How to find the way to rows and columns of matrix

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  Click on your name at the top of this page, then click on "view profile".

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  Good bye

  DPT

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• How to find the value duplicate of each column.

  I have it here are four columns,
  How can I find the duplicate of each columns value.
  
  with All_files like)
  Select ' 1000 'like BILL, "2000" AS DELIVERYNOTE, CANDELINVOICE ' 3000', '4000' CANDELIVERYNOTE of all union double
  Select ' 5000 ', ' 6000', ' 7000 ', ' 8000' Union double all the
  Select '9000 ', '1000', '1100',' 1200' from dual union all
  Select ' 1200 ', ' 3400', ' 6700 ', ' 8790' Union double all the
  Select ' 1000 ', ' 2000', ' 3000 ', ' 9000' Union double all the
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  )
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  Output should be as shown below.
  
  1000 2000 3000 4000
  9000 1000 1100 1200
  1200 3400 6700 8790
  1000 2000 3000 9000
  
  Required to check uniqueness columns.
  
  Thank you.

  Hello

  If you are not too concerned about performance, this should give you the desired result:

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  FROM (
    SELECT a.*,
           count(*) over(partition by t.column_value) cnt
    FROM All_files a,
         table(
           sys.odcivarchar2list( a.INVOICE
                               , a.DELIVERYNOTE
                               , a.CANDELINVOICE
                               , a.CANDELIVERYNOTE ) ) t
  )
  WHERE cnt > 1
  ;
  

• Referring to the dynamic cursor rows and columns in SQL

  I have a procedure that dynamically reads a schema name and a table name in a table entry. The code must loop through all the rows and the columns in each table and the output data. I'm done with what I want to achieve 95%, but there is a little bug. The dbms_output.put(*col.column_name* ||) line '',''); ' ||
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  CREATE OR REPLACE PACKAGE BODY some_proc
  -Function and procedure implementations
  PROCEDURE create_files IS
  CURSOR c_tbls IS
  SELECT * FROM tbl_list;
  l_sql VARCHAR2 (4000);
  BEGIN
  -To loop through all the tables
  FOR tbl IN c_tbls LOOP
  l_sql: = "DECLARE" | «C_tbl_recs CURSOR IS» | ' SELECT * ' |. '
  'FROM ' | tbl.schema_name | '.' || tbl.table_name | '; ' ||
  ' t_tbl_rowtype c_tbl_recs % ROWTYPE; ' || "START" |
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  ' END; ';
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  EXECUTE IMMEDIATE l_sql;
  END LOOP;
  EXCEPTION
  WHILE OTHERS THEN
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  END;
  END;

  Is this what you are looking for?
  (it took a few minutes)

  create or replace
  package some_proc is
  procedure create_files;
  end;
  /
  
  CREATE OR REPLACE
  PACKAGE BODY some_proc
  IS
    -- Function and procedure implementations
  PROCEDURE create_files
  IS
    CURSOR c_tbls
    IS
      SELECT * FROM tbl_list;
  
    CURSOR c_cols (p_table_owner VARCHAR2, p_table_name VARCHAR2)
    IS
      SELECT column_name
      FROM all_tab_columns
      WHERE owner   =p_table_owner
      AND table_name=p_table_name
      ORDER BY all_tab_columns.column_id;
  
    l_sql     VARCHAR2(32000);
  
    separator VARCHAR2(1):=';';
  
  BEGIN
    --Loop through all tables
    FOR tbl IN c_tbls
    LOOP
      dbms_output.put_line('TABLE: '||tbl.schema_name||'.'||tbl.table_name);
      l_sql := 'DECLARE ' ;
      l_sql := l_sql|| '  CURSOR c_tbl_recs IS ' ;
      l_sql := l_sql||'    SELECT * FROM ' || tbl.schema_name || '.' || tbl.table_name || '; ' ;
      l_sql := l_sql||'    linenr number:=1; ';
      l_sql := l_sql||'BEGIN ' ;
      l_sql := l_sql|| ' FOR rec IN c_tbl_recs LOOP ';
      FOR c IN c_cols(tbl.schema_name,tbl.table_name)
      LOOP
        l_sql:=l_sql ||' if linenr=1 then  dbms_output.put('''||c.column_name||''||separator||'''); end if; ' ;
      END LOOP;
      l_sql :=l_sql||'  dbms_output.put_line(''''); linenr:=linenr+1; ';
      FOR c IN c_cols(tbl.schema_name,tbl.table_name)
      LOOP
        l_sql:=l_sql ||' dbms_output.put(rec.'||c.column_name||'||'''||separator||'''); ' ;
      END LOOP;
      l_sql:=l_sql||'  end loop; ';
      l_sql:=l_sql||'  dbms_output.put_line(''''); ';
      l_sql:=l_sql||'  dbms_output.put_line(''''); ';
      l_sql:=l_sql||'end;';
      EXECUTE IMMEDIATE l_sql;
    END LOOP;
  EXCEPTION
  WHEN OTHERS THEN
    dbms_output.put_line(SQLERRM);
  END;
  END;
  /
  

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• How to find the index is local and the global in the dictionary of the oracle

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  Is there a way to know if the index partition is global or local oracle dictionary.

  select index_name, locality from all_part_indexes
  

• How to find the middle name of any column NAME

  I wrote under request

  why this market not could you please help me?

  Select substr (ename, instr (ename,' ', 1, 1), instr (ename, ' ', 1.2)) of e1

  InStr, primary function must return the first position of the space and

  2 nd instr, function should return 2nd space

  so we can specify in substr function to extract the form position of string from this place to that place

  It would be very useful that you explain the reason

  Best regards

  Prem kumar

  Select

  -case when length (substr (ename, instr (ename,' ', 1.2))) = length (ename) then

  (case when length (substr (name, instr (ename,' ', 1.1))) = length (ename) then null)

  of another substr (ename, instr (ename,' ', 1, 1) + 1) end)

  of another substr (ename, instr (ename,' ', 1, 1) + 1, instr(ename,' ',1,2)-instr(ename,' ',1,1)-1)

  end middle_name

  of e1;

  Select

  -case when length (substr (ename, instr (ename,' ', 1.2))) = length (ename) then

  (case when length (substr (ename, instr (ename,' ', 1.1))) = length (ename) then null)

  of another substr (ename, instr (ename,' ', 1, 1) + 1) end)

  of another substr (ename, instr (ename,' ', 1, 1) + 1, instr(ename,' ',1,2)-instr(ename,' ',1,1)-1)

  end middle_name

  from (select 'asw nag raj' ename of double)

  Union

  Select "raj asw ght" double

  Union

  Select 'raj asw dfjadf Tom' from dual) e1;

• How to find the locaion of a particular column in a database

  Hi experts,
  
  I have the column name x. I want to know under what table it is present.
  
  
  What may be the syntx for sql.
  
  Thank you
  V

  select owner,table_name
  from all_tab_columns
  where column_name = 'XXX'
  /
  

  where XXX is the column name, looking for

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  Catalog/shared /..., but it is a binary file that is not sent to the customers.

  Hey kobe,.

  You can try this:

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• How to find the second largest in a pl/sql table

  Hello friends,
  
  I want to find the first and second maximum items in a pl/sql table.
  
  Here's the code...
  
  DECLARE
  Max_earnings_type TYPE TABLE IS NUMBER;
  max_earnings_tab max_earnings_type: = max_earnings_type();
  number of v_count: = 0;
  number of v_max_earnings;
  
  
  Can someone give me how to find the maximum first max and second in the type of the given table.
  
  appreciate your help.
  
  Thank you/kumar
  
  Published by: kumar73 on October 21, 2010 09:42

  kumar73 wrote:

  When I tried to implement your logic in my application, I get the following error...

  PL/SQL: digital or value error: NULL index key value table

  What happens if the PL/SQL table has NULL values. Question is how you want to handle NULL values. You want to ignore nulls as GROUP BY do? If you want to consider NULL values, you can say if you want to order the NULLS FIRST or NULLS LAST. I guess that logical GROUP BY:

  DECLARE
      TYPE max_earnings_type IS TABLE OF NUMBER;
      TYPE max_earnings_sorted_type IS TABLE OF NUMBER
        INDEX BY BINARY_INTEGER;
      max_earnings_tab        max_earnings_type;
      max_earnings_tab_sorted max_earnings_sorted_type;
  BEGIN
      SELECT  sal + comm
        BULK COLLECT
        INTO  max_earnings_tab
        FROM  emp;
      FOR v_i in 1..max_earnings_tab.count LOOP
        IF max_earnings_tab(v_i) IS NOT NULL
          THEN
            max_earnings_tab_sorted(max_earnings_tab(v_i)) := 1;
        END IF;
      END LOOP;
      DBMS_OUTPUT.PUT_LINE('MAX value in PL/SQL table is ' || nvl(to_char(max_earnings_tab_sorted.last),'NULL'));
      DBMS_OUTPUT.PUT_LINE('Second MAX value in PL/SQL table is ' || nvl(to_char(max_earnings_tab_sorted.prior(max_earnings_tab_sorted.last)),'NULL'));
  END;
  /
  MAX value in PL/SQL table is 2650
  Second MAX value in PL/SQL table is 1900
  
  PL/SQL procedure successfully completed.
  
  SQL> SELECT  sal + comm
    2    FROM  emp;
  
    SAL+COMM
  ----------
  
        1900
        1750
  
        2650
  
        1500
  
    SAL+COMM
  ----------
  
  14 rows selected.
  
  SQL>
  

  SY.

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  Hi all

  How to find the first Sunday and the second Saturday of each month

  Thank you

  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

  994122 wrote:

  Hello

  I need to pass the months parameter how to do this? like Jan, Feb etc... (one of those)

  Do you have a procedure?

  Should you output only for the months you passed in the parameter?

  The easiest way is to set the parameter as date. When you go such as p_date as DATE ' 2014-10-01', then you can

  PROCEDURE two_dates)

  p_date IN DATE

  p_first_sunday DATE

  p_second_saturday DATE

  )

  IS

  BEGIN

  p_first_sunday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-12', 'DAY'));

  p_second_saturday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-11', 'DAY')) + 7;

  END two_dates;

  Or you describe what you need.