CVI2010-operator sizeof returns an incorrect size of a struct

Hello

in CVI2010 the sizeof operator returns an incorrect struct size if it contains 4 bytes and other spaces. I guess that the addresses in the struct are also not as c-programmer thinks. First a minimalist code example:

typedef struct
{
oneByte tank;
long fourByte;
} TestStruct;

main void)
{
int size;
TestStruct tmpVar;
size = sizeof (TestStruct);
Here are the dimensions = 8 instead of 5

}

Over the past years and last cvi-versions I had never compiled with the compiler Borland, which returns the correct size. Because the Borland compiler is not included in CVI 2010, I am using the compiler to build-in the standard. In my opinion, the compiler looks to optimize the code somehow, my project cannot work with.

Because I read the direct struct of binary files I'm looking for a to code based, solution.

Is it possible to disable the relevant optimization?

Thanks for your help and your response.

Markus

The compiler may have different alignments for the fields of the struct: a usual behavior is to them be aligned on a 4 byte boundary, that is each field starts on a multiple of 4 bytes from the beginning of the structure in memory. This seems to be the behavior of the compiler that you are using currently, who returns as the size of the structure 8 after aligning the fields.

Alignment of the structure can be modified with a #pragma appropriate preprocessor directive: adding #pragma pack (1); in your code tells the compiler to pack the structure without filler fields; After that this statement sizeof returns the size 5-bytes are waiting for you.

Tags: NI Software

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