Beginner; Help with lens opting for a Photo of the city

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  Hi people of Oracle
  
  I use Oracle
  
  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production
  With partitioning, OLAP, Data Mining and Real Application Testing options
  
  I have a few responses from students and the valid values are + / / (alphabet) o/p and spaces at the end of the scam only not in the middle.
  
  According to my condition, the registration number 2 3.4 must be in the request but I'm alone (chart 3).
  
  Can we use REG_EXP
  
  Help, please.
  
  Thanks in advance.
  
  Rajesh
  
  with x as)
  (
  SELECT '+-+-POPPPPPP' STUDENT_RESPONSE, 1 numero_enregistrement FROM DUAL Union all the
  SELECT ' + --AOPPPPPP++' STUDENT_RESPONSE, 2 numero_enregistrement FROM DUAL Union all the
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  OR (INSTR (UPPER (TRIM (STUDENT_RESPONSE)), '+') = 0)
  OR (INSTR (UPPER (TRIM (STUDENT_RESPONSE)), 'O') = 0)
  OR (INSTR (UPPER (TRIM (STUDENT_RESPONSE)), 'P') = 0)
  OR (INSTR (UPPER (TRIM (STUDENT_RESPONSE)),' ')! = 0)
  )
  )

  Hi, Renon,

  Rb2000rb65 wrote:
  Hi people of Oracle

  I use Oracle

  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production
  With partitioning, OLAP, Data Mining and Real Application Testing options

  Thanks for posting this (and the WITH clause for sample data). It is very useful.

  I have a few responses from students and the valid values are + / / (alphabet) o/p and spaces at the end of the scam only not in the middle.

  You combine several qeustions responses in a single VARCHAR2 column? It would be better to have a separate line for each question.

  According to my condition, the registration number 2 3.4 must be in the request but I'm alone (chart 3).

  What exactly are your needs? You try to find the rows where the student_response contains one of the forbidden characters, or if it contains a space anywhere, but at the end of the string?

  Can we use REG_EXP

  Yes, but it's pretty easy and probably more effective, do not use regular expressions in this case:
  Here's one way:

  SELECT     record_number
  ,     student_response
  FROM     x
  WHERE     TRANSLATE ( UPPER ( RTRIM (student_response, ' '))
              , 'X+-OP'
              , 'X'
              )     IS NOT NULL
  ;
  

  In other words, once you remove the spaces and all occurrences of '+', '-', 'o' or 'P', then the forbidden characters are left, and you want to select the line, if there is one of these.

  If you really, really want to use a regular expression:

  SELECT     record_number
  ,     student_response
  FROM     x
  WHERE     REGEXP_LIKE ( RTRIM (student_response)
                , '[^-+OP]'          -- or '[^+OP-]', but not '[^+-OP]'.  Discuss amongst yourselves
                , 'i'
                )
  ;
  

  but, again, it will be probably slower than the first solution, using TRANSLATE.

  Published by: Frank Kulash, October 17, 2011 13:05

  Published by: Frank Kulash, October 17, 2011 13:41
  What follows is a bit simpler that TRANSLATE:

  SELECT     record_number
  ,     student_response
  FROM     x
  WHERE     RTRIM ( UPPER ( RTRIM (student_response, ' '))
             , '+-OP'
             )          IS NOT NULL
  ;
  

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  a.app_id

  c.full_name

  , count (*) as the controls

  of t_application one

  t_app_audit b

  c of the emp

  where a.app_id = b.app_id

  and b.processed_by = c.id

  and a.app_type in ('NETWORK', "DATABASE")

  and b.app_id by (not in

  Select app_id

  of t_app_audit

  where processed_by in ('1234, ' 5467')

  )

  GROUP OF A.APP_ID, c.full_name;

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  Hello

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