HELP SQL (auto / full outer join with date corresponding)

Similar Questions

• [8i] need help with full outer join combined with a cross join...

  I can't understand how to combine a full outer join with a different type of join... is it possible?
  
  Here are some create table and insert for examples of database:

  CREATE TABLE     my_tab1
  (     record_id     NUMBER     NOT NULL     
  ,     workstation     VARCHAR2(4)
  ,     my_value     NUMBER
       CONSTRAINT my_tab1_pk PRIMARY KEY (record_id)
  );
  
  INSERT INTO     my_tab1
  VALUES(1,'ABCD',10);
  INSERT INTO     my_tab1
  VALUES(2,'ABCD',15);
  INSERT INTO     my_tab1
  VALUES(3,'ABCD',5);
  INSERT INTO     my_tab1
  VALUES(4,'A123',5);
  INSERT INTO     my_tab1
  VALUES(5,'A123',10);
  INSERT INTO     my_tab1
  VALUES(6,'A123',20);
  INSERT INTO     my_tab1
  VALUES(7,'????',5);
  
  
  CREATE TABLE     my_tab2
  (     workstation     VARCHAR2(4)
  ,     wkstn_name     VARCHAR2(20)
       CONSTRAINT my_tab2_pk PRIMARY KEY (workstation)
  );
  
  INSERT INTO     my_tab2
  VALUES('ABCD','WKSTN 1');
  INSERT INTO     my_tab2
  VALUES('A123','WKSTN 2');
  INSERT INTO     my_tab2
  VALUES('B456','WKSTN 3');
  
  CREATE TABLE     my_tab3
  (     my_nbr1     NUMBER
  ,     my_nbr2     NUMBER
  );
  
  INSERT INTO     my_tab3
  VALUES(1,2);
  INSERT INTO     my_tab3
  VALUES(2,3);
  INSERT INTO     my_tab3
  VALUES(3,4);

  And, the results that I want to get:

  workstation     sum(my_value)     wkstn_name     my_nbr1     my_nbr2
  ---------------------------------------------------------------
  ABCD          30          WKSTN 1          1     2
  ABCD          30          WKSTN 1          2     3
  ABCD          30          WKSTN 1          3     4
  A123          35          WKSTN 2          1     2
  A123          35          WKSTN 2          2     3
  A123          35          WKSTN 2          3     4
  B456          0          WKSTN 3          1     2
  B456          0          WKSTN 3          2     3
  B456          0          WKSTN 3          3     4
  ????          5          NULL          1     2
  ????          5          NULL          2     3
  ????          5          NULL          3     4

  I tried a number of different things, google my problem and no luck yet...

  SELECT     t1.workstation
  ,     SUM(t1.my_value)
  ,     t2.wkstn_name
  ,     t3.my_nbr1
  ,     t3.my_nbr2
  FROM     my_tab1 t1
  ,     my_tab2 t2
  ,     my_tab3 t3
  ...

  So, what I want, it's a full outer join of t1 and t2 on workstation and a cross join of one with the t3. I wonder if I can't find examples of it online because it is not possible...
  
  Note: I'm stuck dealing with Oracle 8i
  
  Thank you!!

  Hello

  The query I posted yesterday is a little more complex that it should be.
  My_tab2.workstation is unique, there is no reason to make a separate subquery as mt1. We can join my_tab1 to my_tab2 and get the SUM in a subquery.

  SELECT       foj.workstation
  ,       foj.sum_my_value
  ,       foj.wkstn_name
  ,       mt3.my_nbr1
  ,       mt3.my_nbr2
  FROM       (     -- Begin in-line view foj for full outer join
            SELECT        mt1.workstation
            ,        SUM (mt1.my_value)     AS sum_my_value
            ,        mt2.wkstn_name
            FROM        my_tab1   mt1
            ,        my_tab2   mt2
            WHERE        mt1.workstation     = mt2.workstation (+)
            GROUP BY   mt1.workstation
            ,        mt2.wkstn_name
                          --
                  UNION ALL
                          --
            SELECT      workstation
            ,      0      AS sum_my_value
            ,      wkstn_name
            FROM      my_tab2
            WHERE      workstation     NOT IN (     -- Begin NOT IN sub-query
                                             SELECT      workstation
                                     FROM      my_tab1
                                     WHERE      workstation     IS NOT NULL
                                   )     -- End NOT IN sub-query
         ) foj     -- End in-line view foj for full outer join
  ,       my_tab3  mt3
  ORDER BY  foj.wkstn_name
  ,       foj.workstation
  ,       mt3.my_nbr1
  ,       mt3.my_nbr2
  ;
  

  Thanks for posting the CREATE TABLE and INSERT statements, and very clear expected results!

  user11033437 wrote:
  ... So, what I want, it's a full outer join of t1 and t2 on workstation and a cross join of one with the t3.

  She, exactly!
  The trickiest part is when and how get SUM (my_value). You could address the question of exactly what my_tab3 must be attached to a cross that's exactly what should look like the result set of the full outer join between my_tab1 and my_tab2 to. To do this, take your desired results, remove columns that do not come from the outer join complete and delete duplicate rows. You will get:

  workstation     sum(my_value)     wkstn_name
  -----------     -------------   ----------
  ABCD          30          WKSTN 1
  A123          35          WKSTN 2
  B456          0          WKSTN 3
  ????          5          NULL          
  

  So the heart of the problem is how to get these results of my_tab1 and my_tab2, which is done in the subquery FOJ above.

  I tried to use auto-documenté in my code names. I hope you can understand.
  I could spend hours explaining the different parts of this query more in detail, but I don't know that I would lose some of that time, explain things that you already understand. If you want an explanation of the specific element (s), let me know.

• Help with sql FULL OUTER JOIN

  Hi all
  I need assistance with SQL FULL OUTER JOIN.
  
  How to write with FULL OUTER JOIN, the query.
  I tried like
  
  
  I have 3 different queries.
  
  Query q: SELECT emp_id LN.emp_id.
  Sum (LN_amount) loan_amt
  MY_LON_TAB LN
  WHERE LN_amount > 20000
  LN.emp_id GROUP;
  
  
  
  Query b: SELECT PLN. EMP_ID emp_id,
  Sum (PLAN_AMOUNT) plan_amt
  FROM PLN MY_PLAN_TAB
  where PLAN_AMOUNT <>0
  GROUP BY PLN. EMP_ID;
  
  
  Query C:
  
  SELECT FLX. EMP_ID emp_id,
  SUM (PRORATE_AMOUNT) PRORATE_AMT
  OF MY_FLX_TAB FLX
  WHERE PRORATE_AMOUNT <>0
  FLX GROUP. EMP_ID;
  
  
  Suppose that the different subquery above 3 a, b, c respectively. each subquery with emp_id and respective amount.
  
  like a.emp_id, a.loan_amt
  b.emp_id, b.plan_amt
  c.emp_id, c.prorate_amt
  
  I show all the empid with their amount respective.
  schenario: If an account made, but not vice-versa b
  and B have record, but not vice versa c
  and a credit record but not vice versa c
  
  first: I have external is associated with the A and B
  Second: join external then complete the total outcome of (a & b) with c
  but empid c just as empty.
  
  
  My output is:
  
  emp_id a.loan_amt, b.plan_amt c.prorate_amt
  101 5000 null null
  102 4500 null 2000
  103 6700 null null
  
  
  How to solve the foregoing to the ANSI (FULL OUTER JOIN) method.
  Please suggest me.
  
  Thanks in advance...
  PKM

  Hello

  It is very difficult for anyone to say what you're doing wrong if they do not know what you are doing. Post your code FULL OUTER JOIN.
  My best guess is:

  WITH     a     AS
  (
       SELECT     ...      -- What you posted as query a
  )
  ,     b     AS
  (
       SELECT     ...      -- What you posted as query b
  )
  ,     c     AS
  (
       SELECT     ...      -- What you posted as query c
  )
  SELECT     COALESCE ( a.emp_id
             , b.emp_id
             , c.emp_id
             )     AS emp_id
  ,     ...     -- whatever other columns you want
  FROM          a
  FULL OUTER JOIN     b  ON     b.emp_id =            a.emp_id
  FULL OUTER JOIN     c  ON     c.emp_id = COALESCE (a.emp_id, b.emp_id)
  ;
  

  I hope that answers your question.
  If not, post a small example (CREATE TABLE and INSERT statements) data for all tables and the results expected from these data (if not what you have already posted).

• Help required in a full outer join

  In my view, the query below can be changed at the full outer join. But, I was not able to do.
  I need your help to change to the full outer join. My current request is

  SELECT CLAIMNO,'1' INDX FROM D_CLAIM@CMS2PROD
  WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null
  MINUS
  SELECT CLAIMNO,'1' FROM D_CLAIM
  WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null
  UNION
  SELECT CLAIMNO,'2' FROM D_CLAIM
  WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null
  MINUS
  SELECT CLAIMNO,'2' FROM D_CLAIM@cms2prod
  WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null

  Something like:

  select nvl(p.claimno,s.claimno) claimno,
         nvl2(p.claimno,'PROD','STAGING') the_source,
         :the_clntsys clntsys,
         :the_facility facility
    from (select claimno
            from d_claim
           where clntsys = :the_clntsys
             and facility = :the_facility
         ) p
         full outer join
         (select claimno
            from d_claim@cms2prod        /* never tried with remote */
           where clntsys = :the_clntsys
             and facility = :the_facility
         ) s
         on p.claimno = s.claimno
   where p.claimno is null
      or s.claimno is null
  

  Concerning

  Etbin

• Full outer join

  30%
  
  Hello
  
  I have a few questions to ask. Please see below I have provided a script to recreate my problem.
  
  Question 1.
  
  I have the following query does not work when I include columns (see 1.2) in the select but will run when I use the Asterix symbol (see 1.1)
  
  * 1.1 runs with no problems *.

  select *
    from ora full outer join txt on ora.ora_id_y = txt.txt_id_y;

  * 1.2 returns error.*

  select txt.txt_id_y
       , txt.txt_n
       , txt.txt_y
       , ora.ora_n
       , ora.ora_y
    from ora full outer join txt on ora.ora_id_y = txt.txt_id_y;
  
  Error report:
  SQL Error: ORA-00918: column ambiguously defined
  00918. 00000 -  "column ambiguously defined"
  *Cause:    
  *Action:

  Question 2.
  
  Is it possible to use a query with joins free and using multiple outer joins to accomplish what I have under which is seen 6 to access the query I have to Question 1.
  
  CREATE THE SCRIPT

  drop table master;
  
  create table master
  ( id varchar2 (10 char)
  , txt varchar2 (1 char)
  , ora varchar2 (1 char)
  );
  
  INSERT INTO MASTER (ID, TXT, ORA) VALUES ('orange' , 'Y', 'Y');
  INSERT INTO MASTER (ID, TXT, ORA) VALUES ('apple', 'Y', '');
  INSERT INTO MASTER (ID, TXT, ORA) VALUES ('orange'  , 'Y', 'N');
  INSERT INTO MASTER (ID, TXT, ORA) VALUES ('peach'  , 'Y', '');
  
  create or replace force view ora_n
  as
  select id
       , count (ora) ORA_N
    from master
   where ora in ('N')
   group by id;
  
  create or replace force view ora_y
  as
   select id
       , count (ora) ORA_Y
    from master
   where ora in ('Y')
   group by id;
  
  create or replace force view txt_n
  as 
   select id
       , count (txt) TXT_N
    from master
   where txt in ('N')
   group by id;
  
  create or replace force view txt_y
  as 
   select id
         , count (txt) TXT_Y
    from master
   where txt in ('Y')
   group by id;
   
  create or replace force view ora
  as 
  select ora_n.id ora_id_n
       , ora_y.id ora_id_y
       , ora_n.ora_n
       , ora_y.ora_y
    from ora_n full outer join ora_y on ora_n.id = ora_y.id;
  
  create or replace force view txt
  as 
  select txt_y.id txt_id_n
       , txt_y.id txt_id_y
       , txt_n.txt_n
       , txt_y.txt_y
    from txt_n full outer join txt_y on txt_n.id = txt_y.id; 

  Published by: benton on August 21, 2012 10:48
  
  Published by: benton on August 21, 2012 11:11

  Found: support for Oracle, there are:

  Bug 6319169 : ORA-918, FULL OUTER JOIN
  Reproduced on 10.2.0.1,10.2.0.3.
  Fixed to the product Version 11.0
  WORKAROUND solution: alter session set '_column_elimination_off' = true;

• What is the Assembly of 4 or 5 tables FULL OUTER JOIN logic?

  the query is as below:
  
  as you can see, I need FULL OUTER JOIN, these 5 tables and get a column from each table that is based on three common columns (ORG_iD, CUST_ID, CURRENT_DT).
  
  And I wonder what is the logic of the 5 FULL OUTER JOIN table?
  It will return if there is a folder that exists in the single table COL1? or table, COL2 and COL3 and so on. Basically any combination of these 5 tables.
  
  

      SELECT (CASE WHEN COL1.ORG_ID IS NOT NULL THEN COL1.ORG_ID
                   WHEN COL2.ORG_ID IS NOT NULL THEN COL2.ORG_ID
                   WHEN COL3.ORG_ID IS NOT NULL THEN COL3.ORG_ID
                   WHEN COL4.ORG_ID IS NOT NULL THEN COL4.ORG_ID
                   ELSE COL5.ORG_ID 
              END) ORG_ID,
              (CASE WHEN COL1.CUST_ID IS NOT NULL THEN COL1.CUST_ID
                   WHEN COL2.CUST_ID IS NOT NULL THEN COL2.CUST_ID
                   WHEN COL3.CUST_ID IS NOT NULL THEN COL3.CUST_ID
                   WHEN COL4.CUST_ID IS NOT NULL THEN COL4.CUST_ID
                   ELSE COL5.CUST_ID
              END) CUST_ID, 
              (CASE WHEN COL1.CURRENT_DT IS NOT NULL THEN COL1.CURRENT_DT
                   WHEN COL2.CURRENT_DT IS NOT NULL THEN COL2.CURRENT_DT
                   WHEN COL3.CURRENT_DT IS NOT NULL THEN COL3.CURRENT_DT
                   WHEN COL4.CURRENT_DT IS NOT NULL THEN COL4.CURRENT_DT
                   ELSE COL5.CURRENT_DT 
              END) CURRENT_DT, 
            'VENDORS' as ITEM_NAME,
            V_AGE_IND as ACCT_AGE_IND,  
            COL1.AMT_ZSHT,  
            COL2.AMT_YFYS,  
            COL3.AMT_YFYS, 
            COL4.AMT_YFYS,  
            COL5.AMT_BZL,  
            'NAV',
            sysdate
      FROM COL1  
                FULL OUTER JOIN COL2 ON (COL1.ORG_ID=COL2.ORG_ID AND COL1.CURRENT_DT=COL2.CURRENT_DT AND COL1.CUST_ID=COL2.CUST_ID)  
                FULL OUTER JOIN COL3 ON (COL2.ORG_ID=COL3.ORG_ID AND COL2.CURRENT_DT=COL3.CURRENT_DT AND COL2.CUST_ID=COL3.CUST_ID)  
                FULL OUTER JOIN COL4 ON (COL3.ORG_ID=COL4.ORG_ID AND COL3.CURRENT_DT=COL4.CURRENT_DT AND COL3.CUST_ID=COL4.CUST_ID)  
                FULL OUTER JOIN COL5 ON (COL4.ORG_ID=COL5.ORG_ID AND COL4.CURRENT_DT=COL5.CURRENT_DT AND COL4.CUST_ID=COL5.CUST_ID)  

  Any ideas?
  
  Thank you

  Hello

  When you perform a JOIN EXTERNAL COMPLETE multi - build that way, whenever you add a new table, you can just join the previous table because this table could be all NULL values for a given row. You can reach each new table to the first table, either, for the same reason. You must enclose each new table with all previous tables, like this:

  FULL OUTER JOIN COL2 ON  COL2.ORG_ID     =           COL1.ORG_ID
                 AND COL2.CURRENT_DT =           COL1.CURRENT_DT
                 AND COL2.CUST_ID    =           COL1.CUST_ID
  FULL OUTER JOIN COL3 ON  COL3.ORG_ID     = COLAESCE (COL1.ORG_ID,     COL2.ORG_ID)
                 AND COL3.CURRENT_DT = COALESCE (COL1.CURRENT_DT, COL2.CURRENT_DT)
                 AND COL3.CUST_ID    = COALESCE (COL1.CUST_ID,    COL2.CUST_ID)
  FULL OUTER JOIN COL3 ON  COL4.ORG_ID     = COLAESCE (COL1.ORG_ID,     COL2.ORG_ID,     COL3.ORG_ID)
                 AND COL4.CURRENT_DT = COALESCE (COL1.CURRENT_DT, COL2.CURRENT_DT, COL3.CURRENT_DT)
                 AND COL4.CUST_ID    = COALESCE (COL1.CUST_ID,    COL2.CUST_ID,    COL3.CUST_ID)
  FULL OUTER JOIN COL3 ON  COL5.ORG_ID     = COLAESCE (COL1.ORG_ID,     COL2.ORG_ID,     COL3.ORG_ID,     COL4.ORG_ID)
                 AND COL5.CURRENT_DT = COALESCE (COL1.CURRENT_DT, COL2.CURRENT_DT, COL3.CURRENT_DT, COL4.CURRENT_DT)
                 AND COL5.CUST_ID    = COALESCE (COL1.CUST_ID,    COL2.CUST_ID,    COL3.CUST_ID,    COL4.CUST_ID)  
  

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements), and the results you want from this data.
  Explain how you get these results from these data.
  Always tell what version of Oracle you are using.

• Left Outer Join with sum

  Dear elders,
  
  
  
  Firstly, sorry if my question is considered to be 'very novice' but I have this problem of confusion.
  
  Can I use the left outer join with summary?
  For example:
  
  Work table

  JobCode      JobGroupCode      
  111A         1100              
  112B         1100               
  113C         1100
  121A         1200
  333F         3300               

  Table No.

  JobGroupCode    ParentCode
  1100            1000
  1200            1000
  1300            1000
  3300            3000

  Activity table

  Jobcode      Mandays
  111A         5
  112B         7
  113C         3

  I want to choose with this result

  Job.JobCode    Job.JobGroupCode     JobGroup.Parentcode       Mandays
  111A           1100                 1000                      5
  112B           1100                 1000                      7               
  113C           1100                 1000                      3
  121A           1200                 1000                      0
  333F           3300                 3000                      0

  All I did was:

  select j.jobcode, j.jobgroupcode, jg.parentcode, sum(a.mandays)
    from job j
   inner join jobgroup jg on j.jobgroupcode = jg.jobgroupcode
    left join activity a on j.jobcode = a.jobcode
   group by j.jobcode, j.jobgroupcode, jg.parentcode

  and I got was only jobcode activity table, not exactly what I want to get all the work table jobcode. Could you please tell me, where I was wrong?
  
  result

  Job.JobCode    Job.JobGroupCode     JobGroup.Parentcode       Mandays
  111A           1100                 1000                      5
  112B           1100                 1000                      7               
  113C           1100                 1000                      3

  Thank you very much.
  
  Published by: user11197113 on May 25, 2009 03:31
  
  Published by: user11197113 on May 25, 2009 03:32

  Hello (and welcome!).

  Edit

  OK, try this:

  select j.jobcode, j.jobgroupcode, jg.parentcode, NVL(sum(a.mandays),0)
    from job j
   inner join jobgroup jg on j.jobgroupcode = jg.jobgroupcode
    left join activity a on j.jobcode = a.jobcode
   group by j.jobcode, j.jobgroupcode, jg.parentcode
  

  That will give you this:

  JOBC JOBG PARE SUM(A.MANDAYS)
  ---- ---- ---- --------------
  111A 1100 1000              5
  112B 1100 1000              7
  113C 1100 1000              3
  121A 1200 1000              0
  333F 3300 3000              0
  

  These are real results of your test data.

• full outer join: how to get without null values?

  full outer join: how to get without null values?

  Hello

  Please go well this url

  http://asktom.Oracle.com/pls/asktom/f?p=100:11:999478429860455:P11_QUESTION_ID:6585774577187

  Thank you
  Prakash P

• Diff "full outer join" is going. "(+)" SELECT syntax?

  As far as I know there are two ways to set an outer join:
  
  Select... from tab1 external t1 full join tab2 t2 on t1.id = t2.id;
  or:
  SELECT... from tab1 tab2 t2, t1 where t1.id = t2.id (+)
  
  They are absolutely equivialent?
  
  Who are the most common one?
  
  Who serve as well on other databases (DB2, MySQL)?
  
  Can I put an additional WHERE clause at the end of the first statement:
  
  SELECT... from tab1 t1 outer join t2 on t1.id = t2.id tab2 complete WHOSE...;

  Select... from tab1 external t1 full join tab2 t2 on t1.id = t2.id;

  It's FULL OUTER JOIN

  SELECT... from tab1 tab2 t2, t1 where t1.id = t2.id (+)

  It's LEFT OUTER JOIN.

  They are quite different.

  FULL OUTER JOIN - retrieves all the rows from tab1 and tab2

  LEFT OUTER JOIN - gets all the tab1 and lines than the line that matches the join condition of tab2.

  Here is a simple test.

  create table tab1(id integer)
  /
  create table tab2(id integer)
  /
  begin
    insert into tab1 values(1);
    insert into tab1 values(2);
    insert into tab1 values(3);
  end;
  /
  begin
    insert into tab2 values(3);
    insert into tab2 values(4);
    insert into tab2 values(5);
  end;
  /
  Select t1.id, t2.id
    from tab1 t1 full outer join tab2 t2
      on t1.id =t2.id
  /
  Select t1.id, t2.id
    from tab1 t1, tab2 t2
   where t1.id = t2.id(+)
  /
  

  Run it and see the result.

• SSRS for lack of outer join with the Oracle data source

  It seems to be a problem with the Oracle driver used in the Reporting SERVICES query designer.

  When you use an Oracle data source, if I create an outer join in the graphic designer, it automatically inserts '{OJ' before the join and '} ' after her.  This is an incorrect syntax for Oracle and refuses to start.  The curly braces and the JO editable in designer text, but if I go back to the graphic designer and immediately to reintegrate them.

  Only, this has started to happen a year or two ago - before that it worked, but with the old (+) syntax.

  Can it not be healed?  It makes things very difficult.

  -Geoff

  Hi Geoff,

  Thanks for posting in the Microsoft Community.

  However, the question you posted would be better suited in the Forums of the Oracle Support; We recommend that you post your query in Oracle Support Forums to get help:

  https://forums.Oracle.com/forums/main.jspa;JSESSIONID=8d92100c30d8fb401bcbd10b46c38c9ddf1a3242549a.e34SbxmSbNyKai0Lc3mPbhmSc3aNe0? CategoryID = 84

  If you have any other questions or you need Windows guru, do not hesitate to post your questions and we will be happy to help you.

• Outer join with a constant

  Outer join when made between the columns of the two tables is easy to understand and I'm familiar with it. But when it comes to the same join with a constant, my head starts spinning... you guys can help me with this? I would appreciate that show you with examples.
  Thanks a ton.

  Hello

  >
  Ok... I want to understand the output of the last sql statement given here.
  ...
  Select * from a, b
  where col_a (+) = col_b
  and col_a (+) = 1

  It shows put it is as follows
  col_a, col_b
  1 1
  2 NULL
  NULL NULL

  Joining means: 'display all rows in table b and the corresponding rows in the table one '.
  Since it is an outer join, it also means "view b lines even if there is no corresponding row in a.

  Thus, the output contains 3 lines, which correspond to the 3 lines in b.
  Only one of them (the one with col_b = 1) had a game in a.col_a, if the column is NULL in the other lines.

  With the sample data you posted, you will get the same results without condition

  and     col_a (+) = 1
  

  If you want to understand what makes this condition, use some examples of data where this condition would fail.
  For example, add this line to the table a:

  insert into a values (2);
  

  and run your original query (including the)

  and     col_a (+) = 1
  

  ). what output you get? You get the same exact results you did without the new line in a.

  In other words, the b line where col_b = 2 has still no matches in the table has.
  True, there is now a line of table where col_a = 2, but which does not constitute a game. A match is defined by two conditions:

  where   col_a (+) = col_b
  and     col_a (+) = 1
  

  in order to have a pair of lines which meets only the first condition

  where   col_a (+) = col_b
  

  is not enough.

• Help for a LEFT OUTER JOIN query

  Hello, all,.

  I'm having some trouble setting up an Oracle 11 g Server SQL query, and I could use some help.

  Let's say tableA is blogs; tableC is comments for blog entries; tableB is the associative array:

  tableA
  blogID        blogTitle       blogBody      dateEntered
  1             This is a test  More text...  2016-05-20 11:11:11
  2             More testing    Still more!   2016-05-19 10:10:10
  3             Third charm!!   Blah, blah.   2016-05-18 09:09:09
  

  tableC
  commID        userID          userText      dateEntered
  10            Bravo           I like it!    2016-05-20 11:21:31
  11            Charlie         I don't!      2016-05-20 11:31:51
  12            Alpha           Do it again!  2016-05-19 10:20:30
  13            Bravo           Still more?   2016-05-19 10:30:50
  14            Charlie         So, what?     2016-05-19 10:35:45
  15            Bravo           Blah, what?   2016-05-18 09:10:11
  16            Alpha           Magic number! 2016-05-18 09:11:13
  

  tableB
  blogID        commID
  1             10
  1             11
  1             12
  2             13
  2             14
  3             15
  3             16
  
  
  
  

  I'm trying to get blogID, blogTitle, blogBody and the number of comments for each blog entry.  But, since I'm on to_char() for date and COUNT (commID) for the total number of comments, I am not "a group by expression.

  Here is an example of pseudo-SQL of what I'm trying.

  SELECT a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS') as dateEntered, COUNT(c.commID) as total
  FROM tableA a LEFT OUTER JOIN tableB b ON b.blog_ID = a.blog_ID
                LEFT OUTER JOIN tableC c ON c.commID = b.commID
  WHERE a.blogID = '1'
  GROUP BY blogID, blogTitle, blogBody
  ORDER BY to_date(dateEntered,'MM-DD-YYYY HH24:MI:SS') desc
  

  I'm sure it's something simple, but I just DO NOT see it.  Can you help me?

  V/r,

  ^_^

  Try:

  GROUP BY a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS')
  

  See you soon

  Eddie

• outer join with the additional constraint

  Hello

  With the help of Oracle 11 g R2.

  I would of outer join tables 2 together and put down restrictions on the types of records that are returned in the query result. Here's a mock-up of the tables and data.

  create table aaa (col1 number not null, col2 number not null)

  create table bbb (col1 number not null, col2 number not null)

  insert into values of aaa (1: 80)

  insert into values aaa (2, 90)

  insert into values aaa (3, 80)

  insert into values aaa (4, 90)

  insert into values aaa (5, 80)

  
  insert into bbb values (3, 600)

  insert into values of bbb (4, 700)

  This is the query

  
  select a.col1, a.col2, b.col1, b.col2
  from aaa a, bbb b
  where a.col1 = b.col1 (+)
  and   (a.col2, b.col2) <> ((90, 700))
  

  The result of the query is as follows.

  col1 col1 col2 col2

  1 80

  3 80 3 600

  5 80

  Where col1 = 4 has been deleted, which is an expected result. However, where col1 = 2 has also been removed, which is not a desired outcome. Your response is appreciated.

  Hello

  Here is a way that works for the given sample data:

  SELECT *.

  AAA a

  LEFT OUTER JOIN bbb b ON a.col1 = b.col1

  WHERE the NVL (a.col2, 0) <> 90

  OR NVL (b.col2, 0) <> 700

  ;

  I don't know if that will satisfy your requirements with other data, since you didn't say what your needs are.

  Whenever you have a WHERE clause is applied after the outer join, all columns of the table in option (table bbb in this example) must be used in an NVL, NVL2 or something like a CASE expression that takes into account null values; otherwise, the effect will be the same as an inner join.

• Left outer join without data in a table

  I have two tables defined (see below). Emp table has given, and there is still no data in the table of Emp_Type! Now it is empty.
  
  I want to write a query that returns the data from the tables, even if there is no data in the Emp_type table. I use a left outer join but it return nothing. Can anyone help?
  

  create table EMP
  (
    EMPID   NUMBER(10,2),
    EMPNAME VARCHAR2(100)
  );
  
  INSERT INTO emp (empid,empname) values (1, 'Mark');
  INSERT INTO emp (empid,empname) values (2, 'Jason');
  INSERT INTO emp (empid,empname) values (3, 'Kevin');
  INSERT INTO emp (empid,empname) values (4, 'Drew');
  INSERT INTO emp (empid,empname) values (5, 'Jessica');
  INSERT INTO emp (empid,empname) values (6, 'Pena');
  INSERT INTO emp (empid,empname) values (7, 'Roxanne');
  
  create table EMP_Type
  (
    ID          NUMBER(10,2),
    EMPID       NUMBER(10,2),
    TYPE_ID     NUMBER(10,2),
    END_DATE    DATE
  );
  
  No data
  
  select *
    from emp e
    left outer join emp_Type t
      on e.empid = t.empid
   WHERE t.type_id = 1
     and t.end_date is null;

  WHERE t.type_id = 1

  will be ever true when table has no rows (or t.type_id is NULL?)

• Outer join with Oracle syntax

  Hi, I am new to oracle and I worked this request for reports for about 2 weeks, please take a look at my request

  SELECT mmt.transaction_date "Transaction Date", 
              msib.segment1 "Item", 
              gcc.segment1||'-'||gcc.segment2||'-'||gcc.segment3||'-'||gcc.segment4||'-'||gcc.segment5||'-'||gcc.segment6||'-'||(nvl(gcc.segment7,'000000')) "account",
              (CASE mttype.transaction_type_name
              WHEN 'Average cost update' THEN
            ((nvl(mmt.new_cost,0) - nvl(mmt.prior_cost,0)) * nvl(mmt.quantity_adjusted,0)) + nvl(mmt.variance_amount,0)
              ELSE
               (mmt.Primary_quantity * nvl(mmt.actual_cost, 0) + nvl(mmt.variance_amount, 0))
             END) "Transaction Value",
              mttype.description "Transaction Type",
              mmt.subinventory_code "Subinventory",
              ood.organization_code "Org",
              msib.Primary_UOM_Code "UOM",
              mmt.Primary_Quantity "Primary Quantity",
              mtr.description "Reason",
              mmt.transaction_reference "Reference"
  FROM mtl_material_transactions mmt,
           mtl_system_items_b msib,
           mtl_transaction_accounts mta,
           gl_code_combinations gcc,
           mtl_transaction_types mttype,
           Org_Organization_Definitions ood,
           mtl_transaction_reasons mtr
  WHERE mmt.transaction_date >= :P_DATE_FROM 
             and mmt.transaction_date  < :P_DATE_TO +1
             and mmt.organization_id = :P_ORGANIZATION 
             and msib.organization_ID = mmt.organization_ID  
             and msib.inventory_item_id=mmt.inventory_item_id 
             and mta.transaction_id=mmt.transaction_id
             and gcc.code_combination_id = mta.reference_account
             and mttype.transaction_type_id=mmt.transaction_type_id
             and mmt.reason_id=mtr.reason_id(+)
             and ood.organization_id=mmt.organization_id
             and mttype.transaction_type_id = :P_TRANSACTION_TYPE
             and msib.segment1 = :P_ITEM
             AND gcc.segment2 = :P_ACCOUNT

  null values is on the mtl_material_transactions table, which is reason_id, subinventory_code and transaction_reference
  put desired option on would show all archives on mtl_material_transactions with null values
  so I put the symbol of the outer join right?
  BTW
  I tried to put the (+) sign on various locations but it still not good and I am really at a loss

  Hello

  Whenever you have any questions, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and the desired results from these data. I know that's not always easy, but it is really necessary. Compounds that, I do not understand your problem.
  It could be useful that simplify you the problem. If you were not interested in, say, the mta, gcc, tables msib and ood, would you still have the same problem? If so, forget all these tables and just after, CREATE TABLE and INSERT statements for the remaining tables and the results you want from this data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

  The query you posted will not exclude any line of mmt just because it doesn't have a corresponding line in the mtr; That's what the condition:

  and mmt.reason_id=mtr.reason_id(+)
  

  but it will exclude mmt lines if they do not have matching rows in other tables. Maybe you need + plus join and may under certain conditions non-join, such as conditions

  gcc.segment2 (+) = :P_ACCOUNT
  

  Too much. It's just a guess. Without seeing your sample data and the correct results, you should get from this data, I can't say.