How can I convert a part of the day at once?

How to convert a part of the day in one hour, without dividing and modding the number myself?

For example, I calculated the noon solar UTC for etre.733409047. Adding the date gives the correct answer:

SQL > SELECT TO_DATE (' 01 / 01/2012 ', ' DD/MM/YYYY') +.733409047 FROM Dual;

TO_DATE (' 01 / 01/2012 ',)
-------------------
01/01/2012-17:36:07

A few questions to really understand this.

.733409047 is implicitly converted? If so, what kind of data?
If I want to HH should be converted to a date, then TO_CHAR? Or the comma directly convert?

Currently, I'm trying to understand the INTERVAL.

SQL > select interval '. 5' double day.
Select the interval '. 5' double day
*
ERROR on line 1:
ORA-01867: the interval is invalid

So I'm obviously interpreting. Can it be used here?

Hello

Brian Tkatch wrote:
How to convert a part of the day in one hour, without dividing and modding the number myself?

For example, I calculated the noon solar UTC for etre.733409047. Adding the date gives the correct answer:

SQL > SELECT TO_DATE (' 01 / 01/2012 ', ' DD/MM/YYYY') +.733409047 FROM Dual;

TO_DATE (' 01 / 01/2012 ',)
-------------------
01/01/2012-17:36:07

A few questions to really understand this.

.733409047 is implicitly converted? If so, what kind of data?

No, there is no conversion going on here, just the Arithmetic of Date .
In Oracle, if d is a DATE and n is a NUMBER (not necessarily a whole and not necessarily positive), j + n is the DATE is n days later than d.

If I want to HH should be converted to a date, then TO_CHAR? Or the comma directly convert?

Sorry, I don't understand. Do you mean you want to do something like arithmetic dates, but instead to use a number comme.733409047 (which means environ.73 of a day), you want to pass a string as 17: 36:07' (i.e. 17 hours, 36 minutes and 7 seconds)? If so, INTERVAL DAY TO SECOND is probably your best choice. (It seems that you are already thinking in this direction.)

Currently, I'm trying to understand the INTERVAL.

SQL > select interval '. 5' double day.
Select the interval '. 5' double day
*
ERROR on line 1:
ORA-01867: the interval is invalid

So I'm obviously interpreting. Can it be used here?

You can only use integers like that. If you want any number, use arithmetic to date to add (or subtract) a DATE or use NUMTIDSINTERVAL to produce an INTERVAL DAY TO SECOND:

SELECT     NUMTODSINTERVAL (.733409047, 'DAY')     AS intrvl
FROM     dual;

Output:

INTRVL
------------------------------------------------
+000000000 17:36:06.541660800

I hope that answers your question.
If not, post a small example data (CREATE TABLE and INSERT statements), maybe 5 rows and also post the results desired from these data.
Explain, using specific examples, how you get these results from these data.
Always tell what version of Oracle you are using.

Tags: Database

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