Breakup time range
Hello
I have following data in my table of LEAVE. I want to divide each period of leave at different times.
with
leave as)
Select 1 as empid, to_date (08 January 1 2014:00 ',' DD/MM/YYYY HH24 ') as leavefrom, to_date (March 1, 2014 16:00 ',' DD/MM/YYYY HH24 ') as leaveto of all the double union
Select 2 as empid, to_date (08 January 1 2014:00 ',' DD/MM/YYYY HH24 ') as leavefrom, to_date (1 January 2014 16:00 ',' DD/MM/YYYY HH24 ') as leaveto of union double all the
)
Power required is as follows
-------------------------------------------------------------------------------
ID FROM_TIME TO_TIME
-------------------------------------------------------------------------------
1 01/01/2014 08:00 01/02/2014 00:00
1 02/01/2014 00:00 01/03/2014 00:00
1 03/01/2014 00:00 01/03/2014 16:00
2 01/01/2014 08:00 01/01/2014 16:00
I use oracle 10 g
Help, please...
Hello
2730134 wrote:
Hi Frank,.
Power required is as follows...
Sorry, my mistake. I forgot start_date truncated when added to it:
WITH got_ndays AS
(
SELECT empid, leavefrom, leaveto
, CEIL (leaveto - TRUNC (leavefrom)) AS ndays
Annual LEAVE
)
got_maxndays AS
(
SELECT MAX (ndays) AS maxndays
OF got_ndays
)
AS cntr
(
SELECT LEVEL AS n
OF got_maxndays
CONNECT BY LEVEL<=>=>
)
SELECT n.empid
Largest (n.leavefrom
TRUNC (n.leavefrom) + c.n - 1
) AS dayfrom
, The LEAST (n.leaveto
TRUNC (n.leavefrom) + c.n
) AS Degnide
OF got_ndays n
CNTR JOIN c ON c.n<=>=>
ORDER BY n.empid
, c.n
;
Output:
EMPID DAYFROM DEGNIDE
---------- ---------------- ----------------
1 01/01/2014 08:00 01/02/2014 00:00
1 02/01/2014 00:00 01/03/2014 00:00
1 03/01/2014 00:00 01/03/2014 16:00
2 01/01/2014 08:00 01/01/2014 16:00
Tags: Database
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