Age of MSG and Max in RSTP

Similar Questions

• clear the cookies and Max automatically

  On my desktop PC which is hoooked to my TV, I have an option to automatically delete cookies and Max closing FF, but on this laptop that option disappeared. I installed FF only a few months back, while it is on my desk for years. This option is now extirpated from new versions?

  This is what is displayed under the protection of personal information:

  http://oi42.Tinypic.com/oksn13.jpg

  When you choose "Remember history never" then Firefox puts your entire session in private browsing mode. That does not permanently keep cookies between sessions, but I'm not sure the cache. (Logically, that must not be kept either.)

  If you want to choose what to save, change the dropdown to "never remember history" to "Use the custom settings for history" and uncheck "always use private browsing mode. Then, you can manage your shutdown options individually.

• button conrol min and max range option during execution

  Is it possible to change the window button conrol min and max Beach setting during execution?

  Thank you very much Nick.

• In Labview 8.6 and MAX, I can change a scale for a voltage read the string in a task once the application has been built and installed.

  In Labview 8.6 and MAX, I can change a scale for a voltage read the string in a task once the application has been built and installed on a second PC. Where's the info of the scale which is held?

  Hello

  Once you have built your VI and compiled into an executable file and deployed on another machine, it essentially becomes a file read-only, which means that you will not be able to change the balance in this deployed application.

  Kind regards

  Marcus

• the min and MAX values maintain their good values tia sal22

  the min and MAX values maintain their good values tia sal22

  Hi all

  I have problems a little value to stay in their correct min and max values min and max.
  Continue to change their values (up and down) trying to get the max value to only display the maximum value at a given time and the same for the min value.  I looked at the examples max and min and it seems that it should be in a while loop
  http://forums.NI.com/NI/board/message?board.ID=170&thread.ID=359822

  but I would add another while loop and if so put it in the loop for? or is there a better way to do it.

  TIA sal22

  Hi sal22,

  I thought it was just one example you found somewhere, because it is called red rooster. See the attached example.

  Mike

• Delete the min and max labels on chart axis markers

  Hello

  Is it possible to remove the min and max labels on chart axis markers? For example, see the screenshot below. Can I remove the numbers circled in green without changing the range of the axis? In some cases (like this one), the presence of the min and max number of cases other marker values to not be displayed (red line). I am aware that "10" is displayed if I enlarge the graph, but this isn't an option for my application. FYI - the screenshot is from the side before the attached VI.

  Thanks for any help,

  Kind regards

  Stu

  

  You can't delete them because they are the main features to be able to set the max and min on the graph of the Panel before if you use no-AutoScaling.

• I lost at the age of Mythology the titans expansion disc, but I still have key code, is there a way I can download age of mythology and put the key in to make it work?

  I lost at the age of Mythology the titans expansion disc, but I still have key code, is there a way I can download age of mythology and put the key in to make it work?

  Hi mxbot221,

  It is very unfortunate to know that you have lost the game disc. It is indeed a nice game that requires precision and work of the spirit.

  But the good thing is that you can download the demo version of the game among the links below and then, can enter the product key to unlock all its features.

  Here are the links: 1) http://www.microsoft.com/games/pc/titans.aspx

  2) http://www.microsoft.com/games/titans/downloads.aspx

  In addition, you can try to contact the Microsoft Supplemental Parts team for a replacement CD. To locate the phone number, visit the following Microsoft Web site: http://support.microsoft.com/default.aspx?scid=fh; EN-US; CNTACTMS

  Ref: How to replace Microsoft software or hardware, order service packs and upgrades, and replace product http://support.microsoft.com/kb/326246 manuals

  You can also try http://forums.gamesforwindows.com/ Games Microsoft support forum> for more discussions about the game.

  Hope this information was useful.
  -------------------------------------------------------------------
  Naveen
  Microsoft Answers Support Engineer
  Visit our Microsoft answers feedback Forum and let us know what you think.

• Min and Max on a table

  Hello. I want to make a program where I want to generate a sine and take only the monotonous positive part.

  So I thought to find the min and max of the function index and make a program like the one attached.

  As you can see that if you set the frequency to 10 Hz, it works fine... the problem is when you change the frequency such as 20 or 50 H.. t seems that it is not find the min and max correctly.

  Can you suggest me some tips?

  Thank you

  s.turino84 wrote:

  and take only positive part monotonous.

  This means that the derivative is positive.  So, make a derivative.  If the derivative is greater than 0 keep the present value, or the value 0.

  

• virtual memory is low do I put size virtualmemory to intial and max

  virtual memory is low do I put the size of the virtual memory to intial and max?

  R.Click my computer, properties, advanced, virtual memory, change button.

  with selected C:, click on 'letting the system manage' value set 2 X, close, restart

  PC.

  VM can / could be fixed, however, VM is used as 'ram memory', for access to the

  memory RAM & used, is 10 X faster, VM actually slows down the operating system. For

  very good speed of pc, install as much ram memory which is possible, the best

  processor with more memory cache also allows...

• Taskbar and min and max do not show on the homepage and e-mail

  When cleaning key board, the taskbar, and the top part of the page containing the min and max symbols disapperared.  How can I restore them?

  Hello

  I suggest you to try the steps below and check if it helps.

  (a) open Internet Explorer by pressing the button of the window of your keyboard, then clicking on Internet Explorer.

  (b) move your cursor to the top right and click the Tools button, and then click file.

  (c) uncheck the option full screen .

  You can also press F11 on your keyboard, which would help you to get to the normal screen.

  Hope this information is useful.

• A few .msg and .eml files display the contents of gibberish when opened with Internet Explorer

  Facing an Intermittent problem with Internet Explorer.

  Some of the .msg and .eml files do not open with outlook as the default program when opening with Internet Explorer. Downloading these files opens files directly with Internet Explorer and displays the contents of gibberish.

  Abdenour Hello,

  Thank you for the update.

  I appreciate your efforts.

  Please refer to the suggestions of Deepa Raj replied on 24 February 2013 and check if that helps.
  http://answers.Microsoft.com/en-us/Office/Forum/office_2010-Outlook/unable-to-open-msg-files-in-Explorer/a9841e83-89b7-451D-8bd0-6d1bef4e14fd

  Please keep us informed.

  Thank you

• License of CME and max joined

  Hello

  I have 15.4 (3) M4 / CME 10.5 on my 3925 router and my HS detail cme-srst license shows 60 licenses:

  Feature: cme-srst Version: 1.0
  License type: RightToUse
  The license status: Active, in use
  Type of lock: node not locked
  Seller Info: NOTLOCKEDNOTLOCKEDRTU
  Adding license: additive
  Generation version of license: 0 x 8200000
  Number of licenses: 60/0 (in-use/Violation)
  License priority: bass
  Store the Index: 7
  Store name: built-in license storage

  (1) if the license is honor based, can I just keep on adding phones (max 250 possble of this material) without the need of any additional licenses?

  (2) I currently have joined max configured as 50. Can I just increase this value to add more phones CSPC?

  Any help will be greatly appreciated.

  Thanks in advance,

  Benedict of Libin

  Yes, we should not increase the number of phones if we don't have that many number of licenses, you can purchase licenses and keep them with you, no need to install the router of the CME, is a license agreement for the document.

  But still, if you want to increase then you can increase this limit by max-ephone of orders xx xx and max - dn to the title of the telephony service. for example if you set max-ephone 100 currently, and you change this value by max-ephone 140.

  Edit: And you put an exclamation mark after max-ephone then you will get to know how your guy is supported phones.

  Suresh

• Compatibility of Windows 8 with Age of Mythology and Titans

  Bought a new laptop with Windows 8 preload.  The only thing I use the laptop for is to play Age of Mythology and it does not work.  Looked like all the forums for corrections and Windows 8 seems to be preloaded with DirectX11 and all the correct s/w but still the "Initialization failed" error at startup.

  Is there a version of patch to fix this?  Otherwise anyone who upgrades to the new sys Op MS will have this prob.

  Hey Loren,

  Microsoft Age Of Mythology: Titans is not compatible with windows 8. Then I suggest to install the game in compatibility mode and check if it helps. Here is the link that tells you about the incompatibility of the game with Windows 8.

  Windows Compatibility Center

  Follow the steps to install the game in Compatibility Mode:

  a. right click on setting up the file, then select Properties and then tap or click on the compatibility tab.

  b. check the box run this program in compatibility modof e.

  c. press or click the menu drop down and select a previous operating system, and then tap or click OK.

  See the article for more information.

  Make the programs more compatible with this version of Windows

  Hope this information helps. Answer the post with an up-to-date issue report to help you further.

• Min and Max in a row!

  Hi guys,.

  Do you know how I can get the MIN and MAX in a row?

  For example:

  C1 | C2 | C3 | C4 | C5 | C6 | C7 | C8

  10. 50. 70.  5. 90. 135. 4   | 60

  I return 4 and 135.

  I can return it without using the service?

  Thank you

  Eric

  create table t as
  with d as (
    select 1 n from dual
    union all
    select null from dual
  )
  select a.n c1, b.n*2 c2, c.n*3 c3
  from d a, d b, d c;
  
  select c1,c2,c3,
  greatest(
    coalesce(c1,c2,c3),
    coalesce(c2,c3,c1),
    coalesce(c3,c1,c2)
  ) greatest_c,
  least(
    coalesce(c1,c2,c3),
    coalesce(c2,c3,c1),
    coalesce(c3,c1,c2)
  ) least_c
  from t;
  

  C1	C2	C3	GREATEST_C	LEAST_C
  1	2	3	3	1
  1	2		2	1
  1		3	3	1
  1			1	1
  	2	3	3	2
  	2		2	2
  		3	3	3

• Grouping and then find the min and max

  DROP TABLE purge of y;

  CREATE TABLE y
  (
  ID NUMBER (10),
  START_DATE_TIME NUMBER (15),
  END_DATE_TIME NUMBER (15)
  );

  INSERT INTO y VALUES (1, 20140602164819, 20140606140851);
  INSERT INTO y VALUES (1, 20140827141743, 20140827142131);
  INSERT INTO y VALUES (1, 20140827141744, 20140827141835);
  INSERT INTO y VALUES (1, 20140827141744, 20140827142131);
  INSERT INTO y VALUES (1, 20140827141944, 20140827142131);
  INSERT INTO y VALUES (1, 20140827141944, 20140924142131);
  INSERT INTO y VALUES (1, 20140927141944, 20141027142131);
  INSERT INTO y VALUES (2, 20140602164819, 20140606140851);
  INSERT INTO y VALUES (2, 20140827141743, 20140827142131);
  INSERT INTO y VALUES (2, 20140827141744, 20140827141835);
  INSERT INTO y VALUES (2, 20140827141744, 20140827142131);
  INSERT INTO y VALUES (2, 20140827141944, 20140827142131);
  INSERT INTO y VALUES (2, 20140827141944, 20140924142131);
  INSERT INTO y VALUES (2, 20140927141944, 20141027142131);

  COMMIT;

  Select
  *
  Of
  There
  order by 2, 3;

  out necessary: when the output of the table are sorted by start_date_time and end_date_time in ascending order.
  and when the value of for a particular id start_date_time is located between the
  another set of values start_date_time and end_date_time for the same id then min (start_date_time) and max (end_date_time) is the desired output.

  and if there is no overlap then (start_date_time) min and max (end_date_time) is the output desired.

  and for each line of the output in ascending order of line number order addd;

  Example output is in the output table named

  drop table output is serving;

  create an output table
  (
  ID NUMBER (10),
  START_DATE_TIME NUMBER (15),
  END_DATE_TIME NUMBER (15),
  ROW_NUMBER NUMBER (10)
  );

  
  Values to INSERT OUTPUT (1, 20140602164819, 20140606140851, 1);
  Values to INSERT OUTPUT (1, 20140827141743, 20140924142131, 2);
  Values to INSERT OUTPUT (1, 20140927141944, 20141027142131, 3);
  Values to INSERT OUTPUT (2, 20140602164819, 20140606140851, 1);
  Values to INSERT OUTPUT (2, 20140827141743, 20140924142131, 2);
  Values to INSERT OUTPUT (2, 20140927141944, 20141027142131, 3);

  COMMIT;

  SELECT
  *
  Of
  output
  ORDER BY 1,2,3,4;

  Thank you

  SQL_Novice

  Hello

  Your postal code.  It is difficult to tell what you're doing wrong without knowing what you are doing.

  user6166680 wrote:

  Hi Frank:

  Max works for ID 3 values only because there is only one group here, as all other values compared, they overlap with max (end_date_time);

  but when I use MAX for ID 1 and 2, the result set is not the same thing as LAG works because there is a GAP...

  Exactly, you have to find the gaps.  If start_date_time is less than or equal to the MAXIMUM of all the end_date_times earlier, then it isn't a gap; Otherwise, there is a gap.

  What is the problem with MAX?

  WITH got_new_group AS

  (

  SELECT id, start_date_time and end_date_time

  CASE

  WHEN start_date_time <= > MAX (end_date_time) OVER (PARTITION BY id )

  ORDER BY start_date_time

  end_date_time

  ROWS BETWEEN UNBOUNDED PRECEDING

  AND 1 PRECEDING

  )

  THEN 0

  1. OTHER

  END AS new_group

  OF y

  )

  got_group_number AS

  (

  SELECT id, start_date_time and end_date_time

  SUM (new_group) OVER (PARTITION BY ID.

  ORDER BY start_date_time

  end_date_time

  ) AS group_number

  OF got_new_group

  )

  SELECT id

  MIN (start_date_time) AS group_start_date_time

  MAX (end_date_time) AS group_end_date_time

  group_number

  OF got_group_number

  GROUP BY id, group_number

  ORDER BY id, group_number

  ;

  You will notice that it is exactly what I posted earlier, in response #5, except that instead of using the OFFSET it uses MAX.

  Output:

  ID GROUP_START_DATE_TIME GROUP_END_DATE_TIME GROUP_NUMBER

  --------------- --------------------- ------------------- ---------------

  1 20140602164819 20140606140851 1

  1 20140827141743 20140924142131 2

  1 20140927141944 20141027142131 3

  2 20140602164819 20140606140851 1

  2 20140827141743 20140924142131 2

  2 20140927141944 20141027142131 3

  3 20140330041350 47121231000000 1