How to find the max value of scrollV in AS3?

Similar Questions

• Find the max value

  Hi team,

  I have the following query where I need to find the max value

  [code]

  with t as)

  Select 'L1' R_nm, R_Data 'Data', 'Obj' R_Obj, r_prec 'Wd', '2' double val

  Union of all the

  Select 'L1', 'Data', 'Obj', 'No', '4' double

  Union of all the

  Select 'L2', 'Data', 'Obj', 'No', '4' double)

  Select t.*, max (val) on rk (partition r_nm, r_data, r_obj) of t

  [/ code]

  My results should be

  [code]

  r_nm r_data r_obj r_prec rk val

  L1 Data Obj 1 2 Wd

  L1 data Obj 4 No.2

  L2 Data Yes 1 1 Obj

  [/ code]

  Thank you

  
  

  Hello

  It seems that you are not interested in the MAX at all.  Looks like you want to classify the lines, such as one that has the lowest value is assigned the number 1, the 2nd line with the lowest values gets 2,... and line with him gets N-th lowest value N.  If is not serious if the MAX is 4, 2 or 420.

  Here's a way to do it:

  SELECT T.*

  , RANK () OVER (PARTITION BY r_nm, r_obj)

  ORDER BY val

  ) AS rk

  T

  ORDER BY r_nm, r_obj

  val

  ;

  Depending on how you want to deal with links, you can use ROW_NUMBER or DENSE_RANK instead of RANK.

• How to get the Max value in Essbase

  Hello
  
  I have problem to get the max value of 3 years in Essbase.
  How can I get the max value of Dec 2009, Dec 2010, Dec 2011.
  Suppose the value of Dec 2009 = 1000, dec 2010 = 1500 and Dec 2011 = 2000
  I want to get the max value of these three value, how can I do this in the Essbase calculation Script.
  Any idea?
  
  
  Thank you.
  
  Kind regards
  
  Joni

  You did not specify if year and period are there separate dimensions, in any case as always a number of different possbilities and I don't have much time today to think about, but only one method can be to use @MAXRANGE

  DIFFICULTY (other members to set, 'Dec')

  'MemberToStoreAgainst' = @MAXRANGE("MemberToFindMaxRangeFor","2009:"2011");

  ENDFIX

  See you soon

  John
  http://John-Goodwin.blogspot.com/

• How to find the ASCII value of the TAB?

  Hi friends,
  
  I'm trying to find the ASCII value of the TAB character using ASCII standard as:
  
  SELECT ASCII ('< TAB >') FROM DUAL;
  
  I'm running the command above in SQL * more.
  
  Is not treated as TAB.
  It is considered space and give the ASCII value of the space - 32.
  
  Please let me know how?
  
  Version of Database - 9i
  
  Concerning
  Anthony Alix.

  Its only editor that gives you the problem; Try it on TOAD or sql developer, it works perfectly.

  Is there a particular reason you want in sql * more?

• How to find the maximum value in a collection

  Hi all
  
  I'm using Oracle 11 g 2. I need to know the maximum value in a collection of items.
  
  When I run the following, I get the maximum number of collection as '5' but I need the max value itself which is 8, please help.
  
  
  DECLARE
  type v_number1 is table of number of directory indexes;
  
  v_number v_number1;
  
  IDX NUMBER.
  psrc_file VARCHAR2 (10): = '1,2,4,8,6';
  v_src_file_string_array v_number1;
  number of max_temp;
  
  BEGIN
  
  SELECT regexp_substr (psrc_file, "[^,] +', 1, level") coll
  LOOSE COLLECTION v_src_file_string_array
  FROM (SELECT psrc_file FROM dual)
  CONNECTION OF LEVEL < = length (regexp_replace (psrc_file, "[^,] +")) + 1;
  
  -Set up some test values:
  BECAUSE me IN v_src_file_string_array. FIRST... v_src_file_string_array. COUNTING LOOP
  -v_numbers (i): = v_src_file_string_array (i);
  v_number (i): = i;
  END LOOP;
  
  max_temp: = v_number (v_number.first);
  IDX: = v_number.first;
  
  -Display the contents of the table:
  While the idx is not null
  loop
  If (idx) v_number > = max_temp
  then
  max_temp: = v_number (idx);
  end if;
  
  IDX: = v_number.next (idx);
  end loop;
  
  dbms_output.put_line ('Max: ' | max_temp);
  end;
  /
  
  
  Thank you!

  Harinath Arasu says:
  Hi all

  I'm using Oracle 11 g 2. I need to know the maximum value in a collection of items.

  When I run the following, I get the maximum number of collection as '5' but I need the max value itself which is 8, please help.

  DECLARE
  type v_number1 is table of number of directory indexes;

  v_number v_number1;

  IDX NUMBER.
  psrc_file VARCHAR2 (10): = '1,2,4,8,6';
  v_src_file_string_array v_number1;
  number of max_temp;

  BEGIN

  SELECT regexp_substr (psrc_file, "[^,] +', 1, level") coll
  LOOSE COLLECTION v_src_file_string_array
  FROM (SELECT psrc_file FROM dual)
  CONNECT BY LEVEL<= length(regexp_replace(psrc_file,="" '[^,]+'))="" +="">

  -Set up some test values:
  BECAUSE me IN v_src_file_string_array. FIRST... v_src_file_string_array. COUNTING LOOP

  It should be-online 1... v_src_file_string_array. COUNTY

  -v_numbers (i): = v_src_file_string_array (i);
  v_number (i): = i;

  This should be-online v_numbers (i): = v_src_file_string_array (i);

  Can't do you all just...

  DECLARE
       type v_number1 is table of number index by binary_integer;
       v_number v_number1;
       idx NUMBER;
       psrc_file VARCHAR2(10) := '1,2,4,8,6';
       v_src_file_string_array v_number1;
       max_temp number;
  BEGIN
       SELECT regexp_substr(psrc_file, '[^,]+', 1, level) coll
       BULK COLLECT INTO v_src_file_string_array
       FROM (SELECT psrc_file FROM dual)
       CONNECT BY LEVEL <= length(regexp_replace(psrc_file, '[^,]+')) + 1;
  
       FOR i IN 1..v_src_file_string_array.COUNT LOOP
         if max_temp is null or
                  v_src_file_string_array(i) > max_temp then
              max_temp := v_src_file_string_array(i);
            end if;
       END LOOP;
       dbms_output.put_line ('Max: ' || max_temp);
  end;
  

  Or more simply...

  DECLARE
       type v_number1 is table of number index by binary_integer;
       v_number v_number1;
       idx NUMBER;
       psrc_file VARCHAR2(10) := '1,2,4,8,6';
       v_src_file_string_array v_number1;
       max_temp number;
  BEGIN
           SELECT to_number(regexp_substr(psrc_file, '[^,]+', 1, level))
        BULK COLLECT INTO v_src_file_string_array
           FROM (SELECT psrc_file FROM dual)
                CONNECT BY LEVEL <= length(regexp_replace(psrc_file, '[^,]+')) + 1
           order by 1 desc;
       dbms_output.put_line ('Max: ' || v_src_file_string_array(1));
  end;
  

  Published by: JAC on April 3, 2013 18:56
  Unhandled exception...

• How to display the max value of channel report repel?

  Hi all

  I have 2 text boxes start and ready target on my report. I need my minimum value of the layer and the other value to automatically display in the start menu and to target channels max case respectively.

  How can I go about it?

  Rsh

  Hello, RSH,.

  Now, how can I limit the decimal points to 2 digits, say, for example, we use d.dd. How can I use it here?

  You can simply convert the string variables and the format of this string using the str function in DIAdem.

  Here is an example for your specific application:

  Maximum: @@str (CMax("[1]/Speed"), "d.dd").

  I hope this helps.

  Otmar
  

• SQL, find the MAX value and placing it as a QVariant

  I have a database that is loaded and defines the customerID as 0 which is ideal when the database is not be saved and restored, etc.  The question I have is that I added the possibility to users to restore a backup in the app, and now I have to do a query to select MAX (customerID) so that there is no duplicate CustomerID when you add or save items.  Here is the following code, I knew that I must settle, specifically the 0 highlighted in red.  I need zero to be the new customerID max value:

  int SettingsStorage::load(int& lastID, GroupDataModel *model)
  {
      // number of locations loaded.
      QSettings settings(m_author, m_appName);
      int loadedCount = 0;
  
      QVariant items;
      // Get the last customer id first.
      // ID's will be generated by incrementing this number
      // Note values coming from settings should be cast to the
      // required type.
       lastID = settings.value(m_lastCustomerIDKey, 0).toInt();
      items = m_sda->execute("SELECT * from items ORDER BY datefield");
      qDebug()<< "the ID" << items;
      // Load all the locations from the database.
      foreach( const QVariant& temp, items.value() ) {
          Location *p;
          if (loadLocation(temp.value(), p)) {
              model->insert(p);
              loadedCount++;
          }
      }
      return loadedCount;
  }
  

  Ive tried the following, but it doesn't seem to do anything:

  int SettingsStorage::load(int& lastID, GroupDataModel *model)
  {
      // number of locations loaded.
      QSettings settings(m_author, m_appName);
      int loadedCount = 0;
  
      QVariant items;
      // Get the last customer id first.
      // ID's will be generated by incrementing this number
      // Note values coming from settings should be cast to the
      // required type.
       QVariant endID = m_sda->execute("Select MAX(customerID) from items")
       lastID = settings.value(m_lastCustomerIDKey, endID).toInt();
      items = m_sda->execute("SELECT * from items ORDER BY datefield");
      qDebug()<< "the ID" << items;
      // Load all the locations from the database.
      foreach( const QVariant& temp, items.value() ) {
          Location *p;
          if (loadLocation(temp.value(), p)) {
              model->insert(p);
              loadedCount++;
          }
      }
      return loadedCount;
  }
  

  Any help will be loved and marked solutions.

  -Thanks in advance

  I was wrong about executeAndWait(). Somehow, I decided that you use the SqlConnection object, but seems his SqlDataAccess. So disregard my previous post. Keep your execute method, but you must change your code to something like this:

  QVariant endID = m_sda->execute("select max(customerID) as m from items");
  
  QVariantList vlist = endID.value();
  QVariantMap vmap = vlist.first().toMap();
  
  lastID = vmap["m"].toInt(&ok);
  

  So I changed your SQL query slightly and added "that m" so I will have something to refer later.

  Then I cast QVariantList because it is where are the results.

  Then because we know its going to be the only record, I took the 1st element in the list and converted to QVariantMap.

  Last step is to get the maximum.

  Should work this time

• How to find the last value of the row in a Datagrid?

  Hello world

  Thanks in advance.

  I need your help to find the latest data from the line in the Datagrid control.

  In fact I use Datagrid to display my data in flex. In my data, I stored the value of gender of the employees. So if the last row in my datagrid 'female' I need to highlight this particular line. So please help me to solve this problem.

  Thank you

  Charles. J

  mylastrowitem dg.dataProvider.getItemAt = (dg.dataProvider.length - 1).

• How to choose the max value

  Hi all

  I have the following data

  Pat_id Pat_enc_csn_id Dept_id Admit_date

  Z2694664	57982980	4055001	16/05/2014 13:21
  Z00624559	57760008	2055050	08/05/2014 14:37
  Z00624559	57760008	2055076	08/05/2014-21:06

  My requirement is to get the max dept or the date of maximum admission for each patient. my output should therefore

  Pat_id Pat_enc_csn_id Dept_id Admit_date

  Z2694664	57982980	4055001	16/05/2014 13:21
  Z00624559	57760008	2055076	08/05/2014-21:06

  can someone help me with the code please. using 11 g.

  (Note: there are several number of patients not only 2)

  Thank you.

  with t as)

  Select p,

  ROW_NUMBER() over (partition by Pat_id of Admit_date desc order) rn

  from your_table p

  )

  Select Pat_id,

  Pat_enc_csn_id,

  Dept_id,

  Admit_date

  t

  where rn = 1

  /

  SY.

• How to get the Max value with other columns data also.

  Suppose that a query is covered with the data as

  Time of ID
  01 07/12/2014
  02 07/05/2014
  03 16/07/2014
  04 07/07/2014

  I need to get the ID and time to time max.
  that is, should I get
  Time of ID
  03 16/07/2014

  To do this, I wrote a query that gives me necessary data. But I thought that's the best way?
  Is it an effective way to get this data?
  My query that returns the data required is:

  SELECT ID, MAX_DT FROM
  (
  Select 'DUMMY', ID, TIME1, MAX (TIME1) OVER (PARTITION 'DUMMY') AS MAX_DT FROM TAB1
  WHERE ID IN (BLAH BLAH)
  )
  WHERE MAX_DT = (EDT) 1

  Frank mentioned links
  

  
  

  WITH test_data (id, time) LIKE)

  SELECT 01, to_date('2014/07/12','yyyy-mm-dd') FROM dual

  UNION ALL

  SELECT 02, to_date('2014/07/16','yyyy-mm-dd') FROM dual

  UNION ALL

  SELECT 03, to_date('2014/07/16','yyyy-mm-dd') FROM dual

  UNION ALL

  SELECT 04, to_date('2014/07/07','yyyy-mm-dd') FROM dual

  )

  SELECT id, time

  go (select id,

  time,

  Max (Time) on latest_time (order by time lines between unbounded preceding and following unbounded)

  of test_data

  )

  where time = latest_time

  ID	TIME
  3	16/07/2014
  2	16/07/2014

  Concerning

  Etbin

• How to find the maximum value of the alphanumeric column

  Hello
  
  I have following data varchar column.
  
  USR_UDF_ALPHANUMERIC
  --------------------------------
  234123
  CS/123762
  987643
  CS/990087
  999999
  CS/761287
  
  I'm looking to separate the 2 SQL queries which should get the output as CS/990087 for the first query and * 999999 * for the second query.
  
  database is 10g.

  As always: it is documented.

  See:
  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/functions043.htm#i1064409

  And make a few quick searches yourself:
  http://www.Oracle.com/pls/db102/homepage
  or
  http://www.Oracle.com/pls/db112/homepage

• Cannot find the MAX Date value in the USER_TAB_PARTITIONS HIGH_VALUE

  Hi all
  
  I'll try to find the Max value of the date of the HIGH_VALUE from the USER_TAB_PARTITIONS, but my request has failed because the HIGH_VALUE is a LONG column.
  
  Appreciate your valuable contributions here.
  
  Thank you
  MK.

  Maldini says:
  I'll try to find the Max value of the date of the HIGH_VALUE

  You use the PL/SQL:

  SQL> select  high_value
    2    from  user_tab_partitions
    3    where table_name = 'RANGE_SALES'
    4  /
  
  HIGH_VALUE
  ----------------------------------------------------------------------------------------------
  TO_DATE(' 1998-04-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  TO_DATE(' 1998-07-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  TO_DATE(' 1998-10-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  TO_DATE(' 1999-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  TO_DATE(' 1999-04-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  TO_DATE(' 1999-07-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  TO_DATE(' 1999-10-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  TO_DATE(' 2000-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  TO_DATE(' 2000-04-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  TO_DATE(' 2000-07-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  TO_DATE(' 2000-10-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
  
  HIGH_VALUE
  ----------------------------------------------------------------------------------------------
  MAXVALUE
  
  12 rows selected.
  

  Now:

  create or replace
    type DateList
      as
        table of date
  /
  declare
      v_DateList DateList := DateList();
      v_max_high_value date;
  begin
      for v_rec in (select high_value from user_tab_partitions where table_name = 'RANGE_SALES') loop
        if v_rec.high_value != 'MAXVALUE'
          then
            v_DateList.extend;
            execute immediate 'begin :1 := ' || v_rec.high_value || '; end;'
              using out v_DateList(v_DateList.count);
        end if;
      end loop;
      select  max(column_value)
        into  v_max_high_value
        from  table(v_DateList);
      dbms_output.put_line('Table RANGE_SALES max high value is ' || to_char(v_max_high_value,'MM/DD/YYYY HH24:MI:SS'));
  end;
  /
  Table RANGE_SALES max high value is 10/01/2000 00:00:00
  
  PL/SQL procedure successfully completed.
  
  SQL> 
  

  SY.

• How to find the value max and min for each column in a table 2d?

  How to find the value max and min for each column in a table 2d?

  For example, in the table max/min for the first three columns would be 45/23, 14/10, 80/67.

  Thank you

  Chuck,

  With color on your bars, you should have enough experience to understand this.

  You're a loop in the table already.  Now you just need a function like table Max and min. loop.  And you may need to transpose the table 2D.

• How to find the value dated the same day in the last year

  I want to know how to find the value dated the same day in the last year.

  I use now, there is the function with the year and the result is

  Year	Rev	There are Rev
  2011	3000
  2012	4000	3000
  2013	2000	4000
  2014	5000	2000

  It works but it's not that I want. I'm trying to add the column date (Ex.20140101) in my report but it'snot work.

  I want to show:

  Date	Rev	There are Rev
  20110112	200
  20120112	100	200
  20130112	300	100
  20140112	500	300

  If use (< degree >, < time_dim >. < date >, 365), it works but does not correct 100%

  Please help me...

  Thank you very much

  Check this link cool - bi.com

• How to find the bpel instance in 11 g based on the index values

  We have 10 GB BPEL processes where we define the 4 index values for all instances. Whenever the support request comes, ask us the values of index and based on what we're looking for the process instance.
  
  We have now migrated bpel 10g and 11g process. How to find the bpel instance in 11 g based on the index values?

  You can go there. http://soasphere.blogspot.com/2011/04/how-to-Serch-composites-for-index.html. Do a join on the cube_instance and ci_indexes tables.