Getting control string

Similar Questions

• How can I get the string value displayed on a digital control defined for the relative time.

  I have a digital potentiometer to display relative time in increments of 30 minutes.

  I want to record the value displayed on the control string.  Unfortunately, when I use the "convert to decimal string.vi" number, the resulting string is just the value in seconds.

  How can I get the value as a string? (for example 01:30 for an hour and thirty minutes)

  Thank you

  Sean

  Hi Sean.C!

  M_Peeker's suggestion is a good thing.  A stage that could clarify things is that you must set the % t <%H:%M> format string entry.

  < br / > Kristen:.

• How to get a string changed to be reassessed

  Hello, I am very new to TS and do not know if I express the problem clearly. However the question below:

  Trying to change a numeric variable before it is evaluated at execution, and what I have is:

  Val (searchandreplace ("FileGlobals.I_LB_bin [FileGlobals.loop_BINi]", "lb", FileGlobals.mode [locals. ModeI])) / 2

  but after that the replacement seems that the val function can get the value with the new string.

  How can I get a string to represent a value and be evaluated after edit?

  Thank you very much!

  Hello

  I'm assuming you are trying to get a variable expression that is evaluated during the execution. I would like to make the following

  Locals.Num = Val (Evaluate (SearchAndReplace ("Locals.Var_X", "X", Locals.Control_Num)))

  All variables are String, and the output is a number on which you can perform more arithmetic.

  

  Dodnt you need the Locals.Var_X variable at all. I just created during my tests.

  Rognard

• How to get the string (specified by row and column) of txt file with labview

  Hello world

  How to get the string (specified by row and column) of txt file with labview

  THX

  As far as I know, a text file has no column.  Be more specific.  Do you mean something like the 5th word on line 4, where the words are separated by a space, and lines are separated by a newline character?  You can read from the spreadsheet String function and set the delimiter to a space.  This will produce a 2D channels table.  Then use the table to index and give the line number and column number.

• How a control string works as an indicator as well as a control

  Hello!

  I have several controls string in my front panel, and I want to also control box to work as an indicator. The user should be able to write in the control boxes and then save all this information by using a modified version of the example 'Write Configuration settings File.vi'. Then, the user must be able to retrieve the string information later using a modified version of the example of 'Read Configuration settings File.vi'. The problem is I don't want to separate boxes of control and indicator. I want the channel information retrieved is displayed in boxes of chain drive instead.

  Is this possible? If not, can you try to give me some advice on what I can do?

  Best regards

  You can use a local variable of the control to be able to write the data programmatically in it.

• How to make the background of a control string Transparent?

  Hi all

  Is it possible to make the background of a control string Transparent?

  Thank you
  Ritesh

  Hello

  Yes. Over time edit use the color tool and select transparent (the "T" symbol in the upper right corner of the color selection dialog box) to the background color. At run time, use the property of "text color: text color: BG ' control of the chain.

• How can I get control of my computer?

  I am the only user of my own personal computer and I am denied access to > Documents and settings as well as many other locatons.  When I go to > Security tab and try to change the settings, I get "Ynable to save permission changes on Documents and Settings.  Access is denied. "How can I get control of my computer?

  "Documents and Settings" is not a real file location, it is a junction point which has been built into Windows 7, so that old programs would be able to find.  He re - runs the program to the actual location of these files on Windows 7.  You can't do anything to it because it does not exist, except as a pointer.

• Getting a string of an agent customized by groovy

  I have a number of custom scripts agent and I can retrieve values using the query function:

  def qryService = server.get ("QueryService")

  qryStatement = qryService.createStatement ("metrics from table where monitoredHost.name = servername spanning from date time time_span")

  metricValue = avg (qryService.executeStatement (qryStatement))

  I can get the digital values appearing as ObservedValues in the script if editor I come down on the Forum, but I was not able to get the string values that are listed without comment by "ObservedValue".  The avg() statement above won't work of course for a string, but take it from me either Gets an empty container ([{} {}] or something that I have not been able to analyze (I'm a sysadmin, my JAVA and groovy is limited).)  I tried to use topologyobject instead of QueryService but I did not have what I wanted.

  I would like suggestions.

  Right you are, that works.

• 12 c call Webservice JDeveloper get "SQL string is not a DML statement" as a SQLException exception

  Hi guys,.

  I developed a java class to access the database using the OracleDataSource class and run a SQL query with a select statement. It works very well. I have built a wrapper class and as a Web service. I get "SQL string is not a DML statement" as a SQLException exception when I run as a Web service, but it works very well as an application.

  No idea why I get this error? Not sure why WebSercie is having a problem while this works as an application.

  Thank you and best regards,

  Srini Mel

  Solved the problem by myself.

  The first release "SQL string is not a DML statement" is due to an additional line (pstmt2.executeUpdate ()) in the code.

  Second question, receives not the query response is due to bad user input. I walked into 13.21651 instead of 31.21651.

  Thank you!

  Srini

• Get a string from an iterator object. Help

  Hello community,
  
  I have this code fragment in my application and it complains about this line:
  
  strGUID = (String) it.next ();
  
  I'm trying to get the string that I'm pulling in the loop so I can handle. The funny thing is that I am able to print the entire string like this:
  
  out.println (attrName + "=" + it.next () + "< br >");
  
  But I wan to store this string in a variable, and I can't. The code is below. I have bolded two statements that I try to use to store the string in a variable, and it does not work. Advice please?
  
  
  If (uploading! = null) {}
  out.println ("< tr >");
  out.println ("< td valign = top > < attributes b >: < /b > < table >");
  Iterator iter = attrs.keySet () .iterator ();
  out.println ("< td >");
  String strguid = ""; " *
  While (iter.hasNext ()) {}
  String attrName = (String) iter.next ();
  Set attrVals = attrs.get (attrName) (HashSet);
  If ((attrVals! = null) & &! attrVals.isEmpty ()) {}
  Iterator it = attrVals.iterator ();
  While (it.hasNext ()) {}
  out.println (attrName + "=" + it.next () + "< br >");
  * strguid = (String) it.next (); *
  }
  }
  }

  Strange that it fixes the problem now, but when you "which tried" above it did not work.

• Split screen - Get control

  Hello

  I use the split screen.  I want to transfer the control of the Publisher to the Subscriber screen.

  I did it using the requestControlling() function.

  But

  It works fine when I give adobe LCCS username and password to Subscriber too. otherwise its does not work.

  (I need to include this feature with the installation of knocing queue)

  Please send me your suggesstions.

  Thanks in advance

  Siva

  Set your self-promotion variable real rooms using DevConsole or through your code. This would ensure that all users in your room are promoted at the UserRoles.Publisher level.

  Thank you

  Arun

  From: Adobe Forums [email protected]<>[email protected]>

  Reply-To: "[email protected]<>[email protected]> ' [email protected]<>[email protected]>" "

  Date: Monday, October 3, 2011 03:22:18-0700

  To: Arun [email protected]<>[email protected]>

  Topic: Screen sharing - Get control

  Split screen - Get control

  created by Siva.Shttp://forums.adobe.com/people/Siva.S> in Adobe LiveCycle Collaboration Service - see the discussion complete onhttp://forums.adobe.com/message/3950543#3950543

• How get control back to the page when OAException is raised

  Hello
  
  I am facing a problem where I need to get control back to the page after the oaException has been lifted on the page for a scenario (with custom Message).
  Because we have some javascript validations to be run on the same page, even if a warning is lifted through OAException for a few reasons.
  
  Please suggest me if there is no function to take in charge control once after the exception is thrown with the personalized message in the page (or) is there another class or function can be used to send a message with the symbol 'WARNING' that returns control to the page once it is made to go ahead with the postings.
  
  
  I appreciate your valuable answers.
  
  
  Thank you
  Trehout

  Hello

  I think that since this is a warning message, you can use the API putDialogMessage on the code of the controller, then you can do this by using:

    if (test_warning) {
        // Warning condition, adding a warning display to page
        OAException warning = new OAException("APP","MSG_NAME", tokens);
        pageContext.putDialogMessage(warning);
        // Since putDialogMessage does not stop processing,
        // we can call App Module logic or further processing
        am.invokeMethod("DoSomethingAfterWarning");
    } else {
        // Process without warnings
    }
  

  In this way, you can put a Message of dialogue as does an OAException, without harming the javascript validation, I think. Pay attention to the fact, however, that although an OAException stops the treatment at the time wherever it is thrown, a call to putDialogMessage does not stop the code below himself to run. If you need to stop treatment, join this call in an IF block so that it is running and then jump at the end of the processFormRequest or processRequest method.

  It will be useful,
  Thiago

  Published by: Thiago on December 26, 2008 11:48

• control string unable to update the context when running!

  Hello

  I put a chain control in my front panel. but I found the text I typed in that unable to transfer to my program in real time. for example, I type 5 in the chain box and press a button to transfer the character to be somewhere next time I type 6 in this control again and again press buttong. However, this time the controls still trasfer 5 to my program. To fix the bug, I on the occasion of "Update of the value when you type" property of the control. Why? control does not automatically update its value?

  Ah. Ok.  I had this happen to me a few more times and I think that what is happening, is that the mouse button event triggers until the string is updated after the loss of focus.  I fixed that in the past by forcing a change of focus to another control before trying to read the string (in this case).  Here, I changed your code to be 'change of the value OK' and I added a white case to 'OK mouse down.  I think that the order of events are treated is the mouse down?, mouse down and then value change in making the case until your writing to DB is running, it gives the chain time/reason to update.

  This feels cludgy and probably wrong, but it works.  I hope that someone will be along soon to provide a better way.

  In the process of looking into this I took the liberty of your condensation scheme.  I also created a version that did not try to write to DB or automatically exit.  I have attached two versions.

• Get the string invalid Base64 of image of toDataURL() for the first time in 10 of blackberry webworks

  Hello

  I need to get the Contact image converted to string Base64 using BB 10 Webworks (blackberry.pim.contacts) I get only the contact.photos [0] .smallFilePath which returns the path to the phonebook file.

  Now, I want to get the image of this path and convert it to a Base64 string.

  Here's the javascript code :

  var img = document.createElement ('Image');
  var canvas = document.createElement ('Canvas');

  function getBase64Image (p) {}
  img.setAttribute ("src", p);

  Img.width = Canvas.Width;

  Canvas.height = img.height;

  CTX var = canvas.getContext ("2d");
  ctx.drawImage (img, 0, 0);
  Return canvas.toDataURL("image/jpg");

  }

  This means bad Base64 string of image for the first time. When I convert this string to the image it displays white screen. But returns a string in the Mithraeum and after conversion, display a correct image.

  I use Blackberry Z10 (OS 10) for the test.

  I think that the canvas is not drawing image properly for the first time.

  I have searched and tried many things, but not got success. What will be the solution.

  Thanks in advance.

  My guess is that the image did not load the source completely still. Setting the src / image loading is an asynchronous event, which means that your code will continue to the next line regardless of whether the image has loaded yet or not.

  After calling setAttribute instead of execute the code of the Web, you will probably need define an event on img for the load event listener. Once the image is loaded, you can then use the img with canvas variable to retrieve its data.

  Note that getBase64 will return immediately, so you may need to develop some sort of mechanism to wait before returning, or the asynchronous approach and integrate reminders for the success trigger the next piece of code.

• Can not find a way get control individual Dupla and strokes.

  Hi, I have for the redesign of a website of a shipping company. They are located on "Curaçao".  In Illustrator, I drew the following picture of Curaçao to make vector:

  http://static.wixstatic.com/Media/8064f7_1ceabfdbbe6c4819a6322f8ccdb73a62.gif

  Now, the next step is filling in the colors and the strokes and change the opacity of theirndividuallyI. Now that my problem. I tried to expand the picture, made a live paint group. But I can not "Individual" control of fill and stroke.

  I could be overseeing something. It is not an Image complicated... so if someone could help me I would really appreciate it.

  Thank you for the answers quick and entry of Jacob. Really appreciated the help.

  I managed to finally solve the problem.

  I don't have to use the direct Selection tool and change the Anchor Points.

  Other users of 'New' issues with that, I'll explain what I did:

  1 import Image

  2. tracing:

  • Draw the Image in "black and white".
  • Adjust the threshold, railways and the corners to your liking.
  • Make sure you only select only fills and no shots.
  • Ignore white and him vectorize the Image.

  3 enlarge Image

  4. Select the Image and go to the Panel aspect of it and double click on summary to reveal the fill option. (In this case "Fill" is considered the "Stroke" Image)

  5. Select the fill color and adjust the opacity to your liking.

  6. Select the Image. Go to object > live paint > make

  7. Select the tool live paint to color the image.

  After the Image is colored, you need get the opacity control. It was the trickiest part.

  8 select the Image and Expand option must appear in the above. Click on expand

  9 zoom and carefully, double click on the portion of the Image that has been coloured.

  Be sure to select the right path and not the Group. It may take a few tries. If done correctly the color that you previously selected in the sides of the switch of the opacity will be displayed above.

  10. you can change the color and the opacity to your liking.