How to find the difference between standard edition and standard edition one

How to find the difference between oracle database standard edition and standard edition one 64 bit

(a) using sql
(b) using the configuration/installation files

How to find the difference between oracle database standard edition and standard edition one 64 bit

(a) using sql

Select * the option of $ v;

(b) using the configuration/installation files

opatch lsinventory-details

Tags: Database

Similar Questions

  • Find the difference between two date and time

    Hi friends,

    I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."

    select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
    from eval.EVAL_RUNTIME_DETAILS
    where trunc(start_date) = trunc(sysdate) 
    order by sql_step_num;

    You try to get the feel between two char strings.
    And more difference between two dates gives a NUMBER of days.
    Try this:

    select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
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  • How to find the difference between two dates in the presentation layer

    Hi gurus,

    Hello to everyone. Today, I came with the new requirement.


    I need to know the difference between a date and the current date in the formula column application presentation layer.by.



    Thank you and best regards,
    Prates

    Hi Navin,

    TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

    If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

    hope you understand...

    Award points and to close the debate, if your question is answered.

    See you soon,.
    Aravind

  • How to find the difference between two dates in time except Sunday

    Hi all

    I have a table, as shown below.
    SQL> select * from test;
    
    TR_ID                                              CREATE_TIME                                                                       CODE
    -------------------------------------------------- --------------------------------------------------------------------------- ----------
    S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
    S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
    S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
    S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
    S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
    S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
    S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
    S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002
    I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.

    For example:

    TR_ID: S12344
    1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
    1003_Create_time: 12.01.04.188000 AM 6 July 12

    1002 create time is 22:00 Sunday.

    If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.

    I tried the sub query after doing a search on this forum but I am not getting the desired output.
    SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
    ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
    from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
    WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');
    Need help to get the desired o/p

    Hello

    If I unederstand the problem correctly, that's what you want:

    WITH       got_extrema     AS
    (
         SELECT       tr_id
         ,       CAST (MIN (create_time) AS DATE)     AS start_date
         ,       CAST (MAX (create_time) AS DATE)     AS end_date
         FROM       test
         GROUP BY  tr_id
    )
    SELECT       tr_id
    ,       start_date, end_date          -- If wanted
    ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                        - TRUNC (start_date, 'IW')
                 )
               / -7
                  )
                + LEAST ( end_date               -- If end_date is a Sunday
                            , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                     )
                - CASE
                          WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                   THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                   ELSE  start_date
                      END
                )     AS total_hours
    FROM      got_extrema
    ;
    

    I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

    Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
    (a) 1 day is deducted for each week between start_date and end_date
    (b) if End_date is a Sunday, none of the end_date himself hours are counted
    (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

    TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

    Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
    Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
    Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
    Always tell what version of Oracle you are using.
    See the FAQ forum {message identifier: = 9360002}

  • How to find the difference between related areas

    Hi all
    My problem is I have a table in which each woman will be visited maximum 8 times, each woman may or may not
    given a reference in any visit which in turn women will respond to this referral in a next visit
    (not necessarily the next visit), I need to calculate the average number of visits between the visit
    in which the wife received a refferal and visit in which she responds.

    as an example

    woman_id visit_id given_referral respond_to_referral
    -------- -------- -------------- -------------------
    1 1 TRUE NULL
    1 2 TRUE TRUE
    1 3 TRUE NULL
    1 4 TRUE NULL
    1 5 NULL NULL
    1 6 TRUE NULL

    This means that visit 2 response is referral to visit 1 so the difference is 1.
    and the visit 6 response corresponds to the referral in visit 4 so the difference is 4.
    what I can't do is knowing how to know answer to visit 6 associated reference visit 4 No 1 or 2 or 3...

    and I need to find the following table of the foregoing

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    ---------          ---------------------------------------
    1                    1
    1                    2

    quick access to help please

    Published by: M.Jabr on December 14, 2009 08:05
    with t as (
               select 1 woman_id,1 visit_id,'TRUE' given_referral,NULL respond_to_referral from dual union all
               select 1,2,'TRUE','TRUE' from dual union all
               select 1,3,'TRUE',NULL from dual union all
               select 1,4,'TRUE',NULL from dual union all
               select 1,5,NULL,NULL from dual union all
               select 1,6,NULL,'TRUE' from dual
              )
    select  woman_id,
            diff
      from  (
             select  woman_id,
                     visit_id - last_value(case
                                             when given_referral is not null
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                                           end
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                                     order by visit_id
                                     rows between unbounded preceding and 1 preceding
                                    ) diff,
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    ---------- ----------
             1          1
             1          2
    
    SQL> 
    

    SY.

  • How to find the difference between the two timestamp columns

    Dear all,
    Please solve my problem,
    I have Table name of the folder that has the following columns,
    EmpID in the number column, timestamp dat
    who has the following values
    Expand | Select | Wrap | Line numbers
    EmpID dat
    ====== ====
    101 4/9/2012 09:48:54
    101 4/9/2012 09:36:28
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    101 4/10 / 2012 09:33:48
    101 4/10 / 2012 12:36:28
    101 4/10 / 2012 20:36:12
    101 4/11 / 2012 09:36:28
    101 4/11 / 2012 16:36:22
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    3 days different here is so it should return 3 discs with the mentioned columns above,
    Please help me find it.

    Thank you
    Kind regards
    Gurujothi

    Published by: Gurujothi on April 25, 2012 04:45

    Gurujothi wrote:
    Dear Alex,
    Thank you for your reply,
    Depending on whether you are your quesy showing it in hour and minutes format its right but you mention all rows of the query
    If the table has more than 3000 lines then how it is possible to write this much higher request,
    my table with almost 3500 lines.

    You can make a few changes in the above query I posted the last I mentioned?

    Thank you.

    Published by: Gurujothi on April 25, 2012 23:18

    Hello

    You don't need to write whole records 3000 it... alex just wrote that for example have no table as your table...
    so just use the under part of this query as in the previous post, alex:

    select empid, trunc(dat),
           min(dat) as start_dat,  to_char(min(dat), 'hh24:mi:ss') as start_dat_part,
           max(dat) as end_dat, to_char(max(dat), 'hh24:mi:ss') as end_dat_part,
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           || ':' ||  extract(hour from max(dat)-min(dat)) || ' hours'
           || ':' ||  extract(minute from max(dat)-min(dat)) || ' mins'
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    hope this fixes your need

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    Hello
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    962813 wrote:
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    *
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    30
    
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     14     dbms_output.put_line(c);
     15  end;
     16  /
    30
    
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