Cell color table export LabVIEW

Similar Questions

• Color table RTF model based on an attribute cell is retrning an error

  Hi all
  I try to create a report model that contains a table. The table should display data and color according to the data in the table. The cell color is also saved in the xml file, while I'm trying to set the background color using the code

  <xsl:attribute xdofo:ctx="block" name="background-color"><?c3color?></xsl:attribute>

  I get an error which is
  

  Font Dir: D:\Java\jre1.5.0_06\Template Builder for Word\fonts
  Run XDO Start
  RTFProcessor setLocale: en-us
  FOProcessor setData: C:\ReportTemplates\report1.xml
  FOProcessor setLocale: en-us
  java.lang.StringIndexOutOfBoundsException: String index out of range: 0
       at java.lang.String.charAt(Unknown Source)
       at oracle.apps.xdo.template.fo.datatype.Color.parseColorStr(Unknown Source)
       at oracle.apps.xdo.template.fo.datatype.ColorPool.getColor(Unknown Source)
       at oracle.apps.xdo.template.fo.datatype.Background.setBgColor(Unknown Source)
       at oracle.apps.xdo.template.fo.datatype.Background.init(Unknown Source)
       at oracle.apps.xdo.template.fo.datatype.Background.getBackground(Unknown Source)
       at oracle.apps.xdo.template.fo.area.BlockArea.<init>(Unknown Source)
       at oracle.apps.xdo.template.fo.area.BlockContainerArea.<init>(Unknown Source)
       at oracle.apps.xdo.template.fo.area.TableCell.<init>(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.table.FOTableCell.createAreaObject(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.table.FOTableCell.doLayout(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.table.FOTableRow.doLayout(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.table.FOTableBody.doLayout(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.table.FOTableBody.doLayout(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.table.FOTable.doLayout(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.FOBlock.doLayout(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.FOBlock.doLayout(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.FOBlock.doLayout(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.FOFlow.doLayout(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.FormattingEngine.startLayout(Unknown Source)
       at oracle.apps.xdo.template.fo.elements.FormattingEngine.run(Unknown Source)
       at oracle.apps.xdo.template.fo.FOHandler.endElement(Unknown Source)
       at oracle.apps.xdo.common.xml.XSLTHandler$EEEntry.sendEvent(Unknown Source)
       at oracle.apps.xdo.common.xml.XSLTMerger.startElement(Unknown Source)
       at oracle.xml.parser.v2.XMLContentHandler.startElement(XMLContentHandler.java:167)
       at oracle.xml.parser.v2.NonValidatingParser.parseElement(NonValidatingParser.java:1182)
       at oracle.xml.parser.v2.NonValidatingParser.parseRootElement(NonValidatingParser.java:301)
       at oracle.xml.parser.v2.NonValidatingParser.parseDocument(NonValidatingParser.java:268)
       at oracle.xml.parser.v2.XMLParser.parse(XMLParser.java:149)
       at oracle.apps.xdo.template.fo.FOProcessingEngine.process(Unknown Source)
       at oracle.apps.xdo.template.FOProcessor.generate(Unknown Source)
       at RTF2PDF.runRTFto(RTF2PDF.java:632)
       at RTF2PDF.runXDO(RTF2PDF.java:466)
       at RTF2PDF.main(RTF2PDF.java:254)

  but I can't put the cell background color to help

   <xsl:attribute xdofo:ctx="block" name="background-color">red</xsl:attribute>
  <xsl:attribute xdofo:ctx="block" name="background-color">#123456</xsl:attribute>

  the

  <?c3color?>

  Returns the hexadecimal values.
  
  pls help me solve this problem...
  
  
  
  
  Thanks in advance...
  Ranjith.

  Try the following scenario

  for example, you tag in rich text that contains the color value (say - #cc6600)
  so
  You can refer to as follows

  so
  for the conditional formatting

• Under certain conditions changing cell color in a dynamic array.

  I'm developing an application where I'd like to set the background color of a cell in a PivotTable based on the value of the cell content. I have two questions:
  
  the first is that when I use the following EL in the property of inlinestyle, I get the cell colored but not completely just the bottom of the text.
  
  < af:forEach elements = "#{bindings." Var MyView1.attributeDefs}' = 'def' >
  < af:column headerText = "#{bindings." MyView1.labels [def.name]}"id ="c1 ".
  attributeChangeListener = "#{backingBeanScope.backing_my.c1_attributeChangeListener} '"
  rowHeader = "true" >
  < af:outputText value = "#{row [def.name]}" id = 'ot1' "
  GT = inlineStyle "#{row [def.name] 10000?' background-color: Red;':"} "/ >
  < / af:column >
  < / af:forEach >
  
  the second issue is that I want to only apply it to all the columns after the first column have a valid numeric value. I get a NumberFormatException when a nonnumeric value is encountered. Thank you for your help... :)

  As always, you should mention your jdev version...
  You did not mention what you want in a different color. However you can test yourself with a normal component. Play with styles until you get the result you want. Then copy the inlineStyle into your dynamic table. The string can be very long, you be better off using a skin in the first place.

  You second problem cannot be handled only in a managed bean method. Call a method in a managed bean to check if the value of the cell is a number valid and then apply the style for the element.

  Assemble the two solutions, you end up with a method to a bean that checks the value and returns the inlinestyle or the styleclass string.

  Timo

• How to read the color table in a subvi?

  How to read the color table in a subvi? Is it made by a reference to the table or with a global variable? For a better understanding of the problem, I added to vi. Run the "run.vi." I want to see

  the background color of the table "run.vi" in the subvi called "read color.vi".

  How can I do?

  Thanks in advance

  Norick

  pop up on the wire table refernece and establishes 'control '. Add this control to the icon of the sub - VI decision-making and then wire ref of the appellant to this Terminal VI so the calling VI move the ref to the Subvi.

  Ben

• Photoshop CC for mac: in image/mode/bitmap &amp; color table not available

  CC Photoshop for mac

  image/mode /: bitmap & color not available table

  and also do not find Behance in file menu

  Does anyone have this problem?

  Hi michelc76474034

  • By the way, you can only covert grayscale bitmap.
  • To change a color, click the color and choose a new color from the color picker.
  • To change a range of colors, drag the table to choose the range of colors you want to change. In the color picker, choose the first color you want in the range, and then click OK. When the color picker appears again, choose the last color you want in the range, and then click OK.
  • The color selected in the color picker are placed in the selected in the Color Table dialog box.
  • To assign transparency to a color, select the eyedropper tool in the Color Table dialog box and click on the color of the table or image. The sampled color is replaced by the transparency of the image.
  • Click OK in the Color Table dialog box to apply the new colors to the image to indexed color.

  Note: If you have already tried all of the above options, try reinstalling PS CC 2015

  Concerning

  Rohit

• indexed - color mode how to remove a custom color table color

  Hello

  I'm working on a bitmap to which I put my color mode to "indexed color Mode.  I created a custom color table and I added 9 colors.  I would like to delete one of these colors, but I can't find a way to remove a color from my existing custom color table or start with an empty custom color table so that I can add only colours I want.  If someone can tell me how to do either of these things, I'd be very happy.

  Thanks in advance,
  Paul

  I had the same problem. I'm not sure that you can remove colors. I just changed the color, I'm not one of the existing colors that I want. It does not hurt to have two colors of the same value in the table.

  Edit: This is what I warned you about in your other post.

• Change cell color in a table based on the input

  Hi guys

  Please refer to my example, I have attached. I had a 2d with som information table. 1 row = 1 component information and it's electric. This table is put in a table when you press "Update" in the front panel. My goal is that based on index 1 of table (col2 'Edge'), the color of the TableRow should change color. If the contents of the line is S20-1, the color should be red and so on. It works a little bit, but I'll have a few bugs:

  -You must press "Reset" twice in order to remake the Whiteboard.

  -The first colorchange also changes the color of the entire table. I want my whiteboard and lines to change color (header and TableRow unused must be white).

  You can change the first element in the array constant of S20 - 1-S20 - 3 and you will see that my program brings to the whole blue table on the first colorchange.

  Is this a mistake on my part? Or is this a bug in LV (which I doubt)?

  Property nodes are running up and down, and you have the reverse order. You set the color first, and then the active cell, which means that the colour be trolling a run.

  Your code is also too complicated. Here's a quick draft how this could be done. Let me know if you have any questions.

  

• table cell color dynamically and programmatically based on a condition of entry

  Hello
  We use Jdev 11.1.1.6.0 for my ADF development.
  In our page Jspx, we have three components:
  1. a reading table used with an additional column "Error box" in the form of input text
  2. a text entry accepts employeeID running,
  3. a command button on the occasion of the red cell in the column of the error box against the received EmployeeID
  
  Required functionality:
  1. the user will be entered EmployeeID (which has the error of data) in the input text and press the command button
  2.internally, by programming, there is a bean method call from IE button which will accept the entry and check the rowKey in the table corresponding to the EmployeeID using the Iterrator function and retrieve the exact id of this cell in the column ErrorBox.
  3. after obtaining the id, highlight the cell in the column of the error in red box.
  
  I used the following excerpt from the bean to have the feature but does not work and also there is no error indicating that:
  
  * if (row.getAttribute ("EmployeeId")! = null) {*}
  * if (row.getAttribute("EmployeeId").toString () .equalsIgnoreCase ((String) component.getValue ())) {*}
  RowSetIterator empRSIter = iter.getRowSetIterator ();
  Line currentRow = empRSIter.getRowAtRangeIndex (i);
  String tableId = table.getClientId (facesContext);
  RKS RowKeySet = table.getSelectedRowKeys ();
  inputId tableId = + ': ' + i + ': ' + 'ot10;
  org.apache.myfaces.trinidad.render.ExtendedRenderKitService service;
  Service = org.apache.myfaces.trinidad.util.Service.getRenderKitService (facesContext, ExtendedRenderKitService.class);
  service.addScript (facesContext, "field var = AdfPage.PAGE.findComponentByAbsoluteId (" "+ inputId +"'");") field.style.backgroundColor = "red"; ») ;
  
  We strive to highlight the error in the table in the column of the error against the EmployeeId box has received. But we cannot get the functionality. Please suggest.
  Thank you
  Charrier

  Hello

  1. you must maintain the value of the string in a bit more broad (try pageFlowScope, for example) IE - value = "#{pageFlowScope.myBean.empId} '"
  2. Add a partialTriggers for the score table the ID of the text input.
  3.

  #{row.EmployeeId == backingBeanScope.myBean.empId ?'backgroundcolor:red;':'backgroundcolor:black;'}">
  {code}
  should be
  {code}
  #{row.EmployeeId == pageFlowScope.myBean.empId ?'background-color:Red;':''}"> 
  

  Arun-

• Change table cell color according to the input data

  Hi, I have a table in a form and I want the cells to have a dark in each cell if it has not entered data, but the cell background color to change white if no text is entered in the cell. Is it possible to do?  Thank you.

  You can use the fillColor for this property. It depends on your table structure how you do this. If you have relatively small table say 3 columns. 3 rows and then in each cell of sortient / calculate event you can put the following script.

  If (Cell1.rawValue == null & Cell2.rawValue == null & Cell3.rawValue == null)
  {
  Row1.fillColor = "255,0,0";
  }
  else {}
  Row1.fillColor = "255,255,255";
  }

  If you have a larger table, then you must create a function for it.

  Thank you

  Sidonie.

• AF:table cell color is not displayed in Mozilla

  Hi all
  I have a table where I show a few colors based on the data in this particular cell, that coming from the database.
  I've implemented this using Internet Explorer 7. So far, everything is ok.
  Now I'm testing it in mozilla and IE 8, the color does not appear in these browsers.
  I'll put hexcolor inside each cell.
  Pls tell me how can I bring color in Mozilla and Exlorer 8 also. ?
  

  background-color:#{row.GroupColor}

  Studio Edition Version 11.1.1.2.0
  Firefox 8.0
  Explorer 8
  
  
  
  Kind regards
  Rognard

  column inlineStyle works for me... THAT IS TO SAY 8
  background - color:RGB (148,222,255);

• ADF Table cell color based on the value of this field

  Dear all,
  I want to create a table for our new application that contains a table that is used to represent the data in a table or matrix format.
  and each cell of the table should be filled with a color of three colors, based on the value belongs to who will for example: (1-8-> green, 9-20 - yellow etc.).
  I don't know how to implement this. Help, please...
  
  Rognard

  Please post in the subforum that is appropriate for your question.

  http://forums.Oracle.com/forums/Ann.jspa?annID=599

  This blocking thread

• Table column header cell color

  Hello
  
  I use the ADF. My requirement is to fill the table with a specific color column heading, I am able to apply the background color using the contents of the cell in the selector below.
  
  AF | : column-to-head-cell-content
  {
  background-color: rgb (214,231,255);
  }
  
  But I want to use this color instead of the text in the cell to fill the cell.
  
  Please let me know the switch that I need to use to get there.
  
  Thank you.

  Hello

  In the give the link, select the "component" column
  Then select the box "Demo: all '---> the background of the column header is green.
  Hope this is what you are looking for.

  concerning
  Peter

• How to eliminate the cell border color table

  The website that I'm getting is posted at http://www.100presentationstopremier.com/
  
  I am trying to remove the green lines bordering the horizontal orange stripe at the bottom of the header. I can't find any style of autocorrelation. I tried to change the color of brdr in the properties panel.
  
  Thank you
  
  

  It's in your CSS.

  #navigation a: hover {}
  background: #99CC66;
  color: #993300;
  }

  --
  Murray - ICQ 71997575
  Adobe Community Expert
  (If you * MUST * write me, don't don't LAUGH when you do!)
  ==================
  http://www.projectseven.com/go - DW FAQs, tutorials & resources
  http://www.dwfaq.com - DW FAQs, tutorials & resources
  ==================

  "David8765" wrote in message
  News:g4jjvm$NQF$1@forums. Macromedia.com...
  > The above does not appear in my source code page or opinion. Not 99CC66 or
  > the
  > stationary of terms or #navigation.
  >
  > But the buttons don't reversal and color is 99CC66.
  >
  > The site is displayed in http://www.100presentationstopremier.com
  >
  > Any suggestions? Thank you very much.
  >

• Cannot control the color sensor in LabView for Mindstorms

  Hello!  New here.

  I'm currently boning on LabView via 'LabView for Lego Mindstorms' for a possible job in the near future, and I encountered a problem from the beginning.

  I am programming my brick Lego of LabView to simply activate the color sensor which is quite easy: I'm building a while loop and inside I have a block of color sensor attached to a block of text that displays the light intensity of the probe in the text on the brick.  I compile and run the detector turns on and I can read the intensity constantly updated on the brick.  This part works fine.  I would now like to control the light sensor (that doubles as a light source with color LEDs) on the front of the LV Panel.  The book I'm using (LabView for Lego Minstorms) says I should block sensor on the entry "generate light' do right click and choose"Create--> Control"in the menu that appears.  A Boolean command button should appear connected to the sensor block in the block Panel and a push button should appear in the front panel.  This is not what is happening.  Here, the two things are different.

  (1) I have no port "generate light" click on right-click.  This is probably using a version more day of Mindstorms that uses of the book.  It's a matter of book/Mindstorms, which probably cannot be resolved here but I hope that the next issue of problems will make it irrelevant.

  (2) I right click and create the control, but rather than create a Boolean command button as the book predicts, it creates an icon "BrickReference.lvclass".  He connects very well with the light sensor and a corresponding block is created in the front panel, but it is a paper weight that I can tell.  I can't do anything with it.  There are no buttons to push, no slider, button, button radio etc and I can't seem to change into something that somehow work.  I have delete and don't create a no kidding Boolean button from the library, but it does not connect to the photoelectric cell and so I can not compile.  So now, I'm a little stuck.

  I searched "Reference of the brick" online in the context of LabView class and have found little or nothing that talks about its definition or how I can use it to control the light via the front panel sensor.  Help with the software section is not much help, and yet I'm sure there must be a way to control a simple Lego light sensor of the façade for debugging purposes and others.

  If you know what I'm doing wrong or if you know a finish around this issue that will allow me to control a Mindstorms brick from the front in this way, please let me know.

  Thank you!

  Try to post in the forum of Lego.

  http://forums.NI.com/T5/LabVIEW-for-LEGO-MINDSTORMS-and/BD-p/460

• cell color

  Is it possible to set the background color of a particular table cell?

  Yes, it is possilble. using EL expression, you can specify the condition for the inlineStyle property.
  Example Code:

  
    
    .  .
    
    . .
  
  

  Jean Lou

  Published by: Marc Israel on November 9, 2009 20:30

  Published by: Marc Israel on November 9, 2009 21:42