How to convert date to number
HaiHow to convert the date as a number.
Thanks and greetings
srikkanth. M
Look at these messages
Please help me in converting Format of Lilian date
converstion to date
and try something like that.
SELECT sysdate,sysdate-to_date('15-10-1582','DD-MM-YYYY') lilian_dt FROM dual;
Tags: Database
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I also have more problems with that, when I change the throttle (0-100%) is does nothing and my time loop also doesn't stop more. This is just a small part of the full program, it's may be heavy for my computer? (core 1, 6 GHz, 1, 5gig of ram)
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You can change the type of dynamic data for the meter using the function of Double-precision float in the digital - Conversion scheme. For your other question, you are not showing your loop together so I can't help you there. What stops the loop?
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Follow
As long as you have Date column, you can use DB functions to convert them into months (just use the string SUBSTR to extract the month and the year).
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Mark correct or useful if this can help,
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Its ok people, I found a solution. See attached FYI.
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How to convert Datetime in number?
chg_date_time
40265.492
SELECT c.chg_date_time, TO_DATE('01011900','DDMMYYYY') + CHG_DATE_TIME OF CHNGHIST C
After that, run:
2010-03-30 11:48:29
In the above query, convert us number to datetime.
Now, I want to convert Datetime in number.
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NiharSimply activate your expression.
not tested
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I have a sql like this:
I want to display "3" instead of showing the Mar...select to_date('MAR','Mon', 'NLS_DATE_LANGUAGE=American') m from dual
I tried to use to_char(date,'MM'), but the result will return '03'.
I would like to have the output exactly equal to 3.
Thanks Bros.920575 wrote:
I have a sql like this:select to_date('MAR','Mon', 'NLS_DATE_LANGUAGE=American') m from dual
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"3" is a string. It isn't equalt to the string '03'.
Do you want a NUMBER or a string?If you want the chain of characters-1 '3', use 'FMMM"instead of"MM ".
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Srikkanth.MHi Ali,
Did you remove ':' in HH24MISS and checked?
Any specific error?
SQL> create table num 2 (n number); Table created. SQL> insert into num values(1); 1 row created. SQL> update num 2 set n = select to_number(to_char(to_date('00:00:00','HH24:MI:SS') 3 + 4 (sysdate-to_date('11-JAN-10')),'HH24MISS')) dt 5 from dual; set n = select to_number(to_char(to_date('00:00:00','HH24:MI:SS') * ERROR at line 2: ORA-00936: missing expression SQL> update num 2 set n = (select to_number(to_char(to_date('00:00:00','HH24:MI:SS') 3 + 4 (sysdate-to_date('11-JAN-10')),'HH24MISS')) dt 5 from dual); 1 row updated. SQL> select * from num; N ---------- 152429
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