Elapsed time delay does that once in the state machine

Similar Questions

• string does not update in the state machine

  Help

  I'm pulling my hair out on this one.

  I have a control over the channel I want to get the value that out of the front at a certain point in a type of State machine architecture, but the value contained in the string of LabVIEW not updated during the enforcement program for the purposes of the block diagram.

  I checked that the VI is not corrupted by creating this simple VI to illustrate what I'm doing. (otherwise empty)

  The length of the string, or the indicator related to the local variable, or updated a probe on a wire connected to the string if during 2 seconds after the start of the VI, something is typed in the control of the chain.

  LabVIEW 2009 version

  Windows 7 operating system

  This could be and OS related issue? -J' I normally use XP not Windows 7 with 2009 and I've never noticed this before.

  Any quick feedback this weekend would be greatly appreciated

  Thank you

  James

  Try setting the chain control to "update the value while typing". (right click...).

• update date and time for 3.6 numbers does not show the time and does not automatically update the date

  The 'update date and time"for numbers of 3.6 does not show the time and does not automatically update the date.  What should I do?  Thank you.

  Hi david,

  where do you find ' update of the date and time.

  Quinn

• Buttons does not return to the early state in the state machine.

  Hello

  I downloaded a program that is used to back up data. I used a machine to States with different States. State 1 is initialization, where it moves automatically select the State, which allows to select one of the remaining States to copy the data. The selection is made by command buttons. Once u pressed a button, it goes to that respective State and in this state when you press the backup, the backup of data occurs. Once the backup is located the program goes back to the selection state. So far, it works fine. The problem then. Once he returned to the selection state after that copy was made, then none of the buttons are working properly. Then when it goes back to select State and I tried to select a State, nothing happens, not even the stop button works. I don't know why this is happen. Please help me solve this problem. Thanking you in advance.

  You have many States where you have the event structures ("All data" "given more older that '" young data that ' 'Defined Data') (worse there are two of them in "Data set")

  Each of these event structures are for a "Backup" mouse event down.  A singularity is now why you use a mouse event down on a button.  This really should be a value change event.  But this is not the big problem.

  The big problem is that all of these structures events are set to lock the front until the end of the case of the event.  Well, when you click the mouse down on this button, all 4 of these structures tail event this event.  If you are luckly, one of the event will execute and process the event.  Others, that you will never run because the state machine will not get through these cases.)

  You have multiple structures of event you VI and certainly not buried in the event.

  Reading guard and recommendations when using events in LabVIEW

  Then fix your VI architecture.  You must limit the structures of the event or a separate parallel loop, or to a single case of your state machine that your code will frequently return to, without any other user interaction, in order to service the structure of the event.

• For the State Machine logic makes me Mad, ideas?

  Hello

  I am a complete newbie to Labview and up to the help of kind people on the forum and tutorials tips, State where I implement a state machine.  However, I can't it behave using logic.

  What I try to do is to test the relay using an automated test procedure.

  The procedure takes the following measures:

  1. a card reader and transistor NI9472 DO turns the relay power via the power of the coil (needs of the variable time period). (It's OK)

  2. account of how can cycles the relay contacts worked, it will easily exceed 100,000 cycles. (It's OK)

  3. every 10 cycles (new variables), the contacts are held closed, load circuit "15A in the state machine" (the current relay is switching, which will be 15 a at 30V) is turned off.

  4. While the State of 15A is off, I need to switch to 'State of 1' and the 'State of the measure' , that it allows the measure to take.

  5. Finally, the "State measure and the"State of A 1"must be turned off and the"15A State switched back on .

  6. this process continues for another 10 cycles and repeats.

  I tried to do by using the States and the logical selection function for different States, where she part works, it does not seem to flow completely.  I'm I missing logic.

  Hoping someone may be able to help, thanks

  Andy

  I really didn't thing you want to be returning this Boolean value in all States.  You should probably also have a different evolution register for each line of output.  Then you simply adjust those that you need to.

• Helps the state machine

  Hello everyine,.

  I'm working on a state machine. I saw a few videos of the same thing and I need help.

  I have attached the code below.

  My problem is that I can not jump since the first case at the last.

  After the execution of the first case I want LabVIEW to check fot the Boolean control attached to the function select. I used an operator oux during the operation. If the condition of "TERMINATE" is satisfied that I want him to be the last case of local variable is used to turn off the START light.

  at the moment I can't go to the latter case. I want the code to keep control of the State, and whenever the user presses the button END the LED should turn off little matter the time of execution.

  PL suggest ways to accomplish a task... am still a beginner

  Concerning

  Jalashwa

  Hi Sindhurakshak,

  You are welcome. I think that the problem still resides on the Structure of the event to the State "WBS". I can suggest the following (say that everything always ends by WBS what I understand of your current code):

  Remove select it and create a new case event for Boolean switch «end». Location of the enum to cancel in this case, as shown below:
  
  The above change means that if the value of "end" Boolean switch is changed (assuming that this will change to true), the case of the event will be held event 'end', which will then the enum value 'End' to the transition of change. Let's say that if the Boolean key 'end' has not changed (which means that has not been pressed), it should run the rest as shown below:
  

  

  

  I'll leave the enum value 'WBS' in the time-out period, assuming you want the State to always run the "WBS" idle state, unless you press the key 'end' to trigger the transition "Terminate".

  It may be useful

  Warm greetings,

  Lennard.C

• A certain time out loop that depends on the other a case structure.

  I did a lot of research on this subject and I think that I reduced the precisoucly of the problem. I want my user to enter a password, and if the password is correct the alarm does not sound. But if that's a mistake, I want the alarm to sound. The problem is that I have no way to tell the alarm to stop the sound when the user enters because the sound is locked in a while loop . I can't seem to do this then that stop the loop for some reason when the user enters a new number.

  I would be very grateful to you, the Aboriginal people if you could help me out here. On the VI I said where is the problem. (The problem occurs inside while loop).
  If you guys have any questions please let me know and I'll try to answer them to the best of my ability.

  All entries for the while loop that are outside of the loop do not change after you enter the loop.  So if the first loop has a 'fake' wired into it, which means not to stop, he will never stop.

  You will need to have something out there that reads a new value every time.

  I must say that it looks like the structure of your program won't work, however.  The structure of the event above can shoot outside while occurs only once each time the large loop, so right now he can never more touches after a 'real' in case of emergency structures, enroll you in the lower part of the block diagram.

• I can fax, but the date does not appear on the fax machine, the display or confirmation. need information for fix

  HP7500A printer, just bought. Works very well except for the date. Because I must have proof of fax sending, it does not work.

  Hi Mbailey212,

  You have the date and time on the machine itself? to do:

  Go to the front screen of the printer and make sure that the printer screen is on the home screen, if it is not, the light house at the top left lights. If so, touch and it will take you to the home page, then right arrow once and select settings, scroll to preferences and select it. At the top you should see the date and time, select this option and enter the date and time.

  I would like to know if this helps or not.

• Reset the PID.vi only once on the State transition

  Hello

  I'm controlling a fatigue gear using LabVIEW test bed and I use the PID.vi to control the hydraulic circuit. During the transition from the start as a test State, I need once the PID (the integrated error) values to be reset during the transition. The current configuration constantly resets the PID causing the hydraulic output voltage to be lower than the set value. I can't understand how to be set to Boolean false to pass true during the transition from the State and then back to false to prevent resets of the other by default. I have attached the current revision of my code.

  Thank you very much for your help!

  Trace

  It's a good idea, but it is not necessary to select blocks with the true and false as inputs, just equality by different and use the output directly to reset.

  Also, I see that you have PID blocks in two separate cases. Note that those will act independently from each other - if you reset into a State, then move to another State, it will not be reset. Maybe it's what you want, and maybe it isn't, but be sure to put multiple instances of the PID block that control the same in different cases. You can also see weird integral questions when you place in case, if a long time share when you run the same instance.

• backkey does not work after the state change

  Hello

  I have a simple vision containing a "Channels" list in the State and a histogram in State "Charts".

  This point of view has an assigned custom backkeyhandler that simply changes the status back to 'Channels' if backkey material has been activated in mode "Charts".

  The application starts and presents two items in his list.

  If I touch one of the its entry, I load the data for this article and change the "Charts" view that displays the bar graph.

  By pressing the previous button does nothing in the emulator and brings back me to the homescreen on my nexus s.

  But if I touch the graph bars once before pressing the previous button, it takes back me to the State "Charts".

  Using the debugger with a breakpoint in the confirmed following function, this function will be not be called after a state change if I don't touch the graph bar.

  If it is possible to use two views for the presentation of the list and graphics, I need the backkey to work in different States, because I want to use the States to

  use different layouts for tablets vs phones.

  Any ideas?

  Michael

  protected

  function view1_backKeyPressedHandler(event:FlexEvent): Sub

  {

  TODO self-generating method stub

  if (currentState == 'Charts' ) {}

  Event.preventDefault ();

  setCurrentState)

  'Channels' );

  }

  }

  Hey,.

  The problem is that the focus of the scene is directed to the list, once it has been removed from the display list.  Here's what happens:

  1) tap on the item "Item 1."

  (2) stage.focus is automatically set to this article

  (3) change the graphics state

  (4) list is removed from the display list

  5) press return

  (6) no event is triggered because of the list has the focus but is not on the display list

  To work around this problem, set to null stage.focus just after changing state.  If your list change manager would look like this:

  protected function list1_changeHandler(event:IndexChangeEvent):void

  {

  setCurrentState ("Charts");

  internship. Focus = null;

  }

  In my internal tests with 4.5.1 this solves your problems.

  Let me know if this does not work.

  Chiedo

• Bug: Find/replace does not work if the statement contains the string is too long

  Hello

  in my sequence, I press Ctrl + F to open the Find dialog box and enter a string. All the checkboxes are checked 'Elements for search' and ' limit the search to "is not enabled.

  Now comes the finding it is only announcing the discovery in the main sequence.

  Other places in a sous-suite that are part of a labview vi action setting is not in the list. Also if I open the sequence and I'm looking at this place.

  If I create a comment in the subsequence containing the searchstring, then it is.

  When I open the properties of the action of labview and open the parameter that contains the string and click on check for errors, and then close all and supplementary search then the value lies.

  Is it possible that the variable is too long setting? It's about 200 characters and one thing very nested SationGlobals and the table and the TestSockets. Search string Dees is finally an arrayindex in this grand statement.

  It seems that this is the problem.

  Is this a known bug?

  Solved.

  There was an empty character at the end of the search string...

• printer does not work in the windows machine 8

  my printer does not work in this new machine of windows 8. tried everything to fix the problem. It won't send email documents to the printer either. just doesn't get it. Ive had kodak install drivers, and just, it will not work on this computer. It was fine on windows vista. the printer is set by default on this computer, then why it wont work on this one. not happy with windows 8 at all. wish I never bought it

  Hello

  As Kodak OEM is responsible for the good operation of the printer and their
  drivers provided. Check their documentation online, with the support of Kodak, and
  drivers.

  Good luck, you need to update or reinstall the latest driver.

  Kodak - printers
  http://support.en.kodak.com/app/home/src/gosupport/selected/true

  Kodak - Support and downloads
  http://support.kodak.com/app/intfSel/intf_redirect/L2FwcC9ob21lL3NyYy9nb3N1cHBvcnQvc2VsZWN0ZWQvdHJ1ZS9jaGFuZ2UvdHJ1ZS9vcmlnX2ludGYva29kYWtfYjJjX2Vu/change_country/true

  ====================================================

  The main issue is probably the drivers, but these can help:

  Windows 8 - Fix printer problems
  http://Windows.Microsoft.com/en-us/Windows/printer-problems-in-Windows-help#fix-printer-problems=Windows-8&V1H=win8tab1&V2H=win7tab1&V3H=winvistatab1&v4h=winxptab1

  Windows 8 - How to troubleshoot printing problems in Windows
  http://Windows.Microsoft.com/en-us/Windows-8/How-to-solve-printing-problems

  Windows 8 - install a printer
  http://Windows.Microsoft.com/en-us/Windows-8/install-a-printer

  Windows 8 - find and install printer drivers
  http://Windows.Microsoft.com/en-us/Windows-8/find-and-install-printer-drivers

  I hope this helps.
  --------------------------------------------------------------------------------------------
  Rob Brown - Microsoft MVP<- profile="" -="" windows="" and="" devices="" for="" it :="" bicycle="" -="" mark="" twain="" said="" it="">

• the other hard drive to the host system does not show in the virtual machine

  I tried but I couldn't find an article on how to get the other host hard disk appears in the my window of the computer of the VM guest.  I don't want a virtual disk or anything like that, just access the other hard disk of the local host without having to map a drive to it if possible.  Thank you!

  Physical disks are not supported on VMware Server 2 (at least not via GUI options).

• problem with the state machine

  Hello! I have a VI to monitor a storage tank. I tried to do by creating a simple state machine that changes the value(on/off) of some faucets based on 2 conditions:

  -When a certain temperature reaches a predetermined value AND its derivative is<0, the="" state="" must="" change="" from="" on="" to="">

  -When some time passes, the State should change from off to on.

  Unfortunately I can't get this working as it never changes state (by example, if I start with him always stay on 'on' and vice versa).

  Could you please tell me what I'm doing wrong? I enclose the screenshots of the 2 States.

  Thank you!

  Sounds like your shift which could not not be wired properly.

• Race conditions manifested in the state machine in queue

  Hello

  I ' am developing a vi in which I use a design of producer-consumer model.
  the producer s enqueue States for the consumer. but at a certain point in execution of I want to enqueue the next state of the statemachine consumer, within the State of the consumer himself. This causes a problem?
  in other words I have given queue in the loop of consumer can also. so the man the next state of consumers will depend on the data in queue

  Thank you

  I make extensive use of Handleres of Message queue where the "producer" and the consumer enqueue for the same queue.

  A "Firinstance" of work today: here are two screenshots of a part of the same code

  

  

  The top loop controls the State of a semi autonomous process where data is collected.

  1. an event is detected, triggering the start of the measuring cycle
  2. Data are being gathered
  3. Another event tells the top loop that it's time to stop collecting data and "Analize" is sent to the end opposite to the consumer
  4. The buffer empty analize, formats the data and continues to the State of "Log".

  The thing to remember is to use a priority queue.  Enqueue to place free and flush properly, in front of end control.  See also 'A trip to Grandma's House'.

  It is a very powerful technique for applications where you want abstract on the 'what' and 'When' the how and just leave a "do".

  And Yes, if I had chosen a unrestricted data (string, var) rather than an enum type and built the lower loop as a child class, you have a "player".