How to create the partition on a column in a table on a daily basis
Hi allI wrote a query that does not, I have a column of varchar type, and I want to create the partition of the table on that column based daily interval. but ist is in error...
my query is...
create the table user_detail
(username varchar2 (50))
The user ID number,
country varchar2 (25).
accupation varchar2 (100),
company varchar2 (100),
joindate varchar2 (14))
partition by range (joindate)
INTERVAL (NUMTOYMINTERVAL (1, 'DAY'))
(PARTITION newone VALUES LESS THAN (to_date (April 13, 19 ', 'aa-mm-dd')));
error is:
Error from the 1 in the command line:
create the table user_detail
(username varchar2 (50))
The user ID number,
country varchar2 (25).
accupation varchar2 (100),
company varchar2 (100),
joindate varchar2 (14))
partition by range (joindate)
INTERVAL (NUMTOYMINTERVAL (1, 'DAY'))
(PARTITION newone VALUES LESS THAN (to_date (April 13, 19 ', 'aa-mm-dd')))
Error in the command line: 1 column: 0
Error report:
SQL error: ORA-14751: type of invalid data for the partitioning column of a partitioned table interval
Can I create partition on the varchar data type?
On ORA11gR1 it works:
--virtual column
CREATE TABLE TEST(joindate VARCHAR2(14), part_joindate AS (to_date(joindate,'dd.mm.yyyy'))) partition by range (part_joindate)
INTERVAL(NUMTOYMINTERVAL(1, 'YEAR'))
(PARTITION newone VALUES LESS THAN (to_date('2013-04-19', 'yyyy-mm-dd')))
;
INSERT INTO TEST(joindate) VALUES('19.04.2013');
SELECT * FROM TEST;
DROP TABLE TEST;
--aux column
CREATE TABLE TEST(joindate VARCHAR2(14), part_joindate AS (to_date(joindate,'dd.mm.yyyy'))) partition by range (part_joindate)
INTERVAL(NUMTOYMINTERVAL(1, 'YEAR'))
(PARTITION newone VALUES LESS THAN (to_date('2013-04-19', 'yyyy-mm-dd')))
;
INSERT INTO TEST(joindate) VALUES('19.04.2013');
SELECT * FROM TEST;
DROP TABLE TEST;
Published by: spajdy on April 19, 2013 14:58
Tags: Database
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