Can I do regular expressions or Boolean logic in the search?

Similar Questions

• MacBook Pro (retina, 15 inches, beginning 2013) El Capitan 10.11.3, Simple question here: I can't open FinalCut Express (4, I believe). The wheel turns for hours. How can I install/uninstall and will I lose all my old films (for the most part stored on ex

  MacBook Pro (retina, 15 inches, beginning 2013) El Capitan 10.11.3, Simple question here: I can't open FinalCut Express (4, I believe). The wheel turns for hours. How can I install/uninstall and will I lose all my old films (for the most part stored on external hard drives). Thanks for your suggestions.

  You will not lose anything, but the app if you uninstall. If you decide to uninstall use this app to make sure that all the other files which depends on FCE are also deleted however I can't give you any assurance as to whether you will be able to reinstall so that it works correctly. It is a software that has not been supported for almost 5 years and there are conflicting reports as to its compatibility with OS X 10.11. Can't I test it myself.

  Maybe someone else will chime in with their own experiences.

  Russ

• regular expression to exclude spaces in the string

  Now that I'm that sleazy, I need help with a regular expression.

  They must pass (or permutations it):

  [00123]

  [R012]

  [r083]

  These should fail (or permutations it):

  [test]

  [I was here]

  [098 876]

  Ooh [29873 eifvuh]]

  I have most of it (the ' [' must be first; the '] "must be the last;) There must be some middle numbers, but I can't write an expression that will fail if there are 1 or more spaces in the string.

  Thank you!

  Tay

  Several possibilities: try this regular expression.

  ^\[[a-za-Z]*[0-9]+[a-zA-Z0-9]*\]$

• Regular expression to remove space after the tag < a... >?

  Hello

  I'm relatively new to using regular Expressions, but am in need who will help me find all the tags < a... > with space immediately after this tag and replace it with the exact same tag, but not space after the tag < a... >.

  Thus, for example, a regular expression that there is:

  < a href = "somelink.html" > Somelink < /a >

  as well as:

  "< a href =" # "MM_swapImgRestore" onmouseover = "MM_swapImage (' sub-nav_button_professional_portal',", ' images/sub-nav_button_ professional_portal_f2.png', 1 ') "> Somelink < /a >

  And just remove the space in the hyperlink.  Does anyone know how to do this?

  Find-

  \ (.*)\

  Replace-

  $2

  Post edited by: Murray * CPA *.

• How can I click on firefox and get fox and the search box nothing else

  I want that Firefox opens with a photo of the Fox and a search box, as he has done before. I had to reinstall and now I have a horrible page full of stuff not the Nice Fox, I had. I am 73 and am not interested in all the frills. Please do not abuse my email with ads.

  You may have installed a character who does not work for you.

  You can uninstall your current Persona and go back to the default theme (Tools > Modules > appearance/themes).

  See:

  • https://support.Mozilla.org/KB/using+themes+with+Firefox
  • http://KB.mozillazine.org/themes (Light theme)
  • https://support.Mozilla.org/KB/troubleshooting+extensions+and+themes

• How can I clear my card data that appears under the search categories cards?

  How can I remove card slots that appear under the search card categories? I have not saved favorites and I already deleted locations lately, but for some reason any previous locations appear under the different search category.

  Click on "Favorites" you show in your screen shot with zero places.

  Then, click "Recent" down to the Center.

  Then click on 'Clear' at the top left.

• I can't open any speed in libraries or use the search bar?

  I can't open all the files in the library and I can not use the library. I also can't save a file or download from the internet.

  I tried this in alternate accounts and in SafeMode with no results any incidents causing windows Explorer is not responding.
  also my computer (i7 2 hearts) is really slow going now.
  Details
  AppHangB1

  Application name: explorer.exe

  Application version: 6.1.7601.17567

  Application timestamp: 4d6727a7

  Hang Signature: a2cb

  Hang Type: 0

  OS version: 6.1.7601.2.1.0.256.48

  Locale ID: 1033

  Signing of additional blocking 1: a2cbfc356a44949ca048d9436f714346

  Signing of additional blocking 2: 2cc8

  Signing of additional blocking 3: 2cc8bef8d5e9f680ea8dddf4c3f1e3e4

  Signing of additional blocking 4: a2cb

  Signing of additional blocking 5: a2cbfc356a44949ca048d9436f714346

  Signing of additional blocking 6: 2cc8

  Signing of additional blocking 7: 2cc8bef8d5e9f680ea8dddf4c3f1e3e4
  Edit: randomly, it resolves itself and returns to its broken state

  Hello

  I suggest you run the utility to search and indexing built into Windows 7 and see if it can help you solve the problem.

  http://Windows.Microsoft.com/en-us/Windows7/open-the-search-and-indexing-Troubleshooter

  I hope that helps!

• Can I write an expression for a value of the model you are looking at, rather than a specific model?

  I know that I can make an expression to a particular layer in a model specific to get a value, for example. COMP ("OpeningTitle01"). Layer ("TITLENAME") .text .sourceText will get the value of the TITLENAME layer in the model OpeningTitle01, but I want to make several compositions (so I can add them to the queue of rendering at the same time) where each will change the value of the underlying model.  Is this possible?  The model where I will use the expression is nested on 5 levels below the top level, and I want to put the value in a layer in each of the new compositions.  Any help is appreciated-thanks guys!

  If what you're asking, is if you can use an expression to cause a layer inside precomp to render different text based on that comp the precomp happens to be nested in, the answer is no.

• Can be used as part of the regular expression user input data?

  Hello!!

  Yet another querry me... This time want to know is possible to use the chain of user input in the context of speech reqular for instant search... I am aiming to add the search functionality in my game... Where I m going to have several items available in the list... what I intend is to have a text box where I accept user input and instant search still a noob in AS3... so, if using RegExp my goal?

  Suggestions please...

  Thanks in advance...

  Yes - you can build a regular expression like this:

  new RegExp("bob", "gi");

• Multiline - Regular Expression Match string

  I'm trying to understand the format of a regular expression to pull select off multi-line string lines and fill in these lines as the individual elements of an array of strings using regular expressions to Match. The total length of the multiline string may vary as well as the text in the string. The string can contain letters, numbers and special characters. I've attached an example VI. In the example of VI, I want to only return lines starting by "device #" in the table. The number of lines starting by "device #" can vary, but I want to capture them all.

  Or is there a better functioning to be used instead of the corresponding regular Expression that will give me the desired result?

  aaronb wrote:

  I'm trying to understand the format of a regular expression to pull select off multi-line string lines and fill in these lines as the individual elements of an array of strings using regular expressions to Match. The total length of the multiline string may vary as well as the text in the string. The string can contain letters, numbers and special characters. I've attached an example VI. In the example of VI, I want to only return lines starting by "device #" in the table. The number of lines starting by "device #" can vary, but I want to capture them all.

  Or is there a better functioning to be used instead of the corresponding regular Expression that will give me the desired result?

  Corresponding regular expression works well for this.

  

  Ben64

• Build a regular expression for data series of Arduino.

  All,

  I have a few Arduinos Council integrated into a test configuration that I can't save the data of.  I now need to be able to see my data in real-time as it comes on the serial port.  I found a VI that seems like it should work, my problem is that I can't get a regular expression to work.

  The VI is not mine, but if I can get this working, I can easily put it in my VI.

  Here's my Arduino code; This is the timestamp, followed four data points, with delimiters tab. It prints on the serial port as

  190876 762314 814437 1108235 1091719

    Serial.print(sTime);
    //Serial.print(", ");
    Serial.print("\t");   
  
    data = getdata(dataRead);
    data = data>>4;
    Serial.print(data);
    //Serial.print(", ");
    Serial.print("\t");  
  
    data = getdata(dataRead1);
    data = data>>4;
    Serial.print(data);
    //Serial.print(", ");
    Serial.print("\t");  
  
    data = getdata(dataRead2);
    data = data>>4;
    Serial.print(data);
    //Serial.print(", ");
    Serial.print("\t");  
  
    data = getdata(dataRead3);
    data = data>>4;
    Serial.println(data);
  

  I think it is especially a problem with regular expression.  Any advice or pointers would be great.

  I wish there was a place where you just have to copy and paste my thong in and get a regular expression.

  Do not use bytes to the port!

  Take advantage of the termination character you have.  Activate it on the series set up and set it to the newline character.

  Now the VISA Read will wait until she has the entire line (or timeout if it does not).  Then you can analyze your data out there.

  I think the problem with your code, it's that you're looking for a backslash n.   Not a line break.  Turn it on the style of display of this constant and you will see it is fixed for normal display and backslash is no bar display.

• Chips with 3 delimiter characters using regular expressions

  Hello world

  I have a function that is able to mark the input in a collection string using regular expressions.

  In case the input string is a character such as the comma or semicolon delimiter,

  We can just get the result we want like the example below.

  SQL> select * from v$version;
  
  
  BANNER
  --------------------------------------------------------------------------------
  Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
  PL/SQL Release 11.2.0.1.0 - Production
  CORE    11.2.0.1.0      Production
  TNS for 64-bit Windows: Version 11.2.0.1.0 - Production
  NLSRTL Version 11.2.0.1.0 - Production
  

  SQL> with tab1 as (
    2      select 'abc,dfg,h,,1234' as col1 from dual
    3  )
    4  select regexp_substr(col1, '([^,]*)(,|$)', 1, level, 'i', 1) as result
    5  from tab1
    6  connect by level <= regexp_count(col1, ',')+1;
  
  
  RESULT
  ---------------
  abc
  dfg
  h
  
  1234
  

  But in the case where the channel of entry has 2 types of delimiter and each delimiter consists of 3 characters as below

  I wonder if it is possible to get the result as below.

  The input string: 01| ^ | ABCD| ^ | 111| * | 02| ^ | efgh| ^ | 222

  Separators: | * | is divided into lines, | ^ | is divided into columns

  Expected result:

  col1 col2 col3

  Row1 - > 01 abcd 111

  row2-> efgh 02 222

  Simply put, take a next

  The input string: 01| ^ | ABCD |^| 111 |*| 02 |^| efgh |^| 222

  Separator: | * |

  Result:

  01. ^ | ABCD | ^ | 111

  02. ^ | efgh | ^ | 222

  How can I achieve this using regular expressions?

  Kind regards

  Euntaek

  You need to know the number of the column from the outset:

  with tab1 as)

  Select ' 01 | ^ | ABCD | ^ | 111. * | 02. ^ | efgh | ^ | 222' as double col1

  )

  Select rownum,

  regexp_substr (regexp_substr (col1 '(.*?) ((\|\*\|)| $) ', 1, level, null, 1),'(.*?) ((\|\^\|)| $) ', 1, 1, null, 1) col1,.

  regexp_substr (regexp_substr (col1 '(.*?) ((\|\*\|)| $) ', 1, level, null, 1),'(.*?) ((\|\^\|)| $) ', 1, 2, null, 1) col2.

  regexp_substr (regexp_substr (col1 '(.*?) ((\|\*\|)| $) ', 1, level, null, 1),'(.*?) ((\|\^\|)| $) ', 1, 3, null, 1) col3

  of tab1

  connect by level<= regexp_count(col1,'\|\*\|')="" +="">

  /

  ROWNUM COL1 COL2 COL3

  ---------- ----- ----- -----

  1 01 abcd 111

  2 efgh 02 222

  SQL >

  SY.

• Find the words (wild cards) using regular expressions

  I'm testing to see if the words are present for revision 1 of a drawing of the cartridge.

  The script search the digit 1 followed by a date, a title, and 4 sets of initials.

  The number 1 is static, (date, title and original are the cards that they are different for each design).

  I use regular expressions to match the words.

  The regular expression highlighted in blue is the number 1 and the date.

  Him remains highlighted in orange does not match the title and initials.

  If anyone can help with the regular expression that is most appreciated.

  Once I got that work will add the form fields for the initials, noting only the console at this point for the tests.

  numWords = this.getPageNumWords (0);

  number of words on the page

  loop through the words on the page

  for (var j = 0; j < numWords-1; j ++)

  {/ / get the pair of words to test}

  ckWords = this.getPageNthWord (0, j) + ' ' + this.getPageNthWord (0, j + 1); test words

  Check if 1 26.05.16 THE STRENGTHENING REVISED MM SB AE GM word string is present

  If (ckWords.match(/ ^ 1\s [0-9] {1,2}.)) [0-9] {1,2}. [0-9] {2} \s\w+(\s+\w+){1,7}/))

  {

  Console.println (ckWords);

  }

  }

  You can use something like this:

  ckWords = this.getPageNthWord (0, j) + ' ' + this.getPageNthWord (j, 0, + 1) + ' ' + this.getPageNthWord (0, + 2 j) + ' ' + this.getPageNthWord (0, j + 3) + ' ' + this.getPageNthWord (0, j + 4) + ' ' + this.getPageNthWord (0, j + 5) + ' ' + this.getPageNthWord (0, j + 6);

  If (! ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} \.\d {2} \s\w+ (?:-s + \w +) {1.8} \s([A-Z]{2})\s([A-Z]{2})-s ([A - Z] {2}) \s([A-Z]{2})$ /)) ckWords + ckWords + "" + this.getPageNthWord (0, j + 7);

  If (! ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} \.\d {2} \s\w+ (?:-s + \w +) {1.8} \s([A-Z]{2})\s([A-Z]{2})-s ([A - Z] {2}) \s([A-Z]{2})$ /)) ckWords + ckWords + "" + this.getPageNthWord (0, j + 8);

  If (ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} {2} \s\w+ \.\d (?:-s + \w +) 1.8 ([A - Z] {2}) \s([A-Z]{2})\s([A-Z]{2})\s {} \s([A-Z]{2})$ /))

  {

  ...

• Helps the understanding of regular Expressions

  Hello people,
  
  I need help to understand Regular Expressions.
  

  -- This returns the Expected string from the Source String. ", Redwood Shores,"
  SELECT
    REGEXP_SUBSTR('500 Oracle Parkway, Redwood Shores, CA,aa',
                  ',[^,]+,', 1, 1) "REGEXPR_SUBSTR"
    FROM DUAL;
  
  REGEXPR_SUBSTR
  -------------------------------
  , Redwood Shores,
  
  However, when the query is changed to find the Second Occurrence of the Pattern, it does not match any. IMV, it should return ", CA,"
  
  SELECT
    REGEXP_SUBSTR('500 Oracle Parkway, Redwood Shores, CA,aa',
                  ',[^,]+,', 1, *2*) "REGEXPR_SUBSTR"
    FROM DUAL;
  
  REGEXPR_SUBSTR
  -------------------------------
  NULL

  Can someone help me understand why second query not returning ", CA, '?
  
  I did research on this forum and found the link on the thread "https://forums.oracle.com/forums/thread.jspa?threadID=2400143" for the basic tutorials.
  
  
  
  Kind regards
  P.

  The reason is that the comma between 'Redwood Shores' and 'CA' already represents the first occurrence.
  So it can not match the second occurrence at the same time.

  You can replace to (remove the trailing ',' in the regex):

  SELECT  REGEXP_SUBSTR('500 Oracle Parkway, Redwood Shores, CA,aa',',[^,]+', 1, 1) REGEXPR_SUBSTR  FROM DUAL;
  
  SELECT  REGEXP_SUBSTR('500 Oracle Parkway, Redwood Shores, CA,aa',',[^,]+', 1, 2) REGEXPR_SUBSTR  FROM DUAL;
  

  Published by: hm on 14.06.2012 00:52

  When you remove also the leading comma you get to the BlueShadows solution.

• AFExactMatch and regular Expressions

  Hello

  I'm working on something similar to this http://forums.adobe.com/message/4215772#4215772.

  My first shot at it.  Found it useful messages of try67 and George.  I'm almost there and now, I'm stumped.

  My Custom Format Script is the following:

  Custom Format script for the text field

  If (event.value) event.value += '% ';

  My typing a custom Script is the following:

  Custom keystroke script

  DigOnlyKS();

  My custom calculation script is the following:

  If (event.value == "") event.value = 0;

  My Javascript Document is:

  function DigOnlyKS() {}

  Get everything that is currently in the field

  var val = AFMergeChange (event);

  Refuse entry if other thing that the figures

  Event.RC = AFExactMatch (/ \d* /, val);

  Event.RC = AFExactMatch (/^100\.0| [1-9] {1,2}\.\d{1}|0\.\d{1}$/, val);

  }

  Valid entries must be: 100.0, 1.0 to 99.9, and 0.1 to 0.9.

  The regular Expression seems to work on the Regex testers online.

  However, I can't enter anything in the field with the foregoing.

  If replace my Regex with the link above - ^ \d+\. ? \d{0,2}$ - I can enter data in the field.

  However, if I remove the? the - ^\d+\.\d{0,2}$ - regex to require (I think) the decimal places, I can't enter anything in the field.

  Clearly, Miss something.

  Thank you.

  Regular expression is not appropriate for a typo script until the value has been committed, and even in this case, it may be too restrictive (for example, does not allow for ".") 9 »).

  The way I would be inclined to implement would be to put the strike and Validate Format (not calculate) scripts to call the following functions, respectively.

  // Custom Keystroke script calls this
  function percent_ks() {
  
      AFNumber_Keystroke(1, 1, 0, 0, "", false);
  
  }
  
  // Custom Format script call this
  function percent_fmt() {
  
      AFNumber_Format(1, 1, 0, 0, "", false);
      if (event.value) event.value += "%";
  
  }
  
  // Custom Validate script calls this
  function percent_val() {
  
      if (event.value === "") event.value = 0;
  
      // Only allow numbers from 0 to 100
      if (+event.value >= 0 && +event.value <= 100) {
          // round to nearest tenth
          event.value = util.printf("%.1f", event.value);
      } else {
          event.rc = false;
          app.alert("Your error message goes here.", 3);
      }
  
  }
  

  It lets you enter values outside the valid range, but the validation script takes care of it. It also allows more than one digit to the right of the decimal, but the validation script it rounds up to the tenth closest. Make sense?

  Edit: correction of fault