Beginning and end of the week according to YYYYWW
Hi allI have a date like format
201050
201051
201052
201101
I wanted to display their dates of beginning and end of the relevant year - week.
SQL> with t as (
2 select 201050 yw from dual union all
3 select 201051 from dual union all
4 select 201052 from dual union all
5 select 201101 from dual union all
6 select 201102 from dual
7 )
8 --
9 --
10 select yw, trunc (trunc (to_date (substr (yw, 1, 4), 'yyyy') + 7, 'iyyy') + 7 * (substr (yw, 5) - 1), 'iw') start_dt
11 from t
12 /
YW START_DT
--------------- -----------
201050 13/dec/2010
201051 20/dec/2010
201052 27/dec/2010
201101 03/jan/2011
201102 10/jan/2011
5 rows selected.
SQL>
Tags: Database
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- JANUARY 3, 13 JANUARY 9, 13
- 10 JANUARY 13 JANUARY 16, 13
- 17 JANUARY 13 23 JANUARY 13
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- 7 NOVEMBER 13 NOVEMBER 13, 13
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- 19 DECEMBER 13 DECEMBER 25, 13
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Why the "weeks" in November, have all 7 days, while the "weeks" in the first or the last week in the other month usually have less? (For example, February 28 is a 'week' alone.)
The following works for the other months:
WITH all_days AS
(
SELECT DATE "2013-01-01' + LEVEL - AS a_date 1
OF the double
CONNECT BY LEVEL<=>=>
)
SELECT DISTINCT
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, TRUNC (a_date, 'MONTH')
) AS week_begin
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;
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January 17, 2013 January 23, 2013
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January 31, 2013 January 31, 2013
February 1, 2013 February 6, 2013
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February 14, 2013 February 20, 2013
February 21, 2013 February 27, 2013
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...
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November 21, 2013 November 27, 2013
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