Delete the min and max labels on chart axis markers

Hello

Is it possible to remove the min and max labels on chart axis markers? For example, see the screenshot below. Can I remove the numbers circled in green without changing the range of the axis? In some cases (like this one), the presence of the min and max number of cases other marker values to not be displayed (red line). I am aware that "10" is displayed if I enlarge the graph, but this isn't an option for my application. FYI - the screenshot is from the side before the attached VI.

Thanks for any help,

Kind regards

Stu

You can't delete them because they are the main features to be able to set the max and min on the graph of the Panel before if you use no-AutoScaling.

Tags: NI Software

Similar Questions

the min and MAX values maintain their good values tia sal22

the min and MAX values maintain their good values tia sal22

Hi all

I have problems a little value to stay in their correct min and max values min and max.
Continue to change their values (up and down) trying to get the max value to only display the maximum value at a given time and the same for the min value. I looked at the examples max and min and it seems that it should be in a while loop
http://forums.NI.com/NI/board/message?board.ID=170&thread.ID=359822

but I would add another while loop and if so put it in the loop for? or is there a better way to do it.

TIA sal22

Hi sal22,

I thought it was just one example you found somewhere, because it is called red rooster. See the attached example.

Mike

Grouping and then find the min and max

DROP TABLE purge of y;
CREATE TABLE y
(
ID NUMBER (10),
START_DATE_TIME NUMBER (15),
END_DATE_TIME NUMBER (15)
);
INSERT INTO y VALUES (1, 20140602164819, 20140606140851);
INSERT INTO y VALUES (1, 20140827141743, 20140827142131);
INSERT INTO y VALUES (1, 20140827141744, 20140827141835);
INSERT INTO y VALUES (1, 20140827141744, 20140827142131);
INSERT INTO y VALUES (1, 20140827141944, 20140827142131);
INSERT INTO y VALUES (1, 20140827141944, 20140924142131);
INSERT INTO y VALUES (1, 20140927141944, 20141027142131);
INSERT INTO y VALUES (2, 20140602164819, 20140606140851);
INSERT INTO y VALUES (2, 20140827141743, 20140827142131);
INSERT INTO y VALUES (2, 20140827141744, 20140827141835);
INSERT INTO y VALUES (2, 20140827141744, 20140827142131);
INSERT INTO y VALUES (2, 20140827141944, 20140827142131);
INSERT INTO y VALUES (2, 20140827141944, 20140924142131);
INSERT INTO y VALUES (2, 20140927141944, 20141027142131);
COMMIT;
Select
*
Of
There
order by 2, 3;
out necessary: when the output of the table are sorted by start_date_time and end_date_time in ascending order.
and when the value of for a particular id start_date_time is located between the
another set of values start_date_time and end_date_time for the same id then min (start_date_time) and max (end_date_time) is the desired output.
and if there is no overlap then (start_date_time) min and max (end_date_time) is the output desired.
and for each line of the output in ascending order of line number order addd;
Example output is in the output table named
drop table output is serving;
create an output table
(
ID NUMBER (10),
START_DATE_TIME NUMBER (15),
END_DATE_TIME NUMBER (15),
ROW_NUMBER NUMBER (10)
);

Values to INSERT OUTPUT (1, 20140602164819, 20140606140851, 1);
Values to INSERT OUTPUT (1, 20140827141743, 20140924142131, 2);
Values to INSERT OUTPUT (1, 20140927141944, 20141027142131, 3);
Values to INSERT OUTPUT (2, 20140602164819, 20140606140851, 1);
Values to INSERT OUTPUT (2, 20140827141743, 20140924142131, 2);
Values to INSERT OUTPUT (2, 20140927141944, 20141027142131, 3);
COMMIT;
SELECT
*
Of
output
ORDER BY 1,2,3,4;
Thank you
SQL_Novice

Hello

Your postal code. It is difficult to tell what you're doing wrong without knowing what you are doing.

user6166680 wrote:

Hi Frank:

Max works for ID 3 values only because there is only one group here, as all other values compared, they overlap with max (end_date_time);

but when I use MAX for ID 1 and 2, the result set is not the same thing as LAG works because there is a GAP...

Exactly, you have to find the gaps. If start_date_time is less than or equal to the MAXIMUM of all the end_date_times earlier, then it isn't a gap; Otherwise, there is a gap.

What is the problem with MAX?

WITH got_new_group AS

(

SELECT id, start_date_time and end_date_time

CASE

WHEN start_date_time <= > MAX (end_date_time) OVER (PARTITION BY id )

ORDER BY start_date_time

end_date_time

ROWS BETWEEN UNBOUNDED PRECEDING

AND 1 PRECEDING

)

THEN 0

1. OTHER

END AS new_group

OF y

)

got_group_number AS

(

SELECT id, start_date_time and end_date_time

SUM (new_group) OVER (PARTITION BY ID.

ORDER BY start_date_time

end_date_time

) AS group_number

OF got_new_group

)

SELECT id

MIN (start_date_time) AS group_start_date_time

MAX (end_date_time) AS group_end_date_time

group_number

OF got_group_number

GROUP BY id, group_number

ORDER BY id, group_number

;

You will notice that it is exactly what I posted earlier, in response #5, except that instead of using the OFFSET it uses MAX.

Output:

ID GROUP_START_DATE_TIME GROUP_END_DATE_TIME GROUP_NUMBER

--------------- --------------------- ------------------- ---------------

1 20140602164819 20140606140851 1

1 20140827141743 20140924142131 2

1 20140927141944 20141027142131 3

2 20140602164819 20140606140851 1

2 20140827141743 20140924142131 2

2 20140927141944 20141027142131 3

3 20140330041350 47121231000000 1

I've updated to 8.0 and now firefox will not open and I get an error message indicating that 7.0.1 is not compatible with version 8.0 of the Min and max version 8.0. What can I do now?

I tried to uninstall 7.0.1 and reinstall only and still it would not to date and problems such as the loss of my favorites and have different toolbars and Add ons whenever I opened it. I lost so many bookmarks and it became so frustrating that I decided to try to upgrade to see if that could overcome the problems. And now I have this problem. When I did a search on my hard drive to see the components of firefox how was I found firefox files and documents in all directions and I was wondering if I should just delete everything related to firefox to clean all residual files which could be causing problems and then start a clean download , but I didn't want to delete files in windows and didn't know what I should delete and I have to leave. Can anyone help? I miss my firefox and the wish that I had never upgraded to 7.0.1.

If you use ZoneAlarm Extreme Security then try turning off virtualization.
- http://KB.mozillazine.org/Browser_will_not_start_up#XULRunner_error_after_an_update
See also:
- [880050/questions/880050]

Compare the min and max columns

Hello

I want to compare colum 1,2,5

If max - min > 1 = failure

How could I go making the?

I think I should just remove all columns with 0, but I'm having a hard time to remove.

can someone guide me how do.

Thank you

Using the MIN and MAX functions

Hello

Guide to please the following:

I have a table with records like below:

Invoice ID RegistrationNo InvoiceDate
1 AB-1 JANUARY 1, 10
2 CB-4 MARCH 23, 10
3 AB-1 1ST JULY 10
4 FG-2 AUG 1, 10
AB - 5 1 7 FEBRUARY 11
CB - 6 4 FEBRUARY 8, 11
7 CB-4 12 AUG 11

I want to pass the result of the SQL query, as below

For RegistrationNo = AB-1

Reffacture RegistrationNo InvoiceDate
3 AB-1 1ST JULY 10
AB - 5 1 7 FEBRUARY 11

For RegistrationNo = CB-4

Reffacture RegistrationNo InvoiceDate
CB - 6 4 FEBRUARY 8, 11
7 CB-4 12 AUG 11

I want to get that two records by RegistrationNo with the previous date of min, whose date max more forward.

Kind regards

Something like that?

WITH A AS (SELECT 1 INV_ID, 'AB-1' REG_NO, TO_DATE ('01-JAN-10', 'dd-mon-rr') INV_DATE FROM DUAL
            UNION
           SELECT 2 INV_ID, 'CB-4' REG_NO, TO_DATE ('23-mrz-10', 'dd-mon-rr') INV_DATE FROM DUAL
            UNION
           SELECT 3 INV_ID, 'AB-1' REG_NO, TO_DATE ('01-JUL-10', 'dd-mon-rr') INV_DATE FROM DUAL
            UNION
           SELECT 4 INV_ID, 'FG-2' REG_NO, TO_DATE ('01-AUG-10', 'dd-mon-rr') INV_DATE FROM DUAL
            UNION
           SELECT 5 INV_ID, 'AB-1' REG_NO, TO_DATE ('07-FEB-11', 'dd-mon-rr') INV_DATE FROM DUAL
            UNION
           SELECT 6 INV_ID, 'CB-4' REG_NO, TO_DATE ('08-FEB-11', 'dd-mon-rr') INV_DATE FROM DUAL
            UNION
           SELECT 7 INV_ID, 'CB-4' REG_NO, TO_DATE ('12-AUG-11', 'dd-mon-rr') INV_DATE FROM DUAL)
SELECT INV_ID,
       REG_NO,
       INV_DATE
  FROM (SELECT INV_ID,
               REG_NO,
               INV_DATE,
               ROW_NUMBER() OVER (PARTITION BY REG_NO ORDER BY INV_DATE DESC) RN
          FROM A
       )
 WHERE RN<3
ORDER BY REG_NO,
         INV_DATE DESC

Taskbar and min and max do not show on the homepage and e-mail

When cleaning key board, the taskbar, and the top part of the page containing the min and max symbols disapperared. How can I restore them?

Hello

I suggest you to try the steps below and check if it helps.

(a) open Internet Explorer by pressing the button of the window of your keyboard, then clicking on Internet Explorer.

(b) move your cursor to the top right and click the Tools button, and then click file.

(c) uncheck the option full screen .

You can also press F11 on your keyboard, which would help you to get to the normal screen.

Hope this information is useful.

Min and Max on a table

Hello. I want to make a program where I want to generate a sine and take only the monotonous positive part.

So I thought to find the min and max of the function index and make a program like the one attached.

As you can see that if you set the frequency to 10 Hz, it works fine... the problem is when you change the frequency such as 20 or 50 H.. t seems that it is not find the min and max correctly.

Can you suggest me some tips?

Thank you

s.turino84 wrote:

and take only positive part monotonous.

This means that the derivative is positive. So, make a derivative. If the derivative is greater than 0 keep the present value, or the value 0.

Min and Max in a row!

Hi guys,.

Do you know how I can get the MIN and MAX in a row?

For example:

C1 | C2 | C3 | C4 | C5 | C6 | C7 | C8

10. 50. 70. 5. 90. 135. 4 | 60

I return 4 and 135.

I can return it without using the service?

Thank you

Eric

create table t as
with d as (
  select 1 n from dual
  union all
  select null from dual
)
select a.n c1, b.n*2 c2, c.n*3 c3
from d a, d b, d c;

select c1,c2,c3,
greatest(
  coalesce(c1,c2,c3),
  coalesce(c2,c3,c1),
  coalesce(c3,c1,c2)
) greatest_c,
least(
  coalesce(c1,c2,c3),
  coalesce(c2,c3,c1),
  coalesce(c3,c1,c2)
) least_c
from t;

C1	C2	C3	GREATEST_C	LEAST_C
1	2	3	3	1
1	2		2	1
1		3	3	1
1			1	1
	2	3	3	2
	2		2	2
		3	3	3

Hello I (IPAD MINI DEVICE) and problem in my memory I have 12.5 GB, and using less of it and A Nofticate it indicates your size will end soon, or something like that I deleted the apps and that he got 100 MB and after all the Nofticate come back and some

Hello I Have (IPAD MINI DEVICE) and have problem In My Memory I have 12.5 GB, and using less of it and A Nofticate it indicates your size will end soon, or something like that I deleted the apps and got 100 MB and after all in the Nofticate come back and something has my size and it says Iam using fully 12.5 GB and I amnt Iam using just use it 4 or 5 GB

Try to provide the exact text of the message you see. "size will end or something" identifies not enough information for anyone to be able to solve the problems.

In addition, check if reference is made to the size on the device, called space iCloud.

How can I go into a used computer and change the username to the mine and to make a new password or delete the old user of my computer completely? (preferably get rid of the former user)?

I need to know how to solve this problem in detail please

I bought a computer with windows xp service pack 3 and when I start it the old user keeps popping up asking for a password. I want to know how to enter and change the username to the mine and to make a new password or delete the old user of my computer completely (preferably get rid of the former user)?

See the following link to delete the account: http://support.microsoft.com/kb/279783

Help the query to list all the days between MIN and MAX date in a table

Hello

Sorry, this may have already responded earlier, but I really struggled to find a previous response with the new provision of the RTO.

In a DB 11 g, I date MIN and MAX in a table:

{code}

SELECT MIN (process_date) start_date, MAX (process_date) end_date FROM my_table;

{code}

I would get every day between these 2 dates. I mean even is there is no record in the table for a date.

Is this possible?

Thanks in advance,

Olivier

Hello

Do you mean something like this?

ranit@XE11GR2>> ed
Wrote file c:\rb\1.sql

  1  with xx as
  2  (
  3      select
  4     to_date('05-06-2013','dd-mm-yyyy') min_d,
  5     to_date('20-06-2013','dd-mm-yyyy') max_d
  6      from dual
  7  )
  8  --
  9  -- end of test data
 10  --
 11  select
 12     min_d + level date_x
 13  from xx
 14* connect by level<=(max_d-min_d)
ranit@XE11GR2>> /

DATE_X
-------------------
06-06-2013 00:00:00
07-06-2013 00:00:00
08-06-2013 00:00:00
09-06-2013 00:00:00
10-06-2013 00:00:00
11-06-2013 00:00:00
12-06-2013 00:00:00
13-06-2013 00:00:00
14-06-2013 00:00:00
15-06-2013 00:00:00
16-06-2013 00:00:00
17-06-2013 00:00:00
18-06-2013 00:00:00
19-06-2013 00:00:00
20-06-2013 00:00:00

15 rows selected.

button conrol min and max range option during execution

Is it possible to change the window button conrol min and max Beach setting during execution?

Thank you very much Nick.

Find dates MIN and MAX
Please, advise how correctly find MIN and MAX dates.
The XML code:
```
<DATES>
<DT>2011-02-24</DT>
<DT>2011-02-25</DT>
<DT>2011-02-26</DT>
<DT>2011-02-27</DT>
<DT>2011-02-28</DT>
</DATES>
```
Model:
```
<?xdoxslt:minimum(DT)?>
<?xdoxslt:maximum(DT)?>
```
The output:
```
0
20110224
```
Expected results:
```
2011-02-24
2011-02-28
```
Hello

If your data is:

2008-10-04

1

2009-10-21

3

2009-11-05

4

2008-11-10

2

The maximum is given by: / ROWSET/ROW/DT [.. / DT_RANK = count (//ROW)]
and the minimum is: / ROWSET/ROW/DT [.. / DT_RANK = 1]

There may be more effective, but it works.

concerning

Jorge

I cancelled iTunes on a Macbook Air, issued by the school. All my music is stored/saved on my iMac at home. If I delete the playlists and songs of the Macbook it will affect my master library?

I cancelled iTunes on a Macbook Air, issued by the school. All my music is stored/saved on my iMac at home. If I delete the playlists and songs of the Macbook it will affect my master library?

Unless you're 'home sharing', which he does not seem like you are, two libraries (macbook and iMac) are distinct, so a change does not affect the other. Best way to test would be to remove a few songs you can download easily and see if it changes. But I don't think it will be a problem.

Delete the min and max labels on chart axis markers

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