How to assign the temporary tablespace to a table

temporary tablespace can be attributed to the user.

Tags: Database

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How to rename the temporary tablespace group name

How to rename the temporary tablespace group name? I have to remove all the temporary tablespace under the Group and then re-create the temporary tablespace again.
EBS r12.1.1
Database 11.0.1.7
Please see any id doc.
concerning
pritesh Rodriguez

Thanks for your update. I have solved my problem by creating a new group and add temporary tablespace to new goup.

concerning

pritesh Rodriguez

How to reduce the UNDO Tablespace
Hello
We had an UNDO Tablespace to 22 GB but it's using just 2GB. How to shrink the undo tablespace. We use the database in production cluster 3 node 10.2.0.4
Is there is way we can worry about UNDO Tablespace or should I create an UNDO tablespace and assign the undo tablespace to DB and let fall the old CANCEL?
How to ensure that the transactions are done and free to abandon the old CANCEL?
That's what we must restart all three nodes each node has its own UNDO Tablespace.

Need help on this issue.

would appreciate your quick response.

Thank you
No you have not.

concerning
Mohamed

Who fills the temporary tablespace?
Hello

a small question. How can I select which / what statement fills the temporary tablespace?

Thank you!
Hello

Check the sessions that are connect to DB, which is to use the temporary tablespace

Select *.
session $ v
where in saddr (select session_addr
v $ tempseg_usage v
where v.tablespace = 'TEMP')

You can query the v$ sort_segment, v$ sort_usage and v$ tempeg_usage know for the temp tablespace.

-Pavan Kumar N

How to assign the next value in the sequence directly in a variable?

How to assign the next value in the sequence directly in a variable without using a table TWICE in PL/SQL.

BluShadow wrote:

How about a quick test on 11g, just to see if you directly select a sequence in a variable is significantly better than the mark of DOUBLE.

...

Nope... no obvious difference.

This is because there is none: Oracle's SELECT sequence. NEXTVAL FROM DUAL under the covers. The direct assignment is just a convenient encoding for us, but it does not change the work that accomplishes Oracle.
```
create sequence s;
alter system flush shared_pool;
declare
l_num number;
begin
l_num := s.nextval;
end;
/
select sql_text from v$sql where parsing_schema_name = user;
```
SQL_TEXT

Report the number of l_num; begin l_num: = s.nextval; end;

Select sql_text from v$ sql where parsing_schema_name = user

Select double S.NEXTVAL

The loss of the temporary tablespace planted the Instance?
DB version: 10 gr 2 and higher

The loss of the temporary tablespace planted the DB. A database can survive without sorting and Index - rebuilt (main uses of the Temp tablespace). Right?
sb92075 wrote:
Handle: J.Kiechle
Status level: Beginner
Join date: January 21, 2008
Messages total: 129
Total issues: 22 (16 pending)
many questions and so few answers.
:-(

What this has to do with Sb?

Results complete post of
SELECT * from version of v$.

OP mentioned 10 gr 2 and higher. But otherwise too, it won't really matter as this seems to be a generic question IMO. The only difference version that would leave 10 g, restart the db would make the temporary tablespace once again, that's all!

Aman...

How to add the new column in existing table to our desired location?

How to add the new column in existing table to our desired location?
For example, I have to add the new column 'course' before the salary column in the emp table.

I think the best way is to add the column at the end of the table and create a new view with the order of the columns...

Another option...

places the data into a temporary table and recreate the table with the correct order of the columns, and then insert data to the table from the temporary table

Refer

Add column (from table) in the desired position

Example:

CREATE TABLE temp_my_user LIKE)

SELECT * FROM password);

DROP TABLE password;

(Password) CREATE TABLE

userID NUMBER

, first name VARCAHR2 (25)

, middleInitial VARCHAR2 (1)

(, name VARCHAR2 (25));

INSERT INTO password (userID, firstName, lastName)

(SELECT username

first name

lastName

OF temp_my_user);

DROP TABLE temp_user;

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Hi

Yep, use Index Array as Gerd says. Also, using the context help ( + h) and looking through the array palette will help you get an understanding of what each VI does.

This is fundamental LabVIEW stuff, perhaps you'd be better spending some time going through the basics.

-CC

SQL_TEXT
Report the number of l_num; begin l_num: = s.nextval; end;
Select sql_text from v$ sql where parsing_schema_name = user
Select double S.NEXTVAL

How to find the child level for each table in a relational model?

Earthlings,

I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.

So: How to find the child level for each table in a relational model?

I have a database of relacional (9.2), all right?

.
     O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
    /↑\ Fks
   O"O O" <-- level 2 for first table (circle)
  /↑\ Fks
"o"o"o" <-- level 1 for middle table (circle)
   ↑ Fk
  "º"

Tips:
-Each circle represents a table;
-Red no tables have foreign key
-the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.

I started to think about the following:

First of all, I need to know how to take the kids:

select distinct child.table_name child
  from all_cons_columns father
  join all_cons_columns child
 using (owner, position)
  join (select child.owner,
               child.constraint_name fk,
               child.table_name child,
               child.r_constraint_name pk,
               father.table_name father
          from all_constraints father, all_constraints child
         where child.r_owner = father.owner
           and child.r_constraint_name = father.constraint_name
           and father.constraint_type in ('P', 'U')
           and child.constraint_type = 'R'
           and child.owner = 'OWNER') aux
 using (owner)
 where child.constraint_name = aux.fk
   and child.table_name = aux.child
   and father.constraint_name = aux.pk
   and father.table_name = aux.father;

Thought...
We will share!

Thanks in advance,
Philips

Published by: BluShadow on April 1st, 2011 15:08
formatting of code and hierarchy for readbility

Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

SQL> create table my_emp (
  2    emp_id number primary key,
  3    emp_name varchar2(10),
  4    manager_id number
  5  );

Table created.

SQL> ed
Wrote file afiedt.buf

  1  create table my_mgr (
  2    manager_id number primary key,
  3    employee_id number references my_emp( emp_id ),
  4    purchasing_authority number
  5* )
SQL> /

Table created.

SQL> alter table my_emp
  2    add constraint fk_emp_mgr foreign key( manager_id )
  3         references my_mgr( manager_id );

Table altered.

SQL> ed
Wrote file afiedt.buf

  1   select level lvl,
  2          child_table_name,
  3          sys_connect_by_path( child_table_name, '/' ) path
  4     from (select parent.table_name      parent_table_name,
  5                  parent.constraint_name parent_constraint_name,
  6                  child.table_name        child_table_name,
  7                  child.constraint_name   child_constraint_name
  8             from user_constraints parent,
  9                  user_constraints child
 10            where child.constraint_type = 'R'
 11              and parent.constraint_type = 'P'
 12              and child.r_constraint_name = parent.constraint_name
 13           union all
 14           select null,
 15                  null,
 16                  table_name,
 17                  constraint_name
 18             from user_constraints
 19            where constraint_type = 'P')
 20    start with child_table_name = 'MY_EMP'
 21*  connect by prior child_table_name = parent_table_name
SQL> /
ERROR:
ORA-01436: CONNECT BY loop in user data

If you have a cycle, you have some problems.

(1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

SQL> ed
Wrote file afiedt.buf

  1   select level lvl,
  2          child_table_name,
  3          sys_connect_by_path( child_table_name, '/' ) path
  4     from (select parent.table_name      parent_table_name,
  5                  parent.constraint_name parent_constraint_name,
  6                  child.table_name        child_table_name,
  7                  child.constraint_name   child_constraint_name
  8             from user_constraints parent,
  9                  user_constraints child
 10            where child.constraint_type = 'R'
 11              and parent.constraint_type = 'P'
 12              and child.r_constraint_name = parent.constraint_name
 13           union all
 14           select null,
 15                  null,
 16                  table_name,
 17                  constraint_name
 18             from user_constraints
 19            where constraint_type = 'P')
 20    start with child_table_name = 'MY_EMP'
 21*  connect by nocycle prior child_table_name = parent_table_name
SQL> /

       LVL CHILD_TABLE_NAME               PATH
---------- ------------------------------ --------------------
         1 MY_EMP                         /MY_EMP
         2 MY_MGR                         /MY_EMP/MY_MGR
         1 MY_EMP                         /MY_EMP
         2 MY_MGR                         /MY_EMP/MY_MGR

(2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

-Generate the DDL for all tables without constraint
-Can generate the DDL for all primary key constraints
-Can generate the DDL for all unique key constraints
-Can generate the DDL for all foreign key constraints

This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

Justin

How to recover the second line of a table
Hello

Could someone let me know how to recover the second line of a table without using the coumn the names of columns in the table.

By default the table EMP or used in the case of scott connection can be used as an example of table.

Concerning
```
select e.* from(
select e.*,  rownum rn from emp e)e
where e.rn =2
```
did you expect that?

T440p how to assign the new function to a certain key?

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Try KeyTweak (re) Mapper tool or the same.

How to assign the TAB sequence?

Hey...

Can someone tell me how to assign tab...? I mean if I have a few buttons and controls on the front panel are trying to view the login Panel; whenever I press TAB on the keyboard, I want that the selection of buttons & controls should be in order... Can someone tell me how...?

See the order of Edit\Tabbing, and with the right button on the control of Navigation Advanced\Key

See you soon!

When I do exp (expdp), why use the temporary tablespace?

Dear
Imp (impdp) is using temporary tablespace.
but I'm not using tablespace temp, while exp (expdp) is running.
I think that exp (expdp) will not use temporary tablespace. is it not?
Please let me know?

He could. It must run queries on the data dictionary. Some of these applications may require the temp tablespace.

Hemant K Collette

How to assign the value to the application-level element

Hello
I'm learning to APEX. I use version 4.2.6.
My question is, I set a text field called 'FINANCIAL_YEAR' in the login page. I wanted to know how to assign this value to a text element of Application level (on page sent), so that I can get this value through at my request.
Thank you
-Anand

anand_gp wrote:

Yes, I created a 'text area' under 'HTML' in the 'Home' page Who accepts the exercise of a table through LOV. I intend to assign this value to a global variable so that this variable can be read in any of the application to filter the result set from different tables (not yet built the rest of the application). To do this, I was intending to use "Shared components"-> "Elements of Application". I'm still not quite sure how it works.

Start by reading the documentation on elements of application.

Go to the shared components > Application parts and create your G_FINANCIAL_YEAR item. Value Session State Protection Restricted - can not be set the browser so that the value is not editable by the user, falsification of URLS or scripts.

On the home page, if there is not already a button to submit the value of the fiscal year, add one in the HTML area, with the Action as a submit Pageclick. Otherwise, you can do without the button and using submit Page in Page Action when the changed value select the parameter in the list so he can undergo.

Then, in the section of the Page processing, create a calculation:

Point Type: Application-level element

Calculate Item: Application: G_FINANCIAL_YEAR

Point calculation: After submit

Type of calculation: Value of the element

Calculation:

Run the application, select a value in the list of the fiscal year and submit the page. Review of current session state in the viewer of session state by clicking on the link of Session in the toolbar developer. Select the Elements of Application in the view list, and then click set. The element of your application and its current value must be visible. You can now reference value throughout your application by using the appropriate syntax.

You should also consider if a default value (for example the current year) using a calculation Application from the point of calculation on the new Instance and coordinate the application point and part of the homepage using point application as the Source of value or an expression with Source page element, the value always, replacement of value that exists in the session state.

How to assign the different VTEP subnet for each grid of a group pool?

The design guide NSX to use L3 access design, it is recommended to use the same number VLAN per rack, but with the other subnet
10.66. < id rack >.0
10.77. < id rack >.0
10.88 < id rack >.0
10.99 < id rack >.0
If the client compute cluster spread on grids, then we will have a different subnet for each rack VTEP, something like (assuming that vlan 77 is for VTEP0
< rack 1 > 10.77.1.1, 10.77.1.2, 10.77.1.3...
< rack 2 > 10.77.2.1, 10.77.2.2, 10.77.2.3...
During the preparation of the host, GUI invites you to assign VTEP for Pool DHCP/IP, looks like most of the cases we use Pool of IP, then for the compute cluster, how can assign us VTEP IP in a different subnet in a single group?
Thank you
Clarisse

You have two options:

(1) DHCP using support on every TOR address suggest you. This is the recommended approach

(2) DHCP then changing manually the VMkernel interface IP address on each ESXi host to match the required subnet - this is not recommended because it is not automatic, but is still supported

How to assign the temporary tablespace to a table

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