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• SDO_NN cannot be assessed without using the index when put inside subquery

  Hi all

  I met a problem when you use the function sdo_nn to find the nearest neighbor. Here is my scenario:

  _ I have 2 customer and store tables.

  Customer table _ a client_ID and a 2D sdo_geom point

  _ Store table has store_ID and a 2D polygon sdo_geom.

  In the beginning, I have this query to find the nearest store to each customer as below:

  Select s.STORE_ID, c.CLIENT_ID

  store customer, s c

  where sdo_nn (s.MYPOLYGON, c.MYPOINT, 'sdo_num_res = 1', 1) = "TRUE";

  _It works as expected when it returns a table showing the nearest store each customer.

  _Now I want to count the number of customers who have the same nearest store:

  Select / * + INDEX (store store_spatial_idx, client_spatial_idx client) * / count (nearest_store. CLIENT_ID)

  from (select s.STORE_ID, c.CLIENT_ID

  store customer, s c

  where sdo_nn (s.MYPOLYGON, c.MYPOINT, 'sdo_num_res = 1', 1) = "TRUE") nearest_store

  Group of nearest_store. STORE_ID;

  This query generates the following error:

  Error report-

  SQL error: ORA-13249: SDO_NN cannot be assessed without using the index

  ORA-06512: at the 'MDSYS. MD", line 1723

  ORA-06512: at the 'MDSYS. MDERR", line 17

  ORA-06512: at the 'MDSYS. PRVT_IDX', line 9

  13249 00000 - '%s '.

  I'm pretty new to spatial databases and hope get help to go further. Thank you in advance!

  Hello Pinball,

  Oracle space tends to be a quite complex with many variables and moving parts.  We chatted about the group to a sort of FAQ or guidelines to help people like you submit questions that actually answers.  First of all, you really have to tell us the version of Oracle you are using.  Particularly the problems involving the optimizer, version down to the exact defined patch number is a good idea.  Secondly, you took the time to submit the question so I guess you want a response.  If you really want to see the answer and then providing an example is one of the most important things that you can do.  I'm going to do here for you, but in general people on this forum come and go and are often pushed into lurkitude, so if you want the coax to provide you with an example of work is the key.

  DROP TABLE store1 PURGE;
  CREATE TABLE store1(
      store_id INTEGER NOT NULL
     ,shape    MDSYS.SDO_GEOMETRY
     ,PRIMARY KEY(store_id)
  );
  
  DROP TABLE client2 PURGE;
  CREATE TABLE client2(
      client_id INTEGER NOT NULL
     ,shape    MDSYS.SDO_GEOMETRY
     ,PRIMARY KEY(client_id)
  );
  
  CREATE OR REPLACE PROCEDURE seeder(
      p_client_count IN NUMBER
     ,p_store_count IN NUMBER
  )
  AS
    sdo_foo MDSYS.SDO_GEOMETRY;
    int_counter NUMBER;
    FUNCTION random_point
    RETURN MDSYS.SDO_GEOMETRY
    AS
        num_x1 NUMBER;
        num_y1 NUMBER;
  
    BEGIN
        num_x1 := dbms_random.value(-179,179);
        num_y1 := dbms_random.value(-89,89);
  
        RETURN MDSYS.SDO_GEOMETRY(
            2001
           ,8265
           ,MDSYS.SDO_POINT_TYPE(
                num_x1
               ,num_y1
               ,NULL
            )
           ,NULL
           ,NULL
        );
  
    END random_point;
  
  BEGIN
    int_counter := 1;
    FOR i IN 1 .. p_client_count
    LOOP
        -- Create a client point
        sdo_foo := random_point();
        INSERT INTO client2
        VALUES (
            int_counter
           ,sdo_foo
        );
        int_counter := int_counter + 1;
  
    END LOOP;
  
    int_counter := 1;
    FOR i IN 1 .. p_store_count
    LOOP
        -- Create a store polygon of some kind
        sdo_foo := MDSYS.SDO_GEOM.SDO_ARC_DENSIFY(
            MDSYS.SDO_GEOM.SDO_BUFFER(
                random_point()
               ,5000
               ,0.05
            )
           ,0.05
           ,'arc_tolerance=0.05'
        );
        INSERT INTO store1
        VALUES (
            int_counter
           ,sdo_foo
        );
        int_counter := int_counter + 1;
  
    END LOOP;
  
    COMMIT;
  
  END seeder;
  /
  
  BEGIN
    seeder(10000,200);
  END;
  /
  
  BEGIN
    INSERT INTO user_sdo_geom_metadata(
        table_name
       ,column_name
       ,diminfo
       ,srid
    ) VALUES (
        'STORE1'
       ,'SHAPE'
       ,MDSYS.SDO_DIM_ARRAY(MDSYS.SDO_DIM_ELEMENT('X',-180,180,.05),MDSYS.SDO_DIM_ELEMENT('Y',-90,90,.05))
       ,8265
    );
  
    COMMIT;
  
  EXCEPTION
    WHEN OTHERS
    THEN
        NULL;
  
  END;
  /
  
  BEGIN
    INSERT INTO user_sdo_geom_metadata(
        table_name
       ,column_name
       ,diminfo
       ,srid
    ) VALUES (
        'CLIENT2'
       ,'SHAPE'
       ,MDSYS.SDO_DIM_ARRAY(MDSYS.SDO_DIM_ELEMENT('X',-180,180,.05),MDSYS.SDO_DIM_ELEMENT('Y',-90,90,.05))
       ,8265
    );
  
    COMMIT;
  
  EXCEPTION
    WHEN OTHERS
    THEN
       NULL;
  
  END;
  /
  
  CREATE INDEX store1_spx ON store1
  (shape)
  INDEXTYPE IS MDSYS.SPATIAL_INDEX
  NOPARALLEL;
  
  CREATE INDEX client2_spx ON client2
  (shape)
  INDEXTYPE IS MDSYS.SPATIAL_INDEX
  NOPARALLEL;
  
  /* Works as expected */
  SELECT
  s.store_id
  ,c.client_id
  ,MDSYS.SDO_NN_DISTANCE(1)
  FROM
  store1 s
  ,client2 c
  WHERE
  MDSYS.SDO_NN(
      s.shape
     ,c.shape
     ,'sdo_num_res=1'
     ,1
  ) = 'TRUE';
  
  /* No worky? Works for me */
  SELECT
  ns.store_id
  ,COUNT(ns.client_id)
  FROM (
     SELECT
      s.store_id
     ,c.client_id
     FROM
      store1 s
     ,client2 c
     WHERE
     MDSYS.SDO_NN(
         s.shape
        ,c.shape
        ,'sdo_num_res=1'
        ,1
     ) = 'TRUE'
  ) ns
  GROUP BY
  ns.store_id
  ORDER BY
  ns.store_id;
  

  So I wrote this about 12 c (12.1.0.2.0) and everything works fine for me.  Then I moved back from 11 GR 2 (11.2.0.4.0) and of course, there are questions.  So I guess that you don't use flavor of 11g.  So at this point we can look at the docs and see for 11g, have you often need to specify which table is the head and that is the one that has the spatial index to use.
  http://docs.Oracle.com/CD/E11882_01/AppDev.112/e11830/sdo_operat.htm#SPATL1032

  Its rather interesting that the optimizer of 12 c knows what you want, when I had to squint myself at your request and to play a little with the refining.  Note that SDO_NN is sensitive, because the geometry of the main table should come second in the operator.  I did not know that on the top of my head.

  
  SELECT
  /*+ LEADING(c) INDEX(s store1_spx)  */
   s.store_id
  ,c.client_id
  ,MDSYS.SDO_NN_DISTANCE(1)
  FROM
   store1 s
  ,client2 c
  WHERE
  MDSYS.SDO_NN(
      s.shape
     ,c.shape
     ,'sdo_num_res=1'
     ,1
  ) = 'TRUE';
  
  SELECT
   ns.store_id
  ,COUNT(ns.client_id)
  FROM (
     SELECT
     /*+ LEADING(c) INDEX(s store1_spx)  */
      s.store_id
     ,c.client_id
     ,MDSYS.SDO_NN_DISTANCE(1)
     FROM
      store1 s
     ,client2 c
     WHERE
     MDSYS.SDO_NN(
         s.shape
        ,c.shape
        ,'sdo_num_res=1'
        ,1
     ) = 'TRUE'
  ) ns
  GROUP BY
  ns.store_id
  ORDER BY
  ns.store_id;
  

  So I think that is your answer.  Give it a shot and see if this fits the Bill.  Of course, moving to 12 c would be useful for such things.  It would be interesting to collect more examples of this kind of space thing where 12 c is the answer. Also, would be nice if we could mark somehow this discussion as applying only to 11g and earlier versions.

  See you soon,.

  Paul

• SDO_NN giving ORA-13249: SDO_NN cannot be assessed without using the index

  Hi people,
  
  I do not understand why the SDO_NN gives ORA-13249 in circumstances.
  
  SQL > SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and title like '%' and rownum < 10;
  
  TITLE
  --------------------------------------------------------------------------------
  MultiPoint_305199
  LineString_691779
  MultiPolygon_180478
  MultiPolygon_358113
  MultiPolygon_53008
  MultiPolygon_249905
  MultiPolygon_204076
  MultiPolygon_636994
  MultiPoint_464514
  
  9 selected lines.
  
  SQL > SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and timestamp > = to_timestamp (January 6, 2011 ', ' dd/mm/yyyy') and rownum < 10;
  SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and timestamp > = to_timestamp (January 6, 2011 ', ' dd/mm/yyyy') and rownum < 10
  *
  ERROR on line 1:
  ORA-13249: SDO_NN cannot be assessed without using the index
  ORA-06512: at the 'MDSYS. MD", line 1723
  ORA-06512: at the 'MDSYS. MDERR", line 17
  ORA-06512: at the 'MDSYS. PRVT_IDX', line 49
  
  The spatial index is created with:
  CREATE the INDEX SlavaTest_geometry_idx_spatial ON SlavaTest (geometry) INDEXTYPE IS mdsys.spatial_index;
  
  'Title' and 'timestamp' columns have an index.
  
  Note the query comes from Hibernate and I can't change it's arbitrary.

  Slava2 wrote:
  What this means - there is a bug in Oracle?

  Well, it could probably be considered a, but [url http://docs.oracle.com/cd/E11882_01/appdev.112/e11830/sdo_operat.htm#i78067] documentation on SDO_NN warns you:

  Documentation says:
  However, if the column in the WHERE clause predicate specifies a non-space column in the table for geometry1 with an associated index, make sure that this index is not used by specifying the NO_INDEX indicator for this index.

  See you soon,.
  Stefan

• SDO_NN cannot be assessed without using the index

  Hello
  I'll try to find more close neighbours of a point using two tables (grafo_ped_links & haltestellen) and I fail miserably quiet.
  
  Select h.desc_i, grafo_ped_links h.numpal g, haltestellen h where (g.geometry, h.geometry) sdo_nn = 'true' and g.start_node_id = 355 and rownum < = 5
  *
  ERROR on line 1:
  ORA-13249: SDO_NN cannot be assessed without using the index
  ORA-06512: at the 'MDSYS. MD", line 1723
  ORA-06512: at the 'MDSYS. MDERR", line 17
  ORA-06512: at the 'MDSYS. PRVT_IDX', line 49
  
  But I am able to find the nearest neighbor on individual tables (singularly) without any problem. I'm even able to find a WITHIN_DISTANCE using two tables (below the sql statement).
  
  Select h.numpal from grafo_ped_links g, haltestellen h where SDO_WITHIN_DISTANCE (h.geometry, g.geometry, 'DISTANCE = 0.5 UNIT = KM') = 'TRUE' and g.start_node_id = 355;
  
  NUMPAL
  ----------
  5122
  5103
  5102
  5120
  5100
  5301
  5302
  5303
  
  I even dropped the indexes of the two tables and recreated them again. I read somewhere that the problem could be due to a lack of advice, so I tried the following and I still get the same error.
  
  
  Select / * + LEADING (g) INDEX (h haltestellen_ridx) * / h.desc_i, h.numpal
  of grafo_ped_links g, h haltestellen
  where (g.geometry, h.geometry) sdo_nn = 'true' and g.start_node_id = 355 and rownum < = 5
  
  Select / * + INDEX (h haltestellen_ridx) NO_INDEX (g grafo_ped_links_ridx) * / h.desc_i, h.numpal
  of grafo_ped_links g, h haltestellen
  where (g.geometry, h.geometry) sdo_nn = 'true' and g.start_node_id = 355 and rownum < = 5
  
  Select / * + USE_NL (h, g) VALUE * / h.desc_i, h.numpal
  of grafo_ped_links g, h haltestellen
  where sdo_nn (g.geometry, h.geometry, 'sdo_num_res = 5', 1) = 'true' and g.start_node_id = 355 and rownum < = 5
  
  
  Anyone can please, show me the way, or give a hint. I use oracle spatial 11g.
  
  Thank you!
  Cook
  
  Published by: user611283 on December 30, 2009 06:11

  It should be 'TRUE '.

  Select h.desc_i, grafo_ped_links h.numpal g, haltestellen h where (h.geometry, g.geometry) sdo_nn = 'TRUE' and g.start_node_id = 355 and rownum<=>

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