explain the nvl in the not exists

Hello

I try inserting sample_sender table sample_receiver

CREATE TABLE sample_sender

(

A_ID NUMBER,

b_id NUMBER,

sum_total NUMBER,

NUMBER of sum_toatal2

code VARCHAR2 (6).

default_value NUMBER

);

(1) insert into sample_sender values (10,11,100,120, NULL, NULL);

(2) insert into sample_sender values (10,11,100,120, NULL, 1);

CREATE TABLE sample_receiver

(

A_ID NUMBER,

b_id NUMBER,

sum_total NUMBER,

NUMBER of sum_toatal2

code VARCHAR2 (6).

default_value NUMBER

);

INSERT INTO sample_receiver

(

A_ID,

b_id,

sum_total,

sum_toatal2,

code,

default_value

)

SELECT a.a_id,

a.b_id,

a.sum_total,

a.sum_toatal2,

a.code,

a.default_value

OF sample_sender one

WHERE THERE IS NO

(

SELECT 1 b sample_receiver

WHERE a.a_id = b.a_id

AND a.b_id = b.b_id

-AND NVL(a.code,'X') = NVL(b.code,'X')

-AND NVL(a.default_value,-1) = NVL (b.default_value-1)

);

First I used the 1st insert command

so my sample_sender table has 1 row and my line of table 1 sample_receiver

and I tried once again inserted with the 2nd order insertion so my sample_sender table has 2 rows and my sample_receiver line of the table only 1 who is ranked Exist

That ' S why we can NVL used, but I want to know how TI NVL works here?

Thank you

Post edited by: additional Message added to Rajesh123

Hello Renon,

It seems to me that your problem is the absence of primary key of the SAMPLE_RECEIVER - I would say that PK should probably be on (a_id, b_id).

Your INSERTION try inserting "everything which is in sample_sender and is not yet in sample_receiver ', but with a PK on (a_id, b_id) the condition would simply be

INSERT INTO...

SELECT...

WHERE DOES NOT EXIST (SELECT 1

WHERE a.a_id = b.a_id

AND a.b_id = b.b_id

)

But if there is no PK on the table (and not even a UNIQUE index on (a_id, b_id)), it seems that people have stated that a way to uniquely identify a line had to use (allocation a_id, b_id, code, default_value), with the added complexity that the code and default_value can be NULL ((BTW in your definition and b_id a_id allocation table can also be NULL... I guess that it is a mistake and that the fields are declared as NOT NULL)).

And conditions with NULL values are a bit complicated as for example a.code = b.code is NOT 'true' if the code is NULL (even if it is null, both for a and b).

So to compare the 'code', common sense is: a.code = b.code OR a.code IS NULL AND b.code IS NULL

In your post, this was changed in NVL (a.code, 'X') = NVL (b.code, 'X') which is not really the same thing... It's OK only if 'X' is 'impossible value' for the 'code' (otherwise if you're unlucky, you might have a row with a.code = 'X' and b.code = NULL and the test will judge that they are 'the same').

Same remark with the value - 1 for default_value.

Suggestion: check the definitions of table for "NOT NULL", and if possible (it should always be possible) defines a key primary on the tables so that the conditions use simple equal. (reminder: a PK columns are "NOT NULL")

Best regards

Bruno Vroman.

Tags: Database

Similar Questions

Understanding behavior of the not exists Clause

I do not understand why the following selects does not produce the same result set. First, I did not write and the second that I did:
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of ftvorgn one
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I would like to understand the difference between the two queries.

The second query compares trunc (ftvorgn_nchg_date) and trunc (ftvorgn_eff_date) on the same line; the first query checks the lines with the same ftvorgn_orgn_code. If it finds a match on another line, then the current line will not be selected. This is the reason why she returns fewer rows than the other.

How to use the not exists query
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Using obiee 11g,.
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the query is like that

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There are 4 tables.
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That's what I need in a report, these tables are used in other places also.
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Thank you
This implementation in the report itself can be a difficult and tedious work... But it is better to be RPD - physical type - select a Table
USE NOT IN in place of NOT exist... You can just use a SELECT statement to SELECT the TYPE of TABLE

I hope that's clear

That IS NULL is done by replacing the NOT EXISTS operator with an outer join?
DB version: 10 gr 2

An example of searchoracle.target.com

The query that contains a NOT EXISTS operator
```
SELECT M.ModulId, M.Modul FROM MODULE M
WHERE NOT EXISTS
( SELECT PROJEKTMODUL.IdModul 
  FROM PROJEKTMODUL 
  WHERE M.ModulId = PROJEKTMODUL.IdModul 
  AND PROJEKTMODUL.IdProjekt = 23 )
```
is replaced by an equivalent outer join query
```
select distinct
       M.ModulId
     , M.Modul 
  from MODULE M
left outer
  join PROJEKTMODUL
    on M.ModulId = PROJEKTMODUL.IdModul
   and PROJEKTMODUL.IdProjekt = 23
 where PROJEKTMODUL.IdProjekt is null
```
I do not understand what
```
PROJEKTMODUL.IdProjekt is null
```
fact in the above rewritten query.
He is to perform an anti-jointure. As far as I know Oracle (starting with version 10g - I thought that release 1) rewritten a Join Anti that resembles your second query of your request NOT EXISTS and NOT IN.

Look at the results of the query without the predicate IS NULL and see what records (from this set) must be selected to show the same results as the first query. Areas of interest match the predicate IS NULL.

Not Exists works not
I'm trying to get a list of menu choice for a responsibility.

If I run the following without the Not exists sql code I get the results below showing the entrance, under providers, banks, etc.. Entry is excluded from this responsibility and are not the case of the banks.

Select r.RESPONSIBILITY_ID away r.responsibility_name, menu1, sub1, prompt1 fme1.prompt fme1.sub_menu_id fme1.menu_id,.
Sub2 menu2, fme2.sub_menu_id FME2.menu_id, fme2.prompt orders2, fme2.function_id fun2
of fnd_responsibility_vl r, fnd_menu_entries_vl fme1, fnd_menu_entries_vl wwf2
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and r.responsibility_name = "ASPT to THE AP Manager"
and fme1. SUB_MENU_ID = fme2.menu_id
and fme1.prompt is not null
and fme2.prompt is not null

RES_ID RES NAME Menu1, Menu2 Sub1 Sub2 prompt prompt function2

50281 ASPT to THE AP Manager 68030 68015 suppliers 68015 68238 entry 1348
68015 68015 68238 ASPT 50281 to THE AP providers consultation Manager 68030 2252
50281 ASPT to THE AP Manager 68030 68015 suppliers 68015 provider merge 1055
50281 ASPT to THE AP Manager 68030 68015 68015 68196 suppliers banks 1066
50281 ASPT to THE AP Manager 68030 68015 suppliers 68015 77218 others

But when I run with the

and NOT Exists (select action_id fnd_resp_Functions
where responsibility_id = r.responsibility_id
and fme2.function_id = action_id or fme2.menu_id = action_id or fme2.sub_menu_id = action_id)

The entry does not appear, this is correct, but banks does not appear and should be:

68015 68015 68238 ASPT 50281 to THE AP providers consultation Manager 68030 2252
50281 ASPT to THE AP Manager 68030 68015 suppliers 68015 provider merge 1055
50281 ASPT to THE AP Manager 68030 68015 suppliers 68015 77218 others

The following query shows that there is no exclusion of the banks menu or functions:

Select count (*) in fnd_resp_functions
where responsibility_id = 50281
and action_id in (68030,68015,1066,68196)

Count = 0
You might have a problem with the parenthesis.

Try like this:
```
...
and NOT Exists(select null from fnd_resp_Functions
               where responsibility_id = r.responsibility_id
               and (fme2.function_id=action_id or fme2.menu_id = action_id or fme2.sub_menu_id = action_id))
```
or
```
...
and NOT Exists(select null from fnd_resp_Functions
               where responsibility_id = r.responsibility_id
               and action_id in (fme2.function_id, fme2.menu_id, fme2.sub_menu_id))
```
Explanation: the AND operator has a higher precedence than the OR operator. So you must always set the parentheses () when you mix AND and OR conditions. Just to be on the safe side.

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ORA-14030: partitioning column does not exist in the CREATE TABLE statement
Hi all

We are trying to create a partition materialized view and get an error below.
ORA-14030: partitioning column does not exist in the CREATE TABLE statement
Our GL_BALANCES21 and GL_CODE_COMBINATIONS21 base tables is already divided by interval of the range on Code_combination_id.
In the same way that we try to partition the view materialized
We get the error.
ORA-14030: partitioning column does not exist in the CREATE TABLE statement
Where the clause there are 4 tables gl_balances21, gl_code_combinations21, gl_periods and gl_set_of_books.

CREATE MATERIALIZED VIEW apps. BAL_PART
PARTITION BY RANGE ("CODE_COMBINATION_ID")
(SCORE LOWER (80000) VALUES,
PARTITION OF LOWER VALUES (160000),
PARTITION OF LOWER VALUES (240000),
PARTITION OF LOWER VALUES (320000),
PARTITION OF LOWER VALUES (400000),
PARTITION OF LOWER VALUES (480000),
PARTITION OF LOWER VALUES (560000),
PARTITION OF LOWER VALUES (640000),
PARTITION OF LOWER VALUES (720000),
PARTITION OF VALUES LESS THAN (800000),
PARTITION OF LOWER VALUES (880000),
PARTITION OF LOWER VALUES (960000),
PARTITION OF VALUES LESS THAN (10400000),
PARTITION OF LOWER VALUES (11200000),
PARTITION OF LOWER VALUES (12000000),
PARTITION OF LOWER VALUES (12800000),
PARTITION OF VALUES LESS THAN (13600000),
PARTITION OF LOWER VALUES (14400000),
PARTITION OF VALUES LESS THAN (15200000),
PARTITION OF LOWER VALUES (16000000),
PARTITION OF VALUES LESS THAN (16800000),
PARTITION OF VALUES LESS THAN (17600000),
PARTITION OF VALUES LESS THAN (18400000),
PARTITION OF VALUES LESS THAN (19200000),
PARTITION OF LOWER VALUES (20000000),
PARTITION OF VALUES LESS THAN (20800000),
PARTITION OF VALUES LESS THAN (21600000),
PARTITION OF VALUES LESS THAN (22400000),
PARTITION OF VALUES LESS THAN (23200000),
PARTITION OF LOWER VALUES (24000000),
PARTITION OF VALUES LESS THAN (24800000),
PARTITION OF VALUES LESS THAN (25600000),
PARTITION OF VALUES LESS THAN (26400000),
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PARTITION OF LOWER VALUES (28000000),
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PARTITION OF VALUES LESS THAN (29600000),
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QUICKLY REFRESH ON DEMAND
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GL.GL_BALANCES21. ROWID C2,
"GL". "" GL_BALANCES21 ". "" ACTUAL_FLAG, "
"GL". "" GL_BALANCES21 ". "" CURRENCY_CODE "
"GL". "" GL_BALANCES21 ". "" PERIOD_NUM, "
"GL". "" GL_BALANCES21 ". "" PERIOD_YEAR ".
"GL". "" GL_BALANCES21 ". "" SET_OF_BOOKS_ID ""SOB_ID"
"GL". "" GL_CODE_COMBINATIONS21 ". "" CODE_COMBINATION_ID ""CCID.
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT1 ",.
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT10, "
"GL". "" GL_CODE_COMBINATIONS21 ". "" DIRECTION11, "
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT12, "
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT13, "
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT14, "
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT2 ",.
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT3. "
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT4, "
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT5, "
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT6, "
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT7. "
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT8, "
"GL". "" GL_CODE_COMBINATIONS21 ". "" SEGMENT9, "
"GL". "" "" GL_PERIODS '. "" PERIOD_NAME,"
NVL ("GL". "GL_BALANCES21" "." " (BEGIN_BALANCE_CR', 0) Open_Bal_Cr,
NVL ("GL". "GL_BALANCES21" "." " (BEGIN_BALANCE_CR', 0) +.
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NVL ("GL". "GL_BALANCES21" "." " (BEGIN_BALANCE_DR', 0) Open_Bal_Dr,
NVL ("GL". "GL_BALANCES21" "." " (BEGIN_BALANCE_DR', 0) +.
NVL ("GL". "GL_BALANCES21" "." " (PERIOD_NET_DR', 0) Close_Bal_Dr,
NVL ("GL". "GL_BALANCES21" "." " (BEGIN_BALANCE_DR', 0).
NVL ("GL". "GL_BALANCES21" "." " (BEGIN_BALANCE_CR', 0) Open_Bal,
NVL ("GL". "GL_BALANCES21" "." " (BEGIN_BALANCE_DR', 0).
NVL ("GL". "GL_BALANCES21" "." " (BEGIN_BALANCE_CR', 0) +.
NVL ("GL". "GL_BALANCES21" "." " (PERIOD_NET_DR', 0).
NVL ("GL". "GL_BALANCES21" "." " (PERIOD_NET_CR', 0) Close_Bal,
NVL ("GL". "GL_BALANCES21" "." " (PERIOD_NET_CR', 0) Period_Cr,
NVL ("GL". "GL_BALANCES21" "." " (PERIOD_NET_DR', 0) Period_Dr
OF GL.GL_CODE_COMBINATIONS21.
GL.GL_BALANCES21,
GL.GL_SETS_OF_BOOKS,
GL.GL_PERIODS
WHERE GL.GL_BALANCES21. CODE_COMBINATION_ID = GL.GL_CODE_COMBINATIONS21. CODE_COMBINATION_ID
AND GL.GL_SETS_OF_BOOKS. SET_OF_BOOKS_ID = GL.GL_BALANCES21. SET_OF_BOOKS_ID
AND GL.GL_PERIODS. PERIOD_NUM = GL.GL_BALANCES21. PERIOD_NUM
AND GL.GL_PERIODS. PERIOD_YEAR = GL.GL_BALANCES21. PERIOD_YEAR
AND GL.GL_PERIODS. PERIOD_TYPE = GL.GL_BALANCES21. PERIOD_TYPE
AND GL.GL_PERIODS. PERIOD_NAME = GL.GL_BALANCES21. PERIOD_NAME
AND GL.GL_PERIODS. PERIOD_SET_NAME = GL.GL_SETS_OF_BOOKS. PERIOD_SET_NAME
and gl.GL_CODE_COMBINATIONS21.summary_flag! = « Y »

ERROR on line 54:
ORA-01013: user has requested the cancellation of the current operation

I checked the metalink note saying that ensure that all columns in a partitioning column list are columns of
the table being created.

Partition is already there, on the column of code_combination_id of gl_balances21 and gl_code_combinations21.

Please suggest.

Thank you
It's your mistake:
```
PARTITION BY RANGE ("CODE_COMBINATION_ID") 
```
but in your projection of column list, you have an alias he:
```
"GL"."GL_CODE_COMBINATIONS21"."CODE_COMBINATION_ID" "CCID",
```
You must use the alias as a partition key, not the name fom the secondary table column.
--
John Watson
Oracle Certified Master s/n
http://skillbuilders.com

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Please help about the FRM-47023 - parameter does not exist in form
Dear all,

Best wishes...

I'm currently doing some additions to existing forms.

in fact, I have two forms, form and b. (form A) based on the tables and B form based on table B

Existing scenario.

Formula A-> table A contains the columns as

A1Col1 - Primary key
A1Col2 - Primary key
A1Col3 - Primary key
A1Col4 - Primay key
A1Col5
A1Col6

Form B-> table B

B1Col1 = A1Col1
B1Col2 = A1Col2
B1Col3 = A1Col3
B1Col4 = B1Col4 (this is newly added column in TableB and form present I do not have this relationship, so I
Add an element of text in form B and made it point to databases and give the coloumn name)
B1Col5
B1Col6

Existing features:

Form A is the main form and there is a button pressed, it will pass (A1Col1 parameters
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Existing for this push in FormA button code is:
```
DECLARE

  pl_id   ParamList;

  pl_name VARCHAR2(15) := 'ls_parm_list';

BEGIN

  if :TableA.A1Col1 > ' ' and

     :TableA.A1Col2 > ' '   and

     :TableA.A1Col3 > ' '    and

     :TableA.A1Col4 > ' '     then (-- (newly added line for current requirement)



      pl_id := Get_Parameter_List(pl_name);

 

      if NOT Id_Null(pl_id) then 

          Destroy_Parameter_List(pl_id);

      end if;



      pl_id := Create_Parameter_List(pl_name);



      Add_Parameter(pl_id,'A1Col1',TEXT_PARAMETER,:TableA.A1Col1);

      Add_Parameter(pl_id,'A1Col2',TEXT_PARAMETER,:TableA.A1Col2);

      Add_Parameter(pl_id,'A1Col3',TEXT_PARAMETER,:TableA.A1Col4);

      Add_Parameter(pl_id,'A1Col4',TEXT_PARAMETER,:TableA.A1Col3); -- (newly added line for current requirement)

      Add_Parameter(pl_id,'A1Col5',TEXT_PARAMETER,:PARAMETER.UID);



      NEW_FORM('FormB',TO_SAVEPOINT,NO_QUERY_ONLY,pl_id);

  end if;

END;
```
Code for the new instance of the form to FormB:
```
DECLARE

  W_WHERE VARCHAR2(100);

BEGIN

  if :PARAMETER.Param1 > ' ' then 

      W_WHERE := 'B1col1=''' || :PARAMETER.param1 || ''' AND B1col2=''' || :PARAMETER.param3 || ''' AND B1col3 =''' || :PARAMETER.param4 || ''' AND B1col4=''' || :PARAMETER.Param4 || '''';



      Set_Block_Property('TableB',DEFAULT_WHERE,W_WHERE);



      execute_query;



      Set_Block_Property('TableB',DEFAULT_WHERE,'');

  end if;



  :SYSTEM.MESSAGE_LEVEL := 25;

END;
```
So now,.

New features:

I need to spend an additional column in TableA (A1Col4) also a parameter to form B so that it will be in the where clause of the form B.

To achieve this requirment,

Step 1:

Step 1: I added B1Col4 to TableB because it did not exist before.

Step 2: I added a text element in FormB, named as "A1Col4" and set its property to iterm Yes to Database and columname to A1Col4.

And then I created a setting called "' A1Col4" to FormB (this iis since I added a new setting FormA pressed button code above)... ".

Now, the real problem I am facing:

I have compiled the forms, and it went well... I ran the FormA... Here are the scenarios:

1. formA is running and when I run the query, it performs gets data, when press the button go form B (to all 4 parameters to formb, I get error. FRM 47023 No. such parameter named A1col4 exists in FormB. even though I have the parameter b form created recently with this name.

2. so I just kept the existing code button pressed (commented on newly added lines, keeping the 3 parameters instead of 4) and removed "' AND B1col4 =" ' | : PARAMETER. Param4 | "' from the whennewform code instance formb, the result is: FormA call FormsB successfully, FormB is to be opened, BUT VERY STRANGE, THAT NEWLY ADDED POINT (COLUMN TABLEB THAT I wanted TO PASS ADDITIONAL PARAMETER FROM FORM 'A') IS MISSING. This text element appears not.

3. If I run FormB alone, then it is querying data, the newly added text element is also displayed but if if I have the same call FormA, error FRM-47023.

I sat for hours and hours to find out what exactly the problem... but no clue...

Sorry for the long post... but in hope and who seek the help of our friends from the OTN network...

Hope that I have explained clearly the problem... By the way that the version is 10G forms.

Thanks for the help in advance for everyone...

Kind regards
Prasanth
they are in the same folder

If you're on 10G, being in the same folder does not mean automatically that the forms be made on this issue. In your EPS file, there is a parameter named FORMS_PATH, forms are searched for in directories listed there. To verify your env file. also, you could search the entire disk by issuing a
```
dir formb.fmx /s
```
from the root directory of your disks.

NEGATIVE / NO / not exists - which is the best
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I have to run to delete records parent and child on the production database that has very large amount of data (in millions of records) on Oracle10g. Scripts are currently using INs NOT to delete records of child as below:

delete from T1 where T1.x is not null and T1.x not in (select x T2);

I was intending to change it to:

removing the T1 where T1.x is not null and not in T1.x (select x from T2 where x is NOT NULL);

Could someone help me please with a better way to write this? It will be faster if I use LESS or NOT Exists on NOT IN?

Sorry to bother you all with the basic question, but there don't seem to be a specific rule for the use of a higher (may be because Oracle10g uses CBO)?.

Any help is appreciated and thanks in advance.
It doesn't seem to be a specific rule for the use of a higher

There is always 2 responses that are always true:

-Depends on
-Why?

See f.i.: http://asktom.oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:1794145000346577404 #1796559000346100662

In your case, the first answer applies.
You should TEST the best solution, there is no general rules regarding finding 'the best' a.
It depends on your data, selectivity your index, statistics etc. etc..

Just measure (explain the plan, trace, tkprof) and test different scenarios and you will find the best solution that works for you.

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