How to find the difference between two dates in time except Sunday

Similar Questions

• Find the difference between two date and time

  Hi friends,
  
  I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
  
  

  select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate) 
  order by sql_step_num;

  You try to get the feel between two char strings.
  And more difference between two dates gives a NUMBER of days.
  Try this:

  select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate)
  order by sql_step_num;
  

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

• How to tell the difference between two dates

  Hello:
  
  I have a question on how to get the difference in quantities for two dates in the replies and dashboard.
  
  This is the scenario. I have two guests date and three columns. The first column must be the sum of the amounts for the first quick date. The second column should be the sum of the amounts for the second fast date. And the third column is the difference between the first two columns.
  
  Basically, I'm trying to do something similar to a function of sum of two lines but trying to get the difference between the two rows. Any help to solve this problem would be appreciated.

  Use the COLUMN FILTERS level...

  the first column with the first variable of date quick presentation of the filter

  Similarly, the second column in the second variable of quick overview of date filter

  Kind regards
  Rambeau

• How to find the difference between standard edition and standard edition one

  How to find the difference between oracle database standard edition and standard edition one 64 bit
  
  (a) using sql
  (b) using the configuration/installation files

  How to find the difference between oracle database standard edition and standard edition one 64 bit

  (a) using sql

  Select * the option of $ v;

  (b) using the configuration/installation files

  opatch lsinventory-details

• Find the difference between two numbers (DBL)

  Hi all

  Is there a function in labview other than the subtraction function that can find the difference between the two numbers given?

  Thank you

  Davidson

  
  

• How to store the difference between two timestamps as a number?

  Hello
  I need to find the difference between 2 variables of timestamp and the result will be stored as a number in minutes?
  as
  declare
  timestamp (7) of the fir_timestamp: = 1 January 2012 13:30 ';
  timestamp (7) of the sec_timestamp: = 1 January 2012 14:00 ';
  c number;
  Start
  c:=((sec_timestamp-fir_timestamp)/(24*60));
  dbms_output.put_line (c);
  end;

  962813 wrote:
  declare

  -fir_timestamp timestamp (7): ='01 - jan - 2012 13:30 ';
  timestamp (7) of the sec_timestamp: = 1 January 2012 14:00 ';  Incorrect type declaration

  fir_timestamp timestamp: = 1st January 12 01.30.00.000000 PM';
  sec_timestamp timestamp: = 1st January 12 02.00.00.000000 PM';
  c number;
  Start
  c: = ABS ((extrait (HEURE de sec_timestamp) - extract (fir_timestamp TIME)) * 60) +.
  ABS ((extrait (MINUTE de sec_timestamp) - extract (fir_timestamp MINUTE)));
  dbms_output.put_line (' interval Min Total:-' | c);
  end;
  /
  declare
  *
  ERROR on line 1:
  ORA-01830: date format picture ends before converting all of the input string
  ORA-06512: at line 6

  Follow what Paul has done...

  In fact, you do not need timestamp, date data type is enough

  SQL> declare
    2     fir_timestamp date :=
    3        to_date('01-jan-2012 13:30:00','dd-mon-yyyy hh24:mi:ss');
    4     sec_timestamp date :=
    5        to_date('01-jan-2012 14:00:00','dd-mon-yyyy hh24:mi:ss');
    6     c number;
    7  begin
    8     c:= round((sec_timestamp-fir_timestamp)*24*60);
    9     dbms_output.put_line(c);
   10  end;
   11  /
  30
  
  PL/SQL procedure successfully completed.
  

  If you want to place on timestamp

  SQL> declare
    2     fir_timestamp timestamp :=
    3        to_timestamp('01-jan-2012 13:30:00','dd-mon-yyyy hh24:mi:ss');
    4     sec_timestamp timestamp :=
    5        to_timestamp('01-jan-2012 14:00:00','dd-mon-yyyy hh24:mi:ss');
    6     c number;
    7  begin
    8     c:= round((
    9     to_date(to_char(sec_timestamp,'ddmmyyyyhh24miss'),
   10             'ddmmyyyyhh24miss')-
   11          to_date(to_char(fir_timestamp,'ddmmyyyyhh24miss'),
   12             'ddmmyyyyhh24miss')
   13           )*24*60);
   14     dbms_output.put_line(c);
   15  end;
   16  /
  30
  

• How to calculate the difference between a Date column and the Date yesterday in the analysis (in the formula in the column)

  . For example, I need to calculate the difference between a date column, 'Table_Name '. "' Column_Name ' and (Current_Date-1). I tried different ways to do this. But nothing seems to work.

  Try the below formula.

  Replace "Time". "" Date "with your column.

  TIMESTAMPDIFF (SQL_TSI_DAY, "Time". "Date", TIMESTAMPADD (SQL_TSI_DAY-1, CURRENT_DATE))

  Thank you!

• How to calculate the difference between two times by the NUMBERS

  I'm so bothered by the fact that I can't understand that.

  Cell B2 - 08:00

  Cell C2 - 10:50

  (How can cell D2 - I get this cell to calculate the difference and say 02:50?)

  I know it's probably one of the most basic operations, but for the life of me I can't understand it. The cells B2 and C2 are formatted for a 24-hour clock. But if I tell the system to just subtract the two, I get "0,118. Everything I find on the forum search goes beyond what I need. Can someone help me?

  Thank you

  Hi sapirs,

  Departure and arrival of the cells are in Date and time with Date format: no and time: 24-hour clock.

  

  Formula in D2 (fill down)

  = C2−B2

  

  The results become a duration format, but under automatic (numbers automatically worth this format)

  

  If you wish, you can change the cells of lasting results.

  What Data Format have your result cells?

  Kind regards

  Ian.

• Dynamic action - Get the difference between two dates + times

  I have problems a little dynamic to work action. I'm trying to get the time between two dates with the time difference.
  
  Here is what I got (this is apex 4.0):
  
  Two date pickers + two numbers fields (date/start/end times)
  
  I created a dynamic action on the page who fires on the point lose focus (above points).
  
  The real action for the DA is the body of the PL/SQL function:

  declare
    end_date DATE;
    start_date DATE;
  Begin
    start_date := to_char(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MON-YYYY HH:MIAM');
    end_date := to_char(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MON-YYYY HH:MIAM');
    :P1_HOURS := end_date-start_date;
  End;

  When I change the values on the page, I get the following error:
  
  AJAX call back Server error ORA-06502: PL/SQL: digital or value error: character number conversion error to set the value.
  
  I'm guessing that there is a problem with the date formatting, but I can't make it work. Thanks in advance!

  Hi djston,

  because you chose the dynamic action of 'Set value' with the "Body of the PL/SQL function" type you need to return the value. Try the following code

  declare
    end_date DATE;
    start_date DATE;
  Begin
    start_date := to_date(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MM-YYYY HH:MIAM');
    end_date := to_date(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MM-YYYY HH:MIAM');
    RETURN (end_date-start_date)*24;
  End;
  

  and P1_REQUESTED_HOURS like 'item affected. "

  Concerning
  Patrick
  -----------
  My Blog: http://www.inside-oracle-apex.com
  APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
  Twitter: http://www.twitter.com/patrickwolf

  Published by: Patrick Wolf on January 17, 2011 10:54

• How to find the difference between the two timestamp columns

  Dear all,
  Please solve my problem,
  I have Table name of the folder that has the following columns,
  EmpID in the number column, timestamp dat
  who has the following values
  Expand | Select | Wrap | Line numbers
  EmpID dat
  ====== ====
  101 4/9/2012 09:48:54
  101 4/9/2012 09:36:28
  101 4/9/2012 18:16:28
  101 4/10 / 2012 09:33:48
  101 4/10 / 2012 12:36:28
  101 4/10 / 2012 20:36:12
  101 4/11 / 2012 09:36:28
  101 4/11 / 2012 16:36:22
  Here, I need to display the following columns
  
  EmpID, min (DAT) as start, max (dat) as end and difference (max (dat) - min (dat) for each day,
  for example,.
  End difference EmpID Strart
  101 4/9/2012 09:48:54 09/04/2012 18:16:28 8.28
  Like this.
  3 days different here is so it should return 3 discs with the mentioned columns above,
  Please help me find it.
  
  Thank you
  Kind regards
  Gurujothi
  
  Published by: Gurujothi on April 25, 2012 04:45

  Gurujothi wrote:
  Dear Alex,
  Thank you for your reply,
  Depending on whether you are your quesy showing it in hour and minutes format its right but you mention all rows of the query
  If the table has more than 3000 lines then how it is possible to write this much higher request,
  my table with almost 3500 lines.

  You can make a few changes in the above query I posted the last I mentioned?

  Thank you.

  Published by: Gurujothi on April 25, 2012 23:18

  Hello

  You don't need to write whole records 3000 it... alex just wrote that for example have no table as your table...
  so just use the under part of this query as in the previous post, alex:

  select empid, trunc(dat),
         min(dat) as start_dat,  to_char(min(dat), 'hh24:mi:ss') as start_dat_part,
         max(dat) as end_dat, to_char(max(dat), 'hh24:mi:ss') as end_dat_part,
         max(dat)-min(dat) diff, to_char(max(dat)-min(dat), 'hh24:mi:ss') diff_part,
         extract(day from max(dat)-min(dat)) || ' days'
         || ':' ||  extract(hour from max(dat)-min(dat)) || ' hours'
         || ':' ||  extract(minute from max(dat)-min(dat)) || ' mins'
         || ':' ||  extract(second from max(dat)-min(dat)) || ' sekas'
  from trans
  group by empid, trunc(dat)
  

  hope this fixes your need

• How to calculate the difference between 2 dates, but with interruptions and stops between

  Hello

  How can I calculate the difference in minutes between 2 dates but taking into account the existence of a table in the Appendix, so if between start_date and end_date arguments, there is no 'work time' then this part of the time will not be included in the total difference.

  Records of the time table example:

  Time_configuration	start_hour	end_day	end_hour
  2	19:00	3	07:00
  3	19:00	4	07:00

  so for example first record said that on Monday you start at 19:00 and leave the next day at 7:00 and then save the same sort of thing.

  There is an event that I want to track how many minutes lasted. for example, this event began the day 2 at 19:00 and ended the day 3 at 21:00

  Theoretically, this event really lasted: 840 minutes. This 840 minutes are within the limits of the annex.

  Thanks in advance.

  The storage of the dates not as data type DATE in most cases is bad design. In addition, how do you know what day of the date is 2 at 19:00? East - Monday 2 November 2015 or Monday, March 7, 2016? It is the same for the event. In any case, assuming that both calendar and events don't extend over several weeks:

  According to schedule)
  Select time_configuration 2, 19:00 ' start_hour, end_day 3,' 07:00 ' end_hour of all the double union
  Select 3, 19:00 ', 4,' 07:00 ' double
  ),
  event like)
  Select event_id 1, time_configuration 2, 19:00 ' start_hour, end_day 3: 21:00 ' end_hour of the double
  )
  Select e.event_id,
  Sum)
  less (e.end_day + to_date (e.end_hour, 'HH24'), s.end_day + to_date (s.end_hour, 'hh24:mi')).
  greater (e.start_day + to_date (e.start_hour, 'HH24'), s.start_day + to_date (s.start_hour,'hh24:mi'))))
  ) * 24 * 60 minutes
  Appendix s,
  e event
  where e.start_day + to_date(e.start_hour,'hh24:mi')< s.end_day="" +="">
  and e.end_day + to_date(e.end_hour,'hh24:mi') > s.start_day + to_date(s.start_hour,'hh24:mi')
  E.event_id group
  /

  EVENT_ID MINUTES
  ---------- ----------
  1 840

  SQL >

  SY.

• How to find the difference between related areas

  Hi all
  My problem is I have a table in which each woman will be visited maximum 8 times, each woman may or may not
  given a reference in any visit which in turn women will respond to this referral in a next visit
  (not necessarily the next visit), I need to calculate the average number of visits between the visit
  in which the wife received a refferal and visit in which she responds.
  
  as an example
  
  woman_id visit_id given_referral respond_to_referral
  -------- -------- -------------- -------------------
  1 1 TRUE NULL
  1 2 TRUE TRUE
  1 3 TRUE NULL
  1 4 TRUE NULL
  1 5 NULL NULL
  1 6 TRUE NULL
  
  This means that visit 2 response is referral to visit 1 so the difference is 1.
  and the visit 6 response corresponds to the referral in visit 4 so the difference is 4.
  what I can't do is knowing how to know answer to visit 6 associated reference visit 4 No 1 or 2 or 3...
  
  and I need to find the following table of the foregoing
  
  woman_id difference between referral and response
  ---------          ---------------------------------------
  1                    1
  1                    2
  
  quick access to help please
  
  Published by: M.Jabr on December 14, 2009 08:05

  with t as (
             select 1 woman_id,1 visit_id,'TRUE' given_referral,NULL respond_to_referral from dual union all
             select 1,2,'TRUE','TRUE' from dual union all
             select 1,3,'TRUE',NULL from dual union all
             select 1,4,'TRUE',NULL from dual union all
             select 1,5,NULL,NULL from dual union all
             select 1,6,NULL,'TRUE' from dual
            )
  select  woman_id,
          diff
    from  (
           select  woman_id,
                   visit_id - last_value(case
                                           when given_referral is not null
                                             then visit_id
                                         end
                                         ignore nulls
                                        )
                              over(
                                   partition by woman_id
                                   order by visit_id
                                   rows between unbounded preceding and 1 preceding
                                  ) diff,
                   respond_to_referral
             from  t
          )
    where respond_to_referral = 'TRUE'
  /
  
    WOMAN_ID       DIFF
  ---------- ----------
           1          1
           1          2
  
  SQL> 
  

  SY.

• How to get the difference of two dates in months

  Dear friends,

  I have 4 items on my page.

  2 entered message text (value of loan, monthly deduction)

  2 are message style fields (start date, end date)

  I need to get the difference from above 2 dates in no.. of months. (for example say N)

  So with N, loanvalue should be divided and populated as monthly deduction.

  I tried this way, but not able to get the difference of dates

  {if ("populateMonthlyDeduction". Equals (PageContext.GetParameter (EVENT_PARAM)))}

  System.out.println ("enter populateMonthlyDeduction loop1");

  String xxDeductionStartDate = vo.getCurrentRow ().getAttribute("DeducStartDt").toString ();

  System.out.println ("xxDeductionStartDate is:" + xxDeductionStartDate);

  TXN OADBTransaction = am.getOADBTransaction ();

  java.sql.Date DeductionSDate = null;

  java.sql.Date DeductionEDate = null;

  if(xxDeductionStartDate!=null)

  {

  java.sql.Date startDate = txn.getOANLSServices () .stringToDate (xxDeductionStartDate);

  DeductionSDate = startDate;

  System.out.println ("DeductionSDate is:" + DeductionSDate);

  }

  String xxDeductionEndDate = vo.getCurrentRow ().getAttribute("DedEndDt").toString ();

  if(xxDeductionEndDate!=null)

  {

  java.sql.Date endDate = txn.getOANLSServices () .stringToDate (xxDeductionEndDate);

  DeductionEDate = endDate;

  System.out.println ("DeductionEDate is:" + DeductionEDate);

  }

  int difInDays = xxDeductionEndDate-xxDeductionStartDate; -Please correct me

  How reach it .plz help.

  Thank you

  Aravinda

  I used a custom like this method and calls this method daysBetween PFR.

  I got it. Thanks to you all.

  public int daysBetween(As Date, Date etDate)

  {

  return (int) ((etDate.getTime () - stDate.getTime (()) / (1000 * 60 * 60 * 24));

  }

  If ("populateMonthlyDeduction". Equals (PageContext.GetParameter (EVENT_PARAM)))

  {

  System.out.println ("enter populateMonthlyDeduction loop1");

  String dedStDt = vo.getCurrentRow ().getAttribute("DeducStartDt").toString ();

  String dedEndDt = vo.getCurrentRow ().getAttribute("DedEndDt").toString ();

  If (! dedStDt.Equals (null) &! dedEndDt.equals (null))

  {

  SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");

  Date sdate = new Date();

  Date edate = new Date();

  String sdate1 = null;

  String edate1 = null;

  try {}

  sdate = dateFormat.parse (dedStDt);

  EDATE = dateFormat.parse (dedEndDt);

  SimpleDateFormat dateFormat1 = new SimpleDateFormat("dd-MMM-yyyy");

  sdate1 = dateFormat1.format (sdate);

  edate1 = dateFormat1.format (edate);

  int days = daysBetween(sdate, edate);

  int diffInMonths = days/30;

  System.out.println ("days is:" + days);

  System.out.println ("diffInMonths is:" + diffInMonths);

  String sTotValueTuitionFees = vom.getCurrentRow ().getAttribute("TotValueTuitionFees").toString ();//pageContext.getParameter("LoanValue").toString();

  int iTotValueTuitionFees = Integer.parseInt (sTotValueTuitionFees);

  int iMonthlyDeduction = iTotValueTuitionFees/diffInMonths;

  String sMonthlyDeduction = String.valueOf (iMonthlyDeduction);

  System.out.println ("iMonthlyDeduction is:" + sMonthlyDeduction);

  OAMessageStyledTextBean bMonthlyDeduction = (OAMessageStyledTextBean) webBean.findChildRecursive ("MonthlyDeduction");

  bMonthlyDeduction.setValue (pageContext, sMonthlyDeduction);

  }

  catch (ParseException exception) e

  {

  }

  }

  }

• How to calculate the hours between two dates by the numbers

  If I update 09:00 start time 17:00 end time of shift in C3 and B3, how to use a D3 formula to calculate the number of hours between the two?  Then I can just copy down the lines for nth years...

  It is a spreadsheet of the part-time staff payroll.

  I'm sure that a lot of people out there have done that.

  Help, please.

  Thank you.

  Eddie

  What program of worksheet that you are using? Since you have a newer iMac running El Capitan, I can safely assume that you use NOT AppleWorks, which is a Power PC application that can run on any OS newer than the snow leopard, OS X 10.6.8.

  If you use numbers, try to repost your question in numbers for Mac forum. If you use Microsoft Excel, try posting in the Microsoft forums. LibreOffice also has community support.