How to find the difference between two dates in the presentation layer

Hi gurus,

Hello to everyone. Today, I came with the new requirement.

I need to know the difference between a date and the current date in the formula column application presentation layer.by.

Thank you and best regards,
Prates

Hi Navin,

TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

hope you understand...

Award points and to close the debate, if your question is answered.

See you soon,.
Aravind

Tags: Business Intelligence

Similar Questions

Find the difference between two date and time

Hi friends,

I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."

select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
from eval.EVAL_RUNTIME_DETAILS
where trunc(start_date) = trunc(sysdate) 
order by sql_step_num;

You try to get the feel between two char strings.
And more difference between two dates gives a NUMBER of days.
Try this:

select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
from eval.EVAL_RUNTIME_DETAILS
where trunc(start_date) = trunc(sysdate)
order by sql_step_num;

How do the time difference between two dates?
Hi all

I use this query to get the time difference between two dates.

Select to_timestamp ('2012-10-03 12:00 ',' YYYY-MM-DD hh)-to_timestamp ('2012-10-03 11:00 ',' YYYY-MM-DD hh) as double diff;

but do not get the correct result.

Thank you
Left KEY... Left Padding of tanks.

difference between two dates in the year/month/day in Obiee

Hi gurus,
I know this question have been asked and answered several times but I have a requirement that is a little different, then the previous ones.
I want to calculate the difference between two dates in OBIEE10g in year/month/day format similar to the below SQL output
SQL > select end_date, start_date,
trunc (months_between (end_date, start_date) / 12) years.
months of mod (trunc (months_between (end_date, start_date)), 12).
End_date - add_months (start_date, trunc (months_between (end_date, start_date))) days
t
Thanks in advance
SK

Search for this

"TIMESTAMPDIFF IN THE FORM OF MTHS # YEARS."

or else

To get the current mandate of employees since the date of hiring in the form of # years # mths or # year (s) # month (s)

Concat (concat (cast (TIMESTAMPDIFF (SQL_TSI_Month, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) / 12 as char),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Month (s)'))

Concat (concat (CAST (TIMESTAMPDIFF (SQL_TSI_YEAR, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) as CHAR),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Mth (s)'))

Dynamic action - Get the difference between two dates + times
I have problems a little dynamic to work action. I'm trying to get the time between two dates with the time difference.

Here is what I got (this is apex 4.0):

Two date pickers + two numbers fields (date/start/end times)

I created a dynamic action on the page who fires on the point lose focus (above points).

The real action for the DA is the body of the PL/SQL function:
```
declare
  end_date DATE;
  start_date DATE;
Begin
  start_date := to_char(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MON-YYYY HH:MIAM');
  end_date := to_char(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MON-YYYY HH:MIAM');
  :P1_HOURS := end_date-start_date;
End;
```
When I change the values on the page, I get the following error:

AJAX call back Server error ORA-06502: PL/SQL: digital or value error: character number conversion error to set the value.

I'm guessing that there is a problem with the date formatting, but I can't make it work. Thanks in advance!
Hi djston,

because you chose the dynamic action of 'Set value' with the "Body of the PL/SQL function" type you need to return the value. Try the following code
```
declare
  end_date DATE;
  start_date DATE;
Begin
  start_date := to_date(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MM-YYYY HH:MIAM');
  end_date := to_date(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MM-YYYY HH:MIAM');
  RETURN (end_date-start_date)*24;
End;
```
and P1_REQUESTED_HOURS like 'item affected. "

Concerning
Patrick
-----------
My Blog: http://www.inside-oracle-apex.com
APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
Twitter: http://www.twitter.com/patrickwolf

Published by: Patrick Wolf on January 17, 2011 10:54

Difference between two data aquistion

Hello

I got a data aquistion system that is supposed to keep data acquisition selection until the difference between two points a lot. For example, I get voltage (mv) as 2.31, 2.32, 2.34. 2.33 2.32, 2.33 2.32. the data up to a point, say 0.1V higher or lower than the first. Thewhole procss stop. Thank you for your suggestions.

Try this... (Labview 8.2)

How to find the difference between two dates in time except Sunday

Hi all

I have a table, as shown below.

SQL> select * from test;

TR_ID                                              CREATE_TIME                                                                       CODE
-------------------------------------------------- --------------------------------------------------------------------------- ----------
S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.

For example:

TR_ID: S12344
1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
1003_Create_time: 12.01.04.188000 AM 6 July 12

1002 create time is 22:00 Sunday.

If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.

I tried the sub query after doing a search on this forum but I am not getting the desired output.

SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

Need help to get the desired o/p

Hello

If I unederstand the problem correctly, that's what you want:

WITH       got_extrema     AS
(
     SELECT       tr_id
     ,       CAST (MIN (create_time) AS DATE)     AS start_date
     ,       CAST (MAX (create_time) AS DATE)     AS end_date
     FROM       test
     GROUP BY  tr_id
)
SELECT       tr_id
,       start_date, end_date          -- If wanted
,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                    - TRUNC (start_date, 'IW')
             )
           / -7
              )
            + LEAST ( end_date               -- If end_date is a Sunday
                        , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                 )
            - CASE
                      WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
               THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
               ELSE  start_date
                  END
            )     AS total_hours
FROM      got_extrema
;

I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
(a) 1 day is deducted for each week between start_date and end_date
(b) if End_date is a Sunday, none of the end_date himself hours are counted
(c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
Always tell what version of Oracle you are using.
See the FAQ forum {message identifier: = 9360002}

How to tell the difference between two dates
Hello:

I have a question on how to get the difference in quantities for two dates in the replies and dashboard.

This is the scenario. I have two guests date and three columns. The first column must be the sum of the amounts for the first quick date. The second column should be the sum of the amounts for the second fast date. And the third column is the difference between the first two columns.

Basically, I'm trying to do something similar to a function of sum of two lines but trying to get the difference between the two rows. Any help to solve this problem would be appreciated.
Use the COLUMN FILTERS level...

the first column with the first variable of date quick presentation of the filter

Similarly, the second column in the second variable of quick overview of date filter

Kind regards
Rambeau

Difference between two dates in the server behaviors

Hello all,.
I am trying to create a Recordset by using server behaviors and that I'm not an expert in php, I'm completely lost...
The problem is this: I want to find in a table of all the records where the difference between today's date and date of creation (stored in this table, although course) is superior to, say 30 days. How can I specify the variable field?
Thank you very much in advance for your help!

You must use a sql like query below:

SELECT * FROM table WHERE creationDate< date_sub(now(),="" interval="" 30="">

'table' is the name of the table that you want to select the information of and 'creationDate' being the column 'date' in the database

How to calculate an interval between two dates?
Hi all

I have two dates, and I need to know if the interval between the two is more than 30 days or not. I can't understand how to calculate this interval.
Could someone help me?
Thank you very much.
See the following forumpost:

Re: Calculation of difference in date in BPEL

Kind regards

Melvin

Difference between two dates

Hello
I have two columns both of them date data types.
I would like to know the difference between these two dates.
SELECTION INTERVAL ' + 2342 23:23:23 ' DAY (4) TO THE SECOND - INTERVAL ' + 102 13:13:13 ' DAY (4) SECOND FROM DUAL;
But, I get this:
'+ 2240 10:10:10.000000'
I'd like to see the result in a year-month and jour-deuxieme groups. I can't do anything with + 2240 days...
Thanks in advance!

Hello Adme12

You can use it.

SET LINESIZE 110 PAGESIZE 20

COLUMN today FORMAT A20

COLUMN TOMORROW FORMAT A20

COLUMN YEAR_MONTHS FORMAT A15

COLUMN DAY_SEC FORMAT A30

SET ECHO ON

SELECT TO_CHAR (today, ' JJ.) MR. HH24:MI:SS' YYYY) LIKE TODAY

, TO_CHAR (tomorrow, ' JJ.) MR. HH24:MI:SS' YYYY) TOMORROW

NUMTOYMINTERVAL (MONTHS_BETWEEN (TOMORROW, TODAY), 'MONTHS') AS YEAR_MONTHS

, NUMTODSINTERVAL (TOMORROW - ADD_MONTHS (TODAY, TRUNC (MONTHS_BETWEEN (TOMORROW, TODAY))), 'DAY') AS DAY_SEC

Of

(SELECT SYSDATE + INTERVAL ' + 102 13:13:13 ' DAY (4) ON THE SECOND THAT TODAY ' HUI)

, SYSDATE + INTERVAL ' + 2342 23:23:23 ' DAY (4) ON THE SECOND TOMORROW

OF THE DOUBLE

)

;

TODAY TOMORROW YEAR_MONTHS DAY_SEC

-------------------- -------------------- --------------- ------------------------------

23.04.2014 04:49 10.06.2020 14:59:10 + 000000006-02 + 000000018 10:10:10.000000000

Of course, it is not so good that you have so many 0, but you can convert the result to a char (TO_CHAR) and you can enter.

I hope this helps you!

Kind regards

David

How to find a number between two numbers?
I try to find the numbers between two given user numbers and multiply each of them, but my code so far wont allow me to separate the numbers multiply:

ex: the numbers are 5 and 10: my code gives me 5678910 together online.

How can I sneek the * between these numbers? I know that I am seriously close here's my work so far.

Any help is greatly appreciated.

import java.util.Scanner;

public class FindIt
{
Public Shared Sub main (string args [])
{
Console scanner = new Scanner (System.in);

int userNumber, finIn, finIn2, finIn3;

System.out.Print ("enter a lower limit > = 1 :"); ")

do
{

userNumber = console.nextInt ();

If (< 1 userNumber)
{
System.out.Print ("enter a lower limit > = 1 :"); ")
}

} while (< 1 userNumber);

System.out.println ("the lower limit is" + userNumber);
System.out.println ();
System.out.Print ("enter an upper limit > = 3 :"); ")
finIn = userNumber;
do
{

userNumber = console.nextInt ();

If (userNumber < 3)
{
System.out.Print ("enter an upper limit > = 3 :"); ")
}

} While userNumber < 3.

System.out.println ("the upper limit is" + userNumber);
System.out.println ();
finIn2 = userNumber;

int x, y;
y = 0;
for (x = finIn; x < = finIn2; x ++)

CallIncr();

}
}

Published by: 806590 on October 31, 2010 13:07

Published by: 806590 on October 31, 2010 13:09
Modified the code of the loop to as below

for (x = finIn + 1; x)< finin2;="">

Difference between two date columns

Dear professionals,
How to get different between two columsn (sati_do-sati_od) in format HH24:

select to_char(sati_od,'hh24:mi') "hh:mi format", 
to_char(sati_do,'hh24:mi') "orginal_value_col2",
sati_od "original_value_col1",
sati_do "original value",
sati_do-sati_od "Difference"
from accbtp_pliskljucenjaodobrenja
where idplisklj= 22999;

where this results in:

hh:mi format orginal_value_col2 original_value_col1       original value            Difference             
------------ ------------------ ------------------------- ------------------------- ---------------------- 
09:00        15:00              01.12.10                  01.12.10                  0,25                   
09:00        15:00              01.12.10                  01.12.10                  0,25                   
09:00        15:00              01.12.10                  01.12.10                  0,25                   
09:00        15:00              01.12.10                  01.12.10                  0,25

THX in advance, Adnan

select trunc( mod( (e-j)*24, 24 ) ) ||':'||trunc( mod( (e-j)*24*60, 60 ) )  "Hr:Mi"
     from (
    select t.*,
           trunc(sysdate,'y')+jd+jh/24+jm/24/60 j,
           trunc(sysdate,'y')+ed+eh/24+em/24/60 e
      from t
          ) t

http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:96012348060

Need to query to find missing months between two dates.

A bank customer a monthly overview of databases (in the tens of millions of accounts)

The data are sent with a line per account each month. It is stored in a table called "ACCOUNTS_TAB".

Fields on registration, which

Column	Description	Example of format.
* YRMTH-1	Year and month of the snapshot	6-character numeric, 4-digit year added to months of 2 digits, example 201301, 201311
* AccountID	Unique identifier for an account.	Integer, example 100098322
Opening balance - 1	Initial account balance at the closing of the previous month	$30000
Closing balance - 1

The account balance at the end of the month of closing

$34200

Class-1 relative to investments

.....

...

.....

......

.....

Many more columns, two favorites (*) columns are alone, that you will need for the query. There are no columns to tell when an account is closed, or has just opened, and not separate "master account" - you use this single table for your query that results.

The table was in place from 200301, so many accounts have dozens of lines, if they have been open for many years and other only 1 or 2 ranks, if new.

Write a query to give just a list of accountDs that meet the following criteria.

1) has a record for specific 201503
2) was also a record for the month specific 201602
3) missing one or several months between these two records.

A good account which was opened from 201503 to 201602 inclusive would of course have lines for

201503

201504

201505

201506

201507

201508

201509

201510

201511

201512

201601

201602

It's good to hardcode the month of departure (201503), end of month (201602) and the actual number of months between them (10 exclusive or 12 inclusive) as part of your query.

Once again the account must meet all 3 criteria to be an account issue. If only, they have a partial set of these documents but do not have the month of departure, or is not the end of the month, it is not a problem, only when they have so specified and end early and not a full between game.

Help, please!

Maybe this...

-----

-The Dataset for the test begins

WITH dataset (ACCOUNT_NO, DATES)

AS (SELECT 100, DOUBLE 201503

UNION ALL

SELECT 100, DOUBLE 201504

UNION ALL

SELECT 100, DOUBLE 201505

UNION ALL

SELECT 100, DOUBLE 201506

UNION ALL

SELECT 100, DOUBLE 201507

UNION ALL

SELECT 100, DOUBLE 201508

UNION ALL

SELECT 100, 201509 OF THE DOUBLE

UNION ALL

SELECT 100, DOUBLE 201510

UNION ALL

SELECT 100, 201511 OF THE DOUBLE

UNION ALL

SELECT 100, DOUBLE 201512

UNION ALL

SELECT 100, 201601 DOUBLE

UNION ALL

SELECT 100, DOUBLE 201602

UNION ALL

SELECT 200, DOUBLE 201503

UNION ALL

SELECT 200, DOUBLE 201504

UNION ALL

SELECT 200, DOUBLE 201505

UNION ALL

SELECT 200, DOUBLE 201506

UNION ALL

SELECT 200, DOUBLE 201508

UNION ALL

SELECT 200, DOUBLE 201509

UNION ALL

SELECT 200, DOUBLE 201510

UNION ALL

SELECT 200, DOUBLE 201511

UNION ALL

SELECT 200, DOUBLE 201512

UNION ALL

SELECT 200, 201601 DOUBLE

UNION ALL

SELECT 200, DOUBLE 201602

UNION ALL

SELECT 300, DOUBLE 201503

UNION ALL

SELECT 300, DOUBLE 201504

UNION ALL

SELECT 300, DOUBLE 201505

UNION ALL

SELECT 300, DOUBLE 201506

UNION ALL

SELECT 300, DOUBLE 201507

UNION ALL

SELECT 300, DOUBLE 201508

UNION ALL

SELECT 300, DOUBLE 201509

UNION ALL

SELECT 300, DOUBLE 201510

UNION ALL

SELECT 300, DOUBLE 201511

UNION ALL

SELECT 300, 201601 DOUBLE

UNION ALL

SELECT 300, DOUBLE 201602

UNION ALL

SELECT 400, DOUBLE 201504

UNION ALL

SELECT 400, DOUBLE 201505

UNION ALL

SELECT 400, DOUBLE 201506

UNION ALL

SELECT 400, DOUBLE 201507

UNION ALL

SELECT 400, 201508 DOUBLE),

-The Dataset to test ends

-Hand with clause begins

ResultSet

AS (SELECT account_no,

CASE

WHEN COUNT)

CASE WHEN dates IN (201503, 201602) THEN 1 END)

COURSES (PARTITION BY account_no) = 2

AND (COUNT (DISTINCT SUBSTR (dates, 4)))

COURSES (PARTITION BY account_no) = 12

OR COUNT (DISTINCT SUBSTR (dates, 4))

COURSES (PARTITION BY account_no)<>

AND COUNT (DISTINCT SUBSTR (dates, 1, 4))

(PARTITION BY account_no) > 1

THEN

« Y »

ON THE OTHER

« N »

END

FLG

THE dataset---> replace with your table name

GROUP BY account_no, dates)

SELECT DISTINCT Account_no

FROM THE result set

WHERE flg = 'Y ';

-Hand with the ends of the clause

ACCOUNT_NO

-----------------------

100

300

200

See you soon,.

Manik.

Figure out how many years and days between two dates

Nice day
I've been dealing with the problem for a few days now so I thought that I could send it and see if someone can tell me what I'm doing wrong.
/ * Create a Date with a date object. */
var d1 = getField "(RELEASE. DATE') .value;
/ * Create a date object containing the current date. */
var d2 = getField("Text4").value;
/ * Number of years difference. */
diff = (((d2.valueOf () - d1.valueOf (()) / 1000) / 60) / 60) / 24) / 365;
Displays the field "Text3".
getField("Text3").value = (diff); & #8232;
< END >
RELEASE. Value DATE is January 1, 2011, with a date format dd/mmm/yyyy
Text4 value is March 1, 2011 with a date format dd/mmm/yyyy
The release of Text3 gives me a 'NaN' result
What I'm trying to do is calculated the number of years an employee has had with the company, and then display a balance of days that he had.
Any thoughts would be greatly appreciated.

repeated conversion from date string and number of days for the reuse of code
function Date2Num (cFormat, cDate) {}
Converts a date string formatted in days since the date of the time
Kai var = util.scand (cFormat, cDate);
Math.floor (oDate.getTime (return) / (1000 * 60 * 60 * 24));
}

/ * Create a Date with a date object. */
var d1 = (getField("Enrol_Day").value + "/" + getField("EnrolMonth").value + "/" + getField("EnrolYear").value);
Converts a date in the date object string
oD1 var = util.scand ("dd/mmm/yyyy", d1);
get the current date of the field
var d2 = (getField ("TD. RelDay") .value + ' / ' + getField ("TD. RelMonth") .value + ' / ' + getField ("TD. (RelYear') .value);

calculate the difference in days
diff var = Date2Num ("dd/mmm/yyyy", d2) - Date2Num ("dd/mmm/yyyy", d1);
increment the value if the end date should be included in the calculation
diff ++;
convert days to truncate all years - to the next intiger lowest
var carnavalSVP = Math.floor(diff / 365.25);
get the current year interval - rest of diff days divided by 365.25 days
var nDays = Math.floor (diff % 365.25);

display the entered values
CMSG var = ' end date: "+ d2 +" \t Compute days: ' "+ Date2Num (" dd/mmm/yyyy", d2);
CMSG += "\nStart date:" + d1 + "\t Compute days: '" + Date2Num ("dd/mmm/yyyy", d1);
Total difference in days
CMSG += "\nTotal elapsed days:"+ diff;»
result in years and days
CMSG += "\nYears:" + carnavalSVP + "and" + nDays + 'days'; "."
App.Alert (GSMC, 1, 0, "results");
//

How to find the difference between two dates in the presentation layer

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