"An insufficient number of calibration points function" in the calibration to learn?

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  Thank you for visiting the website of Microsoft Windows Vista Community. The question you have posted is related to Office Excel and would be better suited to the office community. Please visit the link below to find a community that will support what ask you

  http://www.Microsoft.com/Office/Community/en-us/default.mspx?d=1

  Mike - Engineer Support Microsoft Answers
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  Kill them salvation.

  for all B cells on the second act of sheet as "smart cells", if you want to, where they are all automatically use the COUNTIF function using the expression in each corresponding to a cell, instead of the manual set up I have now.

  

  Formula in B2 (and fill by dragging the handle downwards to fill yellow)

  = COUNTIF(Collection::Table 1::$B,A2)

  B2 in the platform table and paste in the length of Table B2. It will show zero because he seeks the wrong column in the table on the sheet Collection.

  

  Click on the "Collection::Table 1: $B" diamond in the formula editor to select.

  Go to the Map Collection and click on the label C.

  AHA! It always displays zero because does not match the description of length:

  "Very short (less than 5 hours)" on the card product and "Very short" on the Collection sheet.

  The descriptions must match exactly.

  The easy way to change them in the Collection journal is to sort the table. But first of all insert another column, and then type 1 then 2 and fill down. Then you can sort to the original order.

  

  Now sort the column Length.

  Change the description (copy and paste into each "block")

  Funny looks because the line height are different

  

  The COUNTIF works because the descriptions are now (the formula now displays column D because of the new column of original order of Collection).

  I'll post this before the time-out annoys me.

  

  Kind regards

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  Hello

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  -Package

  create or replace PACKAGE IS GetMigSamples

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  TYPE sample_record IS RECORD)

  PERSON_ID NUMBER,

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  RETURN sample_table

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  END;

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  v_migtable VARCHAR (64);

  v_stmt_str VARCHAR2 (400);

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  IN v_rec;

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  Thank you

  When I use it

  Select getmigsamples.sp_mig_samples ('M_MY_TABLE') of double

  I get

  FW. SYS_PLSQL_228255_29_1()

  Which I guess means that I have a reference to an object, rather than the actual values in the lines. I tried to corrrect it for centuries and have now arrived at the point of the tear-my-hair-out.

  No - this 'thing' you got is a hidden type of SQL Oracle automatically created to match the type of PL/SQL, that you used. SQL can only work with the SQL types defined at the schema level. But for functions PIPELINED Oracle allows you to specify the types of PL/SQL and it will create SQL HIDDEN types to make it work.

  A pipeline function should be treated as a table. You must use the SCOREBOARD operator

  Select * from table (myFunction);

  Try this simple example

  -type to match record emp

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  (EMPNO NUMBER 4,

  ENAME VARCHAR2 (10),

  USE VARCHAR2 (9).

  MGR NUMBER 4,

  HIREDATE DATE,

  NUMBER OF SAL (7, 2)

  NUMBER OF COMM (7, 2)

  DEPTNO NUMBER (2)

  )

  /

  -records of the emp table

  create or replace type emp_table_type to table of emp_scalar_type

  /

  -function of pipelined

  create or replace function get_emp (p_deptno number)

  return emp_table_type

  PIPELINED

  as

  TYPE EmpCurTyp IS REF CURSOR RETURN emp % ROWTYPE;

  emp_cv EmpCurTyp;

  l_rec emp % rowtype;

  Start

  Open emp_cv SELECT * from emp where deptno = p_deptno;

  loop

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  When the output (emp_cv % notfound);

  line of conduct (emp_scalar_type (l_rec.empno, LOWER (l_rec.ename),

  l_rec.job, l_rec.mgr, l_rec.hiredate, l_rec.sal, l_rec.comm, l_rec.deptno));

  end loop;

  return;

  end;

  /

  Select * from table (get_emp (20))

  See use of the SCOREBOARD operator?