Similar Questions

• Align 45 does not... Some opinions, I cannot draw a line at 45 and 90 degree angle with a line (for example to draw a straight line with SHIFT tool, select and line maintenance, form does not hang at increments of 45 as it was by default) it Note still wo

  Align 45 does not... Just noticed I can't align a line at 45 and 90 degree angle with a line (for example to draw a straight line with SHIFT tool, select and maintaining line, shape is not hang at increments of 45 as it was by default) it notes still works with forms & text etc, but not with a straight line. Having downloaded the latest January 14, 2016

  Last update fixed this Glitch, Illustrator please :-)

• Add the word 'project' at a 45 degree angle

  Good day all.

  I try to incorporate the word "PROJECT" on a 45 degree angle on a form that I would send for review. I tried to add to the 'master' page, but of course he's hiding part of the form. Is there a way that this could be done?

  Thank you

  Chomp

  I've solved this by creating an image of the text that I wanted in photoshop, then put it in a field of the image, making sure to send the master key of the image to the back.

• create 45 degree angle line filling

  Hi guys/girls
  you will need to create 45 degree angle line/fill pattern that appears seamless. Fill will be used on images of different sizes, it's at the base of the fill. Second, the lines should be about 5px apart, black and white.

  Thank you

  Create the hatched pattern, draw a marquee selection around it, then edit--> as motive.

  Mylenium

• degree angle to a 14-bit BCD format

  I need to convert an angle from degrees to a 14-bit BCD format. all that is 0 degrees 0, 359,99 degrees all the 1. What is the best way to go about this?

  Hi adventurer.

  angle (BCD14) = convert to u16 (rest ((degree) / 360) * 16384)

  Is simple math, not?

  BTW.

  It is not called BCD. It's just a different range (0-16383) for the same meaning (0-359, 99 °)...

• Four ratings but no 90 degree angle

  Hi all

  Recently I was given a shape with four sides to draw, each side is different in size with no angle of 90 degrees in any corner, no point of reference was given either. How we start to draw it?

  I've done Center the two vertical lines horizontally, move the hand to the greatest length, group two verticals and top them aligned in line the longest, low aligned the brevity with the most vertical and slipped past corners until they met. Still they where wrong.

  This is the 6th year school math... You know, trapezoids and parallelograms. Wikipedia and Mathworld are your friends... Pythagoras' Theorem, triangles and law of Sines, you know...

  Mylenium

• The screen display is at 45 degree angle

  Hi, I hope someone can help me!  My screen is anti clockwise 45 degrees and I can't turn it around.  This happens I didn't get internet so I unplugged the power without turning off the computer.

  I don't know there is a simple way to do it with the know how.
  Thank you much for the help.

  Control-Alt-arrow high

• find the angle of rotating an image in 8-bit grayscale

  Hi all

  I have an image in grayscale 8 bits of dimension 3969 X 600, the image is slightly tilted. I need to find the rotation angle and apply the rotation before treatment.

  Are there transformation features in LabVIEW to find the angle of rotation?

  Need your suggestions people,

  Hello

  just calculate the slope of the line joining the two points:

  xDiff = p2.x - p1.x

  yDiff = p2.y - p1.y

  [degrees] angle = atan2 (yDiff, xDiff) *(180/pi)

  

  Best regards

  K

• Would be - a lens wide angle work here?

  Hello world! This is my first post and excuse that my ignorance, but I need to see if you guys could help me with something. I just bought a T3i and I have no photography or video production experience but I am really interested in getting my feet wet in these two areas.

  But anyway, I have a tripod and want to shoot my brother and I play tennis. I have always created the tripod at a considerable distance, but if we put in place in the Middle we can only film one side of the Court. A goal wide angle would be able to record both sides of the Court at the same time?

  Watch online examples of photos showing the angle of view.

  You could get a lens fisheye lens 180 degrees and sit right at the net but all objects other than those at the edge of the lens will appear quite small. Fisheye lenses also have effects strong enough curvature. In addition, there are two types of fisheye lenses... a guy makes a full frame, rectilinear image, while the other type restores a round image.

  While appearsimilar focal fisheye lens ultrawide, any given focal length a fisheye gives actually wider than a non-fisheye AOV. Canon now offers a for example 8-15mm fisheye zoom. But since it is designed for cameras full frame, it will be not too wide on your device at sensor crop (I don't have exact specifications for this on a crop sensor camera, only full frame specifications are listed). Tokina offers a zoom 10-17mm fisheye specifically designed for crop sensor cameras, and as such, it can make 180 degrees angle of view of your camera.

  A non-ultra wide angle fisheye will have less curvature distortion, but will always be some extremes and will be also less wide angle of view. For example, the EF-S 10-22mm lens is the widest available Canon, objective: give the AOV 107 in the setting of 10 mm. The wider non-fisheye lens made by any person for the use on your camera is the Sigma 8-16mm, which gives it a degree of 114 AOV is wider. With these lenses ultrawide perspective distortion even exaggerate perspective, more distant objects look very small compared to relatives... even if it is not as extreme as it is with a fisheye lens.

  If it's a one-shot deal and calls fisheye for you, because a fisheye is a rather specialized lens and you can watch in the rental of a lens for this purpose. Ultra wide-angle non-fisheye as the Canon 10-22 mm is often more widely useful, so maybe something you would find much more use for long term and want to buy as rent.

  ***********
  Alan Myers

  San Jose, California, USA.
  «Market softly and carry a great lens.»
  MATERIAL: 5DII, 7D(x2), 50D(x3), some other cameras, various lenses & accessories
  FLICKR & REPROGRAPHY

• Photoshop CS6 rotates 90 degrees to the right alignment of text characters istead vertically?

  Photoshop CS6 rotates 90 degrees to the right alignment of text characters istead vertically?

  I have the same exact problem as this thread.

  The solution is change option East Asia and rearmament of the preferences, but mine is still typing horizontally at a 90 degree angle. Anyone know of any other way?

  Have you tried to reset the text tool and reset the characters available in ground #1.

  Kind regards

  Mohit

• Incorrect form created on the application of any applied angle race point

  Hello

  1. I created a box 200pt X 200 pt

  2 applied angle of 45 degrees.

  3. then, I applied to 45 degrees of Bank.

  Result: I got a form...

  1. I created another box of the same size

  2. I applied 45 degree tilt

  3. then I applied 45 degrees Angle

  Result: I had another form that is different from the first.  Why this watch two forms different even when all values are the same? I tried the same in InDesign and quark and got the same forms in both cases (this second form). What is a defect or the destination behavior for Illustrator?

  

  For InDesign (and probably the same for Quark) these two transformations are attributes of the object. Which means, no matter in what order you have entered values for the fields option, InDesign applies in a fixed order, which is always the same.

  Illustrator applies instead a transformation to the path at the time wherever you enter the value. When you enter the next value transformation applies again the path resulting from the first transformation.

• Keep the angle of a line of direction as you drag a direction point

  Hello

  I have a way with an inflection point. The two branch points form a line of direction with any non-45-degree-angle - 11.8 degrees.

  I want to drag a direction point while keeping the angle of 11.8 degrees exactly.

  Is there a key combination for this (Mac OS)?

  Thanks in advance.

  I asked for this function for 20 years. Short answer: you can't extend a line. Nifty chart said FINALLY Adobe enough: Let's get some real tools in Illustrator. Their Vectorscribe plugin has an extension function that may extend to any path all right, a spiral or Bezier.

• Convert an anchor in a right angle?

  Hello

  I would like to choose an anchor point and adjust it so that it creates a perfect right angle. How can I do?

  Imagine some closed, filled with shape, composed a dozen anchor points. I would choose one of these anchor points (a corner anchor point, not a point of inflection) and adjust it (built-in? script?) while it creates a perfect right angle (90 deg.). This essentially means moving it to just the right place so that the lines connecting its two neighbouring anchor points form a right angle.

  Hope that the description is clear.

  Please, do not assume that the right angle that results would be necessarily oriented along an axis North-South, or any other rational compass statement.

  Thanks a lot for any help or pointers...

  Ariel

  So here's the script I wrote. Looks like it works pretty well, but I did not too widely tested yet.

  // BS"D
  // Create Right Angle
  // An Illustrator CS5 Script (may work in other versions too)
  // Copyright (c) 2014 by Ariel (www.freelancebookdesign.com)
  // This script may be used freely provided these opening comments are not removed.
  // This script will adjust a point on a path (open or closed) so that it forms a 90 degree angle with its two adjacent points.
  // See http://forums.adobe.com/thread/1385409?tstart=60 for more details.
  // To use, select an anchor point on a path. The path must contain at least 3 anchor points.
   // The selected point should not be an end point if the path is open.
   // Run the script. The selected point will be moved the smalled distance possible such that it forms a
   // right angle with its neighbouring points.
  
  try{
      if (app.activeDocument.selection.length == 0){
          throw("Please select an anchor point and try again.");
      }
      var mySelection = app.activeDocument.selection[0];
      if (mySelection.constructor.name != "PathItem"){
          throw ("Please select an anchor point and try again.");
      }
      var myPoints = mySelection.pathPoints;
      if (myPoints.length < 3){
          throw ("The script can only work if there are at least 3 anchor points on the path.");
      }
      var foundSelected = false;
      for (var i = 0; i < myPoints.length; i++){
          var myPoint = myPoints[i];
          if (myPoint.selected == PathPointSelection.ANCHORPOINT){
              foundSelected = true;
              break;
          }
      }
      if (foundSelected == false){
          throw ("Please select one of the anchor points.");
      }
      if (!mySelection.closed && myPoint == myPoints[myPoints.length-1]){
          throw ("The last anchor point was selected. Please select an anchor point between two others.");
      }
      if (!mySelection.closed && myPoint == myPoints[0]){
          throw("Please select an anchor point between two others.");
      }
      var prevIndex = i-1;
      var nextIndex = (i+1) % myPoints.length;
      if (mySelection.closed && prevIndex < 0){
          prevIndex = myPoints.length-1;
      }
      var adjustedPoint = adjustPoint(myPoints[prevIndex], myPoint, myPoints[nextIndex]);
      myPoint.anchor = [adjustedPoint.x, adjustedPoint.y];
      myPoint.rightDirection = [adjustedPoint.x, adjustedPoint.y];
      myPoint.leftDirection = [adjustedPoint.x, adjustedPoint.y];
  }
  catch(e){
      alert(e);
  }
  function adjustPoint(pointA, pointB, pointC){
      // A and C are static. B will be adjusted.
      var Ax = pointA.anchor[0];
      var Ay = pointA.anchor[1];
      var Bx = pointB.anchor[0];
      var By = pointB.anchor[1];
      var Cx = pointC.anchor[0];
      var Cy = pointC.anchor[1];
      // Find new point M that is midway between A and C
      var Mx = 0.5 * (Cx + Ax);
      var My = 0.5 * (Cy + Ay);
      // r = radius of circle whose diameter is AC
      var r = (Math.sqrt((Cx - Ax)*(Cx - Ax) + (Cy - Ay)*(Cy - Ay)))/2;
      // s = the distance between M and B
      var s = Math.sqrt((Bx - Mx)*(Bx - Mx) + (By - My)*(By - My));
      if (s == 0) {
          alert("The script must now disappear in a puff of infinity.");
          // pointB does not need to be moved;
          return {x: Bx, y: By};
      }
      // f is the ration between r and s
      var f = r/s;
      // D is the new point we're looking for
      var Dx = Mx + (Bx - Mx) * f;
      var Dy = My + (By - My) * f;
      return {x: Dx, y: Dy};
  }
  

• Angle of the gradient overlay

  I have a question that has a gradient overlay added as a layer style. It has a 90 degree angle. What I have to do is to rotate this object at 45 degrees, but to keep the angle of the gradient I selected. At the moment if I rotate the object then the gradient overlay maintains at 90 degrees to the document instead of 90 degrees of the real object, it is attached.

  Any ideas how to lock the angle to the object?

  You can convert the layer to a smart object.

• Elements of the plan of work moving on an angle...

  Do not know why this is happening... I select the text tool and click on the artboard to type... the cursor is at a 45 degree angle... I select an element and a shot to the left or right... the item moves on an angle... not left or right. I inadvertently did not alter a setting to make it happen and how can I fix this normal?

  Thank you very much!

  Open the preferences (Cmd [Ctrl] k) and check the Angle of the constraint in the General window (first). Sounds like he got a value outside of 0.