How to convert string to number in TS?
Hello
Anyone know how to convert string to number in TS?
I couldn't find the Num() function.
Thank you
Val()
Tags: NI Software
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How to convert string to number
Hi everoyne, I need to make a program simple calculation of the GPA in 5 classes. Where A, B, C, D, F are the entries for each other...
Here's what I've done so far.
But it seems that it is not recognized when I assigns numeric values to each letter. So I would appreciate any help. I tested for the release of "GP" and input A (4) = CT. The answer for GP should be 4 x 3 = 12. But I get a number beyond that.
I'm relatively new to Labview so sorry if this is a stupid question.
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I would like to make a table of the clusters. Each element of the array corresponds to a single course. Inside of the bunch, I would have a string for the name of the course, an enum for the grade and a digital for the number of credit hours. Use an enum for the grade, so you can make sure that the user space only in the values that you no longer the enum is actually a number. No actual conversion. Then you just use a loop FOR (autoindexing) including some shift registers to keep your totals, then divide the totals of the year by the credit hours.
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How convert string to number
my character
Select form double to_number ('1,6,9,4'); my putting here 1,6,9,4
get the character of number conversion error.
concerning
Published by: vr on March 31, 2011 23:59
Published by: vr on March 31, 2011 23:59VR says:
Getting error while the conversion of character to the number in instring is possible to get the position of the channels at one timeI have the following table, called pack
Acct_No pack2 pack3 pack1
1000 10101011 111111101 01010101111Select * Pack
where instr (pack2, ' 1') and * (to_number (replace('1,6,9,4',','))); * - getting values of function as string '1,6,9,4'If you want to retrieve lines where the position of the first "1" in the pack2 chain is one of the positions in your list number e.g. position 1, 6, 9, or 4?
Something with regexp_like can help...
SQL> ed Wrote file afiedt.buf 1 with pack as (select '1000' as acct_no, '10101011' as pack1, '111111101' as pack2, '01010101111' as pack3 from dual union all 2 select '1001', '10101011', '000011111', '10101010110' from dual union all 3 select '1001', '10101011', '000000001', '10101010110' from dual) 4 -- 5 -- end of test data 6 -- 7 select pack.*, case when regexp_like('1,6,9,4','(^|,)'||to_char(instr(pack2,'1'),'fm9999')||'(,|$)') then 'Yes' else 'No' end as x 8* from pack SQL> / ACCT PACK1 PACK2 PACK3 X ---- -------- --------- ----------- --- 1000 10101011 111111101 01010101111 Yes 1001 10101011 000011111 10101010110 No 1001 10101011 000000001 10101010110 Yes
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There are multiple ways. I will list down few of them.
With the help of the old solution and standard java.
public
static
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public
static
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Hello
As far as I know, the values read from the database is a type of Sting. Now, I want to convert a character number stored in the database of type int.
For example, in "Test.csv" I stored the '9' in the column 'Number' character, then I use the following code to read the character and convert an int in one:
getDatabank("Test").getNextDatabankRecord ();
String Testnumber = "{{db." Test.Numberr}} '; Info (Testnumber);
int number = Integer.parseInt (Testnumber);
However, it seems this does not work, because he says "basic unexpected failure caused by: NumberFormatException occurred." For the input string: «{{db.» Test.Numberr}}.
I think that this error can be caused by the conversion of character '9' int 9.
Can someone tell me how to convert a character to be read from database in an int?
Thank you very much!
Kind regards
AngyoungHello
You can use the same approach. Use eval()
getDatabank("Test").getNextDatabankRecord(); String Testnumber =eval("{{db.Test.Numberr}}") ; info(Testnumber); int number = Integer.parseInt(Testnumber);
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Hello ,
I one variable with the string value " 12 5 , I need to convert to decimal number and kept sound. "
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Non; in fact, the majority of programming languages are hardcoded to the American conventions. But the charge to replace it if necessary is tiny.
You might have a similar problem, if someone enters a number of thousands separators: '12.500,0' If you replace the comma with a period, "parseFloat ("12.500.00")" Fortunately will read the number, all the way to the next ' invalid' character, which corresponds to the second period. And then he'll "12.5"...
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I have a question which is:
How to convert a string that we get by reading an XML in the instance of date value type?
So there is a XML that modifiedDate as an attribute on a node of the XML and how I put this value in an instance variable date?
the timeformat in the XML file is: mm/dd/yyyy hh: mm: = > 31/12/2010 23:57:46
I chose this time format because I want to use the method . parse() which always causes an error, but that's another topic...,.
hope I was clear on the issue,
Thanks in advance for the help.
First of all, you should watch the Date object constructor to find out how to specify different parameters.
public void Date (yearOrTimevalue:Object, month:number, date:number = 1, hour:number = 0, minute:number = 0, second:number = 0, millisecond:number = 0)
Then you need to determne how to break the string by using the String.Split method. The first split() should be the space between the date and time, the second for the slashes in the date and the third for the colon in time.
Then you come to take each of these paintings of substrings and feed them in the constructor as the Number() values.
If you remain unsure how to do this, look at the different terms that I have identified in the help documents and you will find them all explained with examples.
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How to convert a large number to the spell without truncate to 32-bit.
I'm trying to convert a hexadecimal number (string). The number is truncated to 32 bits, which is not what I want. For example, the number 28037546508295 (double) must be 0 x 198000000007. LabVIEW truncates and the resulting string is 0x7FFFFFFF, using number of Hex String.vi. I'm stuck. Thank you.
'Number of hexadecimal string' accepts only data of I32. So, you should see a red dot of coercion when you connect your floating point number.
You must use "Format of value" (also in the String > number of rope/coercion-pallet) and use '%x' as a format string.
hope this helps,
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Hai
How to convert the date as a number.
Thanks and greetings
srikkanth. MLook at these messages
Please help me in converting Format of Lilian date
converstion to date
and try something like that.SELECT sysdate,sysdate-to_date('15-10-1582','DD-MM-YYYY') lilian_dt FROM dual;
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How to convert Datetime in number?
chg_date_time
40265.492
SELECT c.chg_date_time, TO_DATE('01011900','DDMMYYYY') + CHG_DATE_TIME OF CHNGHIST C
After that, run:
2010-03-30 11:48:29
In the above query, convert us number to datetime.
Now, I want to convert Datetime in number.
i.e., 03-30-2010 11:48:29 =? (40265.492)
Thank you
NiharSimply activate your expression.
not tested
SELECT to_date('30/03/2010 11:48:29','dd/mm/yyyy HH24:mi:ss')-TO_DATE('01011900','DDMMYYYY') FROM dual;
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How to convert string to numeric number
I have a list of dollar amounts which amounted to on a cfloop and the query:
< cfset FileCount = 0 >
< cfset FileDollar = 0 >
< cfloop query = "TxtQuery" >
< cfset FileDollar = #FileDollar # + "#Payment_Amt #" >
< / cfloop >
Here's the data (entry in the first column, payment_amt, combined with the title of the FileDollar column):
Payment_amt (Text) FileDollar
14645791.820 14645791.82
5302608003.600 5317253795.42
405642.240 5317659437.66
11354914264.600 6672573702.3
1532528.280 16674106230.5
1532528.280 16675638758.8
1532528.280 16677171287.1
1532528.280 16678703815.4
16470800280.000 33149504095.4
It seems that once it hits the entrance of 11354914264.600 payment_amt, the FileDollar two decimal one.
Is it possible to convert the numeric text field before it gets totaled?Thanks for the help. I eliminated the cfloop to add fields payment_amt and replaced by a Q Q (as you recommended) using a cast statement.
SELECT SUM (CAST (Payment_amt AS decimal)) AS TOTAL_AMT
to TxtQuery
The TOTAL_AMT has correct total field now and is in decimal format.
Thanks again for your help!
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How to convert string data from the serial port to double?
Hello!
I am very new in LabView and attempt to read data from an OHAUS pioneer pa-313 electronic scale via RS232 serial port. I use the VISA. I can read the data and see it as a string to the screen, but when I try to convert it to a double, it is just the integer and decimal numbers have disappeared. Here's the question: what can be the problem? How can I get the decimals as well?
What is your normal decimal point?. or?
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How to convert string to datetime in the transformation of the Ombudsman
Hello
I am getting error below when inserting the data in the database using the database.
Exception occurred when the link was invoked. Exception occurred during invocation of the JCA binding: "JCA binding run reference"insert"operations have to: DBWriteInteractionSpec Execute Failed Exception." insertion failed. The descriptor name: [InsertPayload.XxohInsertStgTable]. Created by Exception [EclipseLink-3001] (Eclipse - 2.3.1.v20111018 persistence Services - r10243): org.eclipse.persistence.exceptions.ConversionException Description of the Exception: object [2015-09-14 15:19:51], class [class java.lang.String], couldn't be converted [class java.sql.Timestamp]. Inner exception: LINK. JCA-11636 couldn't convert Timestamp Exception. Cannot convert a string value in the xml file to a java.sql.Timestamp. Although the databases accept strings representing the timestamps in a variety of formats, the adapter only accepts strings that represent xml ISO dateTime format. The input value must be in the format XS: DateTime to iso 8601, i.e. YYYY-MM - DDTHH:MM:SS.sss - 07:00. Please see the logs
In the transformation of the mediator, the Source element is a string
< xs: element name = "CREATED_DATE" type = "xs: String" > < / xs: element >
Target is of type dateTime
< xs: element name = "Creation_Date" type = "xs: DateTime" minOccurs = "0" nillable = "true" / >
To avoid the above error, I used < xsl: value-of select ='xp20:format - dateTime (/CREATED_DATE, "[Y0001]-[M01]-[D01] [H01]: [m01]: [s01]")'/ > in the transformation, but its does not work. The value is blank display after processing.
Please suggest me how to solve this problem.
Thank you
Sunita
Unfortunately, the format required by the dateTime format is YYYY-MM - DDTHH:MM:SS.sss
You can use the substring, and on the entry's concat function to create YYYY-MM - DDTHH:MM:SS.sss
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How to convert string to [AVLayer]
Hello world.
I have this code:
var myComp = "app.project.activeItem"; var text = '.layer("4").effect("Unsharp Mask")("Amount")'; var myLayer = myComp+text; alert(myLayer.value) // doesn`t work
How can I convert to string (myLayer) [AVLayer] object to get its property?
This should help you closer:
myComp = "app.project.activeItem"; var
var myText = ".layer("4").effect (" unsharp mask ")("Amount").value";
var myVal = eval (myComp + myText);
Alert (myVal);
Dan
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reclassification how to convert string into array
Hi all
I do the code
CREATE OR REPLACE
TYPE 'SAMPLE '. "" SAMPLETABLETYPEVAR ".
PLS-00311:
but I got to l_data error how can I solve
/***************************************************************/
declare
l_str DEFAULT LONG ' pankaj/dukare /';
l_n NUMBER;
SAMPLETABLETYPEVAR l_data: = SAMPLETABLETYPEVAR ();
BEGIN
LOOP
l_n: = INSTR (l_str, "/");
WHEN the OUTPUT (NVL (l_n, 0) = 0);
l_data. EXTEND;
l_data (l_data. (COUNTY): = LTRIM (RTRIM (SUBSTR (l_str, 1, l_n - 1)));
l_str: = SUBSTR (l_str, l_n + 1);
END LOOP;
L_data RETURN;
END;
/********************************************************/
Published by: user9524857 on July 1st, 2009 23:36using your code:
SQL> select * 2 from table (sample_split_string ('this is a long string', ' ') 3 / COLUMN_VALUE --------------------------------------------------------------------- this is a long string
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