count the numbers peaks
Hello, I am new user of labview. I want to count the numebr of spikes which will be detected in the pic detetctor.
now u can suggest me some realted to counts example that appears in the chart or table
thanq
2249kumar wrote:
If the particle has energy (radon) 5 MeV it takes 1. If it was again 5 MeV it takes 2 altogether, it must be with the total counts.
I assume you mean if the energy of radon will less than 5 more than 5 (threshold), add - it to the count (+ 1).
Don't count that peaks after having dropped below 5 and then go back on it 5 (rising edge)? hysteresis?
Also, I assume that you will work on a simple radon energy reading (or point) at a time. Stamps to collect 100 readings in a waveform and then by peak count after collecting your data.
Tags: NI Software
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Maybe not the most elegant, but it should work:
SQL> WITH s AS ( 2 SELECT 2 a, 7 b FROM DUAL UNION 3 SELECT 3 a, 3 b FROM DUAL UNION 4 SELECT 3 a, 6 b FROM DUAL UNION 5 SELECT 9 a, 15 b FROM DUAL UNION 6 SELECT 10 a, 10 b FROM DUAL UNION 7 SELECT 10 a, 15 b FROM DUAL 8 ), 9 t AS ( 10 SELECT level-1 i 11 FROM dual 12 CONNECT BY level <= ( SELECT max(b)-min(a)+1 FROM s ) 13 ) 14 SELECT count(distinct min(a)+i) as cnt 15 FROM s CROSS JOIN t 16 GROUP BY a,b,i 17 HAVING min(a)+i BETWEEN a AND b 18 ; CNT ---------- 13
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Hi all
I am a new user of LabVIEW and I'm going to ask you about a problem that certainly many of you will find quite annoying.
I develop software for a test machine management that uses an another bend, a tachometer that generates a signal of rectangular analog output in volts, 0V to 8V. Like many I thi signal in a waveform graph.
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Help formula: count the number of whites in a column "up to the...» »
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Hi BaronDe,
I need to ask, "why you try to do this? So what you want is possible it will be a complex solution. It may be much easier to get your information in a different way. Indicate these blanks?
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Kill them salvation.
for all B cells on the second act of sheet as "smart cells", if you want to, where they are all automatically use the COUNTIF function using the expression in each corresponding to a cell, instead of the manual set up I have now.
Formula in B2 (and fill by dragging the handle downwards to fill yellow)
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Click on the "Collection::Table 1: $B" diamond in the formula editor to select.
Go to the Map Collection and click on the label C.
AHA! It always displays zero because does not match the description of length:
"Very short (less than 5 hours)" on the card product and "Very short" on the Collection sheet.
The descriptions must match exactly.
The easy way to change them in the Collection journal is to sort the table. But first of all insert another column, and then type 1 then 2 and fill down. Then you can sort to the original order.
Now sort the column Length.
Change the description (copy and paste into each "block")
Funny looks because the line height are different
The COUNTIF works because the descriptions are now (the formula now displays column D because of the new column of original order of Collection).
I'll post this before the time-out annoys me.
Kind regards
Ian.
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Front
After
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/* Copyright 2014, Kasyan Servetsky June 4, 2014 Written by Kasyan Servetsky http://www.kasyan.ho.com.ua e-mail: [email protected] */ //====================================================================================== var scriptName = "Count number of steps - 1.1", doc; PreCheck(); //===================================== FUNCTIONS ====================================== function Main() { var foundItem, header, lastPar, num; app.findGrepPreferences = app.changeGrepPreferences = NothingEnum.NOTHING; app.findGrepPreferences.findWhat = "(?s).+"; app.findGrepPreferences.appliedParagraphStyle = "Steps"; var foundItems = doc.findGrep(true); if (foundItems.length == 0) ErrorExit("Found nothing", true); for (var i = 0; i < foundItems.length; i++) { foundItem = foundItems[i]; if (foundItem.paragraphs.length == 0) continue; header = foundItem.parentStory.paragraphs.previousItem(foundItem.paragraphs[0]); if (header.appliedParagraphStyle.name != "Header") continue; lastPar = foundItem.paragraphs[-1]; num = lastPar.numberingResultNumber; if (num == -1) continue; InsertNum(header, num); } app.findGrepPreferences = app.changeGrepPreferences = NothingEnum.NOTHING; } //-------------------------------------------------------------------------------------------------------------------------------------------------------- function InsertNum(header, num) { app.findGrepPreferences = app.changeGrepPreferences = NothingEnum.NOTHING; app.findGrepPreferences.findWhat = "( \\()(\\d+)( Steps\\))$"; app.changeGrepPreferences.changeTo = "$1" + num + "$3"; app.findGrepPreferences.appliedParagraphStyle = "Header"; var changed = header.changeGrep(); if (changed.length == 0) { header.insertionPoints[-2].contents = " (" + num + " Steps)"; } } //-------------------------------------------------------------------------------------------------------------------------------------------------------- function PreCheck() { if (app.documents.length == 0) ErrorExit("Please open a document and try again.", true); doc = app.activeDocument; if (!app.activeDocument.saved) ErrorExit("The current document has not been saved since it was created. Please save the document and try again.", true); Main(); } //-------------------------------------------------------------------------------------------------------------------------------------------------------- function ErrorExit(error, icon) { alert(error, scriptName, icon); exit(); } //--------------------------------------------------------------------------------------------------------------------------------------------------------
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Hi all
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So you have to get numbers, no numbers, use Grep to find all the numbers: \d+
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Then you have to work at the end of the numbers found in the beginning because the length of the number wioll change, for example 10 (two digits) can change to 9 (one digit). Like this
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See you soon,.
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In CS3 and later versions, you can use this:
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Count the points...
Hello!
In a form, users enter into an input field references to elements separated by a space (TextField.restrict applied to the only digits 0-9, and space).
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