How to get information from my old iPod to my mac

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  How to get information on the parameters (names and types etc.)

  Concerning

  Hello

  SQL > create or replace procedure proc (tes1 number) start the null; end;
  2.

  Created procedure.

  SQL > desc proc
  Proc PROCEDURE
  Name of default input/output argument type?
  ------------------------------ ----------------------- ------ --------
  TES1 NUMBER IN

  Are you referring to the right parameters of proc right?

  Think simple

  -Thank you

  Pavan Kumar N

• get information from inside a trigger of the other tables in the schema even

  Addendum:
  
  ... Sorry I forgot: Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64 bit
  
  *******************
  
  Hello
  
  I'm trying for a few hours to get information from inside a trigger to another table in the same pattern.
  
  My trigger is PSE_BKB. NUM_PHANTOM_BP
  
  I first tried a simple solution...
  
  
  CREATE OR REPLACE TRIGGER PSE_BKB. NUM_TR_PHANTOM_BP
  BEFORE DELETING, INSERTION OR UPDATE
  ON PSE_BKB. NUM_PHANTOM_BP
  REFERRING AGAIN AS NINE OLD AND OLD
  FOR EACH LINE
  DECLARE
  
  v_recht NUMBER (1): = 0;
  v_recht2 NUMBER (1): = 0;
  v_change_mitarbeiter NUMBER (1): = 0;
  v_recht_mitarbeiter NUMBER (1): = 0;
  v_typ varchar2 (20);
  v_obj_key varchar2 (11): = "gugus";
  v_ph_key varchar2 (11);
  -ph_key varchar2 (11);
  v_obj_keys varchar2 (4000): = ', ';
  
  anz_num NUMBER: = 0;
  anz_num_tmp NUMBER: = 0;
  anz_st_si NUMBER: = 0;
  
  
  BEGIN
  
  ...
  Select count (*)
  in anz_num
  of pse_bkb.num_objekt o
  where o.obj_key in
  (select distinct (ov.obj_key)
  of pse_bkb.num_objekt_verb ov
  where ov.phantom_key =: old.phantom_key
  )
  and o.typ = "NUM";
  
  ...
  
  Explanation: my trigger table is PSE_BKB. NUM_PHANTOM_BP.
  
  On the pse_bkb.num_objekt_verb of the table, I have a relationship 1: n to one or several object-key (field named obj_key!) on my referenced key: old.phantom_key. With this obj_key, I want to watch the weather, I have one or more lines in the table type num_objekt "NUM". So the internal selection gives me all the num_objekt_verb obj_key with my: old.phantom_key and with whom I count the number of lines I have on num_objekt with type "NUM".
  
  The problem is that the trigger does not see the table.
  
  I tried many variations.
  
  The latest version I tried was with a cursor inside the trigger definition as in the block of code below.
  
  For debugging purposes, I inserted a RAISE_APPLICATION_ERROR in the inner loop - see below. The v_obj_key variable is never defined, as in all the other variations, I tried-, I still see the predefined "gugus" in the declare section.
  
  It seems that oracle can not read other tables at this point. La: old.phantom_key is defined (in this simple example there would come a return obj_key).
  
  Thanks in advance for your help - and excuse my English.
  
  Trigger code:
  
  CREATE OR REPLACE TRIGGER PSE_BKB. NUM_TR_PHANTOM_BP
  BEFORE DELETING, INSERTION OR UPDATE
  ON PSE_BKB. NUM_PHANTOM_BP
  REFERRING AGAIN AS NINE OLD AND OLD
  FOR EACH LINE
  DECLARE
  
  v_recht NUMBER (1): = 0;
  v_recht2 NUMBER (1): = 0;
  v_change_mitarbeiter NUMBER (1): = 0;
  v_recht_mitarbeiter NUMBER (1): = 0;
  v_typ varchar2 (20);
  v_obj_key varchar2 (11): = "gugus";
  v_ph_key varchar2 (11);
  -ph_key varchar2 (11);
  v_obj_keys varchar2 (4000): = ', ';
  
  anz_num NUMBER: = 0;
  anz_num_tmp NUMBER: = 0;
  anz_st_si NUMBER: = 0;
  
  
  BEGIN
  
  
  Start
  declare
  
  cursor nums is
  
  Select obj_key
  of PSE_BKB.num_objekt_verb
  where phantom_key =: old.phantom_key;
  
  Start
  
  for the RC looping nums
  v_obj_key: = cr.obj_key;
  
  RAISE_APPLICATION_ERROR (-20099,' AGAIN 9 v_obj_key: ' | v_obj_key |) ': old.phantom_key ' | (: old.phantom_key);
  
  When the exit nums % NOTFOUND;
  
  Select count (*) in the pse_bkb.num_objekt anz_num_tmp where obj_key = v_obj_key and type = "NUM";
  anz_num: = anz_num + anz_num_tmp;
  end loop;
  
  end;
  end;
  
  Published by: user832075 on 14.01.2013 06:18

  The reason why you get count_n = 0 in tr_c is that there is no line in B with key_c = 17, to the moment you arrive at tr_c. The removal of B has already occurred, and since you're in a single transaction, the application for tr_c:

  select count(*)
    into   counter_n
    from   a aa
    where  aa.key_a in (select distinct(bb.key_a)
                        from   b bb
                        where  bb.key_c = v_ph_key
                       )
    and    aa.typ = 'n';
  

  'knows' that the row has been deleted then gets a number of 0.

  I added a set of instructions dbms_output to show the order in which triggers run, and that's what I get:

  SQL> delete from b_vw where key_a = 1 and key_c = 17 ;
  in trigger b_tr_vw
  In tr_b
  in tr_c
  delete from b_vw where key_a = 1 and key_c = 17
              *
  ERROR at line 1:
  ORA-20077: Remark: counter_n: 0 counter_s: 0 v_ph_key: 17 old.key_c: 17
  new.key_c:
  ORA-06512: at "OPS$ORACLE.TR_C", line 38
  ORA-04088: error during execution of trigger 'OPS$ORACLE.TR_C'
  ORA-06512: at "OPS$ORACLE.B_TR_VW", line 17
  ORA-04088: error during execution of trigger 'OPS$ORACLE.B_TR_VW'
  

  Thus b_tr_vw trigger is triggered first and deletes a B. trigger fires tr_b as part of this statement to remove and check against A, happening apparently so no error is triggered and succeeds the removal of B. Now tr_b_vw takes back control and deletes C. Since the B line which has key_c = 17 already deleted a control for counter_n > 0 and counter_s = 0 fails and raise you the-20002 error. Note that I'm assuming that the error of-20077 you lift is just to see the values and is not intended to be part of your actual code.

  Because I have really no idea what you're trying to accomplish here I can't offer a lot of advice that you might want to try entering two tr_c of the tr_b_vw trigger validation queries before deliver you the removal of b and put the counter_n > 0 and counter_s = 0 control under tr_b_vw to decide whether or not you want to remove.

  John

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