Bill land - problem with phase

I have a problem of implementation during the attempt to produce traces of Bode for my team designed the hardware. I have now successfully been able to produce the data you expect, with a single question. Part of the phase of data points are the opposite of what is expected. I'll explain the process used...

The material, I log in allows me to inject the signals on channels, but also the flow of these channels of my PC application for analysis. The function that I'm trying to replicate is a frequency sweep, as follows:

-major equipment to replace a channel (the stimulus) with an sine wave frequencies, f

-broadcasting the channel stimulus as well as his response to a certain channel number of cycles, P

-the analysis ("transfer function") on the stimulus and data stream response strings

-connect the frequency (f) with the phase intended to produce a Plot of Bode and corresponding calculated magnitude

-increase the frequency (f) and repeat steps

This code example is 'analysis' performed:

int i, MaxMagIdx, DontCareIdx;

Double * TimeInMag,.
* DontCareArr,
TransferReal,
TransferImg,
TransferMag,
TransferPhase,
DontCare,
AdjFreq;

NIComplexNumber * TimeSweepIn,.
* TimeSweepOut,
* FFTSweepIn,
* FFTSweepOut;

TimeSweepIn = malloc (gSweepCountMax * sizeof (NIComplexNumber));
TimeSweepOut = malloc (gSweepCountMax * sizeof (NIComplexNumber));
FFTSweepIn = malloc (gSweepCountMax * sizeof (NIComplexNumber));
FFTSweepOut = malloc (gSweepCountMax * sizeof (NIComplexNumber));

TimeInMag = malloc (gSweepCountMax * sizeof (double));
DontCareArr = malloc (gSweepCountMax * sizeof (double));

int InputSigIndex;

unsigned char OverrideMsg [L_ADC_OVERRIDE_RQ] is {0};.

for (i = 0; i<>
{
TimeSweepIn [i] .reellement = gSweepInArr [i];
TimeSweepOut [i] .reellement = gSweepOutArr [i];
TimeSweepIn [i] .imaginary = 0.0;
TimeSweepOut [i] .imaginary = 0.0;
}

CxFFTEx (TimeSweepIn, gSweepCountMax, gSweepCountMax, NULL, FALSE, FFTSweepIn);
CxFFTEx (TimeSweepOut, gSweepCountMax, gSweepCountMax, NULL, FALSE, FFTSweepOut);

for (i = 0; i<>
{
ToPolar (FFTSweepIn [i] .reellement, FFTSweepIn [i] .imaginary & TimeInMag [i], & DontCareArr [i]);
}

MaxMin1D (TimeInMag, gSweepCountMax, & DontCare, & MaxMagIdx, & DontCare & DontCareIdx);

CxDiv (.reellement [MaxMagIdx] FFTSweepOut, FFTSweepOut [MaxMagIdx] .imaginary,
FFTSweepIn [MaxMagIdx] .reellement .imaginary FFTSweepIn [MaxMagIdx],
& TransferReal, & TransferImg);

ToPolar (TransferReal, TransferImg, & TransferMag & TransferPhase);

TransferMag = 20 * log10 (TransferMag);
TransferPhase = RadToDeg (TransferPhase);

AdjFreq = (double) ((unsigned long) (gSweepFreq * 0 x 200000000 / (double) 50000000)) * 0 200000000 50000000 x / (double);

fprintf (Logfile_Handle, "% lf\t%lf\t%lf\n", AdjFreq, TransferMag, TransferPhase);

Free (TimeSweepIn);
Free (TimeSweepOut);
Free (FFTSweepIn);
Free (FFTSweepOut);
Free (TimeInMag);
Free (DontCareArr);

It works almost perfectly. The problem is that the calculated phase will be positive when there should be negative and vice versa.

Here's a graph of the data produced:

This is what is expected:

Here are the two bunk:

The expected plot was produced by the log file of cheating. I went and I didn't change the incorrect points to negative values. I want to eliminate this step. As you can see, if incorrect data are reflected on the zero line, it's what we expect. This "expected" given corresponds to what material Analyzer of my colleague (Venable device) when it is used on our device.

We believe that the issue is not with carried out complex math, but a problem in the FFT function or the selection of the index to use on the data table.

Hi PedroMunoz,

It was random semi.

With the help of a licensed physicist with a PhD, the solution was discovered.

When a FFT is performed, the output is a complex signal frequency. Convert this signal complex in amplitude and phase. The signal amplitude must contain a pic. The ridge of the signal amplitude is located at the frequency at which the sample represents. I understood.

However, reading the FFT also of output magntiude contains a second peak. This second peak is negative frequency, and to analyze these data point conjugate complex is necessary. This second Summit should theoretically have the same amplitude, described as:

F (f) = F * (-f)

What interests me in recovering is F (f). What was happening was because F (f) and F * (-f) are theoretically the same (hence, they should the two registry as the maximum value of the table), F * (-f) would sometimes be picked up as the maximum value of the table instead of F (f), perhaps because of the noise. So I just need to make sure that I'm not the negative frequencies in my table.

To ignore the F * (-f), all I had to do was only to watch a half of my output of the FFT. When I change my code for:

TimeInMag = malloc (gSweepCountMax/2 * sizeof (double));
DontCareArr = malloc (gSweepCountMax/2 * sizeof (double));

for (i = 0; i
{
ToPolar (FFTSweepIn [i] .reellement, FFTSweepIn [i] .imaginary & TimeInMag [i], & DontCareArr [i]);
}
MaxMin1D (TimeInMag, gSweepCountMax/2, & DontCare, & MaxMagIdx, & DontCare, & DontCareIdx);

I'm ignoring the negative frequencies. By setting the parameter 'shift' of CxFFTEx to FALSE, it organizes the positive frequencies in the first half, then the negative frequencies in the second. I pick up is no longer the wrong index, which would result in the phase reverse reading.

I hope this helps someone else in the future!

Tags: NI Software

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    02:28 A. Â? ? Â? #35 text 0 File ThreadedTransfer.cpp, Line 273
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    02:28 A. Â? ? Â? #280 CDR-1222 file Writer.cpp, line 203
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    02:28 A. Â? ? Â? #282 text 0 file SCSIPTICommands.cpp, line 289
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    Post edited by: velkoto

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