cwdsp. Sine wave is where the sampling rate?

Hello

According to the method above (CWDSP. Sine wave), the parameters are the following:

(n, a, f, Phase)

n As Variant - [Input] number of samples to generate.
Amp as Variant - [Input] Amplitude of the signal that results.
f As Variant - [Input] frequency of the signal resulting in standardized units of cycles/sample.
The phase as a Variant - initial phase [output] in degrees of the generated signal. Output, the Phase is the phase of the next portion of the signal. Use this setting in the next call to this function to simulate a generator of continuous functions.

We are not lack of sampling frequency?

example:

I want to generate the next sine-

FREQ = 1 kHz

sampling frequency = 10 kHz

(Number of samples) block size = 1024

Amp = 1

How will you use this function for this signal?

I think (but I'm not sure of it...) is: CWDSP. SineWave (1024, 1, 1/10, 0)

There is an example: "power spectrum".  In this example, they do not mention the sampling frequency and the signal is generated as follows:

CWDSP. SineWave (1024, 1, 0, 1000/1024)

No mention of the sampling frequency.

Thank you

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Hey Rafi,

Both of your assertions are correct.  The frequency of de.1Hz at no time is the equivalent of what you would get from sampling equipment of a wave of 10 kHz to 1000 s/s; in both cases, you will see a cycle of the wave every 10 samples, as you are pointing out.

Tags: NI Software

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