How to convert a negative "signed short int" in a picture of two "tank"?
Hello
I'm having difficulties to convert a signed short int (2 byte) in an array of two characters.
My current test is like this:
void ConvertShortIntToByteArray(short int value){ unsigned char byteHi = 0x00; // High Byte of result unsigned char byteLo =0x00; // Low Byte of result unsigned char C1 = 0x00; unsigned char C2 = 0x00; unsigned char C3 = 0x00; unsigned char C4 = 0x00; short int tempValue = 0; C4 = value % 16; tempValue = value / 16; C3 = tempValue % 16; tempValue /= 16; C2 = tempValue % 16; tempValue /= 16; C1 = tempValue % 16; byteHi = C1 << 4; byteHi += C2; byteLo = C3 << 4; byteLo += C4;}
It works OK for positive values (for example say that 240 = 0 x 00 F0) but negative values don't work here.
Is there a way to convert signed short int values to an array of two bytes of an easier way?
I know that common sense would be to go over binary like this:
Assume value = -240: So abs(-240) = 240 = 00 F0 = 0000 0000 1111 0000 One-Complement:1111 1111 0000 1111 Add '1' to the One-Complement: 1111 1111 0000 1111+0000 0000 0000 0001 ------------------- 1111 1111 0001 0000 Result = 1111 1111 0001 0000 = FF 10 = -240
But is there an easier way that doesn't have to go to binary to achieve?
Any help is greatly appreciated.
Thank you and best regards,
Bernd
If you want to just let C do its thing:
void ConvertShortIntToByteArray(short int value) { unsigned char byteHi = value >> 8; // High Byte of result unsigned char byteLo = value; // Low Byte of result }
Or maybe a little more understandable:
void ConvertShortIntToByteArray(short int value) { unsigned char byteHi = (value >> 8) & 0xff; // High Byte of result unsigned char byteLo = value & 0xff; // Low Byte of result }
Tags: NI Software
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