break the barrier of the 137 in xp

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  Please help me solve this problem.

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  I'm not sure that understand the problem you are experiencing.

  If I have a single receiver program that waits for 1 second and processes for 10 (treatment here is simulated by call dbms_lock.sleep), the receiver will be get signal when it then calls waitone.

  declare
    l_msg varchar2(1000);
    l_status integer;
  begin
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    loop
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      dbms_alert.waitone( 'foo_alert', l_msg, l_status, 1 );
      if( l_status = 0 )
      then
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        exit;
      end if;
      dbms_output.put_line( 'Started sleeping at ' || to_char( sysdate, 'hh24:mi:ss' ) );
      dbms_lock.sleep( 10 );
    end loop;
  end;
  

  If the session 1 runs this code and session 2 reports alert while 1 is in the call of dbms_lock.sleep

  SQL> exec dbms_alert.signal( 'foo_alert', 'My message sent at ' || to_char( sysdate, 'hh24:mi:ss') );
  PL/SQL procedure successfully completed.
  
  SQL> commit;
  Commit complete.
  

  Session 2 will be notified of the signal when he returns the call to WAITONE.  Note that the message has been sent 3 seconds after the first call to WAITONE had expired (and thus 3 seconds in the 'work' simulated by DBMS_LOCK. (SLEEP).  The signal has been received once this piece of work was completed, and the loop went back to waiting on the alert.

  SQL> ed
  Wrote file afiedt.buf
  
    1  declare
    2    l_msg varchar2(1000);
    3    l_status integer;
    4  begin
    5    dbms_alert.register( 'foo_alert' );
    6    loop
    7      dbms_output.put_line( 'Started waiting at ' || to_char( sysdate, 'hh24:mi:ss' ) );
    8      dbms_alert.waitone( 'foo_alert', l_msg, l_status, 1 );
    9      if( l_status = 0 )
   10      then
   11        dbms_output.put_line( 'Alert received: ' || l_msg );
   12        exit;
   13      end if;
   14      dbms_output.put_line( 'Started sleeping at ' || to_char( sysdate, 'hh24:mi:ss' ) );
   15      dbms_lock.sleep( 10 );
   16    end loop;
   17* end;
  SQL> /
  Started waiting at 18:07:45
  Started sleeping at 18:07:46
  Started waiting at 18:07:56
  Alert received: My message sent at 18:07:49
  
  PL/SQL procedure successfully completed.
  

  Justin

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  Is this possible via the script. I have attached the screenshot for reference.

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• VMware Tools upgrade changes machineID, breaks the issuance of licenses for some applications

  We have this application called localization, manufactured by Hyland Software. Whenever I've upgrade VMware Tools on our ESXi hosts on all virtual machines, it breaks the granting of licenses for the application and localization will not work until the licensing is completely redone. No idea why this is happening?

  Below is the reading of the application regarding the issuance of licenses, and attached is a screenshot of the error in the application. I'm certainly not asking someone to solve the problem of the application, but what on earth could possibly VMTools change that would have caused this? Thanks in advance!

  RegisterName	dateregistered	Networkid	pcserialnum	usernum	stationdesc	wkstationgrpnum	cachenum	MacAddress	lastLogon	badlogincount	MachineId
  DALONBASE	01/02/2013	BVVGRCRGRKRO	715828130	0	DALONBASE (SELF)	0	0	005056b33b87	04/02/2013	0

  C8C2A6CCADFA02BFBAA68E68D9842B25

  DALONBASE

  04/08/2012

  YIEGRCRGRKRO

  715827788

  0

  DALONBASE (SELF)

  0

  0

  005056b33b87

  01/02/2013

  0

  006EEA89FBC395E1DAD4C3BA17DF7DF2

  If this is what is causing the problem?

  I'm sure of it - about 99.9% Yes.

  And if so, what changes would affect a particular software feature licenses?

  "All the virtual machines have a hardware version, which shows the characteristics of virtual hardware that supports the virtual machine, such as BIOS or EFI, number of virtual slots, maximum number of processors, the maximum memory configuration and other features material." - from http://www.vmware.com/products/datacenter-virtualization/vsphere/compute.html

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