Adding a column of hours and minutes

Similar Questions

• Adding the hours and minutes

  I want to add a long list of hours and minutes in numbers.

  The list will come to 1000 + hours and I want that it displays the actual number of hours and minutes, not expressed in days.

  Impossible to find a way to format the cells to allow me to th

  Did you try & see if a few suggestions here may work?

  • Create a custom cell format - Numbers Help for Mac:

  http://help.Apple.com/numbers/Mac/3.2/#/tan090042718

  The database can provide also other useful elements, if ticked off more.

  Good luck & happy computing!

• convert a number in days, hours and minutes

  Hello

  I have a table that store minutes unpaid.

  I want to get the days, hours and minutes in separate columns

  After working hours, a day is considered to be 8 hours

  That is to say. 480 minutes is considered to be one day.

  create the table unpaidmins as

  (

  Select 480 as unpaidmins of all the double union

  Select 420 as unpaidmins of all the double union

  Select 75 as unpaidmins of all the double union

  Select 55 as double unpaidmins

  )

  
  

  Required result

  --------------------------------------------------------------------

  DAY HOURS MINUTES

  ---------------------------------------------------------------------

  1                         0                          0
  

  
  

  0                         7                         0

  
  

  0                         1                          15
  

  
  

  0                         0                           55

  
  

  -------------------------------------------------------------------

  
  

  
  

  I use oracle 10g

  
  

  Help, please

  
  

  
  

  
  

  
  

  
  

  Select

  trunc(unpaidmins/60/8) as 'DAY '.

  , trunc (mod (unpaidmins, 60 * 8) / 60) "the hours."

  , mod (mod (unpaidmins, 60 * 8), 60) as "MINUTES".

  of unpaidmins

  DAY HOURS MINUTES

  "1"    "0"    "0"

  "0"    "7"    "0"

  "0" "1" "15".

  "0" "0" "55".

• conversion from minutes to hours and minutes

  Hi all
  
  I want to do two things
  
  1. I want to convert minutes to hours and minutes which is
  If there are 350 minutes it should be 5.50
  
  2. I have two times column hrs and time allowed minutes now, I want to join this two in
  in this way
  for example the hrs is 5 and time allowed mins is 40 so I should be join under 5.40
  
  
  Concerning
  Aerts.

  Hello

  The code is a little more readable now, but only a little.

  For example, I can see now that you call most GRAND where the 1st argument is a string:

      greatest(TO_CHAR ( FLOOR (((timeallowedhrs*60+timeallowedmins)-(timetakenhrs*60+timetakenmins)) / 60)) || ':'
  

  This can cause the error, if the 2nd argument is a NUMBER, but how anyone can find what is the 2nd argument to the LARGEST?
  Even though this may not cause the error ORA-01722, there is a good chance that it will give you wrong results. The string "2.00 ' is longer than the string"10 h 45', 2 'being greater than 1'. Perhaps you meant to do more BIG first, then TO_CHAR or maybe you menat another thing altogether.

  You can simplify the code you a lot if you did some calculations (such as (timeallowedhrs * 60) + timeallowedmin) only once, in a subquery.
  For example:

  INSERT INTO  prtempincent (...)
  WITH   got_a_t     AS
  (
       SELECT DISTINCT
            (timeallowedhrs * 60) + timeallowedmin     AS a
       ,     (timetakenhrs   * 60) + timetakenmin     AS t
       ,     jobcardno
       ,     shop
       ...
  )
  SELECT     jobcardno
  ,     '3'
  ,     ... FLOOR ( (a - t)
                  / 60
              ) || ':'
                || TO_CHAR ( MOD ( (a - t)
                                         , 60
                           )
                        , 'FM00'
                        ) ...
  

  I find

  a - t
  

  easier to read and understand (and debug), that

  (timeallowedhrs*60+timeallowedmins)-(timetakenhrs*60+timetakenmins)
  

  How about you?

• Convert seconds to hours and minutes

  Hello
  
  I have a column that stores the elapsed time in seconds. I would like to convert to hours and minutes.
  
  FOR EXAMPLE
  
  126 seconds = 2:06. I can't find anything with a search.
  
  Thanks in advance.

  Hello
  Try this code.
  Salim cordially.

  SELECT TO_CHAR (TRUNC (SYSDATE) + NUMTODSINTERVAL (126, 'second'),
                  'hh24:mi:ss'
                 ) hr
    FROM DUAL;
  
  HR
  --------
  00:02:06
  
  1 row selected.
  

• DateTime picker - given to zero hours and minutes on the second click on the datepicker

  Hello

  (APEX 5.0.1 DB 11.2.0.3.0, operating system IBM AIX 7.1, time zone + 1 hour GMT Bratislava)

   

  we have the date picker in the form region with the date format JJ. MM YYYY HH24

  by clicking "Photo calendar" calendar appears with the date and the time displayed

  This means that you can see in "hours selector" currently and in 'selector of minutes', you can see current minutes

  You can change the date, the hour and minute you want

  by clicking on the button "Close" you get the date and time in the date field picker

  So far so good

  However,.

  If you click again on the calendar "Button photo calendar" appears and

  If your current time (I mean normally on a day) is at 09:59

  You will get Zero (0) hours in the hours, selector

  After you present is from 10:00 correct, you will get 10, 11, 12, 13, etc.

  It's for hours and minutes

  If your current time is 10 minutes, for example 08: 07 , 11: 09 , 12: 03 , etc

  On the second click, you'll get Zero (0) minutes

  Similar problem is in the format JJ. MM YYYY HH: mi where you get the 01 in selector hours until 10:00

  Will he please, focus on the fact that it is always on the second, third,... do not click on the first.

  Any ideas please?

  Kind regards.

  Hello

  It was recorded just as a default of 22376688.

  Thank you.

• Add the hours and minutes so far

  Hello
  I need to write a function that has two input parameters.
  Parameter1 = > Date data type, the value is in GMT.
  Parameter1 = > string value that indicates the time difference and it has the following format.
  
  GMT (sign) HH24Mi
  for the examples:
  GMT + 400, GMT-1400
  
  I need to add the offset (param2) to date (param1) and returned as output.
  
  I wrote a simple code but cannot make it work. I would like to know if there is another way to do it.
  

  create or replace
  Function         F_FUNCTION_NAME(dt date,timeZoneOffset   in   varchar2)
  return date
  As
      offset  varchar2(9);    
  Begin
      Offset := (To_Char(Substr(Substr(Timezoneoffset,4),0,Length(Substr(Timezoneoffset,4))-2)||':'||Substr(Substr(Timezoneoffset,4),-2)));
      return Dt + interval Offset hour to minute;
  End;

  Thank you.

  Hello

  Delete GMT and use the colon between the hours and minutes in this way:

  ALTER SESSION SET nls_date_format='DD-MON-YYYY HH24:MI:SS';
  
  SELECT SYSDATE
       , CAST (CAST (SYSDATE AS TIMESTAMP WITH TIME ZONE) AT TIME ZONE '+4:00' AS DATE) offset_date
    FROM DUAL;
  
  SYSDATE                OFFSET_DATE
  ---------------------- ----------------------
  06-MAR-2013 12:08:01   06-MAR-2013 15:08:01  
  

  Kind regards.
  Al

• How to convert minutes to hours and minutes?

  Hi Sir,
  
  I want to convert minutes is 90 you want to convert hours and minutes this format should be
  
  01:30 format.
  
  I can't in this format?
  
  Thank you

  Or like this...

  SQL> select to_char(trunc(sysdate)+90/(24*60),'HH24:MI') from dual;
  
  TO_CH
  -----
  01:30
  

• Problem converting from minutes to hours and minutes

  Hello
  
  I have a problem with this sql, the locations of this sql is to convert minutes to hours and minutes, for example, as you can see, I'm trying to convert 125 minutes in hours and minutes, so the result I get is 2.5 but it should be of 2.05
  
  If you have an idea how I could get the result to the format: 2.05 which means two hours and 5 minutes?
  
  It's my sql:

  Select trunc(125/60) || '.' || (125 - TRUNC(125/60)*60) result FROM dual;

  Thanks and greetings
  Carlos

  Select trunc(125/60) || '.' || lpad(mod(125,60),2,'0') result FROM dual;
  
  RESU
  ----
  2.05
  
  SQL> 
  

  SY.

• Display the duration in hours and Minutes

  DB version: 11.2.0.4

  We must find the time by finding the difference between END_TIME of START_TIME in the following table.

  I have a requirement in which, if the duration is more than 60 minutes, and then view it in hours: Minutes

  Results below. Is it possible that I can do this?

  create the table event_timings

  (

  event_name VARCHAR2 (3),

  date of the value of start_Time,

  end_time date

  );

  insert into event_timings values ('A', to_date (July 16, 2014 09:15 ',' dd-mm-yyyy hh24 '), to_date (July 16, 2014 09:47 ',' dd-mm-yyyy hh24 '));

  insert into event_timings values ('B', to_date (July 16, 2014 11:15 ',' dd-mm-yyyy hh24 '), to_date (July 16, 2014 12:35 ',' dd-mm-yyyy hh24 '));

  insert into event_timings values ('C', to_date (July 16, 2014 08:15 ',' dd-mm-yyyy hh24 '), to_date (July 17, 2014 11:30 ',' mm-dd-yyyy hh24 '));

  ALTER session set nls_Date_format = "dd-mm-yyyy hh24."

  SQL > select * from event_timings;

  END_TIME-START_TIME EVE

  --- ---------------- ----------------

  A 16/07/2014 09:15 16/07/2014 09:47

  B 16/07/2014 11:15 16/07/2014 12:35

  C 16/07/2014 08:15 17/07/2014 11:30

  Expected results:

  Duration of the event

  -----      --------

  A 32-minute

  B 1 hour 20 minutes

  C 27 h 15 Minutes

  Hi James,

  With the traditional way of "old":

  SELECT

  event_name,

  CASE

  WHEN h > 1

  THEN TRUNC (h) | 'Hours ' | Round ((h-trunc (h)) * 60) | "' Minutes

  ON THE OTHER

  Round (h * 60) | "' Minutes

  END

  FROM (SELECT event_name, (24 *(end_time-start_time)) event_timings h)

  ;

• FIND THE HOURS AND MINUTES IN THE DATES

  Hello
  
  I REQUIRE THE OUTPUT IN HOURS, MINUTES FOR THE DIFFERENCE BETWEEN TWO DATE.
  
  EX:
  
  ((1ER DÉCEMBRE 2009 13:01) - (2 DECEMBER 2009 13:01)))
  
  RELEASED IN: 24.00 (24 HOURS: 00 MINUTES).
  
  Kind regards
  
  C V S

  Hello

  If DATEs are t1d and T2D, then:

  TRUNC ( (dt2 - dt1)
        * 24
        ) || TO_CHAR ( TRUNC (SYSDATE) + (dt2 - dt1)
               , ':MI'
               )
  

  Returns a string like 24:00 ' or '1234:56' or ' 0:12 '

• Hours and minutes in time added

  Hi guys, I currently have a problem where I have two fields of date with timestamps. The only bit that I'm currently interested in these areas is the time factor. When I display them in their field, they have a format of HH24.
  
  I have a start time and end time and duration and duration of type. What I'm trying to do is the following: when the user entered the start time, as lasting say for example 1 and type duation of h. say for example I would like to have the default value of end_datetime to 1: 00 of the departure time. This is the code I use on one when validating the trigger to achieve:
  
  case: blk.duration_type
  When 'H' then
  : blk.end_datetime: =: blk.start_datetime + ((1/24) *: blk.duration);
  When "MINUTES" then
  : blk.end_datetime: =: blk.start_datetime + ((1/24/60) *: blk.duration);
  
  However, whenever this triggers the value placed in end_datetime is 0:00 it is something to do with the use of im data types or anyopne would have a solution to this problem? any help would be much appreciated.

  user13390506 wrote:
  Ahh got it, thanks guys! Florent, you were good, sorry that I just gave you a helpful note, if you post again below I will tell you with a good answer, thanks :).)

  It is not serious :) Essential is to learn something and share knowledge and sincere thanks is more than enough.
  To be very frank, that bit of forums marking I don't want ;)

  -Clément

• Convert number in hours and minutes

  Hello
  
  I have a SQL statement that is used as a source of my report.
  
  One of the columns is the result of the return of a function calc_working_hours and labeled as working_hours. As seen available_time column (which is a numeric field) is converted to hours: minurtes and called by using avail_time
  
  To_char (FLOOR (available_time / 60)). ':' ||
  To_char (MOD (available_time, 60), "FM00") avail_time
  
  
  I need a similar display during the return of the result of the Working_Hours calc_working_hours(carer.operator_id,'CAHTL19',s.start_time). However, this function returns a varchar type as shown below (displayed as 444:00 and I need to show 07:24)
  
  Select
  Carer.operator_id,
  calc_working_hours (Carer.operator_id, 'CAHTL19', s.start_time) Working_Hours,
  available_time,
  To_char (FLOOR (available_time / 60)). ':' ||
  To_char (MOD (available_time, 60), "FM00") avail_time
  of s rhm_op_available_slots, rhm_operators care, rhm_operators sw, rhm_operators tl
  where s.operator_id = carer.operator_id
  and carer.bm_id = sw.operator_id
  and sw.bm_id = tl.operator_id
  and carer.operator_id = '12693'
  
  
  OPERATOR_ID | WORKING_HOURS | AVAILABLE_TIME | avail_time
  12693. 444:00 | 444. 07:24
  12693. 444:00 | 444. 07:24
  12693. 444:00 | 444. 07:24
  12693. 444:00 | 444. 07:24
  12693. 444:00 | 444. 07:24
  12693. 444:00 | 444. 07:24
  
  
  I use 11g and any help would be appreciated gratefully.
  
  Kind regards.

  OK, try this...

  select
  carer.operator_id,TO_CHAR ( FLOOR ((TO_NUMBER(SUBSTR(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time),1,INSTR(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time),':' ,1,1)-1))+
   TO_NUMBER(SUBSTR(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time),INSTR(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time),':' ,1,1)+1,(LENGTH(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time))+1)- (INSTR(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time),':' ,1,1)+1))/60))/ 60)) || ':' ||
   TO_CHAR ( MOD ((TO_NUMBER(SUBSTR(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time),1,INSTR(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time),':' ,1,1)-1))+
   to_number(SUBSTR(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time),INSTR(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time),':' ,1,1)+1,(LENGTH(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time))+1)- (INSTR(:calc_working_hours(carer.operator_id,'CAHTL19',s.start_time),':' ,1,1)+1))/60)), 60), 'FM00') Working_Hours,
  available_time,
  TO_CHAR ( FLOOR (available_time / 60)) || ':' ||
  TO_CHAR ( MOD (available_time, 60), 'FM00') avail_time
  from rhm_op_available_slots s, rhm_operators carer, rhm_operators sw, rhm_operators tl
  where s.operator_id = carer.operator_id
  and carer.bm_id = sw.operator_id
  and sw.bm_id = tl.operator_id
  AND CARER.OPERATOR_ID = '12693'
  

  I hope this works...

  If someone useful or appropriate, please mark accordingly.

• View the hours and minutes to obtain a difference in date

  I can calculate a time difference by subtracting two date values. This translates into a numeric value. My question is how to return the calculated value in a date/time again?

  Hello

  but does Oracle provide a built-in method of doing this?
  

  Yes he did :)

  A simpler than my last request version (well of course assuming you have the TIMESTAMP data type and no date datatype)

  SELECT EXTRACT(DAY FROM &END_DATE - &START_DATE) * 24 +
         EXTRACT(HOUR FROM &END_DATE - &START_DATE) || ':' ||
         EXTRACT(MINUTE FROM &END_DATE - &START_DATE)
    FROM DUAL
  

• How to convert hours and minutes

  Hai All
  
  I calculated working hours
  
  using update dail_att set = to_number wtime (replace (to_char (to_date('00:00','HH24:MI') +)))
  ((outtime-intime), 'HH24'),': ','.')) ;
  
  
  and now how do I convert the latter in minutes
  
  Thanks in advance
  
  Srikkanth.M

  UPDATE  dail_att
  SET     wtime = TO_NUMBER(
                      REPLACE (
                          TO_CHAR(
                              TO_DATE('00:00','HH24:MI') +(outtime - intime)
                              , 'HH24:MI')
                          ,':','.')
                  );
  

  IF the difference is outtime - intimate, why don't not you simply

  (outtime - intime) * 24 -> hours
  (outtime - intime) * 24 * 60 -> minutes
  

  Concerning
  Marcus