FIRST HP: Solving a system of linear equations with a parameter


I know how to solve a system of linear equations by using a setting by hand but I don't know how to set up in the calculator.

Can someone please help me solve the system of linear equations below with a 'p' on the first HP Calculator next parameter?

2 x + 8z = 26

4 x-4y-14z = - 38

8 x - 4y + 2z = 14

The answer to the above equations is:

x = 13 - 4, =(45-15p)/2, z = p y p

Thank you




What you're trying to solve is not really a system of equation with a parameter, but you try to solve a set of 2 equations with 2 variables (x and y).

The case solve command can do for you.

According to the CASE, type:

Solve ([(2*x+8*z) = 26,(4*x-4*y-14*z) = - 38,(8*x-4*y+2*z) = 14], [x, y])

Come in

and the calculator will return

{[-4 * z + 13, 15/2 * z + 45/2]}

which is what you want.


Tags: HP Tablets

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