How to find the tables placed only on pages.

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• How to find the table in a schema, if I only have a particular column name

  Hi all
  
  Ideal if some1 could help me, I know not a column name and I need to find the table that actually holds this column paricular name I know.
  
  is it possible to find this particular table with SQL?
  
  Thank you
  Rahul

  Select the table TABLE_NAME from user_tab_columns where column_name = 'COLUMN_NAME '.

• How to find the table?

  Hello
  
  I have a java Apps to connect to a database of GR 11, 2.
  When I clicked on a "billing" module, I don't 'a number' 1,641.00 error in java logs that cause billing does not be generated.
  I don't even enter this value. I don't know if this error at the level of the table or during analysis on the coast of java it fetch a numeric variable placeholder.
  I simply assume that it is at the database level. And assuming that I am the only user in the database.
  How can I get this operation with the 1,641.00 value and determine which table was is inserted to the error? In V$ SQLAREA maybe?
  

  SYSUSER - 263293-40-1 2012-07-10 11:08:25,578 [http-6700-1] INFO  (support.context.CacheManager) Registering cache 'BusinessObjectInfoCache'
  SYSUSER - 263293-41-1 2012-07-10 11:08:25,859 [http-6700-2] ERROR (api.service.ServiceExecutionPolicy) Rollback: Read failed
  java.lang.NumberFormatException: Not a number: 1,641.00
       at com.ibm.icu.math.BigDecimal.bad(BigDecimal.java:3894)

  Thank you very much
  Kins

  >
  apps itself has no problem.
  >
  I have to disagree. If the application is to throw an exception and the journal contains her not the information necessary for you tell what is causing the exception, and then the application has ALSO a problem.

  java.lang.NumberFormatException: Not a number: 1,641.00
       at com.ibm.icu.math.BigDecimal.bad(BigDecimal.java:3894)
  

  Add additional record to the app to catch the exception and discover the connection, the request and the record that causes the error.

  Troubleshoot, to gather information when the problem actually occurs and work your way backwards.

  If you say that the problem did not exist before the developer made the change then prove it by running the old code against the same data. If it works then the problem is with the change that made the developer.

• How to find the table - is - this normal table or external table?

  Hello
  
  
  Regardless of DML operations in normal and reading tables only access tables outside, is there a way to find the specified table is regular table or the external table?
  
  Thanks in advance.
  
  Suresh.

  One possibility would be to query the ALL_EXTERNAL_TABLES data dictionary view. If there is a line in ALL_EXTERNAL_TABLES to the table, wondering (I assume you know that you query a table, a view, or a synonym), it is an external table. Otherwise, it's an ordinary table.

  Justin

• How to find the tables that are used in a procedure

  Hello
  I need to write a SQL to find (user_source) procedures or triggers (from user_triggers), whose code contains the registerd tables in a table X.
  In other words, I have a table X with files having a column containing tables. I want to write a SQL to obtain these (proc, package and triggers) container objects or use the tables inside
  Can you help me?
  Thank you!

  Mark1970 wrote:
  Hello
  I need to write a SQL to find (user_source) procedures or triggers (from user_triggers), whose code contains the registerd tables in a table X.
  In other words, I have a table X with files having a column containing tables. I want to write a SQL to obtain these (proc, package and triggers) container objects or use the tables inside
  Can you help me?
  Thank you!

  I don't know if I understand your problem, but have you had a glance at the data dictionary views USER_DEPENDENCIES or ALL_DEPENDENCIES?

  It has classified hard dependencies of objects.
  If a table is used directly (not in dynamic SQL code in a string) in an object PL/SQL, the dependency is available in the stated points of view.

• How to find a table behind the OA framework page

  Hello
  can any body tell me how to find the tables behind any page of OA framework in particular for screens of ALS.
  Concerning

  On the tab of the page-->, click on expand all link.

  Here you can find the area of the table and the VO rasthaus to it. When you've got the name of the View object.

  Then click on details of the Business component references-->

  In the object section View find your viewObject and click on it. Here you can find the application attached to it.

  Thank you
  -Anil

• How to find the size of the table?

  Hi all

  Can anyone suggest how to find the size of the table? I had a few (15272 selected lines) on the name of "CMPT_" How can I check only 'CMPT_' size tables?

  
  

  
  

  
  

  
  

  Please someone help give the SQL query to run.

  
  

  Thanks in advance.

  
  

  Vincent
  

  madala03 wrote:

  Hi thanks for the reply

  I'm out like below

  SUM(BYTES/1024/1024)

  --------------------

  25383.25

  But how to check all the name of tables CMPT and their sizes?

  Select nom_segment, dba_Segments sum(bytes/1024/1024) where nom_segment like ' % CMPT GROUP BY nom_segment;

• How to find a table, using the name of the column in the database schema

  Dear all,
  
  Please help me on
  
  using the name of the column, how to find a table name in the database schema.
  
  Thanks in advance

  Hello

  You can query the data dictionary views all_tab_columns and user_tab_columns.
  For example, to find the tables in the scott schema have called deptno columns:

  SELECT  table_name
  FROM    all_tab_columns
  WHERE   owner           = 'SCOTT'
  AND     column_name     = 'DEPTNO';
  

  Remember that anything inside quotes is case-sensitive.

  The all_tab_columns view has one row for each column in each table (or view) that you have the privileges to use.
  The user_tab_columns view is a subset of all_tab_columns, containing only your own tables (and views).

• How to find the value max and min for each column in a table 2d?

  How to find the value max and min for each column in a table 2d?

  For example, in the table max/min for the first three columns would be 45/23, 14/10, 80/67.

  Thank you

  Chuck,

  With color on your bars, you should have enough experience to understand this.

  You're a loop in the table already.  Now you just need a function like table Max and min. loop.  And you may need to transpose the table 2D.

• How to find the primary key columns in the tables in MS Access using SQL queries

  How to find the primary key columns in the tables in MS Access using SQL queries

  Hello

  This is the forum for Windows Vista programs related issues.

  For better assistance, please try instead the Forums in SQL Server .

  Thank you! Vincenzo Di Russo - Microsoft MVP Windows Internet Explorer, Windows Desktop Experience & security - since 2003. ~ ~ ~ My MVP profile: https://mvp.support.microsoft.com/profile/Vincenzo

• How to find the size of the partitioned tables?

  How to find the size of the partitioned tables?

  Select nom_segment, sum (bytes) /(1024*1024) 'Size in MB' from dba_segments
  where owner = 'owner name' and segment_type like '% PARTITION % '.
  Group by nom_segment;

• How to find the relationship between the tables

  Hello
  I am working in Oracle R12
  
  How to find the relationship between these tables INV_MIN_MAX_TEMP, po_requisition_lines_all and Per_all_people_f
  
  These two tables, I joined with po_requisition_lines_all and Per_all_people_f To_person_id of PO and anyone HR table but I can't able to join this table with other tables INV_MIN_MAX_TEMP
  
  concerning
  Srikkanth

  solved

• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

• How to find the second largest in a pl/sql table

  Hello friends,
  
  I want to find the first and second maximum items in a pl/sql table.
  
  Here's the code...
  
  DECLARE
  Max_earnings_type TYPE TABLE IS NUMBER;
  max_earnings_tab max_earnings_type: = max_earnings_type();
  number of v_count: = 0;
  number of v_max_earnings;
  
  
  Can someone give me how to find the maximum first max and second in the type of the given table.
  
  appreciate your help.
  
  Thank you/kumar
  
  Published by: kumar73 on October 21, 2010 09:42

  kumar73 wrote:

  When I tried to implement your logic in my application, I get the following error...

  PL/SQL: digital or value error: NULL index key value table

  What happens if the PL/SQL table has NULL values. Question is how you want to handle NULL values. You want to ignore nulls as GROUP BY do? If you want to consider NULL values, you can say if you want to order the NULLS FIRST or NULLS LAST. I guess that logical GROUP BY:

  DECLARE
      TYPE max_earnings_type IS TABLE OF NUMBER;
      TYPE max_earnings_sorted_type IS TABLE OF NUMBER
        INDEX BY BINARY_INTEGER;
      max_earnings_tab        max_earnings_type;
      max_earnings_tab_sorted max_earnings_sorted_type;
  BEGIN
      SELECT  sal + comm
        BULK COLLECT
        INTO  max_earnings_tab
        FROM  emp;
      FOR v_i in 1..max_earnings_tab.count LOOP
        IF max_earnings_tab(v_i) IS NOT NULL
          THEN
            max_earnings_tab_sorted(max_earnings_tab(v_i)) := 1;
        END IF;
      END LOOP;
      DBMS_OUTPUT.PUT_LINE('MAX value in PL/SQL table is ' || nvl(to_char(max_earnings_tab_sorted.last),'NULL'));
      DBMS_OUTPUT.PUT_LINE('Second MAX value in PL/SQL table is ' || nvl(to_char(max_earnings_tab_sorted.prior(max_earnings_tab_sorted.last)),'NULL'));
  END;
  /
  MAX value in PL/SQL table is 2650
  Second MAX value in PL/SQL table is 1900
  
  PL/SQL procedure successfully completed.
  
  SQL> SELECT  sal + comm
    2    FROM  emp;
  
    SAL+COMM
  ----------
  
        1900
        1750
  
        2650
  
        1500
  
    SAL+COMM
  ----------
  
  14 rows selected.
  
  SQL>
  

  SY.

• How to find the user Apex table

  Hello
  
  Please let me know, how to find the user apex table. I need validate the unique user based on the same, for which I use below function.
  
  DECLARE
  VAL A BOOLEAN;
  BEGIN
  VAL: = APEX_UTIL.IS_USERNAME_UNIQUE (p_username =
  (: P6_USERNAME);
  END;
  
  However, in this case, he always comes back "FALSE," saying new user exists.
  
  Kindly help me in fixing this problem.

  There is a view called apex_workspace_apex_users.

  Details under Home > utilities > Application Express views

  André