Comparison between two tables

Hello

I have two tables USERS and LISTS:

And I want that there is a comparison between these two tables executed when user table USERS connect to the application.

They must compare the columns between the SEXES and AGE and if some users have the same attributes in its ranks as in a line in the table LISTS (here is unique each line) so that the user gets in his line in the column 'LIST_ID' the ID of the line with which attributes between GENDER and AGE.

Example:

USERS TABLE: exampleuser | Boby | McGrahem | Male | 18. -------

LISTS OF TABLE: 28 | examplelist | Male | 18

Once the Login of the user Boby gets in its ranks the ID = 28 because the SEX and AGE corresponds to the row of table LIST:

Result:

USERS TABLE: exampleuser | Boby | McGrahem | Male | 18. 28


CREATE TABLE  "USERS" 
   (    "USERNAME" VARCHAR2(15) NOT NULL ENABLE, 
        "FORRNAME" VARCHAR2(15) NOT NULL ENABLE,                  
        "SURNAME" VARCHAR2(15) NOT NULL ENABLE, 
        "GENDER" VARCHAR2(10) NOT NULL ENABLE,   
        "AGE" NUMBER, 
        "LIST_ID" NUMBER, 
         CONSTRAINT " USERS_PK" PRIMARY KEY ("USERNAME")
  USING INDEX  ENABLE



CREATE TABLE  "LISTS" 
   (    " LIST_ID" NUMBER NOT NULL ENABLE, 
        " LISTNAME" VARCHAR2(50) NOT NULL ENABLE, 
        "GENDER" VARCHAR2(10) NOT NULL ENABLE, 
        "AGE" VARCHAR2(3) NOT NULL ENABLE,  
         CONSTRAINT " LISTS_PK" PRIMARY KEY ("LIST_ID")
  USING INDEX  ENABLE
  

I need help for coding this, if someone be so good.

This is my essay:


DECLARE  
    v_listid varchar2(100);   
    BEGIN  
      
    SELECT  LIST_ID into v_listgid
     FROM LISTS
     WHERE GENDER = (SELECT GENDER
                          FROM USERS 
                        WHERE UPPER(TRIM(USERNAME)) = UPPER(TRIM(:APP_USER)))
     AND AGE = (SELECT AGE
                          FROM USERS  
                        WHERE UPPER(TRIM(USERNAME)) = UPPER(TRIM(:APP_USER)));

     UPDATE USERS   
    SET LIST_ID =  v_listid   WHERE UPPER(TRIM(USERNAME)) = UPPER(TRIM(:APP_USER));  
  
    END;

I'd like to REALLY shy away using the USER name as the primary key, because the fact that users can create duplicate user names... YOU should NEVER base a PK on the entry of user, the better to let the database create and maintain this element of date...

FIX:

UPDATE to users U

SET List_Id = (SELECT List_Id OF lists L WHERE L.Gender = U.Gender and L.SOMENUMBER = U.SOMENUMBER) AND

Upper (U.UserName) = UPPER(:APP_USER);

Don't really want to cut the strings, Oracle which will do since they are of type varchar2 columns...

Thank you

Tony Miller
Software LuvMuffin
Ruckersville, WILL

Tags: Database

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                             obj_name,
                             obj_type)
                          values(1192,
                                'MainObject',
                                'Form');
                                
                                
             insert into object_list (cal_objid,
                             obj_name,
                             obj_type)
                          values(1193,
                                'SecondObject',
                                'Form');  
                                
                                
             insert into object_list (cal_objid,
                             obj_name,
                             obj_type)
                          values(1194,
                                'ThirdObject',
                                'Form');    
                                
                                
              insert into object_list (cal_objid,
                             obj_name,
                             obj_type)
                          values(1195,
                                'FourthObject',
                                'Form');  
                                
                                
    insert into object_list (cal_objid,
                             obj_name,
                             obj_type)
                      values(1196,
                             'FirthObject',
                             'Form');
                             
                         
                             
                             
                              insert into cal_erd values(1193,1192,null);
                              insert into cal_erd values(1194,1193,null);
                              insert into cal_erd values(1195,1194,null);

    in the first table values

    CAL_OBJID OBJ_NAME, OBJ_TYPE OBJ_TITLE DESCRIPTION
    1192 MainObject form
    1193 SecondObject form
    1194 ThirdObject form
    1195 FourthObject form
    1196 FirthObject form

    the second value of the table
    OBJ_CHILD OBJ_PARENT OBJ_REL_TYPE
    1192 1193
    1194 1193
    1195 1194

    SQL script that I am trying

    WITH t AS 
    (SELECT li.obj_name,
            li.obj_type,
            li.obj_title,
            li.DESCRIPTION, 
            LEVEL AS lvl,
            SYS_CONNECT_BY_PATH(li.obj_name, '/')paths 
    FROM object_list li,cal_erd er
     where li.cal_objid = er.obj_parent(+)
         START WITH obj_parent IS NULL
         CONNECT BY
                  NOCYCLE PRIOR obj_child = obj_parent)
  SELECT obj_name,
         LEAD(obj_name) OVER(ORDER BY paths) AS child_name,
         obj_type ,
         obj_title ,
         DESCRIPTION ,
         substr(paths,
                       INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl-1 END) + 1 , 
                       INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl END)                    
                      - INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl-1 END) - 1 ) AS parent_name
    FROM t;


    get value

    OBJ_NAME, OBJ_TYPE OBJ_TITLE DESCRIPTION PARENT_NAME CHILD_NAME
    FirthObject FourthObject form
    FourthObject form

    I what like to be like that

    OBJ_NAME, OBJ_TYPE DESCRIPTION OBJ_PARENT OBJ_TITLE OBJ_CHILD

    SecondObject MainObject form

    ThirdObject SecondObject form MainObject

    fourthObject ThirdObject shape SecondObject

    I would like if possible show the id of ojb_name

    Hello

    Here's a way to achieve the expected results, you want to:

    WITH t AS
    (SELECT obj_parent
          , li.obj_name
          , li.obj_type
          , li.obj_title
          , li.DESCRIPTION
          , LEVEL AS lvl
          , SYS_CONNECT_BY_PATH(li.obj_name, '/')paths
    FROM object_list li
         LEFT JOIN cal_erd er ON (li.cal_objid = er.obj_child)
         START WITH obj_parent IS NULL
         CONNECT BY
                  NOCYCLE PRIOR cal_objid = obj_parent),
t2 AS (
  SELECT LEAD(obj_name) OVER(PARTITION BY substr(paths, 1
                                                      , CASE WHEN INSTR(paths, '/', 1, 2)> 0
                                                             THEN INSTR(paths, '/', 1, 2)-1
                                                             ELSE LENGTH(paths)
                                                        END)
                                 ORDER BY paths) AS child_name
       , obj_name
       , obj_type
       , obj_title
       , DESCRIPTION
       , substr(paths,
                       INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl-1 END) + 1 ,
                       INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl END)
                      - INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl-1 END) - 1 ) AS parent_name
    FROM t)
SELECT *
  FROM t2
 WHERE child_name IS NOT NULL;

    Result:

    CHILD_NAME OBJ_NAME, OBJ_TYPE OBJ_TITLE PARENT_NAME DESCRIPTION

    SecondObject MainObject form

    ThirdObject SecondObject form MainObject

    FourthObject ThirdObject shape SecondObject

    Kind regards

    Steve

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