARCHAR2(30), 
       "RASTATUS" VARCHAR2(30), 
        PRIMARY KEY ("RAID") ENABLE
     )
  
  CREATE TABLE  "PROJECTTORAASSOCIATION" 
     (     "RAID" VARCHAR2(30) NOT NULL ENABLE, 
       "PROJID" VARCHAR2(30) NOT NULL ENABLE, 
       "STARTDATE" DATE, 
       "ENDDATE" DATE, 
       "STATUS" VARCHAR2(30), 
        PRIMARY KEY ("RAID", "PROJID") ENABLE
     )
  
  insert into addresearcharea values ('ra1','raname1',to_date('04/01/2012','mm/dd/yyyy'),'','','Active')
  insert into addresearcharea values ('ra2','raname2',to_date('04/01/2012','mm/dd/yyyy'),'','','Active')
  insert into addresearcharea values ('ra3','raname3',to_date('04/01/2012','mm/dd/yyyy'),'','','Active')
  insert into addresearcharea values ('ra4','raname4',to_date('04/01/2012','mm/dd/yyyy'),'','ra1','Active')
  insert into addresearcharea values ('ra5','raname5',to_date('04/01/2012','mm/dd/yyyy'),'','ra1','Active')
  insert into addresearcharea values ('ra6','raname6',to_date('04/01/2012','mm/dd/yyyy'),'','ra2','Active')
  
  insert into addproject values ('proj1','projname1',to_date('04/01/2012','mm/dd/yyyy'),'','','Research','Active')
  insert into addproject values ('proj2','projname2',to_date('04/01/2012','mm/dd/yyyy'),'','','Research','Active')
  insert into addproject values ('proj3','projname3',to_date('04/01/2012','mm/dd/yyyy'),'','','Research','Active')
  
  insert into projecttoraassociation values ('ra1','proj1',to_date('04/01/2012','mm/dd/yyyy'),'','Active')
  insert into projecttoraassociation values ('ra4','proj1',to_date('04/01/2012','mm/dd/yyyy'),'','Active')
  insert into projecttoraassociation values ('ra2','proj2',to_date('04/01/2012','mm/dd/yyyy'),'','Active')
  insert into projecttoraassociation values ('ra3','proj3',to_date('04/01/2012','mm/dd/yyyy'),'','Active')
  
  insert into allocateassociates values ('proj1',1,to_date('04/01/2012','mm/dd/yyyy'),100,'')
  insert into allocateassociates values ('proj1',2,to_date('04/01/2012','mm/dd/yyyy'),100,'')
  insert into allocateassociates values ('proj2',3,to_date('04/01/2012','mm/dd/yyyy'),100,'')

  In short, here is the data
  
  Research areas: ra1, ra2, ra3
  Void / areas of research for AM1: ra4, ka5
  Void / areas of research for ra2: qxf6
  Void / areas of research for ra3: -.
  
  Projects - proj1, proj2.proj3
  
  Mapping of the area of research projects
  Proj1: ra1 and ra4
  Proj2: ra2
  
  Associate the allocation
  Proj1: 1,2
  Proj2: 3
  
  I need to get wise effort search space and subarea displayed on the same row (if the project is also associated with the search of sub box)
  The user must be able to choose a particular area of research and the results displayed accordingly
  Results expected in the cases where no specific research field are selected

  EFFORT PROJECTID PROJECTNAME RANAME SUBRANAME 
  12.70 proj1 projname1 raname1 ra4 
  6.35 proj2 projname2 raname2 - 
  - proj3 projname3 raname3 - 

  Production in the event of main search box is selected (for example:-ra1)

  EFFORT PROJECTID PROJECTNAME RANAME SUBRANAME 
  12.70 proj1 projname1 raname1 ra4 

  The expected results in the area of research case void are selected (for example:-ra4)

  EFFORT PROJECTID PROJECTNAME RANAME SUBRANAME 
  12.70 proj1 projname1 raname1 ra4 

  The query I wrote

  SELECT 
  to_char(
      SUM(
         (MONTHS_BETWEEN(
                 1+LEAST(
                    LEAST(
                       LEAST(
                            nvl(ar.raenddate,to_date('04/01/2100','mm/dd/yyyy'))
                            ,nvl(pr.enddate,to_date('04/01/2100','mm/dd/yyyy')))
                    ,nvl(aa.enddate,to_date('04/01/2100','mm/dd/yyyy')))
                ,sysdate),
                GREATEST(
                   GREATEST(
                      GREATEST(
                              ar.rastartdate
                              ,pr.startdate)
                         ,aa.allocationstartdate)
                ,to_date('04/01/2012','mm/dd/yyyy'))) 
      * aa.allocationpercent / 100 
      ))
    ,999.99)    AS EFFORT,
  aa.projid AS PROJECTID,
  ap.projname AS PROJECTNAME,
  ar.raname AS RANAME,
  ar2.raid AS SUBRANAME
  FROM AllocateAssociates aa,ProjecttoRAAssociation pr,addProject ap,AddResearchArea ar, AddResearchArea ar2
  WHERE pr.projid = aa.projid (+)
  AND aa.projid = ap.projid 
  AND pr.raid = ar.raid
  AND ar.raid = ar2.parentraid (+)
  group by aa.projid,ap.projname,ar.raname,ar2.raid

  The problems I am facing
  1. I need to get a list of projects that are associated with the search box even if they have no allocation of project. Although I used the outer join, I don't get this result. I used the full outer join, but gave the expected result. (Since there are several tables to assemble. maybe something wrong to join to?) (in the above data, proj3 must also be displayed even if it doesn't have an allocation of project)
  2. If a search box has more than one field of research, there are 2 entries for each sub research field even if the project has been associated with the search under a single box (in the above data, the proj1 has been associated with ra4 only, but the results display the ra4 and ka5)
  3. the query shows two entries for the main research area and one for the research sub area (provided that the project is associated with the correct principal and under research field). But there should be just an entry in a space research containing the name of the two main and under research field
  
  Please help me to solve these problems.
  

• Simulate the 1 - N N - N relationship using the Parent-child structure

  Hello
  
  I have a 1-N relation between SKILL tables and the USER, which means 1 skill can be applied to multiple users. A jurisdiction may have a parent jurisdiction, which means that a ParentSkill inherits all the privileges of his child.
  
  I would like to simulate a N - N relation between the users and the skills by building a vision that goes through the parent-child relationship. This is possible for the construction?
  
  
  Current structure:

  |USERID | USERNAME | SKILLID  |
  +-------+----------+----------+
  |   1   |  Jack    |      1   |
  |   2   |  Simon   |      1   |
  |   3   |  Fred    |      3   |
  +-------+----------+----------+
  
  
  |SKILLID | DESCRIPTION   | PARENTSKILL  |
  +--------+---------------+--------------+
  |   1    |  Mechanic     |      2       |
  |   2    |  Inspector    |      3       |
  |   3    |  Supervisor   |      null    |
  +--------+---------------+--------------+

  Favorite exit (the skillid order is not important):

  |USERID | USERNAME | SKILLID  |
  +-------+----------+----------+
  |   1   |  Jack    |      1   |
  |   2   |  Simon   |      1   |
  |   3   |  Fred    |      3   |
  |   3   |  Fred    |      2   |
  |   3   |  Fred    |      1   |
  +-------+----------+----------+

  I hope that answers your needs:

  WITH
  users as
  (
      SELECT 1 as USERID, 'Jack' as USERNAME, 1 as SKILLID FROM DUAL UNION ALL
      SELECT 2 as USERID, 'Simon' as USERNAME, 1 as SKILLID FROM DUAL UNION ALL
      SELECT 3 as USERID, 'Fred' as USERNAME, 3 as SKILLID FROM DUAL
  ),
  skills as
  (
      SELECT SKILLID,CONNECT_BY_ROOT SKILLID AS ANCESTORS
      FROM
          (
              SELECT 1 as SKILLID, 'Mechanic' as DESCRIPTION, 2 as PARENTSKILL FROM DUAL UNION ALL
              SELECT 2, 'Inspector', 3 FROM DUAL UNION ALL
              SELECT 3, 'Supervisor', NULL FROM DUAL
          )
      CONNECT BY PRIOR PARENTSKILL = SKILLID
  )
  SELECT USERID,USERNAME,ANCESTORS
  FROM skills, users
  WHERE users.skillid = skills.skillid
  /
  

      USERID USERN  ANCESTORS
  ---------- ----- ----------
           1 Jack           1
           2 Simon          1
           3 Fred           3
           3 Fred           2
           3 Fred           1
  

  I hope this helps!

• Default filters that users can delete (in the parent/child Setup)?

  Is it possible in Latitude 2.2.2 to have filters (filters of the range, refinement filters etc.) applied by default (which means that users see these filters when they log-in), but they can also remove (using bread crumbs portlet) if they wanted to? We tried to use the source of data (JSON) filters (using 'baseFunctions' setting) where we have a parent/child Setup, but it seems these filters cannot be removed once applied. Note that filters can be removed if we do not have a parent/child relationship between the data sources, but as soon as we introduce a parent/child relationship between the data sources (which we need), the GET of sticky filters and cannot be deleted. Any reason why the parent/child relationship causes the filters becoming sticky? Any way (alternate) to reach what we want?

  I think that it is a known problem (LSTUDIO-5088) and there could be a fix for this. You can contact technical support to obtain the fix.

  Dave

• Fusion of data/result defines what are parent/child?

  Hello:
  
  I have seen a few examples to make a data model so that a BI report can have master-detail data. They are a set of Q1 data and a set of T2 data with a variable binding to connect the two in a parent/child relationship.
  
  But what I need, it is actually a UNION. I have the same table on multiple instances of database and I want to show the results grouped in a single report, as if it all happened to a table. Examples of master-detail have a section defining the grouping but they group Q1 (see here)
  
  http://blogs.Oracle.com/BIDeveloper/data_template/
  
  and I need to regroup in a column in Q1 and Q2 to "merge" the two sets of data.
  
  Does anyone do this?
  
  Thank you.

  If you define multiple SQL-queries/data models data sets, you can combine them into a single set of data by selecting the concatenated SQL Data Source.

  Choose concatenate them box, concatenation will result in the union.

  RTF again, you can use the two dataset and display as a single table.

• Parent child query

  I got the exit for parent-child relationships
  
  Select
  LPAD (' ', 2 * level) | child
  Of
  prune_test
  Start by
  parent is null
  connect
  child precondition = parent
  
  as
  1
  -12
  -120
  -124
  -127
  -712
  -7122
  -7125
  -7127
  
  But I want like
  Parent child Child1 2 child3
  1
  1 12
  1 12 120
  1-12-124
  1-12-127
  1 12 712
  1 12 712 7122
  1 12 712 7125
  1 12 712 7127
  
  Can someone help me...
  Thank you
  Mani
  
  Published by: Mani on November 4, 2010 18:54

  Do you just need a sys link by road

  with prune_test as
  (select null parent, 1 child from dual union all
   select 1, 12 from dual union all
   select 12, 120 from dual union all
    select 12, 124 from dual union all
     select 12, 127 from dual union all
     select 12, 712 from dual union all
     select 712,71522 from dual union all
     select 712, 7125 from dual union all
     select 712, 7127 from dual
     )
  
  select
  lpad(' ', 2*level) || child, sys_connect_by_path(child,' ')
  from
  prune_test
  start with
  parent is null
  connect by
  prior child=parent 
  

  LPAD('',2*LEVEL)||CHILD     SYS_CONNECT_BY_PATH(CHILD,'')
    1           1
      12            1 12
        120      1 12 120
        124      1 12 124
        127      1 12 127
        712      1 12 712
          71522      1 12 712 71522
          7125      1 12 712 7125
          7127      1 12 712 7127
  

• Update the data to uppercase in the parent/child tables

  Hi gurus!
  
  In production, we have a table product and that is in reference by many tables making parent child relationship. By mistake, we realized last month some products have been added to lowercase and now we have a request to update all these product codes uppercase so that existing code that use these tables have no impact. Appreciate if you can give an idea about how can I update the existing data in the table parent uppercase as well as child records?
  
  Concerning
  Sri

  Are the product code that you need to update what is stored in the tables of children? If Yes, then you must do it in several steps, something like:

  Identify the child tables

  SELECT table_name, constraint_name
  FROM user_constraints
  WHERE r_constraint_name = (SELECT constraint_name
                             FROM user_constraints
                             WHERE table_name = 'PRODUCT_TABLE' and
                                   constraint_type = 'P');
  

  Create new product of upper-case code in the product table:

  INSERT INTO product_table
  SELECT UPPER(product_code), other_columns
  FROM product_table
  WHERE product_code <> UPPER(product_code);
  

  Update the children tables for caps product codes

  UPDATE child1
  SET product_code = UPPER(product_code)
  WHERE product_code <> UPPER(product_code);
  

  Finally, remove the tiny product_table product codes

  DELETE FROM product_table
  WHERE product_code <> UPPER(product_code);
  

  John

• Sum of a stand-alone parent-child table

  I have two tables - a 'key' table containing a parent-child relationship of multi-layer and a table 'amount' that contains the keys for the nodes in the key as well as table of numeric values (for example the amounts).
  I want a query that returns each line in the table of key as well as the sum of the amount amounts of the table for the set of nodes of this key (so the root node would be the sum of all values of quantity).
  
  Here's what I mean: I have two tables, the KEY and the AMOUNT
  
  KEY has two columns, keys, and parent_key; key and parent_key have a relationship CONNECT BY parent_key = prior key (with null for the root parent_key):

  KEY     PARENT_KEY
  0       null
  1       0
  2       0
  3       0
  1A      1
  2A      2
  2B      2
  3A      3
  3B      3
  3C      3
  1A1     1A
  1A2     1A
  2A1     2A
  2A2     2A
  2B1     2B
  3A1     3A
  3A2     3A
  3C1     3C
  3C2     3C

  AMOUNT a two columns, keys, and amount; key points to KEY.key and amount is a value for that particular key
  (Note that all key values are leaf nodes in the KEY table)

  KEY     AMOUNT
  1A1     1 
  1A2     2 
  2A1     3 
  2A2     4 
  2B1     5 
  3A1     6 
  3A2     7 
  3C1     8 
  3C2     9 

  What I want is a result that looks like this, where the amount of each key is the sum of the amounts of its possible keys sheet

  KEY     AMOUNT
  0       45
  1        3
  2       12
  3       30
  1A       3
  2A       7
  2B       5
  3A      13
  3B       0
  3C      17
  1A1      1
  1A2      2
  2A1      3
  2A2      4
  2B1      5
  3A1      6
  3A2      7
  3C1      8
  3C2      9

  For example, the value of the key 2 a, 7, is the sum of the values of 2 a 1 and a 2, 2; key value of 3 is the sum of 3 a 1, a 3, 2, 3, C 1 and 2 of 3.
  
  Is it possible to do this with a single query?
  The idea I came with is, do a select on the KEY with a "Key CONNECT_BY_PATH" column so that each line contains a string that contains the keys of all his ancestors and then do a join on AMOUNT with IN the CONNECT_BY_PATH amount.key column; However, with a large amount of data, it takes a little time. Is there a way faster / more obvious to achieve?

  OK you have almost everything you need. Outer join just your two tables, and then perform a hierarchical query, noting the key root of each tree. Then group the data set resulting:

  with t1 as (select '0' "KEY", '' parent_key from dual
    union all select '1', '0' from dual
    union all select '2', '0' from dual
    union all select '3', '0' from dual
    union all select '1A', '1' from dual
    union all select '2A', '2' from dual
    union all select '2B', '2' from dual
    union all select '3A', '3' from dual
    union all select '3B', '3' from dual
    union all select '3C', '3' from dual
    union all select '1A1', '1A' from dual
    union all select '1A2', '1A' from dual
    union all select '2A1', '2A' from dual
    union all select '2A2', '2A' from dual
    union all select '2B1', '2B' from dual
    union all select '3A1', '3A' from dual
    union all select '3A2', '3A' from dual
    union all select '3C1', '3C' from dual
    union all select '3C2', '3C' from dual
  ), t2 as (select '1A1' "KEY", 1 amount from dual
    union all select '1A2', 2 from dual
    union all select '2A1', 3 from dual
    union all select '2A2', 4 from dual
    union all select '2B1', 5 from dual
    union all select '3A1', 6 from dual
    union all select '3A2', 7 from dual
    union all select '3C1', 8 from dual
    union all select '3C2', 9 from dual
  ), t3 as (
    select t1.key, parent_key, amount
      from t1 left join t2 on t1.key = t2.key
  ), t4 as (
    select CONNECT_BY_ROOT key root_key
         , level lv
         , t3.*
      from t3
      connect by prior t3.key = parent_key
  )
  select root_key "KEY", sum(amount) amount
    from t4
   group by root_key
   order by length(root_key), root_key;
  

• get the error Y child member without parent (3331)

  After updating a cube ASO I get error "child member there without parent (3331). Can someone help me.
  
  thanx
  GYAN

  It can be space or a special character after the Member or an alias name. Remove it and build the hierarchy again it should solve this problem.

  Thank you

• Relationship parent child

  Hello
  
  My data are like that.
  
  PARENT CHILD
  1
  6
  7
  1 12
  1 14
  1 15
  6 61
  6 65
  7 71
  12 120
  12 124
  12 127
  71 712
  712-7122
  
  My required output is
  Parent child
  1 12
  1 120 (12 is the parent for this. But I need to Parent of 12 or 1 (Parent) main)
  1 124 - do-
  1 127 - do-
  7 71
  7 712 (71 is the parent for this. But I need Parent 71 or 7 (main Parent))
  7-7122 (712's parent.)
  
  The origin of this child, I need. How to get there. PL. help.
  
  Thanks in advance
  
  Mano.

  Hello

  This one?

  SQL>
  SQL> with data as (
    2  select null parent , 1 child from dual union all
    3  select null , 6 from dual union all
    4  select null , 7 from dual union all
    5  select 1, 12 from dual union all
    6  select 1, 14 from dual union all
    7  select 1, 15 from dual union all
    8  select 6, 61 from dual union all
    9  select 6, 65 from dual union all
   10  select 7, 71 from dual union all
   11  select 12, 120 from dual union all
   12  select 12, 124 from dual union all
   13  select 12, 127 from dual union all
   14  select 71, 712 from dual union all
   15  select 712, 7122 from dual )
   16  select connect_by_root(child),child  from data
   17  where level > 1
   18  start with parent is null
   19  connect by prior child = parent
   20  /
  
  CONNECT_BY_ROOT(CHILD)      CHILD
  ---------------------- ----------
                       1         12
                       1        120
                       1        124
                       1        127
                       1         14
                       1         15
                       6         61
                       6         65
                       7         71
                       7        712
                       7       7122
  
  11 rows selected.
  
  SQL> 
  

  T

  The amended version looks more like your needs

  Published by: ttt on 17.3.2010 01:16