Generate random numbers

Similar Questions

• How to generate random numbers from 1 to 5

  How to generate random numbers from 1 to 5

  -1110340081

  Thank you I ended up

• Generating random numbers with format 18XX88YYYYY

  I've been tryig to generate random numbers with
  format 18xx88yyyyy
  here
  18, followed by two random number then 88 followed by five random number. Here 18 and 88 are set to place one, two, five and sixth position.
  
  but I am unable to get the logic.
  
  So please help
  
  
  Thanx
  
  Achyot

  Try this:

  SELECT    '18'
         || ROUND (DBMS_RANDOM.VALUE (1, 100))
         || '88'
         || ROUND (DBMS_RANDOM.VALUE (1, 100000))
    FROM DUAL
  

  - - - - - - - - - - - - - - - - - - - - -
  Kamran Agayev a. (10g OCP)
  http://kamranagayev.WordPress.com

• How LabVIEW can generate random numbers according to any pdf or histogram?

  I would like to know if there is a VI that generates a set of random numbers according to any probability density, the probability mass function or the graph histogram (this without explicitly knowing the function).

  Thank you.

  Acoustic wrote:

  I would like to know if there is a VI that generates a set of random numbers according to any probability density, the probability mass function or the graph histogram (this without explicitly knowing the function).

  If you have a given arbitrary distribution, you can simulate random data of thesholding mapping in the integral standard service with a simple random number 0... 1.

  This old post of mine should show you the General procedure and more details. (Is there even an former example). Of course, make sure that the desired function is all positive, of course.

  

  

• Generate random numbers in BPEL

  I have a use case that requires I generate a random number of 2 digits, something similar to "math: random * 100. I noticed that this feature is not readily available in the SOA Composite Editor. Can anyone suggest how this can be done?

  [code]

  "targetNamespace ="http://xmlns.oracle.com/KIMServices/embedded_java/BPELProcess1"

  "xmlns ="http://schemas.xmlsoap.org/ws/2003/03/business-process/"

  "xmlns:client ="http://xmlns.oracle.com/KIMServices/embedded_java/BPELProcess1"

  "xmlns:ORA ="http://schemas.oracle.com/xpath/extension"

  "xmlns:bpelx ="http://schemas.oracle.com/bpel/extension"

  "xmlns:bpws ="http://schemas.xmlsoap.org/ws/2003/03/business-process/"

  "xmlns:bpel2 ="http://docs.oasis-open.org/wsbpel/2.0/process/executable"

  "container ="http://www.w3.org/2001/XMLSchema"

  "xmlns:XP20 ="http://www.oracle.com/XSL/Transform/java/oracle.tip.pc.services.functions.Xpath20"

  "xmlns:oraext ="http://www.oracle.com/XSL/Transform/java/oracle.tip.pc.services.functions.ExtFunc"

  "xmlns:kimbpel ="http://xml.ibridge.nl/nl/rsg/kim/bpel"

  "xmlns:DVM ="http://www.oracle.com/XSL/Transform/java/oracle.tip.dvm.LookupValue"

  "xmlns:HWF ="http://xmlns.oracle.com/bpel/workflow/xpath"

  "xmlns:IDS ="http://xmlns.oracle.com/bpel/services/IdentityService/xpath"

  "xmlns:BPM ="http://xmlns.oracle.com/bpmn20/extensions"

  "xmlns:XDK ="http://schemas.oracle.com/bpel/extension/xpath/function/xdk"

  "xmlns:XREF ="http://www.oracle.com/XSL/Transform/java/oracle.tip.xref.xpath.XRefXPathFunctions"

  xmlns:LDAP ="http://schemas.oracle.com/xpath/extension/ldap" >. "

  Language = "java" >

  try {}

  Random random = new Random();

  int abc = random.nextInt (100);

  setVariableData ("NombrAl", abc);

  }

  end generate random number java

  [[catch (Exception e) {}]] >

  Query = "" / client: processResponse / client: result "/ >"

  [/ code]

  That should do it

• Generate random numbers when the pdf file is opened

  I tried to write a script that generates a random 12-digit number when the PDF opens.  I need the number appears in a certain read only field on the pdf file.  I tried write the script in the script of the document and have failed.  (The number random and another part of the document will be used to extract information from it at a later date.)  Can someone help me with a script so that I can make this possible?

  Do you want a new random number whenever the file is opened? If Yes, enter

  Copy the following code as a script at the level of the document (not inside a function!):

  this.getField("fieldname").value =.

  Math.Floor (Math.Random () * Math.Pow (10,12));

• How the random numbers will be generated

  The "dice" in LabVIEW function is ised to generate random numbers between 0 and 1. If I create a [100000] array with random numbers between 0 and 100, the appearance of 1 to 100 is the same (about 1000 times each), but the appearance of the 0 is only 500.

  So my question is, on the basis of which will be generated random numbers?

  Mitu salvation,

  It is not a problem of the RNG, it's a problem of your function rounded!

  "To U8" allows you to convert the entire random DBL. ToU8 rounds up to the next integer. So all the number of 0-0.5 will get rounded to 0, but all the numbers from 0.5 to 1.5 will get rounded to 1. If you have twice the range of a number rounded to 1 at the beach of rounding to zero - the same goes for your "end of range" with rounding to 100. 100 should be also less likelihood (in your VI) to appear...

  To get the same probability, you should (explicitly) roundpupils before converting in U8!

  BTW. You can also search the forum to get the same answer by searching for "random"...

• The value of the seed of the generator of random numbers in Matlab node

  Hi all

  I need to use random variables inside a Matlab Labview Commsuite node. I generate with the randn() function. Is it possible to put the seed of the random number generator such as the random numbers are reproducible?

  Hi Steve,.

  You can use randn ('seed', seeds) to initialize the random number generator. The seed must be a positive integer value. For example, randn ('seed', 3). In addition, this seed is global within the entire application. This means that if the randn() function is called MathScript multi-node that could run in parallel, random results are not guaranteed to be the same after you change any part of your code. But you should always get the same results for repeated passages of the same code.

• I'm trying to generate a table of random numbers 30. After each 5 readings a new vi must open and indicate to the user than 5 readings were made. and continue with the generation of the table again.

  because I don't have a sensor now, I am currently generating a table of random numbers 30. After each 5 readings a warning should be given to the user 5 readngs are completed. This cycle must be repeated. the size of the table is 30.

  Please help me, waiting for response as soon as possible.

  Once I have the transducer, I'll take 30 analog samples and then after each 5 smaples this wraning will be displayed din a new VI

  Use a while loop with a delay time representing your sampling interval.

  Use is equal to the count Terminal to see if 4, then 4th iteration = 5th sample.

  Use a box structure. The real deal will only run on the 4th iteration.

  In the case of true place a Subvi with your message of your choice in the front panel. Go to the properties of the VI window and set ' open the front panel when it is called.

  The condition to closing of attention is not given to your description.

  Consider that rather than usign a Subvi to do this, you can use the "dialog box one/two/three button" or "display message" live in the palette "user interface and dialogue."

  Please try it out and send your own VI. Do not provide us with a working solution.

  Kind regards

• How can I generate multiple unique random numbers?

  Hello

  I am trying to generate multiple random numbers between a given set of numbers (1-52) and do not have the same number generated twice within this group. I can compare the numbers of last and next with the function to compare, but how would I go about comparison of all numbers generated without using a huge list of shift registers...

  Any help/ideas are welcome and appreciated.

  Jason

  Solved my problem. IM passing the random number through a registry to offset to each case and build a table every time. I then searches the table for the new random number. If the number is not found I get a value of-1, another thing is an index value of 0-everything. If a comparator greater than (-1) indicates that the same number is in the table and then I can raise this matter until the same number is not found.

  Kind regards

  Jason

• generate a list of random numbers

  Hi all
  
  is it possible to generate a list of random numbers within a certain range, and without duplicating a number that is already been used in the list?
  
  TNX for any help...

  Try this ;)

• Random numbers and generate funds

  Hello.

  I would like to create a very simple equation random addition.

  I have: 3 boxes of dynamic text (r1_txt, r2_txt, a1_txt)

  I want the first two random numbers and 'a1_txt' to display the sum of the first two random numbers.

  Everything is perfect to the point of adding the two numbers and drop the answer in a1_text. What should I do for my last line of code?

  Thanks for your help!

  random numbers
  1.
  function randomNumbers (min:Number, max: Number) {}
  var Results:Number = Math.floor (Math.random () * max) + min;
  return results;
  }

  2.
  new_mc.addEventListener (MouseEvent.CLICK, showRandomnumber);

  3.
  function showRandomnumber(event:MouseEvent):void {}
  r1_txt. Text = randomNumbers (1,100)
  r2_txt. Text = randomNumbers (1,100)
  a1_txt. Text = Number (r1_txt.text) + Number (r2_txt.text);
  }

  Your showRandomnumber() function has a few problems.  TextFields working with channels, so whatever it is assigned to a textfield must be a string value.  You should actually get errors for the first two lines.

  function showRandomnumber(event:MouseEvent):void {}
  r1_txt. Text = String (randomNumbers (1,100));
  r2_txt. Text = String (randomNumbers (1,100));
  a1_txt. Text = String (Number (r1_txt.text) + Number (r2_txt.text));
  }

  If you change which is not fix things, then look to your textfields to the problem

• Medium-sized random numbers

  So what I need to do, is to generate a series of random numbers. I've got that.

  However, the tricky part is that I need to average the random number and the previous 3 numbers random and exit on a waveform graph.

  Any help or pointers would be great. Thank you

  Simple as pie. He called a VI means Pt by PT. set your buffer to 4 and it will be an average intensity absorbed with the last 3.

  

• Generate random int with no recurrence

  Hi all

  I want to shuffle playlist and using random as possible to repeat some index of value as

  Generating random integers in the range 1..10.
  Generated : 9
  Generated : 3
  Generated : 3
  Generated : 9
  Generated : 4
  Generated : 1
  Generated : 3
  Generated : 9
  Generated : 10
  Generated : 10
  

  How to do it like this

  Generate random integers in the range 1.10.

  Generating random integers in the range 1..10.
  Generated : 9
  Generated : 1
  Generated : 3
  Generated : 8
  Generated : 4
  Generated : 2
  Generated : 5
  Generated : 7
  Generated : 10
  Generated : 6
  

  Please help me

  use http://www.blackberry.com/developers/docs/6.0.0api/net/rim/device/api/util/IntVector.html
  instead of vector.

  Remember that the numbers in the vector are the track numbers, you don't have to add anything unless you want to reset, you simply delete the number of the piece.

• Random numbers, not so much to chance

  I use a simple piece of code I found online to create a random number between two numbers

  new Random().nextInt(6-1)+1);
  

  I am trying to create random numbers for dice.

  Everything seems to work fine, but the numbers are not that random. I have a loop configuration to display the code above 50 times and it will make a loop over and over again the same number. Here is an example of the results

  1,1,1,1,1,1,4,4,4,4,2,2,2,2,2,1,1,1,1,1

  Therefore, it is quite difficult to create a type of yahtzee game when you always roll a yahtzee on the first roll lol.

  Is there something I'm missing here?

  I agree that the Random function generates only numbers random nickname and there are interesting ways of the algorithm of seeds, I believe that in this case, the problem is that Random is not used correctly.  I think that random is intended to be used as shown in the following fragment.  I also think that random is perfectly satisfactory for use in this case, so I would not personally recommend looking for another algorithm.

  Random myGenerator = new Random(System.currentTimeMillis());
  String thrown = ""; // Yes, this should be a StringBuffer....
  for ( int i = 0; i < 50; i++ ) {
      thrown = thrown + Integer.toString(myGenerator.nextInt(6)+1) + ", ";
  }
  System.out.println("Thrown: " + thrown);
  

  Here is the result of a few tracks:

  Lift: 5, 6, 2, 3, 1, 5, 3, 5, 4, 1, 5, 6, 3, 3, 6, 6, 5, 5, 3, 5, 1, 6, 6, 2, 1, 5, 5, 1, 6, 5, 5, 2, 5, 3, 6, 6, 5, 3, 5, 1, 2, 5, 1, 6, 2, 3, 1, 3, 2, 6,
  Lift: 4, 1, 4, 1, 5, 3, 5, 3, 2, 4, 3, 2, 5, 3, 4, 4, 3, 4, 2, 3, 2, 3, 1, 2, 2, 4, 5, 1, 5, 6, 2, 6, 6, 1, 1, 4, 5, 3, 4, 5, 6, 6, 6, 5, 6, 6, 2, 4, 5, 4,

  Edit: updated to fix the sample code fragment andgive output.