How to find the delimiters

Hello Oracle experts

I am trying to find number of separators to a text string. But I could find only for the first record. Can you if it doesn't matter who you please let me know how to find the record2.

I use

Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production
With partitioning, OLAP, Data Mining and Real Application Testing options

Thank you



with t as
(select 3999 ^ 0077774 ^ Institution ^ Mountwest ^ 1 ^ Lilly ^ Maria ^ [email protected] ^ 555-555-5555 ^ 2 ^ Lilly ^ Maria ^ [email protected] ^ 999-999-9999 ^ 3 ^ Lilly ^ Maria ^ [email protected] ^ 777-888-1234 ^ 1 yyyy xxxxxx Drxxx ^ ^ xxxxxxx ^ AA ^ 99999 ^ MRO ^ U.S. ^ ^ ^ I do not know ^ 2 years ^ Public ^ applicable ^ Urban ^ 1, 000-4, 999 ^ N ^ Conference ^ N ^ 14/04/2009 10:52:51 ^ 24/08/2010 09:26:46 ^ Active ^ ^ I ^ ^' string1 from all the double union)
Select ' ^ ^ ^' double string1
)
Length (STRING1) - length (replace(STRING1,'^','')) SELECT delim_number from T

Try:

SELECT  length(STRING1)-NVL(length(replace(STRING1,'^','')),0) delim_number from T

Tags: Database

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