How to find the value max and min for each column in a table 2d?

Similar Questions

• How to find the value max and min of an attribute for a master VO

  Hello
  Is it possible to find maximum and minimum a master view object attribute values in groovy.
  I need to have the (START_DATE) min and max (end_date), values to pass to my Gantt chart to the table project start date and end date.
  For detail view objects, we can use < accessor > .max (start_date), but to see Master objects?
  
  I use jdeveloper 11.1.1.3.
  
  Thank you
  Guna.
  
  Published by: guna.b on December 13, 2010 11:01

  How about setting GOES to the same point of view and by using the groovy you mentioned in your message

• read the max and min of each column value

  Dear qudoe

  I'm doing a program in labview that challenge me to fight with a time.

  Here, I enclose my labview code in which I have a data file, which includes 500 columns that I need to find the values min and max of each column.

  I tried my best, but it takes 30 seconds to find the min and max value of each column.

  I want to do this in less than a second.

  so can anyone suggest me any necessary correction that can stimulate my program.

  You don't have to open and close the file in a loop all the time and also you don't really need some time for this. Check the related code.

  

  Of course, you can still optimize it for best performance, I just did a quick project to show how simple it is.

• Time series: finding max and min for each month

  Hello world. I'm working on a datasheet that has collected the data points for all day for the past 15 years.

  A column stores the date and column B contains a numeric value.

  I want to do the following:

  Create a new table (call it table #2) that:

  (1) is now a time series on a monthly basis (column A contains "year month"). This is why the table contains a header and 15 * 12 = 60 rows of data

  (2) B Col contains the Max value of this month.

  (3) C Col contains the value this month min

  Table #2 should be calculated automatically because I need to find these values for several series. Any ideas?

  Here is a way that I came up with

  

  In the table above, your original data is in columns B and C.

  I've added three additional columns (A, D and E):

  D2 = Year (B2) & NUMTOBASE (MONTH (B2), 10, 2)

  It's shorthand dethrone select D2, and type (or copy and paste it here) the formula:

  = Year (B2) & NUMTOBASE (MONTH (B2), 10, 2)

  E2 = IF (D1≠D2, 0, E1 + 1).

  Select copy of D2 to E2,

  Select cells D2 at the end of column E, block

  A2 = D2 & NUMTOBASE (E2, 10, 2)

  Select A2, copy

  Select A2 at the end of the A2 column, paste

  now create a second table summary as shown:

  

  For 'Summary Table 2016:

  the first four lines are the lines of header

  There are 35 total lines

  Enter the year in cell B1

  A5 = −4 LINE)

  B5 = SIERREUR (VLOOKUP ($B$ 1 & NUMTOBASE(B$4,10,2) & NUMTOBASE($A5,10,2), data: $A:$ C, 3, 0), "")

  Select cell B5, copy

  Select cells B5 at the end of row 5, dough

  Select A5 thru M5, copy

  Select cell A5 at the end of the M column, paste

  B2 = MIN (B)

  B3 = MAX (B)

  Select the cells B2 to B2, copy

  Select the cells B2 through M3, dough

  now duplicate the table and change the year to 2015 for the next year.

  You can duplicate this table as necessary to summarize a year

• How to reset the value of line number for each header

  Hi all

  I need to reset the line number for each header values.

  create table header_table (header_value varchar2 (100));

  create table line_table (header_value varchar2 (100), number line_number);

  insert into header_table values ('ALAOF');

  insert into header_table values ('ALAOO');

  insert into line_table values('ALAOF',1);

  insert into line_table values('ALAOF',2);

  insert into line_table values('ALAOF',3);

  insert into line_table values('ALAOF',4);

  insert into line_table values('ALAOF',5);

  insert into line_table values('ALAOO,6);

  insert into line_table values('ALAOFO,7);

  insert into line_table values('ALAOO',8);

  insert into line_table values('ALAOO',9);

  insert into line_table values('ALAOO',10);

  insert into line_table values('ALAOO',11);

  insert into line_table values('ALAOO',12);

  Commit;

  TABLE HEADER_:

  header value

  ALAOF

  TRECYBEL

  LINE TABLE:

  header value line_number

  ALAOF 1

  ALAOF 2

  ALAOF 3

  ALAOF 4

  ALAOF 5

  TRECYBEL 6

  TRECYBEL 7

  TRECYBEL 8

  TRECYBEL 9

  TRECYBEL 10

  TRECYBEL 11

  TRECYBEL 12

  But looks like I got out of line below table

  LINE TABLE:

  header value line_number

  ALAOF 1

  ALAOF 2

  ALAOF 3

  ALAOF 4

  ALAOF 5

  TRECYBEL 1 <-reset the beginning of line number with 1 with different header value

  TRECYBEL 2

  TRECYBEL 3

  TRECYBEL 4

  TRECYBEL 5

  TRECYBEL 6

  TRECYBEL 7

  Please help me on this.

  Thanks in advance.

  Hello

  It makes no sense to do it in PL/SQL when you can do it with SQL.

  SQL is generally more efficient than PLSQL.

  And can you explain why you don't want to use analytical functions?

  This will update your table using a MERGE statement and an analytic function:

  MERGE INTO line_table lt
  USING
  (
     SELECT ROWID rid, header_value, row_number() OVER(PARTITION BY header_value ORDER BY ROWNUM) rn
       FROM line_table
  ) src
  ON (src.rid=lt.ROWID)
  WHEN MATCHED THEN
     UPDATE SET lt.line_number = src.rn;
  

  The result is less to:

  HEADER_VAL LINE_NUMBER

  ---------- -----------

  ALAOF 1

  ALAOF 2

  ALAOF 3

  ALAOF 4

  ALAOF 5

  TRECYBEL 1

  TRECYBEL 2

  TRECYBEL 3

  TRECYBEL 4

  TRECYBEL 5

  TRECYBEL 6

  TRECYBEL 7

  Kind regards.

  Al

• How to find the value dated the same day in the last year

  I want to know how to find the value dated the same day in the last year.

  I use now, there is the function with the year and the result is

  Year	Rev	There are Rev
  2011	3000
  2012	4000	3000
  2013	2000	4000
  2014	5000	2000

  It works but it's not that I want. I'm trying to add the column date (Ex.20140101) in my report but it'snot work.

  I want to show:

  Date	Rev	There are Rev
  20110112	200
  20120112	100	200
  20130112	300	100
  20140112	500	300

  If use (< degree >, < time_dim >. < date >, 365), it works but does not correct 100%

  Please help me...

  Thank you very much

  Check this link cool - bi.com

• How to find the first Sunday and the second Saturday of each month

  Hi all

  How to find the first Sunday and the second Saturday of each month

  Thank you

  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

  994122 wrote:

  Hello

  I need to pass the months parameter how to do this? like Jan, Feb etc... (one of those)

  Do you have a procedure?

  Should you output only for the months you passed in the parameter?

  The easiest way is to set the parameter as date. When you go such as p_date as DATE ' 2014-10-01', then you can

  PROCEDURE two_dates)

  p_date IN DATE

  p_first_sunday DATE

  p_second_saturday DATE

  )

  IS

  BEGIN

  p_first_sunday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-12', 'DAY'));

  p_second_saturday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-11', 'DAY')) + 7;

  END two_dates;

  Or you describe what you need.

• How to find the value closest in the table?

  Hi all

  I just want to find the value closest from the string table. That I joined herer as an image.

  Now, if I want to find the value of 350 of the string table and that's not in the table in the output array there should be more close 350 display value...

  Thank you for the support

  Vinal Gandhi

  Hi G Vinal,

  something like the joint comes to my mind.

  It may be useful

  Mike

• How to find the Maxima and Minima for each column of a 2D array?

  Hello

  I have a 2D chart and I would find the maxima and minima of each column of the 2-D table. Even though I know how to get maxima and minima for the whole picture but don't know how columnwise? Any ideas please?

  Thank you

  Rohit

  Hello

  @Smercurio-What you said is true, I should have shown using automatic indexing enabled which is really excellent choice. I just tried to show in a very simple way.

  Anyway, here's the best way

  

• How to read the value attribute and put inside?

  What happens if we want to read the attribute value? And want to put the data of runtime on the value of the attribute as
  
  < psoID ID = "user id" / >
  
  How to get the value of the ID as the user id. And how to put the run value on it?
  
  I can think about is that
  
  /psoID/@ID/value GOLD psoID/@ID/*[local-name () = 'value']
  
  And how to put the value inside ID ="? »
  
  Thank you

  Because we are dealing with a structure of type anyType you must use the functions of node (local name) in combination with predicates ([]) to read or write values (node) of the element:

  To read the value for example use the copy rule:

  
  
  
  

  This wil read:

  /processResponse/result/psoID/@ID

  on the message:

  
  
  
  
  

  You will see the value 'B '.

  To write, you use:

  
  
  
  

  Kind regards

  Melvin

• How to find the session killed and computer name

  Hello
  
  At the time of the batch run killed .somebody this session without me knowing how to find the user particular db level or oslevel .de name which machine they killed how know at the OS level. but when I put the audit_trail = os only user SYSDBA activities are not checked the other activities of the user.
  
  The server is AIX and db version 11i provide the query for conclusion or os level.
  
  Thank you
  DBC.
  
  Published by: dbc001 on March 26, 2013 21:48

  check with who ever is privilleges to kill these perticluar session, if you have few users.
  It is not possible to findout without verification or error info... etc.
  Otherwise, restart these jobs perticluar and follow closely.

• How to find the value?

  How to calculate the value of 2.50e + 2 in the analysis of string function when the %f format string is selected?

  the format may be stung a control

• Find the Max and Min for a table of number...

  My table has 5 numbers in it and also the ability to add more to what the user sees fit. I want to be able to view the maximum and minimum of the table number. I made a loop, but I do not know how do select the highest or lowest number automatically without me selecting manually typing in the middle.

  This is my code to determine this:

  Determine the Min and Max brand
  function maxandminMark() {}
  var markIndex:int;
  markIndex = (marks.indexOf (marks));
  If (markIndex! = - 1).
  {
  for (var i = markIndex; i < marks.length; i ++)
  {
  brands [i] = marks [i + 1];
  }
  trace (maxandminMark);
  }
  }
  }

  Here are two ways...

  1) walk through the comparison table of values

  var numArray:Array = new Array (38,11,45,7,14,9,67,28);
  var minNum:Number;
  var maxNum:Number;
   
  If (numArray.length > 0) {}
  minNum = maxNum = numArray [0];
  }
   
  for (var i: uint = 1; i< numarray.length;="">
  If (numArray [i]<>
  minNum = numArray [i];
  } ElseIf (numArray [i] > maxNum) {}
  maxNum = numArray [i];
  }
  }
   
  trace (minNum, maxNum);

  (2) sort the array numerically and pull out the first and last items

  numArray.sort (Array.NUMERIC);

  trace(numArray[0],numArray[numArray.Length-1]);

• How to find the first max value for each item

  Hello
  
  I have the me_result of the table as below,
  
  SELECT * FROM me_result;
  
  ID     ||| ELITE     ||||||||||| FREQ_ITEM | COMBINED_STR | SUP
  1     ||; 1; 10; 2; 3; 4; 5; 7; 8. 1     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  2     ||; 1; 10; 2; 3; 4; 5; 7; 8. 2     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  3     ||; 1; 10; 2; 3; 4; 5; 7; 8. 3     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  4     ||; 1; 10; 2; 3; 4; 5; 7; 8. 4     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  5     ||; 1; 10; 2; 3; 4; 5; 7; 8. 5     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  6     ||; 10; 2; 3; 4; 5; 8; 9. 1     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9; 1 ||| 1
  7     ||; 10; 2; 3; 4; 5; 8; 9. 2     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  8     ||; 10; 2; 3; 4; 5; 8; 9. 3     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  9     ||; 10; 2; 3; 4; 5; 8; 9. 4     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  10     ||; 10; 2; 3; 4; 5; 8; 9. 5     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  
  
  I need to find the first COMBINED_STR max for each element of the ELITE,
  I mean, max value is the max REGEXP_COUNT (combined_str,' ;')))
  
  really, I try to write down, but I had a lot of values for each ELITE and I need only the first, that
  SELECT * from me_result
  WHERE (ELITE, REGEXP_COUNT (combined_str,' ;')))) IN
  (SELECT ELITE, MAX (REGEXP_COUNT (combined_str,' ;'))))) ME_RESULT ELITE GROUP);
  
  I need the result to be as below.
  
  1; 1; 10; 2; 3; 4; 5; 7; 8-1; 1; 10; 2; 3; 4; 5; 7; : p
  6; 10; 2; 3; 4; 5; 8; 9 1; 10; 2; 3; 4; 5; 8; 9; 1 1
  
  any help please,.
  
  Published by: user11309581 on July 10, 2011 22:03

  Can be

  with t as
  (select 1     ID, ';1;10;2;3;4;5;7;8'     ELITE, 1     FREQ_ITEM, ';1;10;2;3;4;5;7;8' COMBINED_STR, 2 SUP from dual union all
  select 2     ,';1;10;2;3;4;5;7;8'     ,2     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 3     ,';1;10;2;3;4;5;7;8'     ,3     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 4     ,';1;10;2;3;4;5;7;8'     ,4     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 5     ,';1;10;2;3;4;5;7;8'     ,5     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 6     ,';10;2;3;4;5;8;9'     ,1     ,';10;2;3;4;5;8;9;1'     ,1 from dual union all
  select 7     ,';10;2;3;4;5;8;9'     ,2     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 8     ,';10;2;3;4;5;8;9'     ,3     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 9     ,';10;2;3;4;5;8;9'      ,4     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 10     ,';10;2;3;4;5;8;9'     ,5     ,';10;2;3;4;5;8;9'     ,2 from dual
  )
  select ID,ELITE,FREQ_ITEM,COMBINED_STR,SUP
  from (
    SELECT ID,ELITE,FREQ_ITEM,COMBINED_STR,SUP, ROW_NUMBER() over (PARTITION BY ELITE order by id) RN
    FROM t
    WHERE (ELITE,REGEXP_COUNT(combined_str,';')) IN
      (SELECT ELITE,MAX(REGEXP_COUNT(combined_str,';')) FROM t GROUP BY ELITE)
  ) where RN=1
  order by id
  
  ID                     ELITE             FREQ_ITEM              COMBINED_STR      SUP
  ---------------------- ----------------- ---------------------- ----------------- ----------------------
  1                      ;1;10;2;3;4;5;7;8 1                      ;1;10;2;3;4;5;7;8 2
  6                      ;10;2;3;4;5;8;9   1                      ;10;2;3;4;5;8;9;1 1     
  

• Place a value max and min on the date picker

  Apex 4.2

  I have a report interactive apex which is framed by a start_date and end_date a. We will call P1_START and P1_END. They are the two fields of date picker. Once the user selects a date, the report is updated accordingly display the results falling between the date ranges. Pretty sImple. As we know, the date picker has throughout the calendar year. Is there a way to limit the date picker to go only to come or already in a month? So if the user were using the application today, would later return they might choose 24/10/2013 and the furthest in the future would be 12 24, 2013, honorably.

  Any help on this would be greatly appreciated. Thanks in advance.

  Change your date picker control object

  Go to the settings section

  The value of minimum date to "-1 m".

  Maximum date "m + 1"

  Click on the legends of the attribute for more options.