E4X: Select the nodes that match a criterion, and whose children match to another

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• Return all column names of the cells that match a value in a single cell

  

  I want to be able to scan all the cells in column 1 in column 3 (there could be several) which belong to the same line and check if they all have a value y (X). If they have no value, I want all columns to display all the names of the matching columns as follows: "column 1, column 2" for Elemento.

  This can be a good start:

  

  B2 = if (counta (C2) > 0, C$ 1, "" ") & IF (COUNTA (D2) > 0', ' & D$ 1," ") & IF (COUNTA (E2) > 0', ' & E$ 1," "") & IF (COUNTA (F2) > 0', '& F$ 1,' ')

  It's shorthand dethrone select cell C2, then type (or copy and paste it here) the formula:

  = IF (counta (C2) > 0, C$ 1, "" ") & IF (COUNTA (D2) > 0', ' & D$ 1," ") & IF (COUNTA (E2) > 0', ' & E$ 1," "") & IF (COUNTA (F2) > 0', '& F$ 1,' ')

  Select cell B2, copy

  Select the cells B2 the bottom of column D, dough

  To add additional columns, you copy the atomic unit:

  & IF (COUNTA (D2) > 0', '& D$ 1,' ')

  and update D2 with the new column and D$ 1 with the new column.

  then... If you add a new column (G, for example) that you want to change it:

  and IF (COUNTA (D2) > 0', '&D$1,' ')

  TO

  and IF (COUNTA (G2) > 0', "&G$1," ")

  and the updated formula would be:

  = IF (counta (C2) > 0, C$ 1, "" ") & IF (COUNTA (D2) > 0', ' & D$ 1," ") & IF (COUNTA (E2) > 0', ' & E$ 1," "") & IF (COUNTA (F2) > 0', ' & F$ 1,"") & IF (COUNTA (G2) > 0', '& G$ 1,' ')

  fill down like before

• Select the node in af:treeTable

  Hello! My task is to change custom selection works on af:table and make it work for treeTable. Do the current method, I took this tutorial http://www.oracle.com/technetwork/developer-tools/adf/learnmore/25-generic-tree-selection-listener-169164.pdf

  And here's a method I have to change:

  	public void TblStagesOnSelect (SelectionEvent selectionEvent) {}
  	GeneralFunction.makeCurrent (selectionEvent);
  	If (treeTable.getRowAtRangeIndex (treeTable.getCurrentRowIndex ()). GetAttribute ("IdParentStage") == null) {}
  	parentUser.setAttributeValue (tf_idUserRespRequest.getValue ());
  	} else {}
  	for (int i = 0; i < = treeTable.getEstimatedRowCount () - 1; i ++) {}
  	If (treeTable.getRowAtRangeIndex (treeTable.getCurrentRowIndex ()).getAttribute("IdParentStage").equals (treeTable.getRowAtRangeIndex (i) .getAttribute ("IdStage"))) {
  	parentUser.setAttributeValue (treeTable.getRowAtRangeIndex (i) .getAttribute ("IdUserResp"));
  	break;
  	}}}}

  This method has been written to the table, but it does not work on treeTable. Can anyone help?

  did you check that

  JDeveloper, Oracle ADF & amp; Java: Tree Table component in Oracle ADF (hierarchical representation)

  http://www.Oracle.com/technetwork/developer-tools/ADF/learnmore/26-get-selected-tree-node-data-169165.PDF

• Read the nodes that have the same value as the subnodes - XML

  It is more of a general JAVA / XML problem, but given that it is going into my BlackBerry app I thought I'd see if anyone knows.

  Consider a simple XML document:

                      Whatever 1                   Whatever 2               Whatever 3       
  

  Using the standard org.w3c.dom, I can get the nodes in X by the practice...

  NodeList fullnodelist = doc.getElementsByTagName ("x");

  But if I want to go to the next set of 'e', I try to use something like...

  Element element = (Element) fullnodelist.item(0);NodeList nodes = pelement.getElementsByTagName("e");
  

  EXPECTED back '3' nodes (because there are 3 series of 'e'), but it returns '9' - because it gets all entries including the 'e' apperently.

  It would be nice in the above case, because I could probably go through and find what I'm looking for. The problem I have is that when the XML file looks like the following:

              whatever              Something Else                    whatever              Something Else            
  

  When I ask 'e' value, it returns 4, instead of (what I want) 2.

  I am simply not understand how DOM parsing works? Generally, in the past I used my own XML documents so I name never articles like this, but unfortunately this isn't my XML file and I don't have the choice to work like this.

  What I thought I would do, it is write a loop knots "drills down" so that I can combine each node...

    public static NodeList getNodeList(Element pelement, String find)
      {
          String[] nodesfind = Utilities.Split(find, "/");
          NodeList nodeList = null;
  
          for (int i = 0 ; i <= nodesfind.length - 1; i++ )
          {
              nodeList = pelement.getElementsByTagName( nodesfind[i] );
              pelement = (Element)nodeList.item(i);
          }
  
          // value of the nod we are looking for
          return nodeList;
      }
  

  .. While if adopted you ' s/e' in the service, he would return the 2 nodes I'm looking (or elements, perhaps I'm using the wrong terminology?). on the contrary, it returns all the 'e' nodes in this node.

  Anyway, if anyone is still with me and has a suggestion, it would be appreciated.

  Well, there is no doubt that there is a learning curve robust for XML programming. You can take an hour or two and go through one of the tutorials that are circulating on the net. (Like that of w3schools.com.)

  Basically, almost everything in XML is a node, the Document that returns the parser. The API for node tells you that you can test the node type you have by calling getNodeType, which returns one of the constants of type node (Node.ELEMENT_NODE, Node.TEXT_NODE, etc..) If necessary, you can then convert the variable to the corresponding interface (element, text, etc.).

  Similarly, the API documentation say you for any node, calling getChildNodes (or for an element node or Document getElementsByTagName) will give you a NodeList (a little non-types of nodes in the XML API), while calling getFirstChild and getNextSibling to any node will give you another node (or null ).

  Once you learn the API, writing logic of course is not all that hard. For example, if the only 'e' interest tags are those directly under the element root of the document (as shown in your example) you can simply go to them directly:

  Vector getTopENodes(Document doc) {  Vector vec = new Vector();  NodeList nodes = doc.getDocumentElement().getChildNodes();  int n = nodes.getLength();  for (int i = 0; i < n; ++i) {    Node node = nodes.item(i);    if (node.getNodeType() == Node.ELEMENT_NODE &&        "e".equals(node.getNodeName()))    {      vec.addElement(node);    }  }  return vec;}
  

  Note that this example does not assume that all children are nodes of element 'e '. the document could have comments, white space or something else that makes it into the DOM as comment, text or any other type of node.

  On the other hand, if you want to capture every "e" tag which is directly under the ' tag, no matter the level, then you need to do something a little more complicated (it's on the top of my head - no guarantee):

  static class NodeListImp implements NodeList {  private Vector nodes = new Vector();  public int getLength() {    return nodes.size();  }  public Node item(int index) {    return (Node) nodes.elementAt(index);  }  public add(Node node) {    nodes.addElement(node);  }}
  
  NodeList getTargetNodes(Document doc) {  NodeListImp list = new NodeListImp();  getTargetnodes(list, doc.getDocumentElement(), false);  return list;}
  
  void getTargetNodes(NodeListImp list, Node node, boolean parentIsS) {  if (node.getNodeType() == Node.ELEMENT_NODE) {    // node name is tag name for element nodes    String name = node.getNodeName();    if (parentIsS && "e".equals(name)) {      list.add(node);    }    parentIsS = "s".equals(name);    for (Node child = node.getFirstChild();         child != null;         child = child.getNextSibling())    {      getTargetNodes(list, child, parentIsS);    }  }}
  

  I hope that it gets the idea across.

• How to force the Explorer search to show ONLY the files that match the search target?

  I frequently need to search for files with brackets in the name of the file.    However, a bug in the Search Explorer means that search results will fill up with a lot of waste that does not match my search target.

  Example:

  At a command prompt "dir/s * (abc) *.» ' * ' usually works: the name of each file found will contain "(abc)".   (The only time that a search for the command line fails is when the version 8.3 of the name of the file matches the search target, but the name of the actual file does not work.)

  However, in Solution Explorer, look for "* (abc) *.» "*" returns all files with 'abc' in the name, and provides no way to filter the results so that I only see files with '(abc)' in the name of the file.

  This search bug means that you want "* (de) *.» ' * ' at the command prompt returns 72 hits, while searching with Explorer returns 7381 hits!

  Cancellation: Another inconvenience of Windows is when I work at a command prompt I get often unexpected results because the wildcard matching is done against both the full name of the file or folder and the name of 8.3.   Is there a way to force cmd.exe to restrict the wildcard matches only the complete names of the files and folders?  That is to say, is there a way to force cmd.exe to never, ever, use the 8.3 names?

  Hi Rob,

  In order to quickly provide a solution, please answer this question:

  Did you do changes on the computer before the show?

  Follow the steps below to solve the problem:

  Method 1: If you have problems of location of the files, folders, or other items on your computer, try using the search and indexing of troubleshooting to solve the problem. It ensures that the Windows Search service is running and checks if you have the correct permissions to search all the directories on your computer.

  See the article below for additional information and steps.

  Open the troubleshooter for search and indexing

  http://Windows.Microsoft.com/en-us/Windows7/open-the-search-and-indexing-Troubleshooter

   

  Method 2: I also suggest you to re - index files, then check. Follow the article below for the procedure.

  Change advanced indexing options

   http://Windows.Microsoft.com/en-us/Windows7/change-advanced-indexing-options

  See also:

  Improve Windows searches using the index: frequently asked questions

  http://Windows.Microsoft.com/en-us/Windows7/improve-Windows-searches-using-the-index-frequently-asked-questions

  Hope this information helps. Pleave get back if you need help, will be happy to help you.

• How to select a picture, ignore one and many with shift click to choose several without also selecting the image that you have ignored.

  In the grid discovers how to select an image, a jump and select several images following the a l ignored without also selecting the previous image, that you have ignored as well. This is possible in opening

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