How to find the date of a table Max
Hello worldI have two tables in the database. I want to find the maximum routine for a case_id of the lock_date date between jan 20 to January 29, 2012.
But I don't get real output (output routine_date should be 'January 28, 2012' but I m getting "January 31, 2012" ")
Can someone help me where I made the mistake
Master
case_id lock_date
101 23 January 2012
101 January 24, 2012
102 27 January 2012
102 January 29, 2012
101 30 January 2012
101 January 29, 2012
Routine (for current work)
case_id routine_date
101 23 January 2012
103 28 January 2012
102 21 January 2012
102 January 29, 2012
101 21 January 2012
101 28 January 2012
101 31 January 2012
Select m.case_id, r.routine_date from master m, systematic r,
(case_id, max (routine_date) of the systematic group by selecting case_id) rr
where m.case_id = r.case_id
and m.case_id = rr.case_id
and r.routine_date = rr.routine_date
Hello
Here are average dradles:
WITH universe AS
(
SELECT m.case_id
, r.routine_date
, MAX (r.routine_date) OVER (PARTITION BY m.case_id)
AS max_routine_date
FROM master m
, routine r
WHERE m.case_id = r.case_id
AND m.lock_date >= TO_DATE ('20-Jan-2012', 'DD-Mon-YYYY')
AND m.lock_date < TO_DATE ('30-Jan-2012', 'DD-Mon-YYYY')
)
SELECT case_id
, routine_date
FROM universe
WHERE routine_date = max_routine_date
;
You only want to view rowss whose routine_date is the maximum date in a subset. First get this subset
If the universe of data that you are interested in is just the period from January 20 to January 29, then you can start by getting all the data in this range. This is what the above subquery universe.
Now, you want to see only the rows where routine_date is the max_routine_date within this universe, for each case_id. You can use the analytic MAX function to find out what this max_routine_date.
Published by: Frank Kulash, March 2, 2013 11:59
Tags: Database
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