Elapsed time

Similar Questions

• Elapsed time in flat sequence Frames

  I enclose a VI file simplified what I'm trying to do. Ideally, this program starts when "OK" is pressed and cross frames (or steps) to the time indicated as wait times. The program would then reset. It will be meant to time the experimental stages, possibly with release of equipment parameters. I wish I could have a direct timer for each step backwards (ideally) or to give elapsed time. I tried different variations, but nothing seems to give me a direct timer as I'm looking.

  This timer is not entirely necessary, it would be good to know where experience is the place to experience 50 hours that makes us turn.

  I am very new to LabVIEW, please excuse that requires the simplicity of the solution that it likely.

  As a simple state machine, it is trivial. See if the attached VI may give you some ideas.

  Note that since this is a state machine...

  • It can be stopped at any time. If you allow only stop in the slow case, don't wire in other cases.
  • No local variable!
  • No loops inside loops!
  • No sequence!
  • A unique array of clusters setting information specific to the State in one place. Nothing distributed across multiple locations.
  • All States timer reuse the same code, just with two values different (State and duration).
  • For more complex scenarios, you can add more flavors State.
  • Note that I use the output of waiting for the tick ms. (you can also use the number of cycles, but who would need a separate waiting)
  • Simple, scalable, and extensible code. Just add items to the enum and add corresponding cases.
  • modify if needed.

• Elapsed time [new]

  Can Hi anyone help me on this please...

  Comments and suggestions are welcome.

  Kind regards

  NORWEGIAN KRONER

  

  Altenbach says:

  I still don't understand why you need two timers. You can remove the timer B and simply compare the elapsed time of A with B time goal and light the LED if the elapsed time is higher.

  I meant like that.

• Model in the loop timed While the elapsed time

  Hello NOR community,

  I'm trying to use a while loop timed to run controller simulated for a mechanical system test. I need the time loop to run at an even 50 Hz to simulate the controller that will eventually drive the mechanical system. To check the speed at which the loop runs, I made a VI that gets a value from each loop clock and subtracts the value of the clock of the current iteration of the value of the clock of the previous iteration. I have eliminated all other codes this VI except for the recovery of the clock, to ensure that no problem with another code in VI. I find that the time between iterations is not constant, but it is consistent. In other words, the elapsed time can change at each loop, but it changes according to a specific model, such that the average elapsed time is equal to the value that I use for the timed loop. The loop will run faster than posed for several cycles, then slow down during a cycle even at the same time. Here are some examples:

  Running at 5 Hz: elapsed switches schedules between 0.203125 and 0,187500 seconds

  Clocked at 8 Hz: time is constantly 0.125 seconds.

  Operating at 10 Hz: elapsed switches schedules between 0,109375 and 0,093750 seconds

  By examining the differences between elapsed time and the stability of the 8 Hz setting, it seems that there is a minimum time of 0,015625 seconds (64 Hz) division. It is much worse than the 1ms accuracy claimed in documentation. This could be the cause?

  I am running Windows XP with LabVIEW version 8.5.1 and have observed this behavior on several computers with different screws

  Thank you!

  Erik

  Your problem is the function that you use to get the current time.  It's just the time of the Windows clock which has a resolution of 16 msec.

  You must use the function of number of cycles as Jarle has pointed out.

• Elapsed timer

  Hello

  I'm doing this project in motion sensor. I got to work like when it detects a movement it will turn on the Boolean value has led. I'm so now suppose to add some kind of timer which some recommended the passage of time, I tried to find but I do not know how to connect to my program. My task is to set a timer, while 10 minutes elapsed, no movement is detected, it will trigger a logic 1 (digital input) to another program. But now I'm focusing on this program I need to integrate the two to the right. So, how do I do not connect to make as how I had described. And finally I need a reset for that button after it input 1 logic (which will trigger an alarm - another program) it can be reset to zero and count down 10 minutes still. Thank you

  First of all, you keep in your original thread.

  Then take the LabVIEW tutorials.

  LabVIEW Introduction course - 3 hours
  LabVIEW Introduction course - 6 hours

  Then, read the help file for the elapsed time function.

  Finally, set up a simple VI where you can experiment with how this function works.

• different type of terminals of elapsed time of the DAQ assistant

  I connected a digital relay to one of the outputs. I have installation wizard DAQ to operate a valve with the relay. Now, I want to control the valve to drive all... .lets say 20 seconds, until I stop the program. What I need, is to change the State of each 20 seconds. I tried to use the "Out of time", but when I try to connect 'elapsed time' 'Data' on the ass of data acquisition. It reports on the different types of data. What would be the way easy and clean to use a "timer" to operate a relay on a basis of time fixed and periodic? Thanks in advance!

  I enclose a picture of my horrible test...

  I'm using Labview student 2009 edition.

  Put an is not in there also.

  

• How do I know the elapsed time

  
  

  Hello

  The difference between your option (a) and (b) is as below:

  (a) you get timestamp of the time before and after processes and subtract to find the elapsed time between the two... I will suggest you to convert time double data type before subtracting stamps...

  (b) you get "millisecond" of timer tick before and after the process count and subtract to find the elapsed time between the two... and last multiplication is 1000 to convert it to second...

  In my opinion, I'd rather (a)

  Thank you

  HS

• Get the elapsed time in the frame of the specific sequence

  Hello

  I'm running a flat sequence in one of my programs and read time elapsed in a picture in a form vi. I don't want to have the elapsed time for the entire program, just the elapsed time whenever this specific image runs, from scratch whenever that image in the sequence begins. The formula is just a linear equation which is dependent on time, so his criticism that it resets each time in order to provide a line that progresses from t = 0 each time. I tried to use in the context of the time, but I don't know how to set up properly to give the elapsed time, I'm looking for.

  

  I don't know how long the framework works because I just need a way to input what time her (ms or s) to a given point during execution, from t = 0 each execution.

  First of all, your formula.vi should be outside the framework of the sequence.  You can determine the run-time WHEN the framework is completed.  Place a County vi check before and after the image and subtract. (delta t is in milliseconds)

• totalizer of time-elapsed time

  for those who can answer: is it possible that a "totalizer" elapsed time can be built? Im trying to implement a program that will measure the elapsed time a particular resistance will be on. Since the heating element will appear several times, the elapsed time must begin where he left off and continue to count until the next cycle, etc., if resistance is tested in a few months, the totalizer function will be very useful for FMEA (failure mode effects analysis) see the total time on the item was. IM using a structure of weather control box timer is active (true case) and a comparison function for the voltage at the output of a real or fake (0 = false, 120 Volt Volt = true). the timer\totalizer should operate only in the case of true.

  Here's an easy way to do it with registers at offset.

• Reset the clock of 'VI' express of elapsed time, in a case structure.

  I use a box structure. For the event may be TRUE, the program must perform 3 Boolean operations TRUE condition I did use 3 screws to elapsed time. 3 Boolean conditions are executed in 2,5,8 seconds respectively. After 2 seconds, Boolean 1 should light up. After 5 seconds 1 Boolean should turn OFF and Boolean 2 should turn on. After 8 seconds 2 Boolean should turn OFF and 3 Boolean must turn it on and continue to stay THERE unless the FALSE condition is executed.

  During the FALSE condition, all 3 Boolean flags must disable (OFF) and all 3 timers must be reset to zero.

  When running from true to FALSE there is no problem, but when running from FALSE to TRUE, Boolean 3rd continues to stay in State, rather than the State OFF because the timer starts from the point where it was changed instead of reset.

  How can I fix this problem so timers start from 0 seconds to every time the REAL case is executed?

  hope this helps... If not, change your needs

• elapsed time after two output pulses

  I have a gas with an output signal meter (or perhaps more accurately, a closing contact) for each cubic foot, put in the meter. The tricky part is that the closing time varies over time as the gas flow increases.

  I am sucessfully measure the total volume of gas used in a 'run' by using a shift register to compare a change (closed or open) and divide the total by two changes. However, I would like to note the elapsed time for each foot cube through the meter and the putput that on-screen. This number should only be updated when each cubic foot passes through the meter. It's simple if it was just an impulse, or even two an amout set apart, but I have a problem with the irregularity.

  No matter if the timer has elapsed begins on the forehead or the edge down so it starts and ends at the same place and the inverse of this number is then displayed on the screen.

  My current control loop is a timed loop iterations to 250ms on a cRIO 9072.

  Any advice on how to implement or the display would be great!

  Hi, NXT,.

  detect the rising edges of your meter. Store the current time in a shift on rising register and get the difference to the previous hour:

  

• Elapsed time delay does that once in the state machine

  Hello.  I have problems using the delay to show the seconds remaining on an expectation not in a simple state machine.  I have a front panel countdown indicating the time remaining for the step.  I thought that the delay of elapsed time was the way to do.  The problem is the vi work correctly the first time.  But then after that the calendar does not seem to reset at the time I had put.  If I remove the delay and just stick a waiting time in the State, the vi is exhausted because I expect.  This is just to give the user an idea of the time remaining.  What I missing when using the passage of time, or it's just the wrong tool for the job?

  A small question, is that I would like to move the tasks, in this case the LED outside of the loop, so I don't have to repeat the code.  But when I tried moving them outside with only allow constants within the State, they do not work as I expected.  If you have tasks such as operating a set of Boolean values that you are used in several States, what is the the cleaner way to do it without repeating the code?

  Thanks for the help.

  See how it works for you.

• Query with large elapsed time

  Hi I use version 11.2.0.3.0 of oracle.

  We have an executed query last night for around ~ 21hrs and then finished. I check sql execution history in OEM section monitored sql and and I saw the DB time is around 27 ~ dry only, while the elapsed time is ~ 21hrs, unable to understand why. Also when I went through the sql, it seems simple and here the main table contains ~ 600000 (6 Lakes) records and Refrence table contains 4 records. Also when I checked the gv$ active_session_history I don't have much expectation for this sql query event log, there was minimum queue of events as presence "SQL * Net more data to the client', 'direct path read temp'.» So I was wondering if the DB time is in seconds so why time is so high and what exact thing sql did during this time.

  I think even the stats for the main tables seems bland, but then also the operation should not last for the amount of time (~ 21 hours). Please help me understand the scenario and the action we should take.

  This is the execution plan.

  SELECT          master.createtimestmp
      FROM master master, Refrence 
     WHERE master.Refrence_id = Refrence.Refrence_id
           AND (   (Refrence.Refrence_cd = 'A' AND master.createtimestmp <= (:1))
                OR (Refrence.Refrence_cd = 'B' AND master.createtimestmp <= :2)
                             OR ( (    Refrence.Refrence_cd = 'D'
                      AND master.createtimestmp <= :4
                      AND master.master_dltd_in = 0)
                    OR (TRUNC (master.createtimestmp) = TRUNC(:5)
                        AND master.master_dltd_in = 1)
         ))
  ORDER BY master.createtimestmp
  ---------------------------------------------------------------------------------------------
  | Id  | Operation           | Name          | Rows  | Bytes |TempSpc| Cost (%CPU)| Time     |
  ---------------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT    |               |       |  2017K|       |         (1)| 00:04:06 |
  |   1 |  SORT ORDER BY      |               |  844K |  2017K|  302M | 50482   (1)| 00:04:06 |
  |*  2 |   HASH JOIN         |               |  844K |  2017K|       | 13678   (1)| 00:03:59 |
  |   3 |    TABLE ACCESS FULL| Refrence      |     4 |    24 |       |     2   (0)| 00:00:01 |
  |*  4 |    TABLE ACCESS FULL| Master        |  2M   |  1966K|       | 13668   (1)| 00:03:59 |
  ---------------------------------------------------------------------------------------------
  
   

  It's classic based on demand for time for reflection (or network), for example:

  1. open the cursor

  2. remove n lines

  3 do something side app with the retrieved lines

  4 remove n lines more

  5. repeat 3 & 4

  6 complete execution / close the cursor

  Thus, the query can be opened for a number of hours, but in terms of time to database, it is a few seconds.

  The rest is all somewhere between the network and request but no database.

• Calculate the elapsed time between the horodateurs log Table

  Hello

  I'm looking for some codes SQL allows to calculate the elapsed time between the timestamps in a log table.  The log table has some STOP-START operations.

  I just want to calculate the elapsed time between the START and PAUSE of Transactions, as well as START and EXECUTE transactions.

  So, in the example below, the time spent must be:

  START 09:15 break 09:20 (5 Minutes)
  START 09:30 to 09:45 (15 Minutes) FULL

  Total elapsed time for LOG_ID 1234 should be 20 minutes.  This excludes the 09:20 at 09:30 BREAK at the START time.

  LOG_ID	SEQ_NUM	LOG_TYPE_CD	CRE_DTTM
  1234	1	BEGINNING	09-15 - 2013:09:15:00
  1234	2	BREAK	09-15 - 2013:09:20:00

  1234

  3

  BEGINNING

  09-15 - 2013:09:30:00

  1234

  4

  ALL THE

  09-15 - 2013:09:45:00

  Any suggestions?

  Thanks for your time

  -DT

  Hello

  Thanks for posting the CREATE TABLE and INSERT.  be sure to post the results desired from these data.

  user13071913 wrote:

  Hi thanks for the help...

  The date is a true timestamp.  ...

  Here's a sample of CREATE TABLE and a few inserts.  3 ID transaction, each with a series of journal entries.

  CREATE TABLE 'LOG_TABLE_X '.

  (SELECT 'ID' CHAR (14 BYTES) NOT NULL,)

  ACTIVATE THE "LOG_TYPE_FLG" TANK (4 BYTES) NOT NULL,

  ALLOW "LOG_DTTM" DATE NOT NULL

  );

  ...

  I'm so confused.  Is log_dttm a TIMESTAMP, you said in the story, or is it a DATE, as you say in the CREATE TABLE statement, or is it a VARCHAR2 as Thur INSERT statements?  I'll assume it's a DATE.

  I left out an important step yesterday.  The computation of the last_start, we need to use a CASE statement so that we record only the time of events STRT.

  Here's the revised query:

  WITH got_last_start AS

  (

  SELECT id, log_type_flg, log_dttm

  LAST_VALUE (CASE

  WHEN log_type_flg = "STRT".

  THEN log_dttm

  END

  IGNORES NULL VALUES

  ) OVER (PARTITION BY id - can - be

  ORDER BY log_dttm

  ) AS last_start

  OF log_table_x

  )

  SELECT id, log_type_flg, log_dttm

  , (log_dttm - last_start) * 24 * 60 elapsed

  , SUM (log_dttm - last_start) OVER (PARTITION BY ID.

  ORDER BY log_dttm

  ) * 24 * 60 AS total_elapsed

  OF got_last_start

  WHERE log_type_flg IN ("CMPT", "PAUS")

  ORDER BY id, log_dttm

  ;

  Output of your sample data:

  ID LOG_ ELAPSED TOTAL_ELAPSED LOG_DTTM

  -------------- ---- ------------------- -------- -------------

  1111 PAUS 09-26 - 2013:09:09:58.17.17

  1111 CMPT 09-26 - 2013:10:09:58 1.00.83

  2222 CMPT 09-26 - 2013:12:09:58 180.00 180.00

  3333 CMPT 09-26 - 2013:10:09:42 59.73 59.73

  In Oracle, when you subtract one DATE from another DATE, the result is the NUMBER of days between them.  In the above query, I multiplied the past columns and total_elapsed by the number of minutes per day (24 * 60), to show the time in minutes.

• Elapsed time for the materialized view vs Master table query

  Hello all;
  
  Small confusion about time up for the vs Master materialized view table query
  
  

  SQL > select count (*), sum (quan_sold), sum (amt_sold) of the sale;

  COUNT (*) SUM (QUAN_SOLD) SUM (AMT_SOLD)
  6000000 12000000 720480000
  Elapsed time: 00:00:30.54
  

  SQL > create materialized view mv1
  2 activate the rewrite of the query as
  3. select count (*), sum (quan_sold), sum (amt_sold) of the sale;

  Materialized view created.
  Elapsed time: 00:00:01.45
  

  SQL > select count (*), sum (quan_sold), sum (amt_sold) of the sale;

  COUNT (*) SUM (QUAN_SOLD) SUM (AMT_SOLD)
  6000000 12000000 720480000
  Elapsed time: 00:00:00.01
  
  Please see the three cases "Elapsed Time"...
  
  When comparing other cases.
  1. my query takes long time (30.54), extraction of data from the sale
  2. create a materialized view takes less time (01:45) why?
  
  Source: http://uhesse.com/2009/07/08/brief-introduction-into-materialized-views/

  >
  Small confusion about elapsed time for the materialized view vs Master table query

  SQL > select count (*), sum (quan_sold), sum (amt_sold) from the sale.

  COUNT (*) SUM (QUAN_SOLD) SUM (AMT_SOLD)
  6000000 12000000 720480000
  Elapsed time: 00:00:30.54

  SQL > create materialized view mv1
  2 activate the rewrite of the query as
  3. select count (*), sum (quan_sold), sum (amt_sold) of the sale;
  Materialized view created.
  Elapsed time: 00:00:01.45

  SQL > select count (*), sum (quan_sold), sum (amt_sold) from the sale.

  COUNT (*) SUM (QUAN_SOLD) SUM (AMT_SOLD)
  6000000 12000000 720480000
  Elapsed time: 00:00:00.01

  Please see the three cases "Elapsed Time"...

  When comparing other cases.
  1. my query takes long time (30.54), extraction of data from the sale
  2. create a materialized view takes less time (01:45) why?
  >
  Many queries take less time the second time you run them. After the first performance, there may be many, if not all, lines in the buffer cache. Then the second round will not make any or all e/s physical but will obtain data from the buffer cache.

  Also, you haven't checked that the MV was even used for the second run.

  Drop the MV and make the query several times and means of the time. Then create the MV and do the same thing.