allocation of memory for a LStrHandle

Hello

I know that this thing about memory allocation and LStrings has been much already posted but I couldn t find the answer to my question.

Currently I am working with an external code (c ++) and calling a function of vi.

I want normal c ++ channels:

(1) declaring normal c ++ string

(2) conversion c ++ string in a Lstring + pass it as Lstringhandle (this works very well!)

(3) initialize a Lstrhandle for my result (it would work very well if I knew that the length of the resultant Lstring! but because the application is set to call ANY function of vi I don't know what the function and so I do not know the length of the result string)

My problem is really basic, but how do I get the actual length of the modified LString?

Let´s tell my function of vi concatenates 2 strings and returns the result, then the signature of my vi-function should look like this:

void __cdecl Concat (LstrHandle * string1, LStrHandle * string2, LStrHandle result);

at some point, so I need to know the length of the result.

Any ideas?

(it is important that the strings are Lstrings and they are passed as pointers!)

I've tried usinig labviews functions of manager, but this won't work for all of the problem this toddler is integrated.

I appreciate the ideas and help!

Thank you...

Gabriella_ wrote:

Hello

void __cdecl Concat (LStrHandle * string1, LStrHandle * string2, LStrHandle result);

at some point, so I need to know the length of the result.

If your function receives the string1 and string2 as input and returns the result, then the first two by reference and by value, it seems quite a bit back.

Because string1 and string2 are entered, the function is supposed to use, they must be defined and allocated in any case properly by the appellant. But for output handles passed by reference, it is quite valid in LabVIEW since on version 6 to pass a NULL handle and LabVIEW code takes care of allocating a new handle in this case.

So basically if you declare your function like that when, you create your LabVIEW DLLS:

void __cdecl Concat (string1, string2 LStrHandle, LStrHandle LStrHandle * result);

It is quite valid to call this function like this in your C code:

LStrHandle string1; initialization of a string

LStrHandle string2; initialization of a string

Result LStrHandle = NULL;

Concat (string1, string2, & result);

and the result will contain a valid string descriptor on successful return.

If the output parameter is declared by the value, then you obviously can't pass in a NULL handle because the function has no way to return a new handle. Then, you will indeed need to allocate an empty descriptor like this:

LStrHandle result2 = (LStrHandle) DSNewHClr (sizeof (int32));

This allocates a handle with the place for the numElm value and initializes it to 0.

Tags: NI Software

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    The normal use, I am an average of 1.2 G or about memory (of 16 G total); is this normal? Don't not maxing out at all but I was wondering.

    How to define and measure the use of memory for Firefox? Activity monitor? I use Firefox to write this. In the activity monitor, I see Firefox to 347 MB and Firefox Web Content to 259 MB.

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