flatten channel adds the length of the string

Similar Questions

• Add the string '& lang = en '.

  I would like to add the string '& lang = en' to the path variable.

  < cfset newpath = path & "& lang = en" > ".

  < cfoutput > #newpath # < / cfoutput >

  The output is

  index.cfm < = en

  but not the desired output

  index.cfm & lang = en

  Help, please.

  There is a good chance that the exit IS 'index.cfm & lang = en', but your browser is to choose of does not display it like that.

  View the page source to confirm this.

  Short strings like the one that begins with an ampersand symbol (and) are often considered a character encoding on browsers.

  Alternatively, you can force the browser to display the string in the way desired with functions htmlCodeFormat() or htmlEditFormat().  Which, oddly enough, must be able to encode special characters such as the ampersand.

  I.E.

  #htmlEditFormat (newPath) #.

• Add the string with another string.

  I got the text of the source XML document to appear in the BrowserField

   src="wp-content/uploads/2011/01/Chris_bild.jpg" 
  

  I thought too much about it.  The question is more simple I thought originally.

  How can I programmatically insert the string "fie: / / / store/home /" in the string above, so he says?

  src="fie:///store/home/users/wp-content/uploads/2011/01/Chris_bild.jpg"
  

  find the index you want to manipulate, for example using indexof("src=")

  use substrings and add up the parts you want.

• Add the string at the end of the column name

  Hi all
  
  I wonder whether it is possible or not. I created a similar table to another table to help-
  
  
  

  create table table_name in select * from table_name1;

  Now, I want to differentiate the name of the column of the previous table column names. I want to add E at the end of all column names. Is it possible using sql Command in sql or Toad workshop without doing it manually as I have more than 100 columns in this table?
  
  
  
  Thanks in advance.
  
  
  
  Kind regards
  
  
  
  Pascal M

  Hello

  Connected to Oracle Database 10g Express Edition Release 10.2.0.1.0
  Connected as hr
  
  SQL> create table test_1(col1 number, col2 varchar2(30));
  
  Table created
  
  SQL> create table test_2 as select * from test_1;
  
  Table created
  
  SQL> desc test_2;
  Name Type         Nullable Default Comments
  ---- ------------ -------- ------- --------
  COL1 NUMBER       Y
  COL2 VARCHAR2(30) Y                         
  
  SQL>
  SQL> DECLARE
    2     v_table_name USER_TAB_COLUMNS.TABLE_NAME%TYPE := 'TEST_2';
    3     c_column_suffix CONSTANT VARCHAR2(1) := 'E';
    4  BEGIN
    5     FOR REG IN (SELECT UTC.COLUMN_NAME
    6                   FROM USER_TAB_COLUMNS UTC
    7                  WHERE utc.TABLE_NAME = v_table_name) LOOP
    8        EXECUTE IMMEDIATE 'ALTER TABLE ' || v_table_name || ' RENAME COLUMN ' ||
    9                          reg.column_name || ' TO ' ||
   10                          substr(reg.column_name,
   11                                 1,
   12                                 29) || c_column_suffix;
   13     END LOOP;
   14  END;
   15  /
  
  PL/SQL procedure successfully completed
  
  SQL> desc test_2;
  Name  Type         Nullable Default Comments
  ----- ------------ -------- ------- --------
  COL1E NUMBER       Y
  COL2E VARCHAR2(30) Y                         
  
  SQL>
  

  Kind regards

• size of the string channel

  Hi all

  I have worked with a channel with the String data type and fill in the values with a script. This channel is really big, there was more 4 000 000 values long a few times. It worked perfectly fine last week. When I tried to run my script today he woud throwing an error the 262145 index is outside the valid range for the property values.

  Digital channels works well and I has not changed anything in the script related to my channel.

  What could be the problem?

  Best regards

  Christoph

  Hi Edward,.

  It's a little embarrassing... I tried everything but restartung tiara...

  It is simply a lack of memory. Sorry to have bothered you.

  Best regards

  Christoph

• IMAQ flatten image for the 64-bit version of string

  Hello

  I noticed customer odd based on vision "flatten image chain" on labview 64-bit edition. In my program I use flatten image to the string (with compression to JPEG and kind of flatten Image) to compress and send data to another application. I noticed on the compressed image color missmatch. I say red (255,0,0) 32-bit RGB image and I flattened for string and then save this string as a binary JPEG using Write to vi. When I open the file of the picture is blue (0,0,255). It doesen't matter how data is written (big endian, little endian or native) the result is always the same. 32-bit edition Labview, the code worked correctly.

  I reported a bug in the NC and I'm still waiting for a solution to this problem.

  LabVIEW: labview professional development system 2010 32/64 bits (with vision development module) completely v10.0f2 lie

  Systems: labview 64 bit on windows 7 64 bit-> flatten image to string-> false color

  LabVIEW 32-bit on windows 7 64 bit-> flatten image to String-> colors OK

  LabVIEW 32-bit on windows 7 32 bit-> flatten image to String-> colors OK

  A picture of the block diagram that I used to test the conversion is attached.

  See you soon

  Hi 3DVision.

  I think I see the problem... you code looks like he expects that out of "flattening the image of the chain" will actually be a JPG file as a string, because you have chosen to use the JPG compression options. However, this is not the way that VI is intended to be used. It is simply a way to convert an image type of Vision in a string representation which can be easier to haul around (for example via the network, the user file format, etc.). It is a parallel to normal 'flatten' that can be used on any type of data from LabVIEW. The format of this string is the owner and has provisions for storing information that is specific to the Vision images that cannot be represented in the file formats normal image (overlay information, benchmarking, custom, etc. data info). If you are save the string flattened in a file and expects to open as a normal JPG file, it is unlikely to work properly. The only way that it would be guaranteed to work is if you switch to the corresponding VI "unflatten chain. I don't know why it works in 32-bit mode, but it sounds like a lucky fluke.

  For your use case, you probably want to use the VI "IMAQ write the string. This does not give a result string that is identical to the specified file format.

  Eric

• Only allow the string to the list

  Hello
  
  I have an ArrayList.

  ArrayList as = new ArrayList();

  Now, I want to let only the string to add in this list of tables how can I achieve this? Don't want to use generic.
  
  Please guide.

  Ankur Raiyani wrote:
  I was asked to do not use generic.

  In example you saw generics. It is clearly said if you don't want to use generic drugs, and then use the instanceof keyword.

  I want that list allows me only to add the string if I add another object, then it should throw an error.

  Exactly, I give an idea how to use instanceof and allow that string in the arraylist objects.

  If not clear, please go through the below program:

  import java.util.*;
  import java.lang.*;
  class ArrayListForOnlyString
  {
  
       public static void main(String st[])
       {
            List stringArrayList = new ArrayList(){
  
                 public ArrayList ar = new ArrayList();
  
                 public boolean add(Object ob) throws UnsupportedOperationException
                 {
                      if(ob instanceof String)
                      {
                           ar.add(ob);
                           return true;
                      }
                      else
                      throw new UnsupportedOperationException("Only String Object are accepted");
                 }
  
                 public void add(int index, Object ob)
                 {
                      if(ob instanceof String)
                      {
                           ar.add(index,ob);
                      }
                      else
                      throw new UnsupportedOperationException("Only String Object are accepted");
                 }
  
                 public Object[] toArray()
                 {
                      return ar.toArray();
                 }
  
                 public String toString()
                 {
                      return ar.toString();
                 }
  
            };
  
            try
            {
  
            stringArrayList.add(new String("10"));
            stringArrayList.add(1,new String("10"));
                  // Uncomment the below line and run, it 'll give error , as you are trying to add Integer Object to array list.
            //stringArrayList.add(new Integer("10"));
            System.out.println("The objects of arrayList are : "+stringArrayList);
  
           }catch(Exception e)
                 {
                      e.printStackTrace();
                 }
       }
  
  }
  

  Published by: 833545 on August 31, 2011 15:53

• How cut the length of the string IE channel name here, if it exceeds 20 characters or letters. The channel name is dynamically analyzed the spreadsheet/xml file.

  How cut the length of the string IE channel name here, if it exceeds 20 characters or letters. The channel name is dynamically analyzed the spreadsheet/xml file.

  My Council of Europe in the .js file is

  function generateHTMLMarkup (i, channel) {}
  Alert ("this is lang" + str);
  var str ="";
  "Str += '.

  ";
  str += "" +
  "" channel ['name'] +.replace("Low",".") + ""+""
  ";
  "Str += '.
  "+ ""+""+"
  ";
  Alert ("this is lang" + str);
  return str;

  }

  nerateHTMLMarkup: function (i, channel) {}
  Alert ("this is lang" + str);
  var str ="";
  "Str += '.

  ";
  str += "" +
  "" +
  "" + channel ['name'] + "" +.
  "" + "
  ";
  "Str += '.
  "+ "" + "
  ";
  Alert ("this is lang" + str);
  return str;

  etc.

  Give mthe rhythm and the exact code where Ihave tio get implemented.

  in the code, replace change

  channelName var = channel ['name'];

  TO

  channelName var = channel ['name'];

• ArraytoChannels error 'cannot be added because the channels of the target are not all the same length.

  Hello!

  After the end of my second day of test error, I put this question on the table:

  I use ArraytoChannels function to store ADO recordsets as strings. What is strange, is that for the first Recordset, it works; but for the next time through the loop, it always fails with the error message 'cannot be added because the channels of the target are not all the same length.

  I confirmed that:

  the RowData sizes and the ChannelNames are equal,

  both spend the isarray = true test,

  I change the order of the ChannelNames,.

  I have reconnected/disconnected from the oConnexion every time, nothing has changed.

  Apparently I'm missing something - but crazy to know what! -If anyone can share his opinion I'll so much appriciate. Here is my code:

  oTables = Array ("WellStates", "ChokeData", "WellParameters", "FlowData", "PumpData", "SensorsData", "ModelCalculatedData")

  Call OpenSQLConnection
  Set oRecordset = CreateObject ("ADODB. Recordset')
  Call SelectWell
  Call GetWellStateIDs

  Data.Root.Clear
  for j = 0 to ubound(oTables,1)

  sSQLSting = "select * []" & oTables (j) & "] where [WellStateID] between" & WellStateIDFirst & "and" & WellStateIDLast ".
  oRecordset.Open sSQLSting, oConnexion
  Protected oFieldNames: table: ReDim oFieldNames (orecordset. Fields.Count - 1).
  for i = 0 to orecordset. Fields.Count - 1
  oFieldNames (i) = orecordset. Fields.Item (i) .name
  next
  oArray = oRecordset.GetRows (-1, 0, oFieldNames)
  Set oGroup = Data .root .ChannelGroups .Add (oTables (j))

  oArray, oFieldNames arraytochannels
  oRecordset.close
  oConnection.Close
  next

  Sub GetWellStateIDs
  sSQLSting = "select * from [WellStates] where [wellid] =" & WellID
  oRecordset.Open sSQLSting, oConnexion
  oArray = oRecordset.GetRows)
  WellStateIDFirst = oArray (0,0)
  WellStateIDLast = oArray (0, ubound(oArray,2))
  oRecordset.close
  EndSub

  Sub OpenSQLConnection
  Set WshNetwork = CreateObject
  oComputerName = WshNetwork.ComputerName
  oDB = "MX2. Player.DB ".
  Set oConnexion = CreateObject ("ADODB. Connection")
  oProvider = "Provider = SQLOLEDB.1; Integrated Security = SSPI; PeoExecuteist Security Info = True; Data Source ='
  oProvider = oProvider & oComputerName & "\MX; Use procedure for prepare = 1; Machine translation = True; The packet size = 4096; Workstation ID ="
  oProvider = oProvider & oComputerName & " Use encryption for data = False; Tag with column collation when possible = False; Initial Catalog ='
  oProvider = oProvider & oDB
  oConnection.ConnectionString = oProvider
  oConnection.Open
  EndSub

  Another clue. If you check using DIAdem

  Microsoft Windows Script Debugger

  you are able to install the debugger in DIAdem.

  It would potentially have shown that the command does not work as expected.

  Sorry for the inconveniance

  Andreas

• How to get the length of the string a vm?

  Hello

  I'm trying to automate some consolidation of virtual machines and would like to add script. I have over 800 virtual machines manually would not work.

  I would like to

  $allVApps = get-CIVApp

  foreach ($CIVm to ($allVApps |)) Get - CIVM)) {}

  find the number of channels and if greater than 8 consolidate them.

  }

  Someone has this practice? or something else?

  I'm in a cloud environment vSphere 5.5, installed latest powercli.

  Thank you

  Don't know why this does not work for others, but what I posted before work for me.  Here is a more complete version of how get the those of VAPP VM.  There are no doubt more direct ways, but that how I made it so far:

  1. get the VAPP

  $vApp = get-CIvApp-name 'Test-VAPP.

  2. get the VMS of vApp

  $VMs = $vApps.ExtensionData.Children.vm

  3. get the ones for the VM first in the list of $VMs:

  $VMs [0]. VCloudExtension.any.VirtualDisksMaxChainLength

  This last command returns 18 for me which is the "Length of the string" value in the properties of the Virtual Machine to the virtual machine in the vCD UI.

  I hope this helps.

• First Max value to find and add the previous channel values

  Hello, I would like to be able to parse a string to find the first maxima (inflection point) and then add channel so that all the values are equal to the maximum

  the index where the maximum was found.

  To explain better, in the attachment, the original channel's Ych and the channel in the annex is Ych_appended.

  Any help would be appreciated.

  Thank you

  The feature you're looking for better using the SCRIPT of DIAdem.

  First of all, you can find the first maximum in a channel by using the ChnPeakFind function. The document below explains how to use this:

  http://digital.NI.com/public.nsf/allkb/DD069B95FB938C4286256FC8006A09CD?OpenDocument

  The channels that you specify in the function call will contain the value x and y of the first maxima. Then, you will just need to:

  1. Copy the original using ChnCopy channel.
  
  
  2. Find the index of the value to your channel original x axis at which the peak occurs.
  
  
  3. Browse the newly copied channels, replacing the inside with peak values until you reach the index of the value found in step 2.

  I hope this helps.

• TDMS read fails on the channels of different lengths

  Experts in LV...

  It seems that there is an error in the PDM to read functions.   I have a TDMS file generated by a built executable, this file has a group of 9 channels.  Channel 5 is data taken at a higher rate (IE 20 MHz) compared to the date in the other 8 channes (1 Mhz).  1 Mhz channels have 110 000 points, of course, the 20 Mhz channel has 2 200 000 points.

  If I read this by using the playback feature TDMS passing an array of the names of Channel 9.  It runs and returns a table of 9 waveforms with Y0 dt values correct and the correct.  However Channel 4 (the 5th string, that long) a garbage in the data for all points since the stop the 110 000 in other channels.  This trash is as numbers-10 ^ 304 and zero.  The first 110 000 points are correct.

  The file itself is not damaged.  If I read the file in a loop 1 channel at the time, and to build the table of waveforms I get all 9 waveforms and the correct data of variable length.  A trivial example to read the actual data file is attached with the data file (I hope that boards that leave be attached).  Intrigue albums has corrupted data to read it all-in-one and the bottom has the accurate version of loop data.  The waveforms of tables on the left show that corruption occurs precisely at the location 110 000 table where the other tables

  Yes, the data file is too long for the forums.  You can get the program file and the simple example data

  TDMS error.zip

  No Council or if it is a real mistake.  I don't see anything in the documentation that I'm doing something wrong.  The fact that it returns a length of valid array and no error code is leads me to believe it's a bug of LV.

  Hi sth.

  Thank you for your results. The issue you reported is for playback of several channels of scaling in staircase once. (PDM read on several channels in staircase of unscaling works very well). The .tdms file, you provided, including the scaling of the data.

  I can give you two workaround solutions. The first is what you mentioned, read each channel of scale inside a loop. The second is that always read all channels once, but rank all length strings in descending order. (The first is the channel with a maximum length; the last is the channel of a minimum length).

  Kind regards

  Jie

  OR R & D

• find the length of the string

  Hi all
  
  I have a srting that contains two or more channels as for instance, it's my channel (think of this total string as one string) "Bronson, Ms. Jamie", "elder, Ms. Francis '.
  Now I want to calculate the length of the string of replacement of commas and apostrophes with null.
  
  Can someone pls help me with this?
  
  Thank you

  SQL>
    1  with t as (
    2   select '''Bronson, Ms. Jamie'',''Elder, Mrs. Francis''' as mystring
    3  from dual)
    4  select * from t;
  
  MYSTRING
  ------------------------------------------
  'Bronson, Ms. Jamie','Elder, Mrs. Francis'  
  
  SQL>
    1  with t as (
    2   select '''Bronson, Ms. Jamie'',''Elder, Mrs. Francis''' as mystring
    3  from dual)
    4  select replace(replace(mystring, ',', null), '''', null) from t;
  
  REPLACE(REPLACE(MYSTRING,',',NULL),
  -----------------------------------
  Bronson Ms. JamieElder Mrs. Francis
  
  SQL> l
    1  with t as (
    2   select '''Bronson, Ms. Jamie'',''Elder, Mrs. Francis''' as mystring
    3  from dual)
    4  select length(replace(replace(mystring, ',', null), '''', null)) as string_len from t;
  
  STRING_LEN
  ----------
          35  
  

• Length of the string

  Hi all

  I intend to measure the length of the string and the length of the Arc in a gray-scale image. Please advise.

  You need to find to the first circle or outer circle?

  Part of Mathematics:

  The length of the rope of calculation, to find the RADIUS and the angle under which is seen in the center of the rope or perpendicular to the distance between the string and the center of the circle: once you have these settings, you can calculate the length of the rope using formulas:

  Source: http://www.mathopenref.com/chord.html

  Similarly, you can get for the length of the Arc: http://www.mathopenref.com/arclength.html

  Part of image processing:

  -I think that you can get the radius of the internal or external circle based on your requirement, using IMAQ detect forms.

  https://zone.NI.com/reference/en-XX/help/370281M-01/imaqvision/imaq_detect_shapes/

• Merge with VB Script ascii_diadem_9.1_or_later.zip .csv files: how to add the column/channel with filename

  Hello

  I use ascii_diadem_9.1_or_later.zip to merge the data from several .csv files.

  The problem is that I am so some weird futuristic timestamps in a channel

  which do not appear in the original .csv files:

  How to adjust the VB Script automatically adds a new channel to the a .csv resulting

  file with the original name of the .csv file for debugging purposes?

  Any help is greatly appreciated!

  Thanks, Katharina

  Hi Katharina,

  What happens when you drag your tiara BROWSER or Windows Explorer data files in the data portal?  See all date/time values in a table in VIEW of this channel?  The problem may be that you do not have a use but which properly load your data files.  The example is designed to show you how to concatenate several files of data together, but assumes that you could provide / have your own use.  If you use work already, then look for these lines to the top of the VBScript and substituting the name of your use "CSV".  If your files have a file extension different "*.csv", then you must also change the line "FileExt '.

  FileExt  = ' CSV files, *.» CSV »  ' « *. DAT; *. CSV '.
  
  Use = "CSV"  ' "' or 'SpecificDataPluginName '.

  Brad Turpin

  Tiara Product Support Engineer

  National Instruments