How do I change new time of default event in the calendar

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  Although I have studied this issue in forums, I'm still without resolution. New default event for the calendar of 'Calendar' in the game on my Mac of calendars even when it is initially unchecked and hidden in the calendars list.

  I don't see a place in the calendar preferences or in system preferences > iCloud to make changes. I would like new events, write in the default calendar for "Calendar" calendar in my iCloud.com account.

  Any thoughts?

  Well, here's the scoop:

  To set the default calendar, open the calendar, choose calendar > Preferences, and then click general.

  Default calendar

  The calendar where new events are added by default. If you choose "Selected calendar", then the calendar highlight in the calendar list is the default calendar.

  

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  Hi TommieZook, I see that this is your first post here.  Welcome to our community!

  As for your question, there are few parameters that you might need to check.  #1 is the most likely:

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     Press + W to find settings, and then type power to find and open Power Options.  On the left, click "choose when turn off the display" and set the timer accordingly.
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     On the same page of the Power Options, click 'choose when the computer sleeps' to set the timer as well.
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     Windows 8 is not the screensaver on initially, but you can see these settings too.  For easy access, go to the desktop and right click, then choose Customize.  Choose screensaver downstairs and make sure that the setting of the timer is to your liking.

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• How can I change this request, so I can display the name and partitions in a r

  How can I change this request, so I can add the ID of the table SPRIDEN
  from now on gives me what I want:

   
  1,543     A05     24     A01     24     BAC     24     BAE     24     A02     20     BAM     20

  in a single line, but I would like to add the id and the name that is stored in the SPRIDEN table
  
  

   
  SELECT sortest_pidm,
         max(decode(rn,1,sortest_tesc_code)) tesc_code1,
         max(decode(rn,1,score)) score1,
         max(decode(rn,2,sortest_tesc_code)) tesc_code2,
         max(decode(rn,2,score)) score2,
         max(decode(rn,3,sortest_tesc_code)) tesc_code3,
         max(decode(rn,3,score))  score3,
         max(decode(rn,4,sortest_tesc_code)) tesc_code4,
         max(decode(rn,4,score))  score4,
         max(decode(rn,5,sortest_tesc_code)) tesc_code5,
         max(decode(rn,5,score))  score5,
         max(decode(rn,6,sortest_tesc_code)) tesc_code6,
         max(decode(rn,6,score))  score6         
    FROM (select sortest_pidm,
                 sortest_tesc_code,
                 score, 
                row_number() over (partition by sortest_pidm order by score desc) rn
            FROM (select sortest_pidm,
                         sortest_tesc_code,
                         max(sortest_test_score) score
                    from sortest,SPRIDEN
                    where 
                    SPRIDEN_pidm =SORTEST_PIDM
                  AND   sortest_tesc_code in ('A01','BAE','A02','BAM','A05','BAC')
                   and  sortest_pidm is not null  
                  GROUP BY sortest_pidm, sortest_tesc_code))
                  GROUP BY sortest_pidm;
                  

  Hello

  That depends on whether spriden_pidm is unique, and you want to get the results.

  Whenever you have a problem, post a small example of data (CREATE TABLE and INSERT, relevamnt columns only instructions) for all the tables and the results desired from these data.
  If you can illustrate your problem using tables commonly available (such as in the diagrams of scott or HR) so you need not display the sample data; right after the results you want.
  Whatever it is, explain how you get these results from these data.
  Always tell what version of Oracle you are using.

  Looks like you are doing something similar to the following.
  Using the tables emp and dept of the scott schema, producing a line of production by Department showing the highest salary for each job, for a set given jobs:

  DEPTNO DNAME          LOC           JOB_1   SAL_1 JOB_2   SAL_2 JOB_3   SAL_3
  ------ -------------- ------------- ------- ----- ------- ----- ------- -----
      20 RESEARCH       DALLAS        ANALYST  3000 MANAGER  2975 CLERK    1100
      10 ACCOUNTING     NEW YORK      MANAGER  2450 CLERK    1300
      30 SALES          CHICAGO       MANAGER  2850 CLERK     950
  

  On each line, jobs are listed in order by the highest salary.
  This seems to be similar to what you are doing. The roles played by the sortest_pidm, sortest_tesc_code and sortest_test_score in your table sortest are played by deptno, job and sal in the emp table. The roles played by the spriden_pidm, id and the name of your table spriden are played by deptno, dname and loc in the dept table.

  Looks like you already have something like the query below, which produces a correct output, except that it does not include the dname and loc of the dept table columns.

  SELECT    deptno
  ,       MAX (DECODE (rn, 1, job))     AS job_1
  ,       MAX (DECODE (rn, 1, max_sal))     AS sal_1
  ,       MAX (DECODE (rn, 2, job))     AS job_2
  ,       MAX (DECODE (rn, 2, max_sal))     AS sal_2
  ,       MAX (DECODE (rn, 3, job))     AS job_3
  ,       MAX (DECODE (rn, 3, max_sal))     AS sal_3
  FROM       (
             SELECT    deptno
             ,          job
             ,          max_sal
             ,          ROW_NUMBER () OVER ( PARTITION BY  deptno
                                            ORDER BY          max_sal     DESC
                              )         AS rn
             FROM     (
                           SELECT    e.deptno
                     ,           e.job
                     ,           MAX (e.sal)     AS max_sal
                     FROM      scott.emp        e
                     ,           scott.dept   d
                     WHERE     e.deptno        = d.deptno
                     AND           e.job        IN ('ANALYST', 'CLERK', 'MANAGER')
                     GROUP BY  e.deptno
                     ,           e.job
                       )
         )
  GROUP BY  deptno
  ;
  

  Dept.DeptNo is unique, it won't be a dname and a loc for each deptno, so we can modify the query by replacing "deptno" with "deptno, dname, loc" throughout the query (except in the join condition, of course):

  SELECT    deptno, dname, loc                    -- Changed
  ,       MAX (DECODE (rn, 1, job))     AS job_1
  ,       MAX (DECODE (rn, 1, max_sal))     AS sal_1
  ,       MAX (DECODE (rn, 2, job))     AS job_2
  ,       MAX (DECODE (rn, 2, max_sal))     AS sal_2
  ,       MAX (DECODE (rn, 3, job))     AS job_3
  ,       MAX (DECODE (rn, 3, max_sal))     AS sal_3
  FROM       (
             SELECT    deptno, dname, loc          -- Changed
             ,          job
             ,          max_sal
             ,          ROW_NUMBER () OVER ( PARTITION BY  deptno      -- , dname, loc     -- Changed
                                            ORDER BY          max_sal      DESC
                              )         AS rn
             FROM     (
                           SELECT    e.deptno, d.dname, d.loc                    -- Changed
                     ,           e.job
                     ,           MAX (e.sal)     AS max_sal
                     FROM      scott.emp        e
                     ,           scott.dept   d
                     WHERE     e.deptno        = d.deptno
                     AND           e.job        IN ('ANALYST', 'CLERK', 'MANAGER')
                     GROUP BY  e.deptno, d.dname, d.loc                    -- Changed
                     ,           e.job
                       )
         )
  GROUP BY  deptno, dname, loc                    -- Changed
  ;
  

  In fact, you can continue to use just deptno in the analytical PARTITION BY clause. It may be slightly more efficient to just use deptno, as I did above, but it won't change the results if you use all 3, if there is only 1 danme and 1 loc by deptno.

  Moreover, you don't need so many subqueries. You use the internal subquery to calculate the MAX and the outer subquery to calculate rn. Analytical functions are calculated after global fucntions so you can do both in the same auxiliary request like this:

  SELECT    deptno, dname, loc
  ,       MAX (DECODE (rn, 1, job))     AS job_1
  ,       MAX (DECODE (rn, 1, max_sal))     AS sal_1
  ,       MAX (DECODE (rn, 2, job))     AS job_2
  ,       MAX (DECODE (rn, 2, max_sal))     AS sal_2
  ,       MAX (DECODE (rn, 3, job))     AS job_3
  ,       MAX (DECODE (rn, 3, max_sal))     AS sal_3
  FROM       (
                 SELECT    e.deptno, d.dname, d.loc
            ,       e.job
            ,       MAX (e.sal)     AS max_sal
            ,       ROW_NUMBER () OVER ( PARTITION BY  e.deptno
                                         ORDER BY       MAX (sal)     DESC
                                        )       AS rn
            FROM      scott.emp    e
            ,       scott.dept   d
            WHERE     e.deptno        = d.deptno
            AND       e.job                IN ('ANALYST', 'CLERK', 'MANAGER')
                GROUP BY  e.deptno, d.dname, d.loc
            ,       e.job
         )
  GROUP BY  deptno, dname, loc
  ;
  

  It will work in Oracle 8.1 or more. In Oracle 11, however, it is better to use the SELECT... Function PIVOT.

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