How to block a select statement for a table of the specified until validation line

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  kglad wrote:

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  assign x 0, y0 etc. to match the 5 positions of your weapons.

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  ! http://communities.VMware.com/images/emoticons/sad.gif !

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  Outtime date Late_hrs var
  
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  Date of Attend_date
  
  
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  Thanks in advance
  
  Concerning
  
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  Kind regards

  Manu.

  If my answer or the answer to another person has been useful or appropriate, please mark accordingly

• Add more than 2 lines for a select statement without inserting rows in the base table

  Hi all
  
  I have a below a simple select statement that is querying a table.
  
  Select * from STUDY_SCHED_INTERVAL_TEMP
  where STUDY_KEY = 1063;
  
  but here's the situation. As you can see its return 7 ranks. But I must add
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  end at study_end_Date...
  
  
  
  IS IT STILL POSSIBLE WITHOUT INSERT ROWS IN THE TABLE AND PLAYIHY ALL AROUND WITH
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  Published by: S2K on August 13, 2009 14:19

  Well, I don't know if this request is as beautiful as my lawn, but seems to work even when ;)
  I used the "simplified" version, but the principle should work for your table, S2K.
  As Frank has already pointed out (and I fell on it while clunging): simply select your already existing lines and union them with the 'missing documents', you calculate the number of days that you are "missing" based on the study_end_date:

  MHO%xe> alter session set nls_date_language='AMERICAN';
  
  Sessie is gewijzigd.
  
  Verstreken: 00:00:00.01
  MHO%xe> with t as ( -- generating your data here, simplified by me due to cat and lawn
    2  select 1063 study_key
    3  ,      to_date('01-MAR-09', 'dd-mon-rr') phase_start_date
    4  ,      to_date('02-MAR-09', 'dd-mon-rr') measurement_date_taken
    5  ,      to_date('01-APR-09', 'dd-mon-rr') study_end_date
    6  from dual union all
    7  select 1063, to_date('03-MAR-09', 'dd-mon-rr') , to_date('04-MAR-09', 'dd-mon-rr') , to_date('01-APR-09', 'dd-mon-rr') from dual union all
    8  select 1063, to_date('03-MAR-09', 'dd-mon-rr') , to_date('09-MAR-09', 'dd-mon-rr') , to_date('01-APR-09', 'dd-mon-rr') from dual union all
    9  select 1063, to_date('03-MAR-09', 'dd-mon-rr') , to_date('14-MAR-09', 'dd-mon-rr') , to_date('01-APR-09', 'dd-mon-rr') from dual union all
   10  select 1063, to_date('03-MAR-09', 'dd-mon-rr') , to_date('19-MAR-09', 'dd-mon-rr') , to_date('01-APR-09', 'dd-mon-rr') from dual union all
   11  select 1063, to_date('22-MAR-09', 'dd-mon-rr') , to_date('23-MAR-09', 'dd-mon-rr') , to_date('01-APR-09', 'dd-mon-rr') from dual union all
   12  select 1063, to_date('22-MAR-09', 'dd-mon-rr') , to_date('30-MAR-09', 'dd-mon-rr') , to_date('01-APR-09', 'dd-mon-rr') from dual
   13  ) -- actual query:
   14  select study_key
   15  ,      phase_start_date
   16  ,      measurement_date_taken
   17  ,      study_end_date
   18  from   t
   19  union all
   20  select study_key
   21  ,      phase_start_date
   22  ,      measurement_date_taken + level -- or rownum
   23  ,      study_end_date
   24  from ( select study_key
   25         ,      phase_start_date
   26         ,      measurement_date_taken
   27         ,      study_end_date
   28         ,      add_up
   29         from (
   30                select study_key
   31                ,      phase_start_date
   32                ,      measurement_date_taken
   33                ,      study_end_date
   34                ,      study_end_date - max(measurement_date_taken) over (partition by study_key
   35                                                                          order by measurement_date_taken ) add_up
   36                ,      lead(measurement_date_taken) over (partition by study_key
   37                                                          order by measurement_date_taken ) last_rec
   38                from   t
   39              )
   40         where last_rec is null
   41       )
   42  where rownum <= add_up
   43  connect by level <= add_up;
  
   STUDY_KEY PHASE_START_DATE    MEASUREMENT_DATE_TA STUDY_END_DATE
  ---------- ------------------- ------------------- -------------------
        1063 01-03-2009 00:00:00 02-03-2009 00:00:00 01-04-2009 00:00:00
        1063 03-03-2009 00:00:00 04-03-2009 00:00:00 01-04-2009 00:00:00
        1063 03-03-2009 00:00:00 09-03-2009 00:00:00 01-04-2009 00:00:00
        1063 03-03-2009 00:00:00 14-03-2009 00:00:00 01-04-2009 00:00:00
        1063 03-03-2009 00:00:00 19-03-2009 00:00:00 01-04-2009 00:00:00
        1063 22-03-2009 00:00:00 23-03-2009 00:00:00 01-04-2009 00:00:00
        1063 22-03-2009 00:00:00 30-03-2009 00:00:00 01-04-2009 00:00:00
        1063 22-03-2009 00:00:00 31-03-2009 00:00:00 01-04-2009 00:00:00
        1063 22-03-2009 00:00:00 01-04-2009 00:00:00 01-04-2009 00:00:00
  
  9 rijen zijn geselecteerd.
  

  Is there a simpler way (in SQL), I hope that others join, and share their ideas/example/thoughts.
  I feel that it is using more resources there.
  But I have to cut the daisies before now, they interfere my 'grass-green-ess";)

• How to INSERT a SELECT statement with a GROUP BY clause on a table with an IDENTITY column?

  n an application, I intend to truncate and insertion on a 12 c Oracle database, but have found this problem with a IDENTITY column. Even if the INSERT... SELECT statement works on most SELECT uses I tried, if this statement was also a GROUP BY clause, it does not work, delivering a "ORA-00979: not a GROUP BY expression ' complaint. Some examples of code:

  create table aux ( owner_name varchar2(20), pet varchar2(20) );  
  insert into aux values ('Scott', 'dog'); 
  insert into aux values ('Mike', 'dog'); 
  insert into aux values ('Mike', 'cat'); 
  insert into aux values ('John', 'turtle');  
  
  
  create table T1 (
    id number generated always as identity,
    owner_name varchar2(20),
    pet_count number ); 
  select owner_name, count(*) as pet_count from aux group by owner_name; -- works just fine
  insert into T1 (owner_name, pet_count) select owner_name, count(*) as pet_count from aux group by owner_name; -- doesn't work
  

  The select statement works by itself, but it fails as an INSERT... SELECT statement.

  Appreciate the help!

  Looks like a bug. You must open the SR with Oracle. Meanwhile, you could materialize select:

  SQL > insert into T1 (owner_name, pet_count)
  2 with t as (select / * + materialize * / owner_name, count (*) as pet_count to the owner_name group)
  3. Select owner_name, pet_count t
  4.

  3 lines were created.

  SQL > select * from t1;

  ID OWNER_NAME PET_COUNT
  ---------- -------------------- ----------
  1 John                          1
  Scott 2 1
  3 Mike                          2

  SQL >

  Keep in mind index THAT MATERIALIZE is undocumented.

  SY.

• How to write a select statement in which the condition?

  Hello Frs,
  
  Need help in the development of a discoverer report.
  
  My requirement is to write a query similar to this one
  
  Select * from emp is dept_no not in (select Department dept_no where emp_name like ' a % ;))
  
  Help, please.
  
  
  Thank you
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  Hello
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