At my place of work, there are a data server with LAN and internet networking. I want to disable the internet connection before it is infected with the virus.

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• Error: Dragon Naturally Speaking seems to work in Compatibility Mode Windows, which can lead to errors. We recommend to disable the compatibility mode for the program natspeak

  Original title: Dragon Naturally Speaking will not charge. He was working. I have time. The only thing different is my 10 3 demo of windows expiredeinstalled

  Remember - this is a public forum so never post private information such as numbers of mail or telephone!

  Ideas:

  • Dragon Naturally Speaking does not load. He was working. I have time. The only thing different is my demo windows 10 expiredeinstalled 3 programs you have problems with
  • Error messages Dragon Naturally Speaking seems to work in Compatibility Mode Windows, which can lead to errors. We recommend to disable the compatibility mode for the program natspeak
  • Recent changes to your computer
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  Hi jrskona,

  1. don't you make changes before the show?

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  d. click ok to apply the changes.
  e. check if the problem persists.

  If the problem persists, then contact the program vendor support team:see Dragon NaturallySpeaking support

  Visit our Microsoft answers feedback Forum and let us know what you think.

• Need help with query to get days of work there are using the calendar BOM

  RDBMS: 10.2.0.4.0
  Oracle Applications: 11.5.10.2
  
  I try to use the BOM existing in the EBS to calculate working days calendar, there is a report that I am train. The BOM calendar presents the working days and non-working with the weekend days and holidays listed as non-working days. The following query gives correct results, but I'm looking for two different ways to do the same without "the union. I have nothing against the "unions", but I feel that I'm missing a more elegant to get there way. The query will in Discoverer Plus 10.1.2.3, so using a statement 'By' is not supported.
  

  sample data
  
  calendar_code                calendar_date                 seq_num                     
  SAC-WRKDAY                   12/3/2010                     1817
  SAC-WRKDAY                   12/4/2010                                                              
  SAC-WRKDAY                   12/5/2010                                                              
  SAC-WRKDAY                   12/6/2010                     1818                                 
  SAC-WRKDAY                   12/7/2010                     1819                                 
  SAC-WRKDAY                   12/8/2010                     1820     
  SAC-WRKDAY                   12/9/2010                     1821
  SAC-WRKDAY                   12/10/2010                    1822
  SAC-WRKDAY                   12/11/2010                   
  SAC-WRKDAY                   12/12/2010
  SAC-WRKDAY                   12/13/2010                    1823             

  select calendar_code
       , calendar_date
       , seq_num
       , sum(decode(bcd.seq_num,null,0,1))over(partition by bcd.calendar_code order by bcd.calendar_date desc) workdays_ago
  from   bom.bom_calendar_dates bcd
  where  calendar_code = 'SAC-WRKDAY'     
  and    trunc(bcd.calendar_date) < trunc(sysdate)
  
  union
  
  select calendar_code
       , calendar_date
       , seq_num
       , -sum(decode(bcd.seq_num,null,0,1))over(partition by bcd.calendar_code order by bcd.calendar_date ) workdays_ago
  from   bom.bom_calendar_dates bcd
  where  calendar_code = 'SAC-WRKDAY'
  and    trunc(bcd.calendar_date) > trunc(sysdate)

  sample output
  
  calendar_code                calendar_date                 seq_num                      workdays_ago
  SAC-WRKDAY                   12/3/2010                     1817                                  3
  SAC-WRKDAY                   12/4/2010                                                           2
  SAC-WRKDAY                   12/5/2010                                                           2
  SAC-WRKDAY                   12/6/2010                     1818                                  2
  SAC-WRKDAY                   12/7/2010                     1819                                  1
  SAC-WRKDAY                   12/9/2010                     1821                                 -1
  SAC-WRKDAY                   12/10/2010                    1822                                 -2
  SAC-WRKDAY                   12/11/2010                                                         -2
  SAC-WRKDAY                   12/12/2010                                                         -2
  SAC-WRKDAY                   12/13/2010                    1823                                 -3

  Hello

  Of course, you should be able to combine these queries, something like this:

  select calendar_code
       , calendar_date
       , seq_num
       , sum ( CASE
             WHEN  bcd.seq_num IS NULL
             THEN  0
             WHEN  bcd.calendar_date < TRUNC (SYSDATE)
             THEN  1
             ELSE  -1
            END
          ) over ( partition by  bcd.calendar_code
                ,            SIGN (SYSDATE - bcd.calendar_date)
                order by        ABS  (SYSDATE - bcd.calendar_date)
              ) workdays_ago
  from   bom.bom_calendar_dates bcd
  where  calendar_code = 'SAC-WRKDAY'
  and    trunc(bcd.calendar_date) < trunc(sysdate)
  

  If you do not want to display some CREATE TABLE and INSERT statements for the sample data, and then I could test it.

  t_norwillo wrote:
  ... I have nothing against the "unions", but I feel that I'm missing a more elegant to get there way.

  Good thinking!
  When the two branches of the UNION query the same table, there is usually a more effective way: something that only requires a pass through the table.

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  Post edited by: RebeccaW (removed unrelated to Postgres question)

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