expdp default regardless of the name of the directory

Hello
Im trying to run the expdp but he keeps default regardless of the name of the directory!
even if I don't specify any directory (from the Wizard) it still doesn't...

[oracle@linux1 dpdump] $ expdp

Export: Release 11.1.0.6.0 - Production on Saturday, may 8, 2010 18:17:54

Copyright (c) 2003, 2007, Oracle. All rights reserved.

Username: System
Password:

Connected to: Oracle Database 11g Enterprise Edition Release 11.1.0.6.0 - Production
With partitioning, Real Application Clusters, Oracle Label Security, OLAP,.
Options of Data Mining and Real Application Testing
ORA-39002: invalid operation
ORA-39070: unable to open the log file.
ORA-29283: invalid file operation
ORA-06512: at "SYS." UTL_FILE", line 488
ORA-29283: invalid file operation


Anyone have a similar question?
I created utl_file procedure returning with the same question


SQL > execute utltest;
BEGIN utltest; END;

*
ERROR on line 1:
ORA-29283: invalid file operation
ORA-06512: at "SYS." UTL_FILE", line 488
ORA-29283: invalid file operation
ORA-06512: at "Tester. UTLTEST', line 5
ORA-06512: at line 1

PS: I created the directory of export in an another PB (same oracle_home and same physical path of the directory of export) and it works

Hello

Im trying to run the expdp but he keeps default regardless of the name of the directory!
even if I don't specify any directory (from the Wizard) it still doesn't...

Grant you privileges to read/write to this directory?

You can follow the example below:

http://www.orafaq.com/wiki/Oracle_Datapump

Hope this helps.
Best regards
Jean Valentine

Tags: Database

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    Hello. I found this tutorial

    http://KB.VMware.com/selfservice/microsites/search.do?language=en_US & cmd = displayKC & externalId = 1002929

    on hos to move the default location for the snapshots of a virtual computer. How ever what I don't understand is where can I covering the line in the file *.mvx, "workingDir = "new_path_location" ? I just start typing at the end of the file? The file can be edited in Notepad of windows or I should connect to the host using putty and correct it in nano, for example?

    For example, in the same document, they used

    workingDir = "/vmfs/volumes/46f1225f-552b0069-e03b-00145e808070/vm-snapshots"

    I think that " 46f1225f-552b0069-e03b-00145e808070 " is an identifier for the volume. True or not? If yes how can I list all the volumes that are mapped to the host or vCenter Server identifiers?

    Thank you!

    alexiaesx wrote:

    Hello. I found this tutorial

    http://KB.VMware.com/selfservice/microsites/search.do?language=en_US&cmd=displayKC&externalID=1002929

    on hos to move the default location for the snapshots of a virtual computer. How ever what I don't understand is where can I covering, in the file *.mvx, line "workingDir = "new_path_location" ? I just start typing at the end of the file? The file can be edited in Notepad of windows or I should connect to the host using putty and correct it in nano, for example? in any case around, either Notepad or vi or nano - both will be fine.

    For example, in the same document, they used

    workingDir = "/vmfs/volumes/46f1225f-552b0069-e03b-00145e808070/vm-snapshots"

    I think that " 46f1225f-552b0069-e03b-00145e808070 " is an identifier for the volume. True or not? Yes its unique identifier for your vmfs volumes, but its better if you provide your name of store data instead, as if your data store name is XYZ, provide/vmfs/volumes/xyz/vm-snapshot, you can do it using UUID as well but you need to type for long and its not easy to remember.

    If yes how can I list all the volumes that are mapped to the host or vCenter Server identifiers?

    using the cli

    list of esxcli storage vmfs

    using ssh console, this should provide you with all the information for the disks

    Fdisk-lu

    Another thing,

    CD vmfs/volumes /.

    LS - lah

    You can see your vmfs volumes

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