By subtracting the previous row less the current line in SQL

I have a table - orders.

How to subtract the previous row less line current for incoming column

enter image description here

If anyone can help.

Hello

It is not clear what you want. What is the previous row? What order to examine DATE_IN?

Here is an example of using the function DATE_IN LAG to retrieve the previous value of the line consider the sort column.

WITH commands LIKE (select to_date (27 May 2015 ', ' dd/mm/yyyy') date_in, 83 of the double incoming_vol)

Union of all the

Select to_date (May 26, 2015 ', ' dd/mm/yyyy') date_in, 107 double incoming_vol

Union of all the

Select to_date (May 25, 2015 ', ' dd/mm/yyyy') date_in, 20 incoming_vol of the double

Union of all the

Select to_date (May 24, 2015 ', ' dd/mm/yyyy') date_in, 7 incoming_vol of the double

Union of all the

Select to_date (May 22, 2015 ', ' dd/mm/yyyy') date_in, 71 double incoming_vol

)

SELECT date_in

incoming_vol,

NVL (lag (incoming_vol) (date_in release order), 0)-incoming_vol previous_row_minus_current_row

Orders

ORDER BY 1 desc;

DATE_IN INCOMING_VOL PREVIOUS_ROW_MINUS_CURRENT_ROW

----------- ------------ ------------------------------

27/05/2015 83 24

26/05/2015-107-87

25/05/2015-20-13

24/05/2015             7                             64

22/05/2015-71-71

If this isn't what you want then please give the expected results.

Tags: Database

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