How to get report ATML6.01 callerName-property

Similar Questions

• How to get the reference or the property of a member in OOP node?

  Hello world

  Is it possible to get the referral of a member in OOP?

  After you have created a class and an insert, a member of control in the cluster, I conclude that, when a right click on it, there is no element of "creat-> reference" or "create-> property node?

  So, how to get the reference or the property of a member in OOP node?

  Hello

  There are a few reasons that you can't do what you want to do:

  1 al ' LVOOP ordinary (as opposed to the DVRS in LabVIEW 2009, or some other framework / pattern design) are items of LabVIEW by value, as a cluster and therefore you can not create a reference to a class.

  2. a control of the object (this is what you get when you drop an object on a façade) is a 'black box' because you cannot look inside. This is to support the idea that the class data private. This means that you can't get a reference to all internal control when its on a façade

  3. check the references are valid only for the controls in the Panel before and therefore any class (or other piece of data of LabVIEW) on a wire / shift register / constant / anywhere other that of the façade, will have only the data portion of the available control.

  To access the items within a class, you create the accessor screws (you can create them easily by right-clicking a class (or the folder within the class) in the project tree and selecting New-> VI to access data members.) This VI would at least have a unbundle / bundle node (depending on whether its read/write) and could, if you have many more features such as range checking. You can use this VI whenever you want to read the Member your interested.

  I hope this helps.

  Shaun

• How to get the value of the property and the hierarchy specified in a global property, by javascripts

  Hi DRM team:

  I want to get a property value and precise when the hierarchy from. So, I thought that LocalNodeObjects method GetReferenceInHier (hierAbbrev), but the question is coming, I'm working on a global property, node. GetReferenceInHier (hierAbbrev) is not available. How can I get the value of the specified node hierarchy?

  Thanks for any response.

  Jim

  Hi Jim.cyciopes

  Try this-

  var worm is node. Version;

  var hier_ref = worm. HierByAbbrev ("name of your hierarchy");

  var node_ref is hier_ref. NodeByAbbrev (node. ABBREV);

  {if(node_ref!=null)}

  var propval is node_ref. VarValeurProp ("YourPropertyName");

  }

  Return propval;

  Thank you

  Denzz

• How to get the maximum number of iterations in the property of TS

  I was put the loopType from one step to the count of success/failure. For example "stop after 1 iterations pass or a maximum of 3 iterations. The maximum iteration is 3. What my qustion is how to get the maximum iteration of TS property by codes of trial during the race. Thank you very much!

  Corey Chen

  The OPPO test developer

  Hello

  It may be a hack, but RunState.Step.LoopWhileExpression has information.  It will return a string like: "RunState.LoopIndex."< 69="" &&="" runstate.loopnumpassed=""><>

• How to get the device Diagnostic report?

  Hi guys.

  Do you know how to get the device Diagnostic report?

  Is this possible on a Simulator?

  Thank you.

  Hi guys.

  I found the way how to get.

  It's easy.

  In order to get the diagnostics test report, go to Options / settings-> Network Mobile-> select "diagnostic test" in the menu-> then 'run '.

• How to get a column on the road report

  Hi all

  I have a table that has a leave_start_date and leave_end_date of separate columns. Now, I want to create report to list the employee who took part in some days. I want to show it to every weekend (Friday as weekend bu using NEXT_DAY (TRUNC (to_date (start_date), 'IW'), 'FRIDAY')). There are employees who get up early for most of the week, or in some cases more than a month. so now, I want to show that those who leave details for each weekending. I don't know how to get every weekend for leaves starting November 7, 14 and end 21 January 2014.

  can anyone help me please with the query to get the column weekends like

  ENAME	LEAVE_START	LEAVE_END	End of WEEK
  JOHN	AUGUST 31, 2014	21-SEP-2014	AUGUST 29, 2014
  JOHN	AUGUST 31, 2014	21-SEP-2014	05-SEP-2014

  ......

  ENAME	LEAVE_START	LEAVE_END	End of WEEK
  JOHN	AUGUST 31, 2014	21-SEP-2014	20-SEP-2014

  .

  Thanks in advance

  Something like that... ?

  with min_max_dates like)

  Select min (LEAVE_START_DATE) min_LEAVE_START_DATE, max (LEAVE_END_DATE) max_LEAVE_END_DATE

  of Leave_details

  )

  -Make all dates for the weekend Fri, sat and Sun for the max min above range

  , weekend_dates as (select case when to_char (level - 1, 'Dy' + min_LEAVE_START_DATE) in ("sat", "Sun", "Sat") then min_LEAVE_START_DATE + level - 1)

  otherwise null terminator weekend_date

  of min_max_dates

  connect by level<=>

  )

  Select ld.ename, ld.leave_start_date, ld.leave_end_date, wd.weekend_date

  of ld leave_details

  weekend_dates WD

  where wd.weekend_date between ld. LEAVE_START_DATE and ld. LEAVE_END_DATE

  and ld.ename = "JOHN".

  order by ename, weekend_date

  ;

• How to get a ledger_id before release of the report by using FND_PROFILE. Value

  Hi all, I am developing a customized using 10 g generator report. How can I get Ledger_id before release of the report by using FND_PROFILE. VALUE(). I tried with this V_LEDGER_ID: = FND_PROFILE. VALUE('GL_SET_OF_BKS_ID'). But it does not work. Please let me know how to get the legder_id using FND_PROFILE. VALUE before release of the report. Thanks, I'm glad.

  What version of oracle apps?

  have you used the user exist in your report?

  Try using the outputs of the user and P_CONC_REQUEST_ID

• How to get the checkbox value when value list changed in the classic report

  Hello
  I worked with apex 4.2 and I create normal classic report with a checkbox column and a single column change to select list (named loved) now, when I want change to user list
  take the value of the checkbox element and display it in the message.
  
  SQL for the report
  
  {
  SELECT
  "" "< INPUT TYPE ="checkbox"NAME ="f01"VALUE =" "
  || SEQ
  |'">"SEQ, "
  ID,
  DEPT_NO,
  EMP_NAME} I change the column attributes of Dept_NO to display as the selection of the name of the Department (named lov) list.
  
  now, I want when change of user name of the Department, the value of the MESSAGE ALERT SHOW IN SEQ
  
  I create JavaScript on the page
  
  function test (pThis) {}
  var f01_value = $('select[name="f01"]').value;
  
  Alert ("#SEQ:" + f01_value);
  
  }
  < /script >
  I call this javascript function when the change in the list, but the value undefined...
  
  My Question:
  
  How can get this value or any value of the point in reports
  
  concerning
  Ahmed

  Hello
  Check your page now.

  As mentioned earlier, you must use APEX_ITEM. CHECKBOX2.

  APEX_ITEM.CHECKBOX2(2,EMP.EMPNO,null,null,null,'f02_'||lpad(ROWNUM,4,'0')) NO,
  

  And the javascript function will be

  You cannot use $v to get the value of the checkbox element such that it works differently for the boxes, see http://docs.oracle.com/cd/E37097_01/doc/doc.42/e35127/javascript_api.htm #BGBGDGIH.
  Therefore, you use the jQuery val().

  See you soon,.

• How to get the values of the cells of an interactive report?

  Hello
  
  We use the APEX 4.0, with Oracle 10 g r2 on Windows XP.
  
  I have a page with an interactive report, and I configured the "link" column to link to a target custom (instead of see a row).
  This custom target is simply a call to a function of ajax (I hope!) view more information (in another region) on the clicked folder.
  
  I think I have to display the primary key in the report and then get the value of call my function as:

  javascript:my_function(ID);

  to be able to find the information right on the straight line.
  
  But, how to get the value?
  
  Kind regards.
  
  Yann.

  Hello
  Got to the report attributes tab and scroll down to the section of the link column. Click on the lightning bolt next to the column value, a popup displays Columsn names in reports of each locked in a pair of #.

  You pass the column for your javascript like this function

  
  javascript:my_function('#ID#');
  

  Kind regards

• How to get rid of this redundant column in report

  I'm with a simple query using report 6i but having problems to get the format I want. If someone can give me a heads up, I would be very grateful.
  
  I used the report with the following query wizard
  Select fis_year, pay_no, check_amt and pay_date of table A
  
  set up 2 groups
  Group: G_fis_year
  Group: G_pay_no
  Sum (check_amt) at G_fis_year
  Sum (check_amt) at G_pay_no
  
  These are the test data
  data:

  fis_year,pay_no,  check_amt,pay_date
  2009,     001,     345,     01/02/2009
  2009,     001,     786,     01/02/2009
  2008,     002,     678,     03/08/2008
  2008,     003,     789,     06/04/2008

  }
  
  power required:
  

  fis_year   pay_no    total_check_amt  check_date   
  2009          001     1131             01/02/2009 
  
  
  2008          002     678           03/08/2008
            003     789          06/04/2008 

  But I'm getting
  

  fis_year   pay_no    total_check_amt  check_date   
  2009          001     1131             01/02/2009 
                           01/02/2009   ===> how to get rid of this redundant date when they are the same
  
  2008          002     678           03/08/2008
            003     789          06/04/2008 

  wanwan

  Hello
  Report style: left group

  You can use this query:

  Select fis_year, pay_no, pay_date, sum (check_amt)
  the name of the table
  Group of pay_date, fis_year, pay_no
  order of pay_no

  Page layout:
  create report wizard-> write the query select fis_year--> then click then--> select remaining all the fields and click Next
  after u, compile and run the report, you will get you are out.

  * in the data model first group g_fis_year--> fis_year column properties--> order of break must be DESCENDING.

  Answer me after that u got the output

• How to get the required column, the names of tables for the preparation of the report.

  Based on the MD50 how to get the exact name, the table names he joined for report development. as I am new on this project and the purchase of failet for R12.
  How can I start my approach to prepare the data for the report model? How can I search the database based on the respective diagrams of means?
  all input appreciated

  Hello

  You can find information about schema objects in eTRM Web site, you can also consult the documentation for product/module and see if it helps. If you already have any report (standard or custom), you can enable the trace and run the program to see which object it access or open the report using Report Designer and see the code.

  ETRM Oracle
  http://ETRM.Oracle.com

  Oracle Applications documentation
  http://www.Oracle.com/technology/documentation/applications.html

  Kind regards
  Hussein

• How to get the property of the image on the width and height?

  Hi, all, I import image from the outside with the following method, but how to get the w3c_main.png on the width and height property? I will appreciate for your answer.
  
  var mcLoader = new MovieClipLoader()
  mcLoader.loadClip (" http://www.w3.org/Icons/w3c_main.png", image);
  
  or an image. LoadMovie (" http://www.w3.org/Icons/w3c_main.png")

  in the first case use the method onLoadInit() to a listener for your mcl before trying to access your target movieclip laborious and _height properties.

  in the second, use the preloader code to ensure your png loading is completed before attempting to access the _width and _height of your target movieclip properties image.

• How can I report a hacked account to get my money back

  I was sent from iPhones that are not mine. think I was hacked, how do I report it and request a refund

  iTunes Store-what to do if your account has been compromised

• How to get the vertical alignment of a container property?

  Hi all

  I have a container in QML, I put his property in qml. And get anything by comparing the property in the CPP, the application crashed.

  I know what I'm doing wrong. This is the line where it crashes.

  if(detailContainer->verticalAlignment() == VerticalAlignment::Bottom){
  ..
  ..
  }
  

  It was the container root in QML.
  I was able to check alignment in QML but not in the PRC.
  As a child container I can acess it.

• How to get distinct records by using the ListAgg OBIEE report function?

  Hi all

  I get a correct result as mentioned below. But I don't see duplicates in my result here, in my example, I get duplicate for the name of the employee 'Pat '. So how to get Distinct values by using the LISTAGG function?

  Data set of sample with the Department and its employees

  Service employee

  ----------      ----------

  Marketing Michael

  Pat of marketing

  Pat of marketing

  Pat of marketing

  Purchase of Den

  Purchase of Alexander

  Purchase of Shelli

  Purchase of Sigal

  Guy of purchase

  Purchase of Karen

  Using the ListAgg function, we can convert it to:

  Employees of the Department

  -----------     -------------------------------------

  Marketing of Pat, Pat, Pat, Michael

  Purchase of Sigal, Shelli, Karen, Guy, Den, Alexander

  I tried a lot of things, but I'm not able to understand how exactly this can be achieved, if anyone has any idea or suggestions please do share, thanks in advance.

  After much research, I found the solution & I want to share what he finds very useful, we can create SQL logic in the Advanced tab, as below and after you click Rescan, and then you will get your desired results.

  SELECT saw_0, Evaluate_Aggr T1.dept ("ListAgg(%1,'' & '') intra group (about 1%)") ("as long as VarChar (1000), T1.emp) saw_1 FROM)

  SELECT 'emp_dept '. "the Department dept,

  'emp_dept '. "' employee ' emp

  IN THE "DOMAIN".

  GROUP BY dept, emp

  ) T1 GROUP FROM T1.dept ORDER BY saw_0

  Also note here that we have good anti-aliasing for columns parent (ex: saw_0, saw_1), another by mistake oracle bi server.